Develop Reference

windres: The filename, directory name, or volume label syntax is incorrect

I'm using windows 10.
I'm trying to compile a c++ file within c# using MinGW(the MinGW folder is in the projects directory), but it won't compile a resource script (using windres).
Whenever I use windres in cmd it says: "C:/Users/username/AppData/Local/Temp/my.rc:1: unrecognized escape sequence".
but still works.
But when I run the exact same command through c# (by creating a process) it doesn't work at all and says: "The filename, directory name, or volume label syntax is incorrect.".
My code:
String tempDir = Path.GetTempPath();
String file = tempDir + "my.rc";
using (StreamWriter writer = new StreamWriter(file, false, Encoding.ASCII))
{
if (!textIcon.Text.Equals(""))
await writer.WriteLineAsync("25 ICON \"" + textIcon.Text + "\"");
if (checkAdmin.Checked)
{
String manifest = tempDir + #"\manifest.xml";
createManifest(manifest);
await writer.WriteLineAsync("55 24 \"" + manifest + "\"");
}
}
String args2 = "/c \"" + Path.Combine(gccLocation, "windres.exe") + "\" -o \"" + Path.Combine(tempDir, "my.o").Replace("\\", "/") + "\" \"" + file.Replace("\\", "/") + "\"";
//Debug
//args2 = "/k echo " + args2;
ProcessStartInfo psi2 = new ProcessStartInfo();
psi2.FileName = "CMD.exe";
psi2.Arguments = args2;
psi2.UseShellExecute = false;
psi2.CreateNoWindow = true;
//Debug
//psi2.CreateNoWindow = false;
Process windres = Process.Start(psi2);
windres.WaitForExit();
if(windres.ExitCode != 0)
{
MessageBox.Show("Error: Could not create resource file (" + windres.ExitCode + ")");
}

Ended up using a batch file to run the command.
String args2 = "windres.exe -i \"" + Path.GetFullPath(file) + "\" -o \"" + Path.Combine(tempDir, "my.o") + "\"" ;
using (StreamWriter writer = new StreamWriter(tempDir + #"\my.bat", false, Encoding.ASCII))
{
await writer.WriteLineAsync("#echo off");
await writer.WriteLineAsync("cd " + Path.GetFullPath(gccLocation));
await writer.WriteLineAsync(args2);
}
//Debug
//args2 = "/k echo " + args2;
ProcessStartInfo psi2 = new ProcessStartInfo();
psi2.FileName = tempDir + #"\my.bat";
psi2.UseShellExecute = false;
psi2.CreateNoWindow = true;
//Debug
//psi2.CreateNoWindow = false;
Process windres = Process.Start(psi2);
windres.WaitForExit();

How can I archive multiple Folders into a single Zip File using 7zip C#?

I have Multiple folder path:
SourceFilePath="C:\Users\Anuj\Desktop\PSI"
SourceFilePath1="C:\Users\Anuj\Desktop\Google"
SourceFilePath2="C:\Users\Anuj\Desktop\Isp"
I want to Compress These path Using 7zip Command line code along with a Zip Password.
Edit:
//Declare and instantiate a new process component.
System.Diagnostics.Process proc;
proc = new System.Diagnostics.Process();
//Do not receive an event when the process exits.
proc.EnableRaisingEvents = false;
//The "/C" Tells Windows to Run The Command then Terminate
string strCmdLine;
strCmdLine = "/C cd c:\\Program Files\\7-Zip\\ ";
strCmdLine += " & 7z a "// here i need help
System.Diagnostics.Process.Start("CMD.exe", strCmdLine);
proc.Close();
What I actually Did:
var MultiplePathFolders=SourceFilePath+SourceFilePath1+SourceFilePath2
System.Diagnostics.Process proc;
proc = new System.Diagnostics.Process();
proc.EnableRaisingEvents = false;
string strCmdLine;
strCmdLine = "/C cd c:\\Program Files\\7-Zip\\ ";
strCmdLine += " & 7z a " + SyncPath + "\\" + ZipName + "-FileName.7z " + MultiplePathFolders + " -p" + DecryptedPassword + "";
System.Diagnostics.Process.Start("CMD.exe", strCmdLine);
proc.Close();

You can do like this:
string yourPassWord = "Hello";
string yourZipPath="D:\\my7z.7z"; // Your 7z file path
//string yourZipPath="D:\\myZip.zip"; // Or your zip file path
System.Diagnostics.Process proc;
proc = new System.Diagnostics.Process();
proc.EnableRaisingEvents = false;
List<string> foldersAndFiles = new List<string>();
foldersAndFiles.Add("D:\\F1"); // Add folder
foldersAndFiles.Add("D:\\F2"); // Add folder
foldersAndFiles.Add("D:\\file.txt"); // Add file
string cmd = "a -tzip -p\"" + yourPassWord + "\" \"" + your7zPath + "\"";
foreach(var item in foldersAndFiles)
{
cmd += " \"" + item + "\"";
}
proc.StartInfo.FileName
= "c:\\Program Files\\7-Zip\\7z.exe"; // Be sure this file exist.
proc.StartInfo.Arguments = cmd;
proc.Start();
proc.Close();

cmd command is not recognized as > an internal or external command, operable program or batch file

when i run this code.
public void WaterMarkingUsingCommandLine(string videopath, string imagepath)
{
string OutputFolder = AppDomain.CurrentDomain.BaseDirectory + "Output\\" + System.IO.Path.GetFileNameWithoutExtension(videopath) + "_Output.mp4";
string ffmpegPath = #""""+AppDomain.CurrentDomain.BaseDirectory + #"ffmpeg.exe""";
string ffmpegParams = #"-i """+videopath+#""" -i """+imagepath+#""" -filter_complex ""overlay=10:10"" """+OutputFolder+#"""";
Process ffmpeg = new Process();
ffmpeg.StartInfo.FileName = "cmd.exe";
ffmpeg.StartInfo.Arguments = "/k " + ffmpegPath + " " + ffmpegParams;
ffmpeg.Start();
}
I see this in cmd.
'c:\users\jafar.baltidynamolog\documents\visual' is not recognized as
an internal or external command, operable program or batch file.
C:\Users\jafar.baltidynamolog\Videos\videos>
The problem seems to be due to space.As told in other questions, I have added commas around the filenames but still it is not working.
Update
By Debugging i found that value of
ffmpeg.StartInfo.Arguments=
"/k \"c:\users\jafar.baltidynamolog\documents\visual studio
2010\Projects\VideoProjectBilal\VideoProjectBilal\bin\Debug\ffmpeg.exe\"
-i \"C:\Users\jafar.baltidynamolog\Videos\videos\SampleVideo_360x240_2mb.mp4\"
-i \"C:\Users\jafar.baltidynamolog\Videos\images\2.png\" -filter_complex \"overlay=10:10\" \"c:\users\jafar.baltidynamolog\documents\visual studio
2010\Projects\VideoProjectBilal\VideoProjectBilal\bin\Debug\Output\SampleVideo_360x240_2mb_Output.mp4\""

Try changing this line:
string ffmpegPath = #""""+AppDomain.CurrentDomain.BaseDirectory + #"ffmpeg.exe""";
for this: string ffmpegPath = #"""" + AppDomain.CurrentDomain.BaseDirectory + "ffmpeg.exe";
Update
Try this:
string OutputFolder = AppDomain.CurrentDomain.BaseDirectory + "Output\\" + System.IO.Path.GetFileNameWithoutExtension(videopath) + "_Output.mp4";
string ffmpegPath =AppDomain.CurrentDomain.BaseDirectory + "ffmpeg.exe";
string ffmpegParams = "-i " + videopath + " -i " + imagepath + " -filter_complex overlay=10:10 " + OutputFolder ;

ffmpeg.exe freezes

I'm using Asp.Net C# Framework 4 and currently developing a video conversion application. I'm also using ffmpeg to convert from all uploaded formats to flv. I'm first converting uploaded file to mpg and after to flv due to problems I encountered while trying conversion directly to flv from mp4 sometimes. But ffmpeg freezes as soon as it's done with conversion process to mpg file. When I run task manager and check the processes list, it just stands there using no CPU resource. When I end the ffmpeg process directly from task manager, other process take place which converts from mpg to flv and preview file (jpg) and works smoothly. Due to freezing of first process, the second process cannot start when I try to upload from my web page's file upload form. I appreciate any response from now. Here is my code:
string duration = "00:00:00";
//converting video
Process ffmpeg;
ffmpeg = new Process();
// convert to mpg 1st
ffmpeg.StartInfo.Arguments = " -i \"" + Server.MapPath("static/user/vid/") + videolink + "\" -f mpeg -b 300k -ac 2 -ab 128k -ar 44K \"" + Server.MapPath("static/user/vid/") + mpglink + "\"";
ffmpeg.StartInfo.FileName = Page.MapPath("bin/ffmpeg.exe");
ffmpeg.StartInfo.CreateNoWindow = true;
ffmpeg.StartInfo.UseShellExecute = false;
ffmpeg.StartInfo.RedirectStandardOutput = true;
ffmpeg.StartInfo.RedirectStandardError = true;
ffmpeg.Start();
ffmpeg.WaitForExit();
ffmpeg.Close();
// mpg 2 flv
ffmpeg = new Process();
ffmpeg.StartInfo.Arguments = " -i \"" + Server.MapPath("static/user/vid/") + mpglink + "\" -f flv -s 624x352 \"" + Server.MapPath("static/user/vid/") + flvlink + "\"";
ffmpeg.StartInfo.FileName = Page.MapPath("bin/ffmpeg.exe");
ffmpeg.StartInfo.CreateNoWindow = true;
ffmpeg.StartInfo.UseShellExecute = false;
ffmpeg.StartInfo.RedirectStandardOutput = true;
ffmpeg.StartInfo.RedirectStandardError = true;
ffmpeg.Start();
ffmpeg.BeginOutputReadLine();
string error = ffmpeg.StandardError.ReadToEnd();
ffmpeg.WaitForExit();
try
{
duration = error.Substring(error.IndexOf("Duration: ") + 10, 8);
}
catch
{
}
if (ffmpeg.ExitCode != 0)
{
ltrUpload.Text = "<div class=\"resultbox-negative\" id=\"divResult\">Problem occured during upload process. Error code: " + error + "<br>" + "</div>";
return;
}
ffmpeg.Close();
// generate preview image
ffmpeg.StartInfo.Arguments = " -i \"" + Server.MapPath("static/user/vid/") + flvlink + "\" -s 624x352 -ss 00:00:03 -an -vframes 1 -f image2 -vcodec mjpeg \"" + Server.MapPath("static/user/vid/") + flvlink.Replace(".flv", ".jpg") + "\"";
ffmpeg.StartInfo.FileName = Page.MapPath("bin/ffmpeg.exe");
ffmpeg.StartInfo.CreateNoWindow = true;
ffmpeg.StartInfo.UseShellExecute = false;
ffmpeg.StartInfo.RedirectStandardOutput = true;
ffmpeg.StartInfo.RedirectStandardError = true;
ffmpeg.Start();
ffmpeg.WaitForExit();
ffmpeg.Close();
// deleting original file and mpg
FileInfo fi = new FileInfo(Server.MapPath("static/user/vid/") + videolink);
if (fi.Exists) fi.Delete();
fi = new FileInfo(Server.MapPath("static/user/vid/") + mpglink);
if (fi.Exists) fi.Delete();

I know this is a very old question, but if someone gets here because of a Google search, the answer is the following:
You would have to read the redirected error output of the first ffmpeg process, too, even if you do not need it. It will result in a deadlock if you do not read the redirected error output because your program will wait for the process to finish, but the process waits for the filled error output stream to be read. You can look it up here.
// convert to mpg 1st
ffmpeg.StartInfo.Arguments = " -i \"" + Server.MapPath("static/user/vid/") + videolink + "\" -f mpeg -b 300k -ac 2 -ab 128k -ar 44K \"" + Server.MapPath("static/user/vid/") + mpglink + "\"";
ffmpeg.StartInfo.FileName = Page.MapPath("bin/ffmpeg.exe");
ffmpeg.StartInfo.CreateNoWindow = true;
ffmpeg.StartInfo.UseShellExecute = false;
ffmpeg.StartInfo.RedirectStandardOutput = true;
ffmpeg.StartInfo.RedirectStandardError = true;
ffmpeg.Start();
// Use asynchronous read operations on at least one of the streams.
// Reading both streams synchronously would generate another deadlock.
ffmpeg.BeginOutputReadLine();
string tmpErrorOut = ffmpeg.StandardError.ReadToEnd();
ffmpeg.WaitForExit();
ffmpeg.Close();
So you would have to read the redirected error and output streams like you did with your second ffmpeg process.
The same goes for your generating image preview part!

private bool ReturnVideo(string fileName)
{
string html = string.Empty;
//rename if file already exists
int j = 0;
string AppPath;
string inputPath;
string outputPath;
string imgpath;
AppPath = Request.PhysicalApplicationPath;
//Get the application path
inputPath = AppPath + "Upload\\Videos\\OriginalVideo";
//Path of the original file
outputPath = AppPath + "Upload\\Videos\\ConvertVideo";
//Path of the converted file
imgpath = AppPath + "Upload\\Videos\\Thumbs";
//Path of the preview file
string filepath = Server.MapPath("../Upload/Videos/OriginalVideo/" + fileName);
while (File.Exists(filepath))
{
j = j + 1;
int dotPos = fileName.LastIndexOf(".");
string namewithoutext = fileName.Substring(0, dotPos);
string ext = fileName.Substring(dotPos + 1);
fileName = namewithoutext + j + "." + ext;
filepath = Server.MapPath("../Upload/Videos/OriginalVideo/" + fileName);
}
try
{
this.fileuploadImageVideo.SaveAs(filepath);
}
catch
{
return false;
}
string outPutFile;
outPutFile = "../Upload/Videos/OriginalVideo/" + fileName;
int i = this.fileuploadImageVideo.PostedFile.ContentLength;
System.IO.FileInfo a = new System.IO.FileInfo(Server.MapPath(outPutFile));
while (a.Exists == false)
{ }
long b = a.Length;
while (i != b)
{ }
string cmd = " -i \"" + inputPath + "\\" + fileName + "\" \"" + outputPath + "\\" + fileName.Remove(fileName.IndexOf(".")) + ".flv" + "\"";
ConvertNow(cmd);
ViewState["fileName"] = fileName.Remove(fileName.IndexOf(".")) + ".wmv";
string imgargs = " -i \"" + inputPath + "\\" + fileName.Remove(fileName.IndexOf(".")) + ".wmv" + "\" -f image2 -ss 1 -vframes 1 -s 280x200 -an \"" + imgpath + "\\" + fileName.Remove(fileName.IndexOf(".")) + ".jpg" + "\"";
ConvertNow(imgargs);
return true;
}
private void ConvertNow(string cmd)
{
string exepath;
string AppPath = Request.PhysicalApplicationPath;
//Get the application path
exepath = AppPath + "ffmpeg.exe";
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo.FileName = exepath;
//Path of exe that will be executed, only for "filebuffer" it will be "wmvtool2.exe"
proc.StartInfo.Arguments = cmd;
//The command which will be executed
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.CreateNoWindow = true;
proc.StartInfo.RedirectStandardOutput = false;
proc.Start();
while (proc.HasExited == false)
{ }
}
if (fileuploadImageVideo.HasFile)
{
ReturnVideo(this.fileuploadImageVideo.FileName.ToString());
string filename = fileuploadImageVideo.PostedFile.FileName;
fileuploadImageVideo.SaveAs(Server.MapPath("../upload/Video/"+filename));
objfun.Video = filename ;
}

how can i convert a video into image files using ffmpeg in c#?

string inputpath = strFileNamePath;
string outputpath = "C:\\Image\\";
//for (int iIndex = 0; iIndex < 1000; iIndex++)
//{
//string fileargs = "-i" + " " + inputpath + " -ab 56 -ar 44100 -b 200 -r 15 -s 320x240 -f flv " + outputpath + "SRT.flv";
string fileargs = "-i" + " " + inputpath + " " + outputpath + "image.jpg";
System.Diagnostics.Process p = new System.Diagnostics.Process();
p.StartInfo.FileName = "C:\\Documents and Settings\\Badr\\My Documents\\Visual Studio 2008\\Projects\\Video2image2video.\\ffmpeg\\ffmpeg.exe";
p.StartInfo.Arguments = fileargs;
p.StartInfo.UseShellExecute = false;
p.StartInfo.CreateNoWindow = true;
p.StartInfo.RedirectStandardOutput = true;
p.Start();
i have this code this creates only 1 image of video i apply a loop but i repeatedly generates the initial image how can i get images of all the video
thanx in advance

From the documentation of ffmpeg:
You can extract images from a video,
or create a video from many images:
For extracting images from a video:
ffmpeg -i foo.avi -r 1 -s WxH -f
image2 foo-%03d.jpeg
This will extract one video frame per
second from the video and will output
them in files named foo-001.jpeg',
foo-002.jpeg', etc. Images will be
rescaled to fit the new WxH values.
So just change the arguments you pass to ffmpeg and you should be up and running.

Hi do you want to take images in video files when you for to return in in this way;
for (int i = 0; i < iImageCount; i++)
{
string sInputVideo = Page.MapPath(...);
string sImageCapture = Page.MapPath("") + "\\Videolar\\" + ImageName+ "_" + iResim + ".jpg";
ffmpeg.StartInfo.Arguments = " -i \"" + sInputVideo + "\" -s 108*100 -ss " + iImageCapture + " -vframes 1 -f image2 -vcodec mjpeg \"" + sImageCapture + "\"";
ffmpeg.StartInfo.FileName = (Server.MapPath("Referanslar/ffmpeg.exe"));
ffmpeg.Start();
ffmpeg.WaitForExit();
ffmpeg.Close();
iImageCapture += 1;
iResim++;
}
You can take pictures as you like by changing it ;)