Develop Reference

A parameter cannot be found that matches parameter name 'all' c#

I am trying to execute a command through c#. I pass a command as a parameter through a function which then executes it on my terminal in VS Code. When I pass the command 'ps' it works, but when I pass the command 'ls - all' it gives me the error: A parameter cannot be found that matches parameter name 'all'. I think it probably has to do something with the space, but I'm not sure. I don't know how to solve it. This is the function I use to pass the command and execute it:
public void ExecuteCommand(string key) {
System.Diagnostics.Process process = new System.Diagnostics.Process();
try {
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
startInfo.FileName = #"powershell.exe";
startInfo.Arguments = "/c " + key;
process.StartInfo = startInfo;
process.Start();
process.Close();
}
catch {
Console.WriteLine("Error occured");
}
Console.WriteLine("Command executed");
}

You have to use the command ls -Force to list all the files including the hidden files.ls -al works in linux.

Start a process with a command line parameter of another executable

I'm trying to pass an .exe to another through C# code.
Here's my code so far:
string ex1 = System.Windows.Forms.Application.StartupPath.ToString() + "\\dev\\psm.exe";
string ex2 = System.Windows.Forms.Application.StartupPath.ToString() + "\\dev\\Application\\app.exe";
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.CreateNoWindow = false;
startInfo.UseShellExecute = false;
startInfo.FileName = ex1;
startInfo.WindowStyle = ProcessWindowStyle.Normal;
startInfo.Arguments = ex2;
try
{
Process.Start(startInfo);
}
catch
{
}
Which argument would work as dragging a file onto the application?
Details:
When you run psm.exe normally, it prompts for file name and directory.
However, when you drag an approved app on psm.exe,
it loads the app automatically.
How can this be done with C#?

You can run another app synchronously like this:
System.Diagnostics.Process myapp = new System.Diagnostics.Process();
myapp.StartInfo.FileName = ex1;
myapp.StartInfo.Arguments = ex2;
myapp.Start();
myapp.WaitForExit();
Depending on how the app you want to launch expects the command line arguments to be passed, you may need this for the arguments:
myapp.StartInfo.Arguments = String.Format("/MyArgumentName={0}", ex2);
That would be the equivalent of:
c:\MyApplicationStartupPath\dev\psm.exe /MyArgumentName=c:\MyApplicationStartupPath\Application\App.exe
Be sure to match the way app.exe expects the parameters in your StartInfo.Arguments

Executing System.Diagnostics.Process cmd.exe only opens command prompt, doesn't execute arguments

Where am I going wrong with this? It's like the arguments are not even getting executed, it just opens the command prompt, and that's it. The "results" (StandardOutput) is exactly what shows up when you just open a new command prompt....says Microsoft Windows [Version 6.1.7600] Copyright...blah then the path where the command prompt is starting from.
Anyway, here's the code that I have:
private static void ExecuteProcess(string processFile, string processArguments)
{
ProcessStartInfo psi = new ProcessStartInfo(processFile, processArguments);
psi.RedirectStandardOutput = true;
psi.RedirectStandardError = true;
psi.UseShellExecute = false;
//psi.CreateNoWindow = true;
Process p = new Process();
p.StartInfo = psi;
try
{
Cursor.Current = Cursors.WaitCursor;
p.Start();
string output = p.StandardOutput.ReadToEnd();
p.WaitForExit();
Cursor.Current = Cursors.Default;
if (p.ExitCode == 0)
MessageBox.Show(output, "Results");
else
throw new Exception(p.StandardError.ReadToEnd());
}
catch (Exception ex)
{
Cursor.Current = Cursors.Default;
MessageBox.Show(ex.ToString(), "Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
}
finally
{
p.Dispose();
}
}
processFile is equal to "cmd.exe"
processArguments is equal to:
csvde -s {servername} -f {filename} -d OU=MyOU,DC=dmz,DC=lan -r "(objectClass=organizationalUnit)" -n
Any help as to why the "arguments" aren't getting executed would be great!
Edit:
One thing I've found so far, Chris's suggestion about the permissions is true, I needed to set:
psi.Verb = "runas";
But when executing the process it didn't look like there was a username associated with the process, so I added this line as well:
psi.UserName = Environment.UserName;
Now I'm getting "the stub received bad data"...

From the docs:
Cmd
Starts a new instance of the command interpreter, Cmd.exe. Used
without parameters, cmd displays Windows XP version and copyright
information.
Syntax cmd [[{/c|/k}] [/s] [/q] [/d] [{/a|/u}] [/t:fg]
[/e:{on|off}] [/f:{on|off}] [/v:{on|off}] string] Top of page
Parameters
/c : Carries out the command specified by string and then
stops.
So you need to:
Pass the full path to the EXE or
Set the working directory to the directory containing the exe
then
Make processFile == "[]csvde.exe", and remove it from processArguments, or
Prepent "/c \"" and append "\"" to processArguments.

I finally got back to working on this and figured out how to get this to work.
I had to specifically set the Username, Password, and Domain of the Process.ProcessStartInfo in order for the process to execute.

Command line program/app + C# class method

When working with a command line program, via a c# class method.
How do you determine if the commandline program was successfully executed and the operation it has performed is ok or has failed?
Also how do you get the screen commandline output into the c# class method?

You can use the Process class to execute a command line command.
The following code captures the standard output to output, and assigns the processes exit code to exitCode.
using (Process p = new Process())
{
p.StartInfo.FileName = exeName;
p.StartInfo.Arguments = args;
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.Start();
string output = p.StandardOutput.ReadToEnd();
p.WaitForExit();
int exitCode = p.ExitCode;
}

Something like:
Process mycommand = new Process();
mycommand.StartInfo.FileName = "myexe.exe";
mycommand.StartInfo.Arguments = "param1";
mycommand.StartInfo.UseShellExecute = false;
mycommand.StartInfo.RedirectStandardOutput = true;
mycommand.Start();
Console.WriteLine(mycommand.StandardOutput.ReadToEnd());
mycommand.WaitForExit();
You usually determine an exe's state wether the exit code is 0, but that is arguably down to the writer of the exe

I assume you're using the Process class to call the command line app.
You can find the exit code of the process using Process.ExitCode. You can redirect its standard output by setting ProcessStartInfo.RedirectStandardOutput before starting it, and then either using Process.StandardOutput or the Process.OutputDataReceived event.

Take a look at this questionenter link description here.
The additional information you might need is process.ExitCode to see if it was sucessful. Of course, the Main method of the console app must return an exit code when it is unsuccessful, which many do not.

For this, you use the Process.Start method. You can control how the process runs with the passed in ProcessStartInfo:
var myProcess = Process.Start(new ProcessStartInfo {
FileName = "process.exe",
UseShellExecute = false,
RedirectStandardOutput = true,
CreateNoWindow = true
});
if (!myProcess.WaitForExit(5000)) { // give it 5 seconds to exit
myProcess.Kill();
}
if (myProcess.ExitCode != 0) {
// error!
}
var output = myProcess.StandardOutput.ReadToEnd(); // access output

Run Command Prompt Commands

Is there any way to run command prompt commands from within a C# application? If so how would I do the following:
copy /b Image1.jpg + Archive.rar Image2.jpg
This basically embeds an RAR file within JPG image. I was just wondering if there was a way to do this automatically in C#.

this is all you have to do run shell commands from C#
string strCmdText;
strCmdText= "/C copy /b Image1.jpg + Archive.rar Image2.jpg";
System.Diagnostics.Process.Start("CMD.exe",strCmdText);
EDIT:
This is to hide the cmd window.
System.Diagnostics.Process process = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
startInfo.FileName = "cmd.exe";
startInfo.Arguments = "/C copy /b Image1.jpg + Archive.rar Image2.jpg";
process.StartInfo = startInfo;
process.Start();
EDIT 2:
It is important that the argument begins with /C, otherwise it won't work. As #scott-ferguson said: /C carries out the command specified by the string and then terminates.

Tried RameshVel's solution but I could not pass arguments in my console application. If anyone experiences the same problem here is a solution:
using System.Diagnostics;
Process cmd = new Process();
cmd.StartInfo.FileName = "cmd.exe";
cmd.StartInfo.RedirectStandardInput = true;
cmd.StartInfo.RedirectStandardOutput = true;
cmd.StartInfo.CreateNoWindow = true;
cmd.StartInfo.UseShellExecute = false;
cmd.Start();
cmd.StandardInput.WriteLine("echo Oscar");
cmd.StandardInput.Flush();
cmd.StandardInput.Close();
cmd.WaitForExit();
Console.WriteLine(cmd.StandardOutput.ReadToEnd());

var proc1 = new ProcessStartInfo();
string anyCommand;
proc1.UseShellExecute = true;
proc1.WorkingDirectory = #"C:\Windows\System32";
proc1.FileName = #"C:\Windows\System32\cmd.exe";
proc1.Verb = "runas";
proc1.Arguments = "/c "+anyCommand;
proc1.WindowStyle = ProcessWindowStyle.Hidden;
Process.Start(proc1);

None of the above answers helped for some reason, it seems like they sweep errors under the rug and make troubleshooting one's command difficult. So I ended up going with something like this, maybe it will help someone else:
var proc = new Process
{
StartInfo = new ProcessStartInfo
{
FileName = #"C:\Program Files\Microsoft Visual Studio 14.0\Common7\IDE\tf.exe",
Arguments = "checkout AndroidManifest.xml",
UseShellExecute = false,
RedirectStandardOutput = true,
CreateNoWindow = true,
WorkingDirectory = #"C:\MyAndroidApp\"
}
};
proc.Start();

Though technically this doesn't directly answer question posed, it does answer the question of how to do what the original poster wanted to do: combine files. If anything, this is a post to help newbies understand what Instance Hunter and Konstantin are talking about.
This is the method I use to combine files (in this case a jpg and a zip). Note that I create a buffer that gets filled with the content of the zip file (in small chunks rather than in one big read operation), and then the buffer gets written to the back of the jpg file until the end of the zip file is reached:
private void CombineFiles(string jpgFileName, string zipFileName)
{
using (Stream original = new FileStream(jpgFileName, FileMode.Append))
{
using (Stream extra = new FileStream(zipFileName, FileMode.Open, FileAccess.Read))
{
var buffer = new byte[32 * 1024];
int blockSize;
while ((blockSize = extra.Read(buffer, 0, buffer.Length)) > 0)
{
original.Write(buffer, 0, blockSize);
}
}
}
}

if you want to run the command in async mode - and print the results. you can you this class:
public static class ExecuteCmd
{
/// <summary>
/// Executes a shell command synchronously.
/// </summary>
/// <param name="command">string command</param>
/// <returns>string, as output of the command.</returns>
public static void ExecuteCommandSync(object command)
{
try
{
// create the ProcessStartInfo using "cmd" as the program to be run, and "/c " as the parameters.
// Incidentally, /c tells cmd that we want it to execute the command that follows, and then exit.
System.Diagnostics.ProcessStartInfo procStartInfo = new System.Diagnostics.ProcessStartInfo("cmd", "/c " + command);
// The following commands are needed to redirect the standard output.
//This means that it will be redirected to the Process.StandardOutput StreamReader.
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = false;
// Do not create the black window.
procStartInfo.CreateNoWindow = true;
// Now we create a process, assign its ProcessStartInfo and start it
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo = procStartInfo;
proc.Start();
// Get the output into a string
string result = proc.StandardOutput.ReadToEnd();
// Display the command output.
Console.WriteLine(result);
}
catch (Exception objException)
{
// Log the exception
Console.WriteLine("ExecuteCommandSync failed" + objException.Message);
}
}
/// <summary>
/// Execute the command Asynchronously.
/// </summary>
/// <param name="command">string command.</param>
public static void ExecuteCommandAsync(string command)
{
try
{
//Asynchronously start the Thread to process the Execute command request.
Thread objThread = new Thread(new ParameterizedThreadStart(ExecuteCommandSync));
//Make the thread as background thread.
objThread.IsBackground = true;
//Set the Priority of the thread.
objThread.Priority = ThreadPriority.AboveNormal;
//Start the thread.
objThread.Start(command);
}
catch (ThreadStartException )
{
// Log the exception
}
catch (ThreadAbortException )
{
// Log the exception
}
catch (Exception )
{
// Log the exception
}
}
}

if you want to keep the cmd window open or want to use it in winform/wpf then use it like this
string strCmdText;
//For Testing
strCmdText= "/K ipconfig";
System.Diagnostics.Process.Start("CMD.exe",strCmdText);
/K
Will keep the cmd window open

Yes, there is (see link in Matt Hamilton's comment), but it would be easier and better to use .NET's IO classes. You can use File.ReadAllBytes to read the files and then File.WriteAllBytes to write the "embedded" version.

with a reference to Microsoft.VisualBasic
Interaction.Shell("copy /b Image1.jpg + Archive.rar Image2.jpg", AppWinStyle.Hide);

This can also be done by P/Invoking the C standard library's system function.
using System.Runtime.InteropServices;
[DllImport("msvcrt.dll")]
public static extern int system(string format);
system("copy Test.txt Test2.txt");
Output:
1 file(s) copied.

Here is little simple and less code version. It will hide the console window too-
System.Diagnostics.Process process = new System.Diagnostics.Process();
process.StartInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
process.StartInfo.FileName = "cmd.exe";
process.StartInfo.Arguments = "/C copy /b Image1.jpg + Archive.rar Image2.jpg";
process.Start();

I have the following method, which I use to run the command prompt commands from C#
In first parameter pass the command you want to run
public static string RunCommand(string arguments, bool readOutput)
{
var output = string.Empty;
try
{
var startInfo = new ProcessStartInfo
{
Verb = "runas",
FileName = "cmd.exe",
Arguments = "/C "+arguments,
WindowStyle = ProcessWindowStyle.Hidden,
UseShellExecute = false,
CreateNoWindow = true,
RedirectStandardOutput = true,
RedirectStandardError = false
};
var proc = Process.Start(startInfo);
if (readOutput)
{
output = proc.StandardOutput.ReadToEnd();
}
proc.WaitForExit(60000);
return output;
}
catch (Exception)
{
return output;
}
}

You can achieve this by using the following method (as mentioned in other answers):
strCmdText = "'/C some command";
Process.Start("CMD.exe", strCmdText);
When I tried the methods listed above I found that my custom command did not work using the syntax of some of the answers above.
I found out more complex commands need to be encapsulated in quotes to work:
string strCmdText;
strCmdText = "'/C cd " + path + " && composer update && composer install -o'";
Process.Start("CMD.exe", strCmdText);

you can use simply write the code in a .bat format extension ,the code of the batch file :
c:/ copy /b Image1.jpg + Archive.rar Image2.jpg
use this c# code :
Process.Start("file_name.bat")

You can use RunProcessAsTask pacakge and run your process async and easily like this:
var processResults = await ProcessEx.RunAsync("git.exe", "pull");
//get process result
foreach (var output in processResults.StandardOutput)
{
Console.WriteLine("Output line: " + output);
}

This may be a bit of a read so im sorry in advance. And this is my tried and tested way of doing this, there may be a simpler way but this is from me throwing code at a wall and seeing what stuck
If it can be done with a batch file then the maybe over complicated work around is have c# write a .bat file and run it. If you want user input you could place the input into a variable and have c# write it into the file. it will take trial and error with this way because its like controlling a puppet with another puppet.
here is an example, In this case the function is for a push button in windows forum app that clears the print queue.
using System.IO;
using System;
public static void ClearPrintQueue()
{
//this is the path the document or in our case batch file will be placed
string docPath =
Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
//this is the path process.start usues
string path1 = docPath + "\\Test.bat";
// these are the batch commands
// remember its "", the comma separates the lines
string[] lines =
{
"#echo off",
"net stop spooler",
"del %systemroot%\\System32\\spool\\Printers\\* /Q",
"net start spooler",
//this deletes the file
"del \"%~f0\"" //do not put a comma on the last line
};
//this writes the string to the file
using (StreamWriter outputFile = new StreamWriter(Path.Combine(docPath, "test.bat")))
{
//This writes the file line by line
foreach (string line in lines)
outputFile.WriteLine(line);
}
System.Diagnostics.Process.Start(path1);
}
IF you want user input then you could try something like this.
This is for setting the computer IP as static but asking the user what the IP, gateway, and dns server is.
you will need this for it to work
public static void SetIPStatic()
{
//These open pop up boxes which ask for user input
string STATIC = Microsoft.VisualBasic.Interaction.InputBox("Whats the static IP?", "", "", 100, 100);
string SUBNET = Microsoft.VisualBasic.Interaction.InputBox("Whats the Subnet?(Press enter for default)", "255.255.255.0", "", 100, 100);
string DEFAULTGATEWAY = Microsoft.VisualBasic.Interaction.InputBox("Whats the Default gateway?", "", "", 100, 100);
string DNS = Microsoft.VisualBasic.Interaction.InputBox("Whats the DNS server IP?(Input required, 8.8.4.4 has already been set as secondary)", "", "", 100, 100);
//this is the path the document or in our case batch file will be placed
string docPath =
Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
//this is the path process.start usues
string path1 = docPath + "\\Test.bat";
// these are the batch commands
// remember its "", the comma separates the lines
string[] lines =
{
"SETLOCAL EnableDelayedExpansion",
"SET adapterName=",
"FOR /F \"tokens=* delims=:\" %%a IN ('IPCONFIG ^| FIND /I \"ETHERNET ADAPTER\"') DO (",
"SET adapterName=%%a",
"REM Removes \"Ethernet adapter\" from the front of the adapter name",
"SET adapterName=!adapterName:~17!",
"REM Removes the colon from the end of the adapter name",
"SET adapterName=!adapterName:~0,-1!",
//the variables that were set before are used here
"netsh interface ipv4 set address name=\"!adapterName!\" static " + STATIC + " " + STATIC + " " + DEFAULTGATEWAY,
"netsh interface ipv4 set dns name=\"!adapterName!\" static " + DNS + " primary",
"netsh interface ipv4 add dns name=\"!adapterName!\" 8.8.4.4 index=2",
")",
"ipconfig /flushdns",
"ipconfig /registerdns",
":EOF",
"DEL \"%~f0\"",
""
};
//this writes the string to the file
using (StreamWriter outputFile = new StreamWriter(Path.Combine(docPath, "test.bat")))
{
//This writes the file line by line
foreach (string line in lines)
outputFile.WriteLine(line);
}
System.Diagnostics.Process.Start(path1);
}
Like I said. It may be a little overcomplicated but it never fails unless I write the batch commands wrong.