I have a 2-dimensional array like below.
If I want to sum all time and score of rows of Each ID that start from lesson startpoint=E and ends by lesson endspoint=I. In the case below, for ID 1 it become (time=190+195+200=585 and score=3+3+4=10) and ID 3 that (time=190+210+160=560 and score=5+4+4=13).
I already came up with following loop.
ID Lesson Time Score
1 C 165 4
1 E 190 3
1 H 195 3
1 I 200 4
2 A 100 2
2 B 150 5
2 D 210 2
2 E 110 4
3 D 130 5
3 E 190 5
3 H 210 4
3 I 160 4
3 J 110 4
4 E 120 3
4 H 150 4
4 J 170 4
-
for (int i=0; i<SizeofDataGrid;i++)//save datatable into array
{
for (int j=0; j<4;j++)
{
FILTERED[i,j]=Convert.ToString(interaction.Rows[i][j]);
}
}
for (int i = 0; i < FILTERED.GetLength(0); i++)
{
string UNIQUEID = UniqueUserId[i];
for (int j = 0; j < SizeofDataGrid; j++)
{
if (UNIQUEID == FILTERED[j,0])// match ID
{
for (int x = 0; x < SizeofDataGrid; x++)
{
if (startpoint == FILTERED[j, 1]) //Match start Lesson
{
TotalTime[1, i] = TotalTime[1, i] + Convert.ToUInt16(FILTERED[j, 2]);
TotalTime[0, i] = i;
TotalScore[1, i] = TotalScore[1, i] + Convert.ToUInt16(FILTERED[j, 3]);
TotalScore[0, i] = i;
}
}
}
}
}
Try this:
// this method does the calculations then puts the values in the totalScore and totaltime variables
public void DoCalculations(string[,] data, string id, out int totalScore, out int totalTime)
{
totalTime = 0;
totalScore = 0;
for (int i = 0; i < data.GetLength(0); i++)
{
if (data[i, 0] != id) continue;
// modify this string to contain the lessons between E and I
if (!"EFGHI".Contains(data[i, 1])) continue;
// do proper error checking unless you're sure they'll always be integers
totalTime += int.Parse(data[i, 2]);
totalScore += int.Parse(data[i, 3]);
}
}
And this is the usage example:
string[,] data = new string[,]
{
{"1", "C", "165", "4"},
{"1", "E", "190", "3"},
{"1", "H", "195", "3"},
{"1", "I", "200", "4"},
{"2", "A", "100", "2"},
{"2", "B", "150", "5"},
{"2", "D", "210", "2"},
{"2", "E", "110", "4"},
{"3", "D", "130", "5"},
{"3", "E", "190", "5"},
{"3", "H", "210", "4"},
{"3", "I", "160", "4"},
{"3", "J", "110", "4"},
{"4", "E", "120", "3"},
{"4", "H", "150", "4"},
{"4", "J", "170", "4"}
};
// will store the total score
int totalScore = 0;
// will store the total time
int totalTime = 0;
// calling the function for the id=3
DoCalculations(data, "3", out totalScore, out totalTime);
Console.WriteLine(totalTime); // will output: 560
Console.WriteLine(totalScore); // will output: 13
Do you know about the break statement? You should be able to create a conditional statement that checks for your condition, then put break; at the bottom of it and you will exit the loop.
I would try to avoid using string[,] FILTERED to store your data. You really can easily create strong data types instead. However, if you must use it then I would convert to a strong data type and then do the calculations.
So, starting with the raw data:
string[,] FILTERED = new string[16, 4]
{
{ "1", "C", "165", "4" },
{ "1", "E", "190", "3" },
{ "1", "H", "195", "3" },
{ "1", "I", "200", "4" },
{ "2", "A", "100", "2" },
{ "2", "B", "150", "5" },
{ "2", "D", "210", "2" },
{ "2", "E", "110", "4" },
{ "3", "D", "130", "5" },
{ "3", "E", "190", "5" },
{ "3", "H", "210", "4" },
{ "3", "I", "160", "4" },
{ "3", "J", "110", "4" },
{ "4", "E", "120", "3" },
{ "4", "H", "150", "4" },
{ "4", "J", "170", "4" },
};
I would first turn this into strongly-type data:
var data =
FILTERED
.Cast<string>()
.Select((x, n) => new { x, n })
.GroupBy(xn => xn.n / 4, xn => xn.x)
.Select(xs => new
{
ID = int.Parse(xs.ElementAt(0)),
Lession = xs.ElementAt(1),
Time = int.Parse(xs.ElementAt(2)),
Score = int.Parse(xs.ElementAt(3)),
});
This gives:
I would then do this query:
var result =
data
.GroupBy(x => x.ID)
.Select(xs => new
{
ID = xs.Key,
Lessions = xs
.Where(x => x.Lession.Intersect("EFGHI").Any())
.ToArray(),
})
.Select(x => new
{
x.ID,
Time = x.Lessions.Sum(y => y.Time),
Score = x.Lessions.Sum(y => y.Score),
})
.ToArray();
That gives me this result:
Now, just as an alternative to mucking around with the intermediate FILTERED array you could just get the data directly from the DataTable like this:
var data =
from row in interaction.Rows.Cast<DataRow>()
select new
{
ID = row.Field<int>(0),
Lession = row.Field<string>(1),
Time = row.Field<int>(2),
Score = row.Field<int>(3),
};
The Peptide Encoding Problem consists on Finding substrings of a genome encoding a given amino acid sequence.
The genetic code describes the translation of an RNA 3-mer (codon) into one of 20 different amino acids. The first three circles, moving from the inside out, represent the 1st, 2nd, and 3rd nucleotides of a given codon. The 4th, 5th, and 6th circles define the translated amino acid in three ways: the amino acid’s full name, its 3-letter abbreviation, and its single-letter abbreviation. Three of the 64 total RNA codons are stop codons, which halt translation and implicitly add a 21st stop symbol to the amino acid alphabet.
The problem consists on having
Input: A DNA string Text and an amino acid string Peptide.
and
Output: All substrings of Text encoding Peptide (if any such substrings exist).
Sample Input:
ATGGCCATGGCCCCCAGAACTGAGATCAATAGTACCCGTATTAACGGGTGA
MA
Sample Output:
ATGGCC
GGCCAT
ATGGCC
the result is gotten by reading triplets so, ATGGCC encodes MA, GGCCAT inverse would be CCGGTA written backwards so it is in fact ATGGCC (CCGGTA.reverse)
the complement of genetic code is C-G, G-C, T-A and A-T
So to solve this problem I first use already defined arrays
using System;
using System.Collections.Generic;
using System.Text;
using System.Text.RegularExpressions;
using System.Linq;
using System.IO;
using System.Collections;
class Program
{
private static string[] CODONS = {
"TTT", "TTC", "TTA", "TTG", "TCT",
"TCC", "TCA", "TCG", "TAT", "TAC", "TGT", "TGC", "TGG", "CTT",
"CTC", "CTA", "CTG", "CCT", "CCC", "CCA", "CCG", "CAT", "CAC",
"CAA", "CAG", "CGT", "CGC", "CGA", "CGG", "ATT", "ATC", "ATA",
"ATG", "ACT", "ACC", "ACA", "ACG", "AAT", "AAC", "AAA", "AAG",
"AGT", "AGC", "AGA", "AGG", "GTT", "GTC", "GTA", "GTG", "GCT",
"GCC", "GCA", "GCG", "GAT", "GAC", "GAA", "GAG", "GGT", "GGC",
"GGA", "GGG", };
private static string[] AMINOS_PER_CODON = {
"F", "F", "L", "L", "S", "S",
"S", "S", "Y", "Y", "C", "C", "W", "L", "L", "L", "L", "P", "P",
"P", "P", "H", "H", "Q", "Q", "R", "R", "R", "R", "I", "I", "I",
"M", "T", "T", "T", "T", "N", "N", "K", "K", "S", "S", "R", "R",
"V", "V", "V", "V", "A", "A", "A", "A", "D", "D", "E", "E", "G",
"G", "G", "G", };
private static string[] AMINO_ABBREVIATIONS = {
"F", "L", "I", "M", "V",
"S", "P", "T", "A", "Y", "H", "Q", "N", "K", "D", "E", "C", "W",
"R", "G" };
private static string[] FULL_NAMES = {
"phenylalanine", "leucine",
"isoleucine", "methionine", "valine", "serine", "proline",
"threonine", "alanine", "tyrosine", "histidine", "glutamine",
"asparagine", "lysine", "aspartic acid", "glutamic acid",
"cysteine", "tryptophan", "arginine", "glycine" };
static void Main()
{
//then input is DNA
string dna = "TTCGAATCCGTATTGCTTTGGTTGGTTGAGAGAGCGACCTACATTGCTAGTCAGAATAGGTGATTCACACAAAGCTTAGCACCTGGGCAGCACCCCGTGATGTAAACCTATGGGAACTAAGGGAGTCCTGCGGTTTTAGCCAGCAAGCGAGCCGGCAGGAACACTCATACCATCGGACGCGTTTGACGCCTCCCCGGAAAGGAAGTATTTGAGCCTCATTATTACGTATTGCCCGTTAGTCGACAAATCAAGCCCTCGTACGCAGCTTATTCGTACGACGTGGAGGCGTTCCCACGGGCCTAACACGATTGGAACACCACCATAGTAGTGTGGTTCAAATACCTCCTTTGGAGATCTAGAGCTTCACTCTGATTCTAGAGGCAACTTTACAATCGCTCTACGAAATTGTATGGACATCATCAACCGGATATTCTGGGGCGGTAGAATTTCTTTTGTTCGAATCGCTCTAGGCCAGGATCAAATTAATTGAATTGCGGACTCAAGGATCGCGATAGCCGACACATCGGACGCTGTAGAAAGCCAGTCTCTGGATTTAATCCACCCTCTATGTTTGACAAAGCACTAAAACGGGATAGTTTCGGGTGGTATAAGTTTCCCAAGACGATTGCATCGCAATTCATCAACAACCATGAACTTACTGTTTTAGTACTTCCACACACCTTGTTAAATTACGCCTTTACTTCATGTTGCGGTGTGTGTTAGATAGTGTGCAGCTACAAGTCTACCGCCATCGCAGCTCGGGATACCGGCAGATGAGATGGTCCTGAGCTCGTACCGGACTCAAACTTTTTCCTTTACTACCTAGGAATCGCCCATGCGAATTTGTCGGACACACACCATTACATTAACGTCACAACAGCTACTGTTAGAATTTTGCTCTTGCAAATCCTGGAAAGAGTTAAAAAAACTCTTCCGCGCGCCAATAGGGTAAATAATAGATAGCCAGACGGCTGTAAGAGGTGATGACATTTGCAACAATCATGCTGTCGCATCTTCCGCAAGTTCATGTCGCGCCTAGGCAATGGATCTGCGAATGGGGGCCACGGGGTATGAACTACGGAATTCTAAGAAAGTTGCCATCCAGAGTTAAGGGTTTGAGGCTAGTTGCATCGCTGGTAACGAACTACCTCATTACTTGGACGCGCAGTGTGACTTCACTCCTGTATAGCGATGATGCCAAGCAGGAATTAGCAAATCTGAAGAGCGTTTCCAAACTGGCCACTTGGACTGACACCTATCGCGGGGGATTTCAGCGCGTGTCGCTCTCACATGAGAGCTGCCGTCAGGAGCGGTAGAGTTTAGAGAGGAATGCGACAAACTCCCTATTCACCTCTCTGGTGATGTAAGGATATTTACGCTTAGTTCTATGCCAGGCTTAGGGCCTCTCGGAACTTTGGTGAGTCCTTATTAATTGATGCTACCTCTCCCTTACCTTCGCCCCAAGTCACGTAGAAGTACTCAATCCTGCTACATGATAATCAAATATTTCCAACGTTGGGAAATCGGTGACATCACATACTAGTTAAGAAACCACTGTCAGTGAACTTATATCCGGGGGAGAAAATCTACTAACTTACATACGCTGTGCGAGCAGTTTTCATTATAAGAAAATATACTCCCGAGGTACCGCATCAAGCACGACATTCCCGGAGAGCATAACATTTCGGTGCACCTGCTTTTGTGCGCTTGCTTGCGGTTATTTATAAACTACGCACAAGGCGCAAACCGCAGTGCGCATGTTTTCTCCGCCTGGCTAGAACTCGACATTCTCGTCAACGCCAATCTATGTGAGAGGATTTAGACCTCTGTGAAAACGAGTCCCTCTATAGAATAAATACCCAGATGCCAATGGGGGTTCTATCCGATGGCAGTGCATGGAGTGGTGGCTCCAGATTAAGGATGAGGAGAGGTAAAGATAACAGTTCGGTCGCCACGACGCGTTGCCAATCGAAATATCAGTACTAAAAGGCCCACCGCTCCGCTTTAGTCCGACTTTACATCCTGTGGAAATTGTCGAACGGAGGCTACATCGGGCTATATGAGTGTGAAAACCTATACTTCTCGCGTCGTTACTCAGTGCCGGTCTCCTGTTTCCCCCAGTCTTACGTACCCTTATTGATATTTGCTTCACGTTGAAACGTCCTAACGCAGCGTAAAGAGGTGTTTGAACCTCATTACTATAAAATCGCGATCGAAGGTAGACTACATACGCAAACGCCGAAACCCTCAGTTGGCCTTGTTGCAAGTATGGAACGTTGTAAAATTTTTCCTAGACGTTGAGCTATCGGTACAAGGTCGTTAGCGTCCTTACCCTTCACTTATATGCCCGACAAAACGCGGGTCCTAGTGCAGTGGTGGGAGCTTGGAATCCCGCAATACAAGGACAACCTGTATCTCGTTCGGCGTTCCGCGATCACTCGATCCCGAACCACTCCAAGCCTGGTTGATCAGCAAAAGCGGAAGGATGGATAAAGGGCTACTGGTTAATGGATGTAAACTTCCAATGATGAAATCCTGGAAACGAGGGATCGGGTTACGGTGGCGAACGGGGTACGGCAACGTGGCTATCTAGAGCCCGACGTTACGACTCATGTACATGCTGCTACGTGGTTGAAGCTGACGTTCAGATGAAGCAGTACTGAGTCCTAGGGCTTACTACTACTCCAATAGGTCTGGCCGGCCAGATACAAAAGTTCGTGGCGGCTCACCCCCTTTCTGGCGGGTGTAGCTTGCTGACCGGTTTGCTCGATAACACAGGCTAGCGAATAGTAATGAGGTTCGAAAACCTCTTTCCAACGACTGAAAGGGTCTACACGAACTATCTACATTTCCCCGCCCATGTCCTTCCGTCTGGTTGCTTCTGGAGATCCTTTCGCATTATACCGCAGCGTAGTGGCTCTGGCATATATGAAAAAATCCTTCTGTGGGTATTTGTGCCATCACTTATTGTTCGTACCGATATGGGATTACAAGTGCGATGTGATAATAAGCGAAGAAGCCAACATGTTACACTGTTCATGCGCTCCGGGTAATGTGCGGGCACCATGCTCAGTTCCCGCTCGCAGTTGTCACTGTCCCTGTTTCGGCACCATAATCAACATTTCCACGGCCACGCTGGTGAATAACCGAGGATACCGAAGTACAGCAAGAATGAGAGCGGGACTCCTCCATCTGCTTGTAATACGCCTTCAAGATAGTCCATAAAACGGTCGGGGTCTTGTTTCGGACTAGCCGCTTTGAAACGGTGCATAGTTGTGTCAAGTGTGGACATTGGCTTTCTATCCTCGTCAGCGATCCTCGGAAAGACTCGGGCAGTCGCCCCGAATCGTAATTAGGTAGTAGTGCGGCTCAAAAACTTCCTTCGACCTAACCGCTATAATGTTCGTAGATATAAATTTCGTTTCAGTATTAACAGGCGCACCGTATATATACGGAATGGTGTCGCCCCATTAGCTGCTCGCCAATATTTATCTAAGACCGCGCGCGTCTAGCGCCTTTAGTAGTTGCACCCGAGTATAGTAATGGGGTTCGAAGACTTCCTTCGCAAGGCTGCCATACTGTATCACAAGTACTGACGGAGCCCCGGAGGAGTGCAGGATACGGCAAAGGAGACCATTACCGGGGCATGAGTCCAAGTTAGCCCGTTAGGTGAAGGACGCTGATACAATAGTGAATCCGTTACTGAAAGGTTTAGAAGACCGGGGGGCTCGCACTAGGTCCAAATATTATGAACCCTACTCCTGCAACTGAATTGGCCGTCCAGGCGATATTTAAAAGGGGTTACTAGCAGGTTCATCGGAGCCCGTACTCCTTCCGGGCATAGTCGTTCGACGGGTAGAAATTCATCCAGTCGTGCCGGATACCCCGAGAATACCCCTATTTTTTGATCCTTCACCATCATCGTCCGCGGACTCATCTAAGTACCTCAGACCGAAACTGTTATCGTAGCGAAGAGCGAACTCGAATGACATCGCTTGTCCAACAGGGAAAATATGTAAAGTATATGCAGATTATTATAGGAAGATCACAAACTCCATCGCGCCTAGGCCAAAGACTTGCCAGAACAACATCTCTTCCAGAGCAAGGAAGTGTTTGAACCTCACTATTATCGAGAGAAGTCCCATGAATTTATAATAGTGAGGCTCAAAAACTTCCTTCATCGTCGGGCGCTGGGGCGAGCTAGGCTTCCCTAGCCGTCATTACTGTACCCACGCCAAATATTATCGAGTATGACTACGAAGCCTTCACAAGGGGCTGCAGTAACAGACTAACTCACGCACACCGCAACTACTATCCTAAATTGAGTAAGAAAACCCTCGACTATAGCCCTTGAATTAAATTCGCTATTTAAGGAAGACCGCGCTTCCGCTCGCCCGCGTATAGTTTACCAGTCCCAAGAAACATGTGTGGCCAGCCTACCTGAAGAGCTGTGTAAAGATAGATTCTGACATCCTCAAAAAGAAGTTTTCGAGCCGCACTACTACGCACGGAGCTCCGTTATTCAAGGCATGTCGAAGTACAGCGTGGTGGCCTCTCCTGTTCTCCACCCCAGCTAAACCCACCTTGTTCGAATTCGCGCAACTGTATATGACATGAACACTTACAGGGGTTAGAAGTTACTGCAACCAAGATAGAGCTCGTCGAAGTAATAGTGCGGTTCAAAAACTTCCTTCAATTGGTCTCATCACTTAAATTTAAGAGCTATTGTGAGTACAGGTACGGATGCGGCTTCAGTGGATCTTCAGCATTCATTCCTTGTAGTAATGGGGTTCGAAGACTTCCTTGCCAGGGTACCAAACAAGTCTTGCGCATCCTCCTCCCTAAGGAGGTATTTGAACCCCACTATTACCCACGATAGAACATGCAGGGTTTGATAGTGGAACACCTTTTAGAATCTGGGGATAAATTCCCAGGACTAATGTATGGCTGTAGTAATGAGGTTCAAAAACCTCCTTTTCAGGTGGATCGCAGGCCGTGCTGCCTCACAAGCTGGGACGCCGTCCACGGTATAGCCGGCGTCGGCAGTTACTGTGAAATAGCGGAAACTCGATCCCAATATATCATCTTACGTTTGGCGCCCAATAGTCGCCCAGTACCCGTTGACAGTTCTTTAACTCGGCTTAGAACTACTAGACAGGTTCAACCGAACCTTGCCCTAGTTCCCACTCCCGTAATTCATTTGGGTTTGCATCTAGAATACTGGAGGGTGCATAGACGAAACGTGTACGTCGGAGAAAACGTAAGAAAATGACCTAGACTCATAGTAGTGAGGTTCGAAGACTTCCTTTCAGTGAAATCGATCCACCACTCGCCGCGAAGAGATAATAGCATAGAGCACAAGTGCGCGAGTAGAGAAAAAGGCTATCCCAACCGGGCACGTCCTTCGTGTTTGGCGTTTACATACGGCACCCCGTTTCTGCACGTTAACCGTCTAGTATCCAACGGTGGATGGCGGACGCTAGACTATAGATATGAGATATCGAGACCTGGAGCTGGGTGTGGCTGCAGCCCGGGTCATTGCGGGCTGTGAATTCAAGGGCATGTAAACAAGCGTATATCGAACAGTGGATGGGCACCTGCAATACTCACGGTAGAGTTAGCTCACAGGATTCACGTTGAGGACTATGAGTCCCTCTTCGCTAGCAGTCTGGGGGGATATGGAGTTTAATAGCTTGACGTAGTAATGGGGCTCAAACACCTCTTTGTGTGAGCACAGCTACTTGCATTAAGAGATTCTAAACAGCGATCATCTCGGCTATTTCGGGCCAGCCTTTTCGGCAGGATGTTATGTAGCATTTCTGGAAGCTTCCCCCTCGAATCTACTAGTGGTGAGAAGATGCCCCACCGATATTACTCTTTAATCTTGAGAAACCTAAAACCGATCTGACCTCAGACGGGCGGCTCCCACCCGAGGATAAACTCGTCAATAATAATGTGGCTCGAACACTTCTTTTCTCACTAGGCTTTTACGACACGCCACATGTATTTAAGCATCTACCTAACTTGTGTCTGCTGATATACAGCGCATTCTACGCCCAACCTACCAATTACTTCAACGTAGTGCGTGGCTAAAATTCAGGGGAGCTTCATCTCTGTCTTAATTTGAAGGTTCTTCCGGGGCGTTTGGGAATCTTCGTGCCTTTTGCGAGGTTAAGGTATCAAAGAAGTTTTCGAACCACATTATTACCGCCTTAAGCACCGGCGCATCCTGCTCGTGACAACTCTACCCTGCCCTGATAAAGGCACTGAACGTTCCAGAGAGTGCATCATTGACACGCGAGCAGGCCACAGTAGCCACAAGACGTATGGGTGATTATAGAATTGGTGGAGGTGTTGTTAACGATCAGGAGGACATTAGTGGGAGTTAGGAAAGACCCTATGTTCTCTCTATCGCGGACTTGTAACTTGACAAGCAAAAGGGTAAGAGAGCTGCACACCGAAGCAGGCCCTTCCTATACCTGTTTTTCCTACGCGTAGAGAGGAATCCAGAAAGGTGATAATTGGCATTCGATGAAAAAACAGTGTGCCACTGACTTAGTTCTATATGTGAAGAGCCTGTTAGCACGTGACGGCGGCCTTGGTATAGAGCCCTTAATGGTCTCCATCGCGTAGTAATGGGGCTCGAAAACCTCCTTACTTGGGATTGCGTGGCCTCCTTGTGAGTCATACACAAGGCTTAGGGCTATGGGGCGATACACTCCTTTTCGCGGCGCATGGGGCGGTGATGCCTACATAGTAGTAGTGACTGCCTTTCTGGGGGGCTATTTGTGGATGACCAACACCTGACCAGCGATGCAATCGCTAGGGGAGGTACACCTCTCATATGTTACAACAATCACCGAATTGTGTTTCGAATTCGAATCAAGTTTGCGGTGTCGACCAGATCTGGTCTTGCTGCCATACCGGGTTCGCCGCCTCCGGTGGATAGAACTGCATCTTAAGACATCTGGACCCAGCGGTAAGTAGCGGGAAGAGTTTAGAGTCATTCGTACAACTACAGGCTAAGGGCTTACTGGGGAGTTGTTGTAGGGCATAAAGATCGCCCCATGACTTTTCGTACTTTCCCCGATAGTTCACTCGCAGCGAGCTGCGGCTGGGCTTCGCCACACGAGTACGGGCAACATTTATCTCCTCTAATCACTGGGCACCGCGCGAGGAAATAGAAAACCCTAATCAGTGCTCATGGGCGCATCTATTGGTCTCCGCATGCACGATGCCGCGGAGTGCTTAGTTGTCCCTGCATAATCTTCGTAGATGTATAAGAGATTACCTATTTATTCGGTTTCGGTTCTAGACGTACCTTGCCGCATGAGTATAGGCTAATGAACTGAGTTGGCGCCAGAGGGAAAGGCATAATAATGCGGCTCGAATACTTCCTTAAGGAAGTATTCGAACCACATTACTAT";
//The given peptide
string givenPeptide = "KEVFEPHYY";
char[] givenPeptideArray = givenPeptide.ToCharArray() ;
string codon="";
string auxCodon="";
string convertedCodon = "";
string clean = "";
int pivot = 0;
int foundFlag = 0;
string cleanReverse = "";
int foundFlagReverse = 0;
string convertedCodonReverse = "";
//so the idea I was working was to loop dna string until getting to 3*givenPeptide.Length
//because dna is red 3 by 3...
//then get givenPeptide.Length and compare each char of given peptide with encoded
//letter of scanned triplet
//so for example first givenpeptide is 'M' so I would search for 'ATG'
//then, if found increment a counter and then search for next 'GCC' etc...
//however When testing with longer string I do not get complete result
//I have
for (int pos = 0; pos < dna.Length - (3*givenPeptide.Length) ; pos++) {
pivot = pos;
for (int codonPos = 0; codonPos < givenPeptide.Length; codonPos++)
{
codon = dna.Substring(pivot, 3);
auxCodon = givenPeptideArray[codonPos].ToString();
convertedCodon = codonToAminoAcid(codon);
convertedCodonReverse = codonToAminoAcid(DNAComplement(codon));
if (auxCodon.Equals(convertedCodon) )
{
foundFlag++;
clean += codon;
}
else
{
foundFlag = 0;
clean = "";
}
if (foundFlag == givenPeptide.Length)
{
Console.WriteLine(clean);
foundFlag = 0;
clean = "";
}
//reverse
if (auxCodon.Equals(convertedCodonReverse))
{
foundFlagReverse++;
cleanReverse += codon;
}
else
{
foundFlagReverse = 0;
cleanReverse = "";
}
if (foundFlagReverse == givenPeptide.Length)
{
Console.WriteLine(cleanReverse);
foundFlagReverse = 0;
cleanReverse = "";
}
pivot+=3;
}
}
}//end main
public static string DNAComplement(string dna)
{
char[] array = dna.ToCharArray();
for (int i = 0; i < array.Length; i++)
{
char let = array[i];
if (let == 'A') array[i] = 'T';
else if (let == 'T') array[i] = 'A';
else if (let == 'C') array[i] = 'G';
else if (let == 'G') array[i] = 'C';
}
Array.Reverse(array);
return new string(array);
}
public static string codonToAminoAcid(String codon)
{
for (int k = 0; k < CODONS.Length ; k++)
{
if (CODONS[k].Equals (codon))
{
return AMINOS_PER_CODON[k];
}
}
// never reach here with valid codon
return "X";
}
}//end class
I should get
AAGGAAGTATTTGAGCCTCATTATTAC
AAAGAGGTGTTTGAACCTCATTACTAT
AAGGAGGTATTTGAACCCCACTATTAC
AAAGAAGTTTTCGAACCACATTATTAC
AAGGAAGTGTTTGAACCTCACTATTAT
AAAGAAGTTTTCGAGCCGCACTACTAC
AAGGAAGTATTCGAACCACATTACTAT
ATAATAATGCGGCTCGAATACTTCCTT
GTAGTAATGGGGCTCGAAAACCTCCTT
GTAGTAATGAGGTTCAAAAACCTCCTT
GTAGTAATGGGGTTCGAAGACTTCCTT
ATAATAGTGAGGCTCAAAAACTTCCTT
ATAGTAATGGGGTTCGAAGACTTCCTT
GTAGTAGTGCGGCTCAAAAACTTCCTT
ATAGTAATGAGGTTCGAAAACCTCTTT
ATAATAATGTGGCTCGAACACTTCTTT
GTAGTAATGGGGCTCAAACACCTCTTT
ATAGTAGTGAGGTTCGAAGACTTCCTT
GTAATAGTGCGGTTCAAAAACTTCCTT
ATAGTAGTGTGGTTCAAATACCTCCTT
However I am only getting:
AAGGAAGTATTTGAGCCTCATTATTAC
AAAGAGGTGTTTGAACCTCATTACTAT
AAGGAAGTGTTTGAACCTCACTATTAT
AAAGAAGTTTTCGAGCCGCACTACTAC
AAGGAGGTATTTGAACCCCACTATTAC
AAAGAAGTTTTCGAACCACATTATTAC
I was thinking on problem and It seems the problem is I am not looping all string each time...
It looks like the problem is two-fold. Your outer for loop doesn't go far enough to catch the very end of the dna string. Secondly, it appears that reversing individual codons doesn't work and that you have to take the entire (givenPeptideLength * 3) character string before getting the complement. The following changes output the strings you put in your example so I'm hopeful that it does what you want. It has the benefit of being much more concise as well.
using System;
using System.Collections.Generic;
using System.Text;
using System.Text.RegularExpressions;
using System.Linq;
using System.IO;
using System.Collections;
namespace DNA
{
class Program
{
private static string[] CODONS = {
"TTT", "TTC", "TTA", "TTG", "TCT",
"TCC", "TCA", "TCG", "TAT", "TAC", "TGT", "TGC", "TGG", "CTT",
"CTC", "CTA", "CTG", "CCT", "CCC", "CCA", "CCG", "CAT", "CAC",
"CAA", "CAG", "CGT", "CGC", "CGA", "CGG", "ATT", "ATC", "ATA",
"ATG", "ACT", "ACC", "ACA", "ACG", "AAT", "AAC", "AAA", "AAG",
"AGT", "AGC", "AGA", "AGG", "GTT", "GTC", "GTA", "GTG", "GCT",
"GCC", "GCA", "GCG", "GAT", "GAC", "GAA", "GAG", "GGT", "GGC",
"GGA", "GGG", };
private static string[] AMINOS_PER_CODON = {
"F", "F", "L", "L", "S", "S",
"S", "S", "Y", "Y", "C", "C", "W", "L", "L", "L", "L", "P", "P",
"P", "P", "H", "H", "Q", "Q", "R", "R", "R", "R", "I", "I", "I",
"M", "T", "T", "T", "T", "N", "N", "K", "K", "S", "S", "R", "R",
"V", "V", "V", "V", "A", "A", "A", "A", "D", "D", "E", "E", "G",
"G", "G", "G", };
private static string[] AMINO_ABBREVIATIONS = {
"F", "L", "I", "M", "V",
"S", "P", "T", "A", "Y", "H", "Q", "N", "K", "D", "E", "C", "W",
"R", "G" };
private static string[] FULL_NAMES = {
"phenylalanine", "leucine",
"isoleucine", "methionine", "valine", "serine", "proline",
"threonine", "alanine", "tyrosine", "histidine", "glutamine",
"asparagine", "lysine", "aspartic acid", "glutamic acid",
"cysteine", "tryptophan", "arginine", "glycine" };
public static string DNAComplement(string dna)
{
char[] array = dna.ToCharArray();
for (int i = 0; i < array.Length; i++)
{
char let = array[i];
if (let == 'A') array[i] = 'T';
else if (let == 'T') array[i] = 'A';
else if (let == 'C') array[i] = 'G';
else if (let == 'G') array[i] = 'C';
}
Array.Reverse(array);
return new string(array);
}
public static string StringToAminoAcid(String input)
{
string result = "";
for (int i = 0; i < input.Length; i += 3)
{
result += codonToAminoAcid(input.Substring(i, 3));
}
return result;
}
public static string codonToAminoAcid(String codon)
{
for (int k = 0; k < CODONS.Length; k++)
{
if (CODONS[k].Equals(codon))
{
return AMINOS_PER_CODON[k];
}
}
// never reach here with valid codon
return "X";
}
static void Main()
{
//then input is DNA
string dna = "TTCGAATCCGTATTGCTTTGGTTGGTTGAGAGAGCGACCTACATTGCTAGTCAGAATAGGTGATTCACACAAAGCTTAGCACCTGGGCAGCACCCCGTGATGTAAACCTATGGGAACTAAGGGAGTCCTGCGGTTTTAGCCAGCAAGCGAGCCGGCAGGAACACTCATACCATCGGACGCGTTTGACGCCTCCCCGGAAAGGAAGTATTTGAGCCTCATTATTACGTATTGCCCGTTAGTCGACAAATCAAGCCCTCGTACGCAGCTTATTCGTACGACGTGGAGGCGTTCCCACGGGCCTAACACGATTGGAACACCACCATAGTAGTGTGGTTCAAATACCTCCTTTGGAGATCTAGAGCTTCACTCTGATTCTAGAGGCAACTTTACAATCGCTCTACGAAATTGTATGGACATCATCAACCGGATATTCTGGGGCGGTAGAATTTCTTTTGTTCGAATCGCTCTAGGCCAGGATCAAATTAATTGAATTGCGGACTCAAGGATCGCGATAGCCGACACATCGGACGCTGTAGAAAGCCAGTCTCTGGATTTAATCCACCCTCTATGTTTGACAAAGCACTAAAACGGGATAGTTTCGGGTGGTATAAGTTTCCCAAGACGATTGCATCGCAATTCATCAACAACCATGAACTTACTGTTTTAGTACTTCCACACACCTTGTTAAATTACGCCTTTACTTCATGTTGCGGTGTGTGTTAGATAGTGTGCAGCTACAAGTCTACCGCCATCGCAGCTCGGGATACCGGCAGATGAGATGGTCCTGAGCTCGTACCGGACTCAAACTTTTTCCTTTACTACCTAGGAATCGCCCATGCGAATTTGTCGGACACACACCATTACATTAACGTCACAACAGCTACTGTTAGAATTTTGCTCTTGCAAATCCTGGAAAGAGTTAAAAAAACTCTTCCGCGCGCCAATAGGGTAAATAATAGATAGCCAGACGGCTGTAAGAGGTGATGACATTTGCAACAATCATGCTGTCGCATCTTCCGCAAGTTCATGTCGCGCCTAGGCAATGGATCTGCGAATGGGGGCCACGGGGTATGAACTACGGAATTCTAAGAAAGTTGCCATCCAGAGTTAAGGGTTTGAGGCTAGTTGCATCGCTGGTAACGAACTACCTCATTACTTGGACGCGCAGTGTGACTTCACTCCTGTATAGCGATGATGCCAAGCAGGAATTAGCAAATCTGAAGAGCGTTTCCAAACTGGCCACTTGGACTGACACCTATCGCGGGGGATTTCAGCGCGTGTCGCTCTCACATGAGAGCTGCCGTCAGGAGCGGTAGAGTTTAGAGAGGAATGCGACAAACTCCCTATTCACCTCTCTGGTGATGTAAGGATATTTACGCTTAGTTCTATGCCAGGCTTAGGGCCTCTCGGAACTTTGGTGAGTCCTTATTAATTGATGCTACCTCTCCCTTACCTTCGCCCCAAGTCACGTAGAAGTACTCAATCCTGCTACATGATAATCAAATATTTCCAACGTTGGGAAATCGGTGACATCACATACTAGTTAAGAAACCACTGTCAGTGAACTTATATCCGGGGGAGAAAATCTACTAACTTACATACGCTGTGCGAGCAGTTTTCATTATAAGAAAATATACTCCCGAGGTACCGCATCAAGCACGACATTCCCGGAGAGCATAACATTTCGGTGCACCTGCTTTTGTGCGCTTGCTTGCGGTTATTTATAAACTACGCACAAGGCGCAAACCGCAGTGCGCATGTTTTCTCCGCCTGGCTAGAACTCGACATTCTCGTCAACGCCAATCTATGTGAGAGGATTTAGACCTCTGTGAAAACGAGTCCCTCTATAGAATAAATACCCAGATGCCAATGGGGGTTCTATCCGATGGCAGTGCATGGAGTGGTGGCTCCAGATTAAGGATGAGGAGAGGTAAAGATAACAGTTCGGTCGCCACGACGCGTTGCCAATCGAAATATCAGTACTAAAAGGCCCACCGCTCCGCTTTAGTCCGACTTTACATCCTGTGGAAATTGTCGAACGGAGGCTACATCGGGCTATATGAGTGTGAAAACCTATACTTCTCGCGTCGTTACTCAGTGCCGGTCTCCTGTTTCCCCCAGTCTTACGTACCCTTATTGATATTTGCTTCACGTTGAAACGTCCTAACGCAGCGTAAAGAGGTGTTTGAACCTCATTACTATAAAATCGCGATCGAAGGTAGACTACATACGCAAACGCCGAAACCCTCAGTTGGCCTTGTTGCAAGTATGGAACGTTGTAAAATTTTTCCTAGACGTTGAGCTATCGGTACAAGGTCGTTAGCGTCCTTACCCTTCACTTATATGCCCGACAAAACGCGGGTCCTAGTGCAGTGGTGGGAGCTTGGAATCCCGCAATACAAGGACAACCTGTATCTCGTTCGGCGTTCCGCGATCACTCGATCCCGAACCACTCCAAGCCTGGTTGATCAGCAAAAGCGGAAGGATGGATAAAGGGCTACTGGTTAATGGATGTAAACTTCCAATGATGAAATCCTGGAAACGAGGGATCGGGTTACGGTGGCGAACGGGGTACGGCAACGTGGCTATCTAGAGCCCGACGTTACGACTCATGTACATGCTGCTACGTGGTTGAAGCTGACGTTCAGATGAAGCAGTACTGAGTCCTAGGGCTTACTACTACTCCAATAGGTCTGGCCGGCCAGATACAAAAGTTCGTGGCGGCTCACCCCCTTTCTGGCGGGTGTAGCTTGCTGACCGGTTTGCTCGATAACACAGGCTAGCGAATAGTAATGAGGTTCGAAAACCTCTTTCCAACGACTGAAAGGGTCTACACGAACTATCTACATTTCCCCGCCCATGTCCTTCCGTCTGGTTGCTTCTGGAGATCCTTTCGCATTATACCGCAGCGTAGTGGCTCTGGCATATATGAAAAAATCCTTCTGTGGGTATTTGTGCCATCACTTATTGTTCGTACCGATATGGGATTACAAGTGCGATGTGATAATAAGCGAAGAAGCCAACATGTTACACTGTTCATGCGCTCCGGGTAATGTGCGGGCACCATGCTCAGTTCCCGCTCGCAGTTGTCACTGTCCCTGTTTCGGCACCATAATCAACATTTCCACGGCCACGCTGGTGAATAACCGAGGATACCGAAGTACAGCAAGAATGAGAGCGGGACTCCTCCATCTGCTTGTAATACGCCTTCAAGATAGTCCATAAAACGGTCGGGGTCTTGTTTCGGACTAGCCGCTTTGAAACGGTGCATAGTTGTGTCAAGTGTGGACATTGGCTTTCTATCCTCGTCAGCGATCCTCGGAAAGACTCGGGCAGTCGCCCCGAATCGTAATTAGGTAGTAGTGCGGCTCAAAAACTTCCTTCGACCTAACCGCTATAATGTTCGTAGATATAAATTTCGTTTCAGTATTAACAGGCGCACCGTATATATACGGAATGGTGTCGCCCCATTAGCTGCTCGCCAATATTTATCTAAGACCGCGCGCGTCTAGCGCCTTTAGTAGTTGCACCCGAGTATAGTAATGGGGTTCGAAGACTTCCTTCGCAAGGCTGCCATACTGTATCACAAGTACTGACGGAGCCCCGGAGGAGTGCAGGATACGGCAAAGGAGACCATTACCGGGGCATGAGTCCAAGTTAGCCCGTTAGGTGAAGGACGCTGATACAATAGTGAATCCGTTACTGAAAGGTTTAGAAGACCGGGGGGCTCGCACTAGGTCCAAATATTATGAACCCTACTCCTGCAACTGAATTGGCCGTCCAGGCGATATTTAAAAGGGGTTACTAGCAGGTTCATCGGAGCCCGTACTCCTTCCGGGCATAGTCGTTCGACGGGTAGAAATTCATCCAGTCGTGCCGGATACCCCGAGAATACCCCTATTTTTTGATCCTTCACCATCATCGTCCGCGGACTCATCTAAGTACCTCAGACCGAAACTGTTATCGTAGCGAAGAGCGAACTCGAATGACATCGCTTGTCCAACAGGGAAAATATGTAAAGTATATGCAGATTATTATAGGAAGATCACAAACTCCATCGCGCCTAGGCCAAAGACTTGCCAGAACAACATCTCTTCCAGAGCAAGGAAGTGTTTGAACCTCACTATTATCGAGAGAAGTCCCATGAATTTATAATAGTGAGGCTCAAAAACTTCCTTCATCGTCGGGCGCTGGGGCGAGCTAGGCTTCCCTAGCCGTCATTACTGTACCCACGCCAAATATTATCGAGTATGACTACGAAGCCTTCACAAGGGGCTGCAGTAACAGACTAACTCACGCACACCGCAACTACTATCCTAAATTGAGTAAGAAAACCCTCGACTATAGCCCTTGAATTAAATTCGCTATTTAAGGAAGACCGCGCTTCCGCTCGCCCGCGTATAGTTTACCAGTCCCAAGAAACATGTGTGGCCAGCCTACCTGAAGAGCTGTGTAAAGATAGATTCTGACATCCTCAAAAAGAAGTTTTCGAGCCGCACTACTACGCACGGAGCTCCGTTATTCAAGGCATGTCGAAGTACAGCGTGGTGGCCTCTCCTGTTCTCCACCCCAGCTAAACCCACCTTGTTCGAATTCGCGCAACTGTATATGACATGAACACTTACAGGGGTTAGAAGTTACTGCAACCAAGATAGAGCTCGTCGAAGTAATAGTGCGGTTCAAAAACTTCCTTCAATTGGTCTCATCACTTAAATTTAAGAGCTATTGTGAGTACAGGTACGGATGCGGCTTCAGTGGATCTTCAGCATTCATTCCTTGTAGTAATGGGGTTCGAAGACTTCCTTGCCAGGGTACCAAACAAGTCTTGCGCATCCTCCTCCCTAAGGAGGTATTTGAACCCCACTATTACCCACGATAGAACATGCAGGGTTTGATAGTGGAACACCTTTTAGAATCTGGGGATAAATTCCCAGGACTAATGTATGGCTGTAGTAATGAGGTTCAAAAACCTCCTTTTCAGGTGGATCGCAGGCCGTGCTGCCTCACAAGCTGGGACGCCGTCCACGGTATAGCCGGCGTCGGCAGTTACTGTGAAATAGCGGAAACTCGATCCCAATATATCATCTTACGTTTGGCGCCCAATAGTCGCCCAGTACCCGTTGACAGTTCTTTAACTCGGCTTAGAACTACTAGACAGGTTCAACCGAACCTTGCCCTAGTTCCCACTCCCGTAATTCATTTGGGTTTGCATCTAGAATACTGGAGGGTGCATAGACGAAACGTGTACGTCGGAGAAAACGTAAGAAAATGACCTAGACTCATAGTAGTGAGGTTCGAAGACTTCCTTTCAGTGAAATCGATCCACCACTCGCCGCGAAGAGATAATAGCATAGAGCACAAGTGCGCGAGTAGAGAAAAAGGCTATCCCAACCGGGCACGTCCTTCGTGTTTGGCGTTTACATACGGCACCCCGTTTCTGCACGTTAACCGTCTAGTATCCAACGGTGGATGGCGGACGCTAGACTATAGATATGAGATATCGAGACCTGGAGCTGGGTGTGGCTGCAGCCCGGGTCATTGCGGGCTGTGAATTCAAGGGCATGTAAACAAGCGTATATCGAACAGTGGATGGGCACCTGCAATACTCACGGTAGAGTTAGCTCACAGGATTCACGTTGAGGACTATGAGTCCCTCTTCGCTAGCAGTCTGGGGGGATATGGAGTTTAATAGCTTGACGTAGTAATGGGGCTCAAACACCTCTTTGTGTGAGCACAGCTACTTGCATTAAGAGATTCTAAACAGCGATCATCTCGGCTATTTCGGGCCAGCCTTTTCGGCAGGATGTTATGTAGCATTTCTGGAAGCTTCCCCCTCGAATCTACTAGTGGTGAGAAGATGCCCCACCGATATTACTCTTTAATCTTGAGAAACCTAAAACCGATCTGACCTCAGACGGGCGGCTCCCACCCGAGGATAAACTCGTCAATAATAATGTGGCTCGAACACTTCTTTTCTCACTAGGCTTTTACGACACGCCACATGTATTTAAGCATCTACCTAACTTGTGTCTGCTGATATACAGCGCATTCTACGCCCAACCTACCAATTACTTCAACGTAGTGCGTGGCTAAAATTCAGGGGAGCTTCATCTCTGTCTTAATTTGAAGGTTCTTCCGGGGCGTTTGGGAATCTTCGTGCCTTTTGCGAGGTTAAGGTATCAAAGAAGTTTTCGAACCACATTATTACCGCCTTAAGCACCGGCGCATCCTGCTCGTGACAACTCTACCCTGCCCTGATAAAGGCACTGAACGTTCCAGAGAGTGCATCATTGACACGCGAGCAGGCCACAGTAGCCACAAGACGTATGGGTGATTATAGAATTGGTGGAGGTGTTGTTAACGATCAGGAGGACATTAGTGGGAGTTAGGAAAGACCCTATGTTCTCTCTATCGCGGACTTGTAACTTGACAAGCAAAAGGGTAAGAGAGCTGCACACCGAAGCAGGCCCTTCCTATACCTGTTTTTCCTACGCGTAGAGAGGAATCCAGAAAGGTGATAATTGGCATTCGATGAAAAAACAGTGTGCCACTGACTTAGTTCTATATGTGAAGAGCCTGTTAGCACGTGACGGCGGCCTTGGTATAGAGCCCTTAATGGTCTCCATCGCGTAGTAATGGGGCTCGAAAACCTCCTTACTTGGGATTGCGTGGCCTCCTTGTGAGTCATACACAAGGCTTAGGGCTATGGGGCGATACACTCCTTTTCGCGGCGCATGGGGCGGTGATGCCTACATAGTAGTAGTGACTGCCTTTCTGGGGGGCTATTTGTGGATGACCAACACCTGACCAGCGATGCAATCGCTAGGGGAGGTACACCTCTCATATGTTACAACAATCACCGAATTGTGTTTCGAATTCGAATCAAGTTTGCGGTGTCGACCAGATCTGGTCTTGCTGCCATACCGGGTTCGCCGCCTCCGGTGGATAGAACTGCATCTTAAGACATCTGGACCCAGCGGTAAGTAGCGGGAAGAGTTTAGAGTCATTCGTACAACTACAGGCTAAGGGCTTACTGGGGAGTTGTTGTAGGGCATAAAGATCGCCCCATGACTTTTCGTACTTTCCCCGATAGTTCACTCGCAGCGAGCTGCGGCTGGGCTTCGCCACACGAGTACGGGCAACATTTATCTCCTCTAATCACTGGGCACCGCGCGAGGAAATAGAAAACCCTAATCAGTGCTCATGGGCGCATCTATTGGTCTCCGCATGCACGATGCCGCGGAGTGCTTAGTTGTCCCTGCATAATCTTCGTAGATGTATAAGAGATTACCTATTTATTCGGTTTCGGTTCTAGACGTACCTTGCCGCATGAGTATAGGCTAATGAACTGAGTTGGCGCCAGAGGGAAAGGCATAATAATGCGGCTCGAATACTTCCTTAAGGAAGTATTCGAACCACATTACTAT";
//The given peptide
string givenPeptide = "KEVFEPHYY";
int resultCount = 0;
int candidateLength = givenPeptide.Length * 3;
string forward = "";
string backward = "";
for (int pos = 0; pos < dna.Length - candidateLength + 1; pos++) // Added the "+ 1"
{
forward = dna.Substring(pos, candidateLength);
backward = DNAComplement(forward);
// Unremark to get a glimpse into what is happening...
//Console.WriteLine("pos: {0}, forward: {1}, backward: {2}, forwardTranslation: {3}, backwardTranslation: {4}",
// pos, forward, backward, StringToAminoAcid(forward), StringToAminoAcid(backward));
if (
(StringToAminoAcid(forward) == givenPeptide)
||
(StringToAminoAcid(backward) == givenPeptide)
)
{
resultCount++;
Console.WriteLine(String.Format("Result {0,3} at position {1,6}... {2}", resultCount, pos, forward));
}
}
Console.WriteLine("Done");
Console.ReadLine();
}//end main
}//end class
}
This question already has answers here:
How do you convert a byte array to a hexadecimal string, and vice versa?
(53 answers)
Closed 7 years ago.
How do I convert a byte[] to a string? Every time I attempt it, I get
System.Byte[]
instead of the value.
Also, how do I get the value in Hex instead of a decimal?
There is a built in method for this:
byte[] data = { 1, 2, 4, 8, 16, 32 };
string hex = BitConverter.ToString(data);
Result: 01-02-04-08-10-20
If you want it without the dashes, just remove them:
string hex = BitConverter.ToString(data).Replace("-", string.Empty);
Result: 010204081020
If you want a more compact representation, you can use Base64:
string base64 = Convert.ToBase64String(data);
Result: AQIECBAg
.Net5.0 Update
Thanks to #antoninkriz's benchmark comparison we can see that Convert.ToHexString is by far the clear winner today
You'd be foolish to use anything other than Convert.ToHexString. In my opinion it clearly wins in: readability, performance, safety
The rest of this is from before Apr 10, 2012:
I thought I would attempt to compare the speed of each of the methods listed here for the hell of it. I based the speed testing code off this.
The result is that BitConverter+String.Replace seems to be faster than most other simple ways. But the speed can be improved with algorithms like Nathan Moinvaziri's ByteArrayToHexString or Kurt's ToHex.
I also found it interesting that string.Concat and string.Join are much slower than StringBuilder implementations for long strings, but similar for shorter arrays. Probably due to expanding the StringBuilder on the longer strings, so setting the initial size should negate this difference.
Took each bit of code from an answer here:
BitConvertRep = Answer by Guffa, BitConverter and String.Replace (I'd recommend for most cases, [edit:] where you can't use Convert.ToHexString)
StringBuilder = Answer by Quintin Robinson, foreach char StringBuilder.Append
LinqConcat = Answer by Michael Buen, string.Concat of Linq built array
LinqJoin = Answer by mloskot, string.Join of Linq built array
LinqAgg = Answer by Matthew Whited, IEnumerable.Aggregate with StringBuilder
ToHex = Answer by Kurt, sets chars in an array, using byte values to get hex
ByteArrayToHexString = Answer by Nathan Moinvaziri, approx same speed as the ToHex above, and is probably easier to read (I'd recommend for speed, [edit:] where you can't use Convert.ToHexString)
ToHexFromTable = Linked in answer by Nathan Moinvaziri, for me this is near the same speed as the above 2 but requires an array of 256 strings to always exist
With: LONG_STRING_LENGTH = 1000 * 1024;
BitConvertRep calculation Time Elapsed 27,202 ms (fastest built in/simple)
StringBuilder calculation Time Elapsed 75,723 ms (StringBuilder no reallocate)
LinqConcat calculation Time Elapsed 182,094 ms
LinqJoin calculation Time Elapsed 181,142 ms
LinqAgg calculation Time Elapsed 93,087 ms (StringBuilder with reallocating)
ToHex calculation Time Elapsed 19,167 ms (fastest)
With: LONG_STRING_LENGTH = 100 * 1024;, Similar results
BitConvertReplace calculation Time Elapsed 3431 ms
StringBuilder calculation Time Elapsed 8289 ms
LinqConcat calculation Time Elapsed 21512 ms
LinqJoin calculation Time Elapsed 19433 ms
LinqAgg calculation Time Elapsed 9230 ms
ToHex calculation Time Elapsed 1976 ms
With: int MANY_STRING_COUNT = 1000; int MANY_STRING_LENGTH = 1024;
(Same byte count as first test but in different arrays)
BitConvertReplace calculation Time Elapsed 25,680 ms
StringBuilder calculation Time Elapsed 78,411 ms
LinqConcat calculation Time Elapsed 101,233 ms
LinqJoin calculation Time Elapsed 99,311 ms
LinqAgg calculation Time Elapsed 84,660 ms
ToHex calculation Time Elapsed 18,221 ms
With: int MANY_STRING_COUNT = 2000; int MANY_STRING_LENGTH = 20;
BitConvertReplace calculation Time Elapsed 1347 ms
StringBuilder calculation Time Elapsed 3234 ms
LinqConcat calculation Time Elapsed 5013 ms
LinqJoin calculation Time Elapsed 4826 ms
LinqAgg calculation Time Elapsed 3589 ms
ToHex calculation Time Elapsed 772 ms
Testing code I used:
void Main()
{
int LONG_STRING_LENGTH = 100 * 1024;
int MANY_STRING_COUNT = 1024;
int MANY_STRING_LENGTH = 100;
var source = GetRandomBytes(LONG_STRING_LENGTH);
List<byte[]> manyString = new List<byte[]>(MANY_STRING_COUNT);
for (int i = 0; i < MANY_STRING_COUNT; ++i)
{
manyString.Add(GetRandomBytes(MANY_STRING_LENGTH));
}
var algorithms = new Dictionary<string,Func<byte[], string>>();
algorithms["BitConvertReplace"] = BitConv;
algorithms["StringBuilder"] = StringBuilderTest;
algorithms["LinqConcat"] = LinqConcat;
algorithms["LinqJoin"] = LinqJoin;
algorithms["LinqAgg"] = LinqAgg;
algorithms["ToHex"] = ToHex;
algorithms["ByteArrayToHexString"] = ByteArrayToHexString;
Console.WriteLine(" === Long string test");
foreach (var pair in algorithms) {
TimeAction(pair.Key + " calculation", 500, () =>
{
pair.Value(source);
});
}
Console.WriteLine(" === Many string test");
foreach (var pair in algorithms) {
TimeAction(pair.Key + " calculation", 500, () =>
{
foreach (var str in manyString)
{
pair.Value(str);
}
});
}
}
// Define other methods and classes here
static void TimeAction(string description, int iterations, Action func) {
var watch = new Stopwatch();
watch.Start();
for (int i = 0; i < iterations; i++) {
func();
}
watch.Stop();
Console.Write(description);
Console.WriteLine(" Time Elapsed {0} ms", watch.ElapsedMilliseconds);
}
//static byte[] GetRandomBytes(int count) {
// var bytes = new byte[count];
// (new Random()).NextBytes(bytes);
// return bytes;
//}
static Random rand = new Random();
static byte[] GetRandomBytes(int count) {
var bytes = new byte[count];
rand.NextBytes(bytes);
return bytes;
}
static string BitConv(byte[] data)
{
return BitConverter.ToString(data).Replace("-", string.Empty);
}
static string StringBuilderTest(byte[] data)
{
StringBuilder sb = new StringBuilder(data.Length*2);
foreach (byte b in data)
sb.Append(b.ToString("X2"));
return sb.ToString();
}
static string LinqConcat(byte[] data)
{
return string.Concat(data.Select(b => b.ToString("X2")).ToArray());
}
static string LinqJoin(byte[] data)
{
return string.Join("",
data.Select(
bin => bin.ToString("X2")
).ToArray());
}
static string LinqAgg(byte[] data)
{
return data.Aggregate(new StringBuilder(),
(sb,v)=>sb.Append(v.ToString("X2"))
).ToString();
}
static string ToHex(byte[] bytes)
{
char[] c = new char[bytes.Length * 2];
byte b;
for(int bx = 0, cx = 0; bx < bytes.Length; ++bx, ++cx)
{
b = ((byte)(bytes[bx] >> 4));
c[cx] = (char)(b > 9 ? b - 10 + 'A' : b + '0');
b = ((byte)(bytes[bx] & 0x0F));
c[++cx] = (char)(b > 9 ? b - 10 + 'A' : b + '0');
}
return new string(c);
}
public static string ByteArrayToHexString(byte[] Bytes)
{
StringBuilder Result = new StringBuilder(Bytes.Length*2);
string HexAlphabet = "0123456789ABCDEF";
foreach (byte B in Bytes)
{
Result.Append(HexAlphabet[(int)(B >> 4)]);
Result.Append(HexAlphabet[(int)(B & 0xF)]);
}
return Result.ToString();
}
Also another answer with a similar process, I haven't compared our results yet.
Hex, Linq-fu:
string.Concat(ba.Select(b => b.ToString("X2")).ToArray())
UPDATE with the times
As noted by #RubenBartelink, the code that don't have a conversion of IEnumerable<string> to an array: ba.Select(b => b.ToString("X2")) does not work prior to 4.0, the same code is now working on 4.0.
This code...
byte[] ba = { 1, 2, 4, 8, 16, 32 };
string s = string.Concat(ba.Select(b => b.ToString("X2")));
string t = string.Concat(ba.Select(b => b.ToString("X2")).ToArray());
Console.WriteLine (s);
Console.WriteLine (t);
...prior to .NET 4.0, the output is:
System.Linq.Enumerable+<CreateSelectIterator>c__Iterator10`2[System.Byte,System.String]
010204081020
On .NET 4.0 onwards, string.Concat has an overload that accepts IEnumerable. Hence on 4.0, the above code will have same output for both variables s and t
010204081020
010204081020
Prior to 4.0, ba.Select(b => b.ToString("X2")) goes to overload (object arg0), the way for the IEnumerable<string> to go to a proper overload, i.e. (params string[] values), is we need to convert the IEnumerable<string> to string array. Prior to 4.0, string.Concat has 10 overload functions, on 4.0 it is now 12
Here is another method:
public static string ByteArrayToHexString(byte[] Bytes)
{
StringBuilder Result = new StringBuilder(Bytes.Length * 2);
string HexAlphabet = "0123456789ABCDEF";
foreach (byte B in Bytes)
{
Result.Append(HexAlphabet[(int)(B >> 4)]);
Result.Append(HexAlphabet[(int)(B & 0xF)]);
}
return Result.ToString();
}
public static byte[] HexStringToByteArray(string Hex)
{
byte[] Bytes = new byte[Hex.Length / 2];
int[] HexValue = new int[] { 0x00, 0x01, 0x02, 0x03, 0x04, 0x05,
0x06, 0x07, 0x08, 0x09, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,
0x0A, 0x0B, 0x0C, 0x0D, 0x0E, 0x0F };
for (int x = 0, i = 0; i < Hex.Length; i += 2, x += 1)
{
Bytes[x] = (byte)(HexValue[Char.ToUpper(Hex[i + 0]) - '0'] << 4 |
HexValue[Char.ToUpper(Hex[i + 1]) - '0']);
}
return Bytes;
}
Alternatively, you could pre-build the translation table like so to achieve even faster results:
http://blogs.msdn.com/b/blambert/archive/2009/02/22/blambert-codesnip-fast-byte-array-to-hex-string-conversion.aspx
I like using extension methods for conversions like this, even if they just wrap standard library methods. In the case of hexadecimal conversions, I use the following hand-tuned (i.e., fast) algorithms:
public static string ToHex(this byte[] bytes)
{
char[] c = new char[bytes.Length * 2];
byte b;
for(int bx = 0, cx = 0; bx < bytes.Length; ++bx, ++cx)
{
b = ((byte)(bytes[bx] >> 4));
c[cx] = (char)(b > 9 ? b + 0x37 + 0x20 : b + 0x30);
b = ((byte)(bytes[bx] & 0x0F));
c[++cx]=(char)(b > 9 ? b + 0x37 + 0x20 : b + 0x30);
}
return new string(c);
}
public static byte[] HexToBytes(this string str)
{
if (str.Length == 0 || str.Length % 2 != 0)
return new byte[0];
byte[] buffer = new byte[str.Length / 2];
char c;
for (int bx = 0, sx = 0; bx < buffer.Length; ++bx, ++sx)
{
// Convert first half of byte
c = str[sx];
buffer[bx] = (byte)((c > '9' ? (c > 'Z' ? (c - 'a' + 10) : (c - 'A' + 10)) : (c - '0')) << 4);
// Convert second half of byte
c = str[++sx];
buffer[bx] |= (byte)(c > '9' ? (c > 'Z' ? (c - 'a' + 10) : (c - 'A' + 10)) : (c - '0'));
}
return buffer;
}
Well I don't convert bytes to hex often so I have to say I don't know if there is a better way then this, but here is a way to do it.
StringBuilder sb = new StringBuilder();
foreach (byte b in myByteArray)
sb.Append(b.ToString("X2"));
string hexString = sb.ToString();
I thought I should provide an answer. From my test this method is the fastest
public static class Helper
{
public static string[] HexTbl = Enumerable.Range(0, 256).Select(v => v.ToString("X2")).ToArray();
public static string ToHex(this IEnumerable<byte> array)
{
StringBuilder s = new StringBuilder();
foreach (var v in array)
s.Append(HexTbl[v]);
return s.ToString();
}
public static string ToHex(this byte[] array)
{
StringBuilder s = new StringBuilder(array.Length*2);
foreach (var v in array)
s.Append(HexTbl[v]);
return s.ToString();
}
}
Very fast extension methods (with reversal):
public static class ExtensionMethods {
public static string ToHex(this byte[] data) {
return ToHex(data, "");
}
public static string ToHex(this byte[] data, string prefix) {
char[] lookup = new char[] { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F' };
int i = 0, p = prefix.Length, l = data.Length;
char[] c = new char[l * 2 + p];
byte d;
for(; i < p; ++i) c[i] = prefix[i];
i = -1;
--l;
--p;
while(i < l) {
d = data[++i];
c[++p] = lookup[d >> 4];
c[++p] = lookup[d & 0xF];
}
return new string(c, 0, c.Length);
}
public static byte[] FromHex(this string str) {
return FromHex(str, 0, 0, 0);
}
public static byte[] FromHex(this string str, int offset, int step) {
return FromHex(str, offset, step, 0);
}
public static byte[] FromHex(this string str, int offset, int step, int tail) {
byte[] b = new byte[(str.Length - offset - tail + step) / (2 + step)];
byte c1, c2;
int l = str.Length - tail;
int s = step + 1;
for(int y = 0, x = offset; x < l; ++y, x += s) {
c1 = (byte)str[x];
if(c1 > 0x60) c1 -= 0x57;
else if(c1 > 0x40) c1 -= 0x37;
else c1 -= 0x30;
c2 = (byte)str[++x];
if(c2 > 0x60) c2 -= 0x57;
else if(c2 > 0x40) c2 -= 0x37;
else c2 -= 0x30;
b[y] = (byte)((c1 << 4) + c2);
}
return b;
}
}
Beats all the others in the speed test above:
=== Long string test
BitConvertReplace calculation Time Elapsed 2415 ms
StringBuilder calculation Time Elapsed 5668 ms
LinqConcat calculation Time Elapsed 11826 ms
LinqJoin calculation Time Elapsed 9323 ms
LinqAgg calculation Time Elapsed 7444 ms
ToHexTable calculation Time Elapsed 1028 ms
ToHexAcidzombie calculation Time Elapsed 1035 ms
ToHexPatrick calculation Time Elapsed 814 ms
ToHexKurt calculation Time Elapsed 1604 ms
ByteArrayToHexString calculation Time Elapsed 1330 ms
=== Many string test
BitConvertReplace calculation Time Elapsed 2238 ms
StringBuilder calculation Time Elapsed 5393 ms
LinqConcat calculation Time Elapsed 9043 ms
LinqJoin calculation Time Elapsed 9131 ms
LinqAgg calculation Time Elapsed 7324 ms
ToHexTable calculation Time Elapsed 968 ms
ToHexAcidzombie calculation Time Elapsed 969 ms
ToHexPatrick calculation Time Elapsed 956 ms
ToHexKurt calculation Time Elapsed 1547 ms
ByteArrayToHexString calculation Time Elapsed 1277 ms
Just to add one more answer to the pile, there is a System.Runtime.Remoting.Metadata.W3cXsd2001.SoapHexBinary class that I've used which can convert bytes to and from hex:
string hex = new SoapHexBinary(bytes).ToString();
byte[] bytes = SoapHexBinary.Parse(hex).Value;
Not sure how it compares (benchmark) to other implementations, but IMO it is pretty simple -- especially for converting from hex back into bytes.
With:
byte[] data = new byte[] { 0x01, 0x02, 0x03, 0x0D, 0x0E, 0x0F };
string hex = string.Empty;
data.ToList().ForEach(b => hex += b.ToString("x2"));
// use "X2" for uppercase hex letters
Console.WriteLine(hex);
Result: 0102030d0e0f
You have to know the encoding of the string represented in bytes, but you can say System.Text.UTF8Encoding.GetString(bytes) or System.Text.ASCIIEncoding.GetString(bytes). (I'm doing this from memory, so the API may not be exactly correct, but it's very close.)
For the answer to your second question, see this question.
Here is a extension method for byte array (byte[]), e.g.,
var b = new byte[] { 15, 22, 255, 84, 45, 65, 7, 28, 59, 10 };
Console.WriteLine(b.ToHexString());
public static class HexByteArrayExtensionMethods
{
private const int AllocateThreshold = 256;
private const string UpperHexChars = "0123456789ABCDEF";
private const string LowerhexChars = "0123456789abcdef";
private static string[] upperHexBytes;
private static string[] lowerHexBytes;
public static string ToHexString(this byte[] value)
{
return ToHexString(value, false);
}
public static string ToHexString(this byte[] value, bool upperCase)
{
if (value == null)
{
throw new ArgumentNullException("value");
}
if (value.Length == 0)
{
return string.Empty;
}
if (upperCase)
{
if (upperHexBytes != null)
{
return ToHexStringFast(value, upperHexBytes);
}
if (value.Length > AllocateThreshold)
{
return ToHexStringFast(value, UpperHexBytes);
}
return ToHexStringSlow(value, UpperHexChars);
}
if (lowerHexBytes != null)
{
return ToHexStringFast(value, lowerHexBytes);
}
if (value.Length > AllocateThreshold)
{
return ToHexStringFast(value, LowerHexBytes);
}
return ToHexStringSlow(value, LowerhexChars);
}
private static string ToHexStringSlow(byte[] value, string hexChars)
{
var hex = new char[value.Length * 2];
int j = 0;
for (var i = 0; i < value.Length; i++)
{
var b = value[i];
hex[j++] = hexChars[b >> 4];
hex[j++] = hexChars[b & 15];
}
return new string(hex);
}
private static string ToHexStringFast(byte[] value, string[] hexBytes)
{
var hex = new char[value.Length * 2];
int j = 0;
for (var i = 0; i < value.Length; i++)
{
var s = hexBytes[value[i]];
hex[j++] = s[0];
hex[j++] = s[1];
}
return new string(hex);
}
private static string[] UpperHexBytes
{
get
{
return (upperHexBytes ?? (upperHexBytes = new[] {
"00", "01", "02", "03", "04", "05", "06", "07", "08", "09", "0A", "0B", "0C", "0D", "0E", "0F",
"10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "1A", "1B", "1C", "1D", "1E", "1F",
"20", "21", "22", "23", "24", "25", "26", "27", "28", "29", "2A", "2B", "2C", "2D", "2E", "2F",
"30", "31", "32", "33", "34", "35", "36", "37", "38", "39", "3A", "3B", "3C", "3D", "3E", "3F",
"40", "41", "42", "43", "44", "45", "46", "47", "48", "49", "4A", "4B", "4C", "4D", "4E", "4F",
"50", "51", "52", "53", "54", "55", "56", "57", "58", "59", "5A", "5B", "5C", "5D", "5E", "5F",
"60", "61", "62", "63", "64", "65", "66", "67", "68", "69", "6A", "6B", "6C", "6D", "6E", "6F",
"70", "71", "72", "73", "74", "75", "76", "77", "78", "79", "7A", "7B", "7C", "7D", "7E", "7F",
"80", "81", "82", "83", "84", "85", "86", "87", "88", "89", "8A", "8B", "8C", "8D", "8E", "8F",
"90", "91", "92", "93", "94", "95", "96", "97", "98", "99", "9A", "9B", "9C", "9D", "9E", "9F",
"A0", "A1", "A2", "A3", "A4", "A5", "A6", "A7", "A8", "A9", "AA", "AB", "AC", "AD", "AE", "AF",
"B0", "B1", "B2", "B3", "B4", "B5", "B6", "B7", "B8", "B9", "BA", "BB", "BC", "BD", "BE", "BF",
"C0", "C1", "C2", "C3", "C4", "C5", "C6", "C7", "C8", "C9", "CA", "CB", "CC", "CD", "CE", "CF",
"D0", "D1", "D2", "D3", "D4", "D5", "D6", "D7", "D8", "D9", "DA", "DB", "DC", "DD", "DE", "DF",
"E0", "E1", "E2", "E3", "E4", "E5", "E6", "E7", "E8", "E9", "EA", "EB", "EC", "ED", "EE", "EF",
"F0", "F1", "F2", "F3", "F4", "F5", "F6", "F7", "F8", "F9", "FA", "FB", "FC", "FD", "FE", "FF" }));
}
}
private static string[] LowerHexBytes
{
get
{
return (lowerHexBytes ?? (lowerHexBytes = new[] {
"00", "01", "02", "03", "04", "05", "06", "07", "08", "09", "0a", "0b", "0c", "0d", "0e", "0f",
"10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "1a", "1b", "1c", "1d", "1e", "1f",
"20", "21", "22", "23", "24", "25", "26", "27", "28", "29", "2a", "2b", "2c", "2d", "2e", "2f",
"30", "31", "32", "33", "34", "35", "36", "37", "38", "39", "3a", "3b", "3c", "3d", "3e", "3f",
"40", "41", "42", "43", "44", "45", "46", "47", "48", "49", "4a", "4b", "4c", "4d", "4e", "4f",
"50", "51", "52", "53", "54", "55", "56", "57", "58", "59", "5a", "5b", "5c", "5d", "5e", "5f",
"60", "61", "62", "63", "64", "65", "66", "67", "68", "69", "6a", "6b", "6c", "6d", "6e", "6f",
"70", "71", "72", "73", "74", "75", "76", "77", "78", "79", "7a", "7b", "7c", "7d", "7e", "7f",
"80", "81", "82", "83", "84", "85", "86", "87", "88", "89", "8a", "8b", "8c", "8d", "8e", "8f",
"90", "91", "92", "93", "94", "95", "96", "97", "98", "99", "9a", "9b", "9c", "9d", "9e", "9f",
"a0", "a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "aa", "ab", "ac", "ad", "ae", "af",
"b0", "b1", "b2", "b3", "b4", "b5", "b6", "b7", "b8", "b9", "ba", "bb", "bc", "bd", "be", "bf",
"c0", "c1", "c2", "c3", "c4", "c5", "c6", "c7", "c8", "c9", "ca", "cb", "cc", "cd", "ce", "cf",
"d0", "d1", "d2", "d3", "d4", "d5", "d6", "d7", "d8", "d9", "da", "db", "dc", "dd", "de", "df",
"e0", "e1", "e2", "e3", "e4", "e5", "e6", "e7", "e8", "e9", "ea", "eb", "ec", "ed", "ee", "ef",
"f0", "f1", "f2", "f3", "f4", "f5", "f6", "f7", "f8", "f9", "fa", "fb", "fc", "fd", "fe", "ff" }));
}
}
}
You combine LINQ with string methods:
string hex = string.Join("",
bin.Select(
bin => bin.ToString("X2")
).ToArray());
No one here mentioned the reason why you get the "System.Byte[]" string instead of the value, so I will.
When an object is implicitly cast to a String, the program will default to the object's public String ToString() method which is inherited from System.Object:
public virtual string ToString()
{
return this.GetType().ToString();
}
If you find that you are often making this conversion, you could simply create a wrapper class and override this method like so:
public override string ToString()
{
// do the processing here
// return the nicely formatted string
}
Now each time you print this wrapper object you will get your value instead of the value from this.GetType().ToString().
As others have said it depends on the encoding of the values in the byte array. Despite this you need to be very careful with this sort of thing or you may try to convert bytes that are not handled by the chosen encoding.
Jon Skeet has a good article about encoding and unicode in .NET. Recommended reading.
I think I made a faster byte array to string convertor:
public static class HexTable
{
private static readonly string[] table = BitConverter.ToString(Enumerable.Range(0, 256).Select(x => (byte)x).ToArray()).Split('-');
public static string ToHexTable(byte[] value)
{
StringBuilder sb = new StringBuilder(2 * value.Length);
for (int i = 0; i < value.Length; i++)
sb.Append(table[value[i]]);
return sb.ToString();
}
And the test set up:
static void Main(string[] args)
{
const int TEST_COUNT = 10000;
const int BUFFER_LENGTH = 100000;
Random random = new Random();
Stopwatch sw = new Stopwatch();
Stopwatch sw2 = new Stopwatch();
byte[] buffer = new byte[BUFFER_LENGTH];
random.NextBytes(buffer);
sw.Start();
for (int j = 0; j < TEST_COUNT; j++)
HexTable.ToHexTable(buffer);
sw.Stop();
sw2.Start();
for (int j = 0; j < TEST_COUNT; j++)
ToHexChar.ToHex(buffer);
sw2.Stop();
Console.WriteLine("Hex Table Elapsed Milliseconds: {0}", sw.ElapsedMilliseconds);
Console.WriteLine("ToHex Elapsed Milliseconds: {0}", sw2.ElapsedMilliseconds);
}
The ToHexChar.ToHEx() method is the ToHex() method shown previously.
Results are as follows:
HexTable = 11808 ms
ToHEx = 12168ms
It may not look that much of a difference, but it's still faster :)
I'm not sure if you need perfomance for doing this, but here is the fastest method to convert byte[] to hex string that I can think of :
static readonly char[] hexchar = new char[] { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F' };
public static string HexStr(byte[] data, int offset, int len, bool space = false)
{
int i = 0, k = 2;
if (space) k++;
var c = new char[len * k];
while (i < len)
{
byte d = data[offset + i];
c[i * k] = hexchar[d / 0x10];
c[i * k + 1] = hexchar[d % 0x10];
if (space && i < len - 1) c[i * k + 2] = ' ';
i++;
}
return new string(c, 0, c.Length);
}
Nice way to do this with LINQ...
var data = new byte[] { 1, 2, 4, 8, 16, 32 };
var hexString = data.Aggregate(new StringBuilder(),
(sb,v)=>sb.Append(v.ToString("X2"))
).ToString();
private static string GuidToRaw(Guid guid)
{
byte[] bytes = guid.ToByteArray();
int сharCount = bytes.Length * 2;
char[] chars = new char[сharCount];
int index = 0;
for (int i = 0; i < сharCount; i += 2)
{
byte b = bytes[index++];
chars[i] = GetHexValue((int)(b / 16));
chars[i + 1] = GetHexValue((int)(b % 16));
}
return new string(chars, 0, chars.Length);
}
private static char GetHexValue(int i)
{
return (char)(i < 10 ? i + 48 : i + 55);
}