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Closed 10 years ago.
I want to code this part of a VB6 application in c#.
How can I change a long into a Hex value?
Public Function longToHex(l As Long) As String
longToHex = Hex(l)
If Len(longToHex) < 4 Then longToHex = String(4 - Len(longToHex), "0") & longToHex
longToHex = Right(longToHex, 2) & Left(longToHex, 2)
End Function
Just format to a padded hex string:
string.Format("{0:X4}", myLong.ToString().Length / 2)
Then transpose the first two characters with the last two.
The VB6 code appears to take the length of sData divided by 2, then converts the length to a Hex string and pads it with 0s to 4 characters if needed. It then transposes the first two characters with the last two.
Seems convoluted -- what is the code supposed to do? Half the length of the string in hex?
This might work: sLen = (sData.length / 2).ToString("X")
Related
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Closed 9 years ago.
I need to put a comma before the last char of a string.
For example:
Input: 101919 = Ouput: 10191,9
What is the best way to do that?
if (input.Length > 0) { input = input.Insert(input.Length - 1, ","); }
With the insert method
strTarget = strTarget.Insert( srtrTarget.Length -1, ",");
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I am currently working on a console text analysis program for an assignment.
My problem is, I need to save all user entered words above 7 letters to a text file. The user can enter words by typing in their paragraph or by loading from a text file.
Any ideas on how I can do this ?
Thanks for any help in advance
Without giving you the code, think about what you really need to do.
Read in the entire text.
Split the text based on spaces / punctuation to identify each word. This will be stored in an array.
Test each split string's length.
Write the results to a file.
I'm not sure how you're getting the user-entered words, but you can do a simple LINQ statement to get the words greater than 7 letters:
//get all words into an array (wordArray)
var bigWords = wordArray.Where(w => w.Length > 7).ToArray();
Then you do something with the bigWords array.
I'm not going to do your assignment for you.
You should check functions such as String.Split, String.Length and String.Substring()
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Closed 10 years ago.
I'm porting a c++ class to C# and i have a difficulty.
I would like to find an equivalent of SpanIncluding.
Here is my cpp code :
while (Notes.Mid(j,1).SpanIncluding("0123456789").IsEmpty()!=NULL){}
Anyone can help me please ?
I believe SpanIncluding starts matching from the start of the string, stopping when the first non-matching character is found.
So one formulation in the general case would be this:
string match = new string(someString.ToCharArray().
TakeWhile(c => "0123456789".Contains(c)).ToArray());
(or an equivalent using a regular expression).
However, in the example given in the question there's only one character so the whole thing probably boils down to a test of whether this character is >= '0' and <= '9':
while(char.IsDigit(Notes[j])) { ... };
I found the MSDN page for SpanIncluding, and it seems like a ridiculously specific function. I can't really understand what it tries to solve, since it has some strange caveats.
LINQ would be one way of implementing it:
string text = "2334562";
IEnumerable<char> spannedChars = text.TakeWhile(c => "1234567890".Contains(c));
This is a more direct port of SpanIncluding than queen3's option, if I understand the MSDN page correctly, because the result set should stop the minute it hits a character not in the spanning string.
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Closed 10 years ago.
I need to convert a char to an int and back.
Here's what I'm using to convert the char to an int:
(char)65 // Returns 'a'
Here's what I'm TRYING to use to convert it back:
(int)'a' // Returns 97
Any ideas what I can do?
try this,
char x = 'a';
int y = (int)x;
65 is the character code for a capital 'A'. 97 is a lower case 'a'.
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I have got a regular expression which I want to be able to accept characters upto a minimum length of 11 characters as against 16 which is the case at the moment.
^[A-Za-z]{6}[0-9LMNPQRSTUV]{2}[A-Za-z]{1}[0-9LMNPQRSTUV]{2}[A-Za-z]{1}[0-9LMNPQRSTUV]{3}[A-Za-z]{1}$
Can some one please suggest the changes?
Thanks
Each {6} gives you the number of character you're expecting, here 6 for your 1st expression.
If you want a range of number of characters, do something like this : {1,6} and it will accept 1 to 6 characters at the beginning of your regex.
Which will give you from 11 to 16 characters in your Regex.
{n} - preceeding symbol (template) is expected to appear exactly n times
{min,max} - preceeding symbol (template) is expected to appear exactly minimum min times but not more than max times
Hope this helps you)