I am trying to show icon on the taskbar, well i did this in this way.
ResourceManager resManager = new ResourceManager("TestAgent.Properties.Resources", GetType().Module.Assembly);
notifyicon.Icon = (Icon)resManager.GetObject("TestAgent");
notifyicon.Visible = true;
notifyicon.Text = "Test Agent";
this.Hide();
this.ShowInTaskbar = false;
this.SetVisibleCore(false);
On other side when try remove icon from the taskbar doing in this way.
notifyicon.Visible = false;
notifyicon = null;
rulehandler = null;
I did this successfully but the problem is when try to remove icon from the taskbar it remove icon successfully from the taskbar but not hide the icon, When hover the mouse on the icon it removes.
Is there anyway to remove icon without mouse hover?
I am doing this in windows form with c#
Simply Dispose it.
In a Windows Form you can subscribe to the global event ApplicationExit ...
Application.ApplicationExit += new EventHandler(this.OnApplicationExit);
private void OnApplicationExit(object sender, EventArgs e) {
notifyicon.Dispose();
}
simply write notifyIcon.Visible = false; (capital I in Icon) before closing the window, and you are good to go.
As simple as that.
Related
I am using NotifyIcon to make my form minimize to tray to work at background.
However below code doesn't show app icon at all. Form goes totally invisible. I have to kill that from task manager.
private void Button1_Click(object sender, EventArgs e)
{
this.WindowState = FormWindowState.Minimized;
if (FormWindowState.Minimized == this.WindowState)
{
Hide();
this.ShowInTaskbar = false;
notifyIcon1.Visible = true;
}
}
What could be the reason? I want to see my app-icon to re-open the form.
You need to assign an Icon to NotifyIcon to show it in system tray. Also you need to set Visible to true.
You can set properties using property grid at design time or you can set them by code. For example, you can use such code:
this.notifyIcon1.Icon = this.Icon;
this.notifyIcon1.Visible = true;
If you don't set the Icon or if the visible is not true, it will not show the icon.
Firstly, I have zero experience programming with .NET so this could be a pretty nooby question...
I'm wondering if it's possible to build an application like xFire - which displays pop-ups in-game to a user.
As the primary application will have focus, how does my application manage to display it's message/popup? Does the primary application have to allow access or something?
Cheers!
Looks like you are looking for NotifyIcon, it displays little pop-ups just as know from Windows.
The example is a little long, but the documentation will surely help you understand.
using System;
using System.Drawing;
using System.Windows.Forms;
public class Form1 : System.Windows.Forms.Form
{
private System.Windows.Forms.NotifyIcon notifyIcon1;
private System.Windows.Forms.ContextMenu contextMenu1;
private System.Windows.Forms.MenuItem menuItem1;
private System.ComponentModel.IContainer components;
[STAThread]
static void Main()
{
Application.Run(new Form1());
}
public Form1()
{
this.components = new System.ComponentModel.Container();
this.contextMenu1 = new System.Windows.Forms.ContextMenu();
this.menuItem1 = new System.Windows.Forms.MenuItem();
// Initialize contextMenu1
this.contextMenu1.MenuItems.AddRange(
new System.Windows.Forms.MenuItem[] {this.menuItem1});
// Initialize menuItem1
this.menuItem1.Index = 0;
this.menuItem1.Text = "E&xit";
this.menuItem1.Click += new System.EventHandler(this.menuItem1_Click);
// Set up how the form should be displayed.
this.ClientSize = new System.Drawing.Size(292, 266);
this.Text = "Notify Icon Example";
// Create the NotifyIcon.
this.notifyIcon1 = new System.Windows.Forms.NotifyIcon(this.components);
// The Icon property sets the icon that will appear
// in the systray for this application.
notifyIcon1.Icon = new Icon("appicon.ico");
// The ContextMenu property sets the menu that will
// appear when the systray icon is right clicked.
notifyIcon1.ContextMenu = this.contextMenu1;
// The Text property sets the text that will be displayed,
// in a tooltip, when the mouse hovers over the systray icon.
notifyIcon1.Text = "Form1 (NotifyIcon example)";
notifyIcon1.Visible = true;
// Handle the DoubleClick event to activate the form.
notifyIcon1.DoubleClick += new System.EventHandler(this.notifyIcon1_DoubleClick);
}
protected override void Dispose( bool disposing )
{
// Clean up any components being used.
if( disposing )
if (components != null)
components.Dispose();
base.Dispose( disposing );
}
private void notifyIcon1_DoubleClick(object Sender, EventArgs e)
{
// Show the form when the user double clicks on the notify icon.
// Set the WindowState to normal if the form is minimized.
if (this.WindowState == FormWindowState.Minimized)
this.WindowState = FormWindowState.Normal;
// Activate the form.
this.Activate();
}
private void menuItem1_Click(object Sender, EventArgs e) {
// Close the form, which closes the application.
this.Close();
}
}
See MSDN.
"As the primary application will have focus, how does my application manage to display it's message/popup? Does the primary application have to allow access or something?"
An application can set itself as "TopMost" which means it appears in front of other "normal" applications that are not TopMost. A well behaved notification will appear without stealing focus from the current application (this is usually achieved with the ShowWindow() API and the SW_SHOWNA flag). This does not require any permission from the currently active application.
Take a look at TaskbarNotifier, a skinnable MSN Messenger-like popup in C# and now in VB.NET too.
I am working on a Windows application, and when I run this application, there are multiple icons appearing on the tray bar:
and when I mouse-over these icons, they disappear.
Does anybody have any idea why this is happening?
protected override void OnClosed(EventArgs e)
{
try
{
notifyIcon1.Visible = false;
notifyIcon1.Icon.Dispose();
notifyIcon1.Dispose();
}
catch(Exception ex)
{
}
base.OnClosed(e);
Environment.Exit(0);
}
Here is how I close my system tray icon to bring up the full application in a program I wrote a while back:
NOTE: this fits well in an event handler in the code behind, hence this.Show() and this.Activate()
NotifyIcon sysTrayIcon = sender as NotifyIcon;
sysTrayIcon.Visible = false;
this.WindowState = WindowState.Normal;
this.Show();
this.Activate();
I've successfully created an app that minimizes to the tray using a NotifyIcon. When the form is manually closed it is successfully hidden from the desktop, taskbar, and alt-tab. The problem occurs when trying to start with the app minimized. At first the problem was that the app would be minimized but would still appear in the alt-tab dialog. Changing the FormBorderStyle to one of the ToolWindow options (from the "None" option) fixed this, but introduced another problem. When the app first starts the titlebar of the minimized window is visible just above the start menu:
Opening the form and the closing it causes it to hide properly. I've tried lots of variations, but here's essentially how it's working right now...
WindowState is set to Minimized in the Designer. After some initialization in the constructor I have the following lines:
this.Visible = false;
this.ShowInTaskbar = false;
When the NotifyIcon is double-clicked I have the following:
this.WindowState = FormWindowState.Normal;
this.Visible = true;
this.ShowInTaskbar = true;
Like I said, I've tried lots of minor variations on this (this.Hide(), etc.). Is there a way to have the NotifyIcon be the primary component such that I can completely start and dispose of the form while leaving the NotifyIcon running? There's got to be a way to start the app with the form minimized without any of the weirdness. Please help me find it!
The right way to do this is to prevent the form from getting visible in the first place. That requires overriding SetVisibleCore(). Let's assume a context menu for the NotifyIcon with a Show and Exit command. You can implement it like this:
public partial class Form1 : Form {
public Form1() {
InitializeComponent();
notifyIcon1.ContextMenuStrip = contextMenuStrip1;
this.showToolStripMenuItem.Click += showToolStripMenuItem_Click;
this.exitToolStripMenuItem.Click += exitToolStripMenuItem_Click;
}
private bool allowVisible; // ContextMenu's Show command used
private bool allowClose; // ContextMenu's Exit command used
protected override void SetVisibleCore(bool value) {
if (!allowVisible) {
value = false;
if (!this.IsHandleCreated) CreateHandle();
}
base.SetVisibleCore(value);
}
protected override void OnFormClosing(FormClosingEventArgs e) {
if (!allowClose) {
this.Hide();
e.Cancel = true;
}
base.OnFormClosing(e);
}
private void showToolStripMenuItem_Click(object sender, EventArgs e) {
allowVisible = true;
Show();
}
private void exitToolStripMenuItem_Click(object sender, EventArgs e) {
allowClose = true;
Application.Exit();
}
}
Note a wrinkle with the Load event, it won't fire until the main form is first shown. So be sure to do initialization in the form's constructor, not the Load event handler.
I'm reading all the answers and see hacks and black magic... (no offense, mates)
No hacks needed. You don't even have to set "ShowInTaskbar=false" and other stuff. Just do this:
//"Form Shown" event handler
private void Form_Shown(object sender, EventArgs e)
{
//to minimize window
this.WindowState = FormWindowState.Minimized;
//to hide from taskbar
this.Hide();
}
NOTE: I strongly recommend NOT TOUCHING the "ShowInTaskbar" property. For example, if your application registers system-wide hotkeys or other similar stuff (hooks, etc) - setting ShowInTaskBar=false and minimizing your app will prevent Windows from sending some messages to your window... And your hooks/hotkeys/etc will stop working.
In the constructor, remove these two lines:
this.Visible = false;
this.ShowInTaskbar = false;
and add after InitializeComponent();:
this.WindowState = FormWindowState.Minimized;
In designer, set ShowInTaskbar to false & FormWindowState to Normal.
EDIT:
If you post the same in Load event, the window does get minimized but still shows minimized on the desktop. I think this is a bug.
When minimizing an application and you want to hide it from Alt+Tab:
You also need to set the Opacity to stop the titlebar showing near the Start Menu when you set the Border Style to a Tool Window.
On Minimize Event:
this.Visible = false;
this.Opacity = 0;
this.FormBorderStyle = FormBorderStyle.FixedToolWindow;
this.ShowInTaskbar = false;
On Normalize Event:
this.Visible = true;
this.Opacity = 100;
this.FormBorderStyle = FormBorderStyle.FixedSingle; //or whatever it was previously set to
this.ShowInTaskbar = true;
Move the following code from the Form's constructor to Form_Main_Load(). With the same setup on Notification_Icon when Form_Resize().
// Hide the Form to System Tray
this.WindowState = FormWindowState.Minimized;
This "quick and dirty fix" worked for me:
$form1.FormBorderStyle = "fixedtoolwindow"
$form1.top = -1000000
$form1.Left = -1000000
$form1.Width = 10
$form1.Height = 10
$form1.WindowState = "normal"
$form1.ShowInTaskbar = $False
$form1.Opacity = 0
$form1.Hide()
Hope it helps someone else...
I mean when the user starts my application(exe). I want it to start directly in system tray, without showing the window. Like antivirus softwares & download managers, which start and run in the system tray silently.
I want the same effect and when user click the "show" button of the notifyIcon's contextmenustrip then only application should show GUI.
I'm using this, but its not working
private void Form_Load(object sender, EventArgs e)
{
this.Hide();
}
May be I need to have Main() function in some other class which has no GUI but has notifyIcon & ContextMenuStrip whose option will instantiate the GUI window class. Right?
The way I usually setup something like this is to modify the Program.cs to look something like the following:
[STAThread]
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
using (NotifyIcon icon = new NotifyIcon())
{
icon.Icon = System.Drawing.Icon.ExtractAssociatedIcon(Application.ExecutablePath);
icon.ContextMenu = new ContextMenu(new MenuItem[] {
new MenuItem("Show form", (s, e) => {new Form1().Show();}),
new MenuItem("Exit", (s, e) => { Application.Exit(); }),
});
icon.Visible = true;
Application.Run();
icon.Visible = false;
}
}
Using this, you don't need to worry about hiding instead of closing forms and all the rest of the hacks that can lead to... You can make a singleton form too instead of instantiating a new Form every time you click the show form option. This is something to build off of, not the end solution.
You need to set up the notify icon as well.
Either manually or via the toolbar (drag a notifyIcon onto your form) create the notifyIcon:
this.notifyIcon = new System.Windows.Forms.NotifyIcon(components);
Then add this code to Form_Load():
// Notify icon set up
notifyIcon.Visible = true;
notifyIcon.Text = "Tooltip message here";
this.ShowInTaskbar = false;
this.Hide();
Though this will, as has been pointed out, briefly show the form before hiding it.
From the accepted answer of this question, the solution appears to be to change:
Application.Run(new Form1());
to:
Form1 f = new Form1();
Application.Run();
in Main().
Have you created a Windows Application in C#?
You need to drag a NotifyIcon control onto the form, the control will be placed below the form because it has no visual representation on the form itself.
Then you set its properties such as the Icon...
Try this one first...