Related
I have a TextBoxD1.Text and I want to convert it to an int to store it in a database.
How can I do this?
Try this:
int x = Int32.Parse(TextBoxD1.Text);
or better yet:
int x = 0;
Int32.TryParse(TextBoxD1.Text, out x);
Also, since Int32.TryParse returns a bool you can use its return value to make decisions about the results of the parsing attempt:
int x = 0;
if (Int32.TryParse(TextBoxD1.Text, out x))
{
// you know that the parsing attempt
// was successful
}
If you are curious, the difference between Parse and TryParse is best summed up like this:
The TryParse method is like the Parse
method, except the TryParse method
does not throw an exception if the
conversion fails. It eliminates the
need to use exception handling to test
for a FormatException in the event
that s is invalid and cannot be
successfully parsed. - MSDN
Convert.ToInt32( TextBoxD1.Text );
Use this if you feel confident that the contents of the text box is a valid int. A safer option is
int val = 0;
Int32.TryParse( TextBoxD1.Text, out val );
This will provide you with some default value you can use. Int32.TryParse also returns a Boolean value indicating whether it was able to parse or not, so you can even use it as the condition of an if statement.
if( Int32.TryParse( TextBoxD1.Text, out val ){
DoSomething(..);
} else {
HandleBadInput(..);
}
int.TryParse()
It won't throw if the text is not numeric.
int myInt = int.Parse(TextBoxD1.Text)
Another way would be:
bool isConvertible = false;
int myInt = 0;
isConvertible = int.TryParse(TextBoxD1.Text, out myInt);
The difference between the two is that the first one would throw an exception if the value in your textbox can't be converted, whereas the second one would just return false.
Be careful when using Convert.ToInt32() on a char!
It will return the UTF-16 code of the character!
If you access the string only in a certain position using the [i] indexing operator, it will return a char and not a string!
String input = "123678";
^
|
int indexOfSeven = 4;
int x = Convert.ToInt32(input[indexOfSeven]); // Returns 55
int x = Convert.ToInt32(input[indexOfSeven].toString()); // Returns 7
You need to parse the string, and you also need to ensure that it is truly in the format of an integer.
The easiest way is this:
int parsedInt = 0;
if (int.TryParse(TextBoxD1.Text, out parsedInt))
{
// Code for if the string was valid
}
else
{
// Code for if the string was invalid
}
int x = 0;
int.TryParse(TextBoxD1.Text, out x);
The TryParse statement returns a boolean representing whether the parse has succeeded or not. If it succeeded, the parsed value is stored into the second parameter.
See Int32.TryParse Method (String, Int32) for more detailed information.
Enjoy it...
int i = 0;
string s = "123";
i =int.Parse(s);
i = Convert.ToInt32(s);
While there are already many solutions here that describe int.Parse, there's something important missing in all the answers. Typically, the string representations of numeric values differ by culture. Elements of numeric strings such as currency symbols, group (or thousands) separators, and decimal separators all vary by culture.
If you want to create a robust way to parse a string to an integer, it's therefore important to take the culture information into account. If you don't, the current culture settings will be used. That might give a user a pretty nasty surprise -- or even worse, if you're parsing file formats. If you just want English parsing, it's best to simply make it explicit, by specifying the culture settings to use:
var culture = CultureInfo.GetCulture("en-US");
int result = 0;
if (int.TryParse(myString, NumberStyles.Integer, culture, out result))
{
// use result...
}
For more information, read up on CultureInfo, specifically NumberFormatInfo on MSDN.
int x = Int32.TryParse(TextBoxD1.Text, out x) ? x : 0;
You can write your own extension method
public static class IntegerExtensions
{
public static int ParseInt(this string value, int defaultValue = 0)
{
int parsedValue;
if (int.TryParse(value, out parsedValue))
{
return parsedValue;
}
return defaultValue;
}
public static int? ParseNullableInt(this string value)
{
if (string.IsNullOrEmpty(value))
{
return null;
}
return value.ParseInt();
}
}
And wherever in code just call
int myNumber = someString.ParseInt(); // Returns value or 0
int age = someString.ParseInt(18); // With default value 18
int? userId = someString.ParseNullableInt(); // Returns value or null
In this concrete case
int yourValue = TextBoxD1.Text.ParseInt();
As explained in the TryParse documentation, TryParse() returns a Boolean which indicates that a valid number was found:
bool success = Int32.TryParse(TextBoxD1.Text, out val);
if (success)
{
// Put val in database
}
else
{
// Handle the case that the string doesn't contain a valid number
}
You can convert string to int many different type methods in C#
First one is mostly use :
string test = "123";
int x = Convert.ToInt16(test);
if int value is higher you should use int32 type.
Second one:
int x = int.Parse(text);
if you want to error check, you can use TryParse method. In below I add nullable type;
int i=0;
Int32.TryParse(text, out i) ? i : (int?)null);
Enjoy your codes....
Conversion of string to int can be done for: int, Int32, Int64 and other data types reflecting integer data types in .NET
Below example shows this conversion:
This shows (for info) data adapter element initialized to int value. The same can be done directly like,
int xxiiqVal = Int32.Parse(strNabcd);
Ex.
string strNii = "";
UsrDataAdapter.SelectCommand.Parameters["#Nii"].Value = Int32.Parse(strNii );
Link to see this demo.
int i = Convert.ToInt32(TextBoxD1.Text);
//May be quite some time ago but I just want throw in some line for any one who may still need it
int intValue;
string strValue = "2021";
try
{
intValue = Convert.ToInt32(strValue);
}
catch
{
//Default Value if conversion fails OR return specified error
// Example
intValue = 2000;
}
You can use either,
int i = Convert.ToInt32(TextBoxD1.Text);
or
int i = int.Parse(TextBoxD1.Text);
You can do like below without TryParse or inbuilt functions:
static int convertToInt(string a)
{
int x = 0;
for (int i = 0; i < a.Length; i++)
{
int temp = a[i] - '0';
if (temp != 0)
{
x += temp * (int)Math.Pow(10, (a.Length - (i+1)));
}
}
return x;
}
You also may use an extension method, so it will be more readable (although everybody is already used to the regular Parse functions).
public static class StringExtensions
{
/// <summary>
/// Converts a string to int.
/// </summary>
/// <param name="value">The string to convert.</param>
/// <returns>The converted integer.</returns>
public static int ParseToInt32(this string value)
{
return int.Parse(value);
}
/// <summary>
/// Checks whether the value is integer.
/// </summary>
/// <param name="value">The string to check.</param>
/// <param name="result">The out int parameter.</param>
/// <returns>true if the value is an integer; otherwise, false.</returns>
public static bool TryParseToInt32(this string value, out int result)
{
return int.TryParse(value, out result);
}
}
And then you can call it that way:
If you are sure that your string is an integer, like "50".
int num = TextBoxD1.Text.ParseToInt32();
If you are not sure and want to prevent crashes.
int num;
if (TextBoxD1.Text.TryParseToInt32(out num))
{
//The parse was successful, the num has the parsed value.
}
To make it more dynamic, so you can parse it also to double, float, etc., you can make a generic extension.
You can convert a string to int in C# using:
Functions of convert class i.e. Convert.ToInt16(), Convert.ToInt32(), Convert.ToInt64() or by using Parse and TryParse Functions. Examples are given here.
This would do
string x = TextBoxD1.Text;
int xi = Convert.ToInt32(x);
Or you can use
int xi = Int32.Parse(x);
Refer Microsoft Developer Network for more information
You can convert string to an integer value with the help of parse method.
Eg:
int val = Int32.parse(stringToBeParsed);
int x = Int32.parse(1234);
In C# v.7 you could use an inline out parameter, without an additional variable declaration:
int.TryParse(TextBoxD1.Text, out int x);
The way I always do this is like this:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace example_string_to_int
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
string a = textBox1.Text;
// This turns the text in text box 1 into a string
int b;
if (!int.TryParse(a, out b))
{
MessageBox.Show("This is not a number");
}
else
{
textBox2.Text = a+" is a number" ;
}
// Then this 'if' statement says if the string is not a number, display an error, else now you will have an integer.
}
}
}
This is how I would do it.
All the above answers are good but for information, we can use int.TryParse which is safe to convert string to int, for example
// TryParse returns true if the conversion succeeded
// and stores the result in j.
int j;
if (Int32.TryParse("-105", out j))
Console.WriteLine(j);
else
Console.WriteLine("String could not be parsed.");
// Output: -105
TryParse never throws an exception—even on invalid input and null. It is overall preferable to int.Parse in most program contexts.
Source: How to convert string to int in C#? (With Difference between Int.Parse and Int.TryParse)
In case you know the string is an integer do:
int value = int.Parse(TextBoxD1.Text);
In case you don't know the string is an integer do it safely with TryParse.
In C# 7.0 you can use inline variable declaration.
If parse successes - value = its parsed value.
If parse fails - value = 0.
Code:
if (int.TryParse(TextBoxD1.Text, out int value))
{
// Parse succeed
}
Drawback:
You cannot differentiate between a 0 value and a non parsed value.
Here is the version of doing it via an Extension Method that has an option to set the default value as well, if the converting fails. In fact, this is what I used to convert a string input to any convertible type:
using System;
using System.ComponentModel;
public static class StringExtensions
{
public static TOutput AsOrDefault<TOutput>(this string input, TOutput defaultValue = default)
where TOutput : IConvertible
{
TOutput output = defaultValue;
try
{
var converter = TypeDescriptor.GetConverter(typeof(TOutput));
if (converter != null)
{
output = (TOutput)converter.ConvertFromString(input);
}
}
catch { }
return output;
}
}
For my usage, I limited the output to be one of the convertible types: https://learn.microsoft.com/en-us/dotnet/api/system.iconvertible?view=net-5.0. I don't need crazy logics to convert a string to a class, for example.
To use it to convert a string to int:
using FluentAssertions;
using Xunit;
[Theory]
[InlineData("0", 0)]
[InlineData("1", 1)]
[InlineData("123", 123)]
[InlineData("-123", -123)]
public void ValidStringWithNoDefaultValue_ReturnsExpectedResult(string input, int expectedResult)
{
var result = input.AsOrDefault<int>();
result.Should().Be(expectedResult);
}
[Theory]
[InlineData("0", 999, 0)]
[InlineData("1", 999, 1)]
[InlineData("123", 999, 123)]
[InlineData("-123", -999, -123)]
public void ValidStringWithDefaultValue_ReturnsExpectedResult(string input, int defaultValue, int expectedResult)
{
var result = input.AsOrDefault(defaultValue);
result.Should().Be(expectedResult);
}
[Theory]
[InlineData("")]
[InlineData(" ")]
[InlineData("abc")]
public void InvalidStringWithNoDefaultValue_ReturnsIntegerDefault(string input)
{
var result = input.AsOrDefault<int>();
result.Should().Be(default(int));
}
[Theory]
[InlineData("", 0)]
[InlineData(" ", 1)]
[InlineData("abc", 234)]
public void InvalidStringWithDefaultValue_ReturnsDefaultValue(string input, int defaultValue)
{
var result = input.AsOrDefault(defaultValue);
result.Should().Be(defaultValue);
}
METHOD 1
int TheAnswer1 = 0;
bool Success = Int32.TryParse("42", out TheAnswer1);
if (!Success) {
Console.WriteLine("String not Convertable to an Integer");
}
METHOD 2
int TheAnswer2 = 0;
try {
TheAnswer2 = Int32.Parse("42");
}
catch {
Console.WriteLine("String not Convertable to an Integer");
}
METHOD 3
int TheAnswer3 = 0;
try {
TheAnswer3 = Int32.Parse("42");
}
catch (FormatException) {
Console.WriteLine("String not in the correct format for an Integer");
}
catch (ArgumentNullException) {
Console.WriteLine("String is null");
}
catch (OverflowException) {
Console.WriteLine("String represents a number less than"
+ "MinValue or greater than MaxValue");
}
You can try the following. It will work:
int x = Convert.ToInt32(TextBoxD1.Text);
The string value in the variable TextBoxD1.Text will be converted into Int32 and will be stored in x.
While I agree on using the TryParse method, a lot of people dislike the use of out parameter (myself included). With tuple support having been added to C#, an alternative is to create an extension method that will limit the number of times you use out to a single instance:
public static class StringExtensions
{
public static (int result, bool canParse) TryParse(this string s)
{
int res;
var valid = int.TryParse(s, out res);
return (result: res, canParse: valid);
}
}
(Source: C# how to convert a string to int)
If I have these strings:
"abc" = false
"123" = true
"ab2" = false
Is there a command, like IsNumeric() or something else, that can identify if a string is a valid number?
int n;
bool isNumeric = int.TryParse("123", out n);
Update As of C# 7:
var isNumeric = int.TryParse("123", out int n);
or if you don't need the number you can discard the out parameter
var isNumeric = int.TryParse("123", out _);
The var s can be replaced by their respective types!
This will return true if input is all numbers. Don't know if it's any better than TryParse, but it will work.
Regex.IsMatch(input, #"^\d+$")
If you just want to know if it has one or more numbers mixed in with characters, leave off the ^ + and $.
Regex.IsMatch(input, #"\d")
Edit:
Actually I think it is better than TryParse because a very long string could potentially overflow TryParse.
You can also use:
using System.Linq;
stringTest.All(char.IsDigit);
It will return true for all Numeric Digits (not float) and false if input string is any sort of alphanumeric.
Test case
Return value
Test result
"1234"
true
✅Pass
"1"
true
✅Pass
"0"
true
✅Pass
""
true
⚠️Fail (known edge case)
"12.34"
false
✅Pass
"+1234"
false
✅Pass
"-13"
false
✅Pass
"3E14"
false
✅Pass
"0x10"
false
✅Pass
Please note: stringTest should not be an empty string as this would pass the test of being numeric.
I've used this function several times:
public static bool IsNumeric(object Expression)
{
double retNum;
bool isNum = Double.TryParse(Convert.ToString(Expression), System.Globalization.NumberStyles.Any, System.Globalization.NumberFormatInfo.InvariantInfo, out retNum);
return isNum;
}
But you can also use;
bool b1 = Microsoft.VisualBasic.Information.IsNumeric("1"); //true
bool b2 = Microsoft.VisualBasic.Information.IsNumeric("1aa"); // false
From Benchmarking IsNumeric Options
(source: aspalliance.com)
(source: aspalliance.com)
This is probably the best option in C#.
If you want to know if the string contains a whole number (integer):
string someString;
// ...
int myInt;
bool isNumerical = int.TryParse(someString, out myInt);
The TryParse method will try to convert the string to a number (integer) and if it succeeds it will return true and place the corresponding number in myInt. If it can't, it returns false.
Solutions using the int.Parse(someString) alternative shown in other responses works, but it is much slower because throwing exceptions is very expensive. TryParse(...) was added to the C# language in version 2, and until then you didn't have a choice. Now you do: you should therefore avoid the Parse() alternative.
If you want to accept decimal numbers, the decimal class also has a .TryParse(...) method. Replace int with decimal in the above discussion, and the same principles apply.
You can always use the built in TryParse methods for many datatypes to see if the string in question will pass.
Example.
decimal myDec;
var Result = decimal.TryParse("123", out myDec);
Result would then = True
decimal myDec;
var Result = decimal.TryParse("abc", out myDec);
Result would then = False
In case you don't want to use int.Parse or double.Parse, you can roll your own with something like this:
public static class Extensions
{
public static bool IsNumeric(this string s)
{
foreach (char c in s)
{
if (!char.IsDigit(c) && c != '.')
{
return false;
}
}
return true;
}
}
If you want to catch a broader spectrum of numbers, à la PHP's is_numeric, you can use the following:
// From PHP documentation for is_numeric
// (http://php.net/manual/en/function.is-numeric.php)
// Finds whether the given variable is numeric.
// Numeric strings consist of optional sign, any number of digits, optional decimal part and optional
// exponential part. Thus +0123.45e6 is a valid numeric value.
// Hexadecimal (e.g. 0xf4c3b00c), Binary (e.g. 0b10100111001), Octal (e.g. 0777) notation is allowed too but
// only without sign, decimal and exponential part.
static readonly Regex _isNumericRegex =
new Regex( "^(" +
/*Hex*/ #"0x[0-9a-f]+" + "|" +
/*Bin*/ #"0b[01]+" + "|" +
/*Oct*/ #"0[0-7]*" + "|" +
/*Dec*/ #"((?!0)|[-+]|(?=0+\.))(\d*\.)?\d+(e\d+)?" +
")$" );
static bool IsNumeric( string value )
{
return _isNumericRegex.IsMatch( value );
}
Unit Test:
static void IsNumericTest()
{
string[] l_unitTests = new string[] {
"123", /* TRUE */
"abc", /* FALSE */
"12.3", /* TRUE */
"+12.3", /* TRUE */
"-12.3", /* TRUE */
"1.23e2", /* TRUE */
"-1e23", /* TRUE */
"1.2ef", /* FALSE */
"0x0", /* TRUE */
"0xfff", /* TRUE */
"0xf1f", /* TRUE */
"0xf1g", /* FALSE */
"0123", /* TRUE */
"0999", /* FALSE (not octal) */
"+0999", /* TRUE (forced decimal) */
"0b0101", /* TRUE */
"0b0102" /* FALSE */
};
foreach ( string l_unitTest in l_unitTests )
Console.WriteLine( l_unitTest + " => " + IsNumeric( l_unitTest ).ToString() );
Console.ReadKey( true );
}
Keep in mind that just because a value is numeric doesn't mean it can be converted to a numeric type. For example, "999999999999999999999999999999.9999999999" is a perfeclty valid numeric value, but it won't fit into a .NET numeric type (not one defined in the standard library, that is).
I know this is an old thread, but none of the answers really did it for me - either inefficient, or not encapsulated for easy reuse. I also wanted to ensure it returned false if the string was empty or null. TryParse returns true in this case (an empty string does not cause an error when parsing as a number). So, here's my string extension method:
public static class Extensions
{
/// <summary>
/// Returns true if string is numeric and not empty or null or whitespace.
/// Determines if string is numeric by parsing as Double
/// </summary>
/// <param name="str"></param>
/// <param name="style">Optional style - defaults to NumberStyles.Number (leading and trailing whitespace, leading and trailing sign, decimal point and thousands separator) </param>
/// <param name="culture">Optional CultureInfo - defaults to InvariantCulture</param>
/// <returns></returns>
public static bool IsNumeric(this string str, NumberStyles style = NumberStyles.Number,
CultureInfo culture = null)
{
double num;
if (culture == null) culture = CultureInfo.InvariantCulture;
return Double.TryParse(str, style, culture, out num) && !String.IsNullOrWhiteSpace(str);
}
}
Simple to use:
var mystring = "1234.56789";
var test = mystring.IsNumeric();
Or, if you want to test other types of number, you can specify the 'style'.
So, to convert a number with an Exponent, you could use:
var mystring = "5.2453232E6";
var test = mystring.IsNumeric(style: NumberStyles.AllowExponent);
Or to test a potential Hex string, you could use:
var mystring = "0xF67AB2";
var test = mystring.IsNumeric(style: NumberStyles.HexNumber)
The optional 'culture' parameter can be used in much the same way.
It is limited by not being able to convert strings that are too big to be contained in a double, but that is a limited requirement and I think if you are working with numbers larger than this, then you'll probably need additional specialised number handling functions anyway.
UPDATE of Kunal Noel Answer
stringTest.All(char.IsDigit);
// This returns true if all characters of the string are digits.
But, for this case we have that empty strings will pass that test, so, you can:
if (!string.IsNullOrEmpty(stringTest) && stringTest.All(char.IsDigit)){
// Do your logic here
}
You can use TryParse to determine if the string can be parsed into an integer.
int i;
bool bNum = int.TryParse(str, out i);
The boolean will tell you if it worked or not.
If you want to know if a string is a number, you could always try parsing it:
var numberString = "123";
int number;
int.TryParse(numberString , out number);
Note that TryParse returns a bool, which you can use to check if your parsing succeeded.
I guess this answer will just be lost in between all the other ones, but anyway, here goes.
I ended up on this question via Google because I wanted to check if a string was numeric so that I could just use double.Parse("123") instead of the TryParse() method.
Why? Because it's annoying to have to declare an out variable and check the result of TryParse() before you know if the parse failed or not. I want to use the ternary operator to check if the string is numerical and then just parse it in the first ternary expression or provide a default value in the second ternary expression.
Like this:
var doubleValue = IsNumeric(numberAsString) ? double.Parse(numberAsString) : 0;
It's just a lot cleaner than:
var doubleValue = 0;
if (double.TryParse(numberAsString, out doubleValue)) {
//whatever you want to do with doubleValue
}
I made a couple extension methods for these cases:
Extension method one
public static bool IsParseableAs<TInput>(this string value) {
var type = typeof(TInput);
var tryParseMethod = type.GetMethod("TryParse", BindingFlags.Static | BindingFlags.Public, Type.DefaultBinder,
new[] { typeof(string), type.MakeByRefType() }, null);
if (tryParseMethod == null) return false;
var arguments = new[] { value, Activator.CreateInstance(type) };
return (bool) tryParseMethod.Invoke(null, arguments);
}
Example:
"123".IsParseableAs<double>() ? double.Parse(sNumber) : 0;
Because IsParseableAs() tries to parse the string as the appropriate type instead of just checking if the string is "numeric" it should be pretty safe. And you can even use it for non numeric types that have a TryParse() method, like DateTime.
The method uses reflection and you end up calling the TryParse() method twice which, of course, isn't as efficient, but not everything has to be fully optimized, sometimes convenience is just more important.
This method can also be used to easily parse a list of numeric strings into a list of double or some other type with a default value without having to catch any exceptions:
var sNumbers = new[] {"10", "20", "30"};
var dValues = sNumbers.Select(s => s.IsParseableAs<double>() ? double.Parse(s) : 0);
Extension method two
public static TOutput ParseAs<TOutput>(this string value, TOutput defaultValue) {
var type = typeof(TOutput);
var tryParseMethod = type.GetMethod("TryParse", BindingFlags.Static | BindingFlags.Public, Type.DefaultBinder,
new[] { typeof(string), type.MakeByRefType() }, null);
if (tryParseMethod == null) return defaultValue;
var arguments = new object[] { value, null };
return ((bool) tryParseMethod.Invoke(null, arguments)) ? (TOutput) arguments[1] : defaultValue;
}
This extension method lets you parse a string as any type that has a TryParse() method and it also lets you specify a default value to return if the conversion fails.
This is better than using the ternary operator with the extension method above as it only does the conversion once. It still uses reflection though...
Examples:
"123".ParseAs<int>(10);
"abc".ParseAs<int>(25);
"123,78".ParseAs<double>(10);
"abc".ParseAs<double>(107.4);
"2014-10-28".ParseAs<DateTime>(DateTime.MinValue);
"monday".ParseAs<DateTime>(DateTime.MinValue);
Outputs:
123
25
123,78
107,4
28.10.2014 00:00:00
01.01.0001 00:00:00
If you want to check if a string is a number (I'm assuming it's a string since if it's a number, duh, you know it's one).
Without regex and
using Microsoft's code as much as possible
you could also do:
public static bool IsNumber(this string aNumber)
{
BigInteger temp_big_int;
var is_number = BigInteger.TryParse(aNumber, out temp_big_int);
return is_number;
}
This will take care of the usual nasties:
Minus (-) or Plus (+) in the beginning
contains decimal character BigIntegers won't parse numbers with decimal points. (So: BigInteger.Parse("3.3") will throw an exception, and TryParse for the same will return false)
no funny non-digits
covers cases where the number is bigger than the usual use of Double.TryParse
You'll have to add a reference to System.Numerics and have
using System.Numerics; on top of your class (well, the second is a bonus I guess :)
Double.TryParse
bool Double.TryParse(string s, out double result)
The best flexible solution with .net built-in function called- char.IsDigit. It works with unlimited long numbers. It will only return true if each character is a numeric number. I used it lot of times with no issues and much easily cleaner solution I ever found. I made a example method.Its ready to use. In addition I added validation for null and empty input. So the method is now totally bulletproof
public static bool IsNumeric(string strNumber)
{
if (string.IsNullOrEmpty(strNumber))
{
return false;
}
else
{
int numberOfChar = strNumber.Count();
if (numberOfChar > 0)
{
bool r = strNumber.All(char.IsDigit);
return r;
}
else
{
return false;
}
}
}
Try the regex define below
new Regex(#"^\d{4}").IsMatch("6") // false
new Regex(#"^\d{4}").IsMatch("68ab") // false
new Regex(#"^\d{4}").IsMatch("1111abcdefg")
new Regex(#"^\d+").IsMatch("6") // true (any length but at least one digit)
With c# 7 it you can inline the out variable:
if(int.TryParse(str, out int v))
{
}
Use these extension methods to clearly distinguish between a check if the string is numerical and if the string only contains 0-9 digits
public static class ExtensionMethods
{
/// <summary>
/// Returns true if string could represent a valid number, including decimals and local culture symbols
/// </summary>
public static bool IsNumeric(this string s)
{
decimal d;
return decimal.TryParse(s, System.Globalization.NumberStyles.Any, System.Globalization.CultureInfo.CurrentCulture, out d);
}
/// <summary>
/// Returns true only if string is wholy comprised of numerical digits
/// </summary>
public static bool IsNumbersOnly(this string s)
{
if (s == null || s == string.Empty)
return false;
foreach (char c in s)
{
if (c < '0' || c > '9') // Avoid using .IsDigit or .IsNumeric as they will return true for other characters
return false;
}
return true;
}
}
public static bool IsNumeric(this string input)
{
int n;
if (!string.IsNullOrEmpty(input)) //.Replace('.',null).Replace(',',null)
{
foreach (var i in input)
{
if (!int.TryParse(i.ToString(), out n))
{
return false;
}
}
return true;
}
return false;
}
Regex rx = new Regex(#"^([1-9]\d*(\.)\d*|0?(\.)\d*[1-9]\d*|[1-9]\d*)$");
string text = "12.0";
var result = rx.IsMatch(text);
Console.WriteLine(result);
To check string is uint, ulong or contains only digits one .(dot) and digits
Sample inputs
123 => True
123.1 => True
0.123 => True
.123 => True
0.2 => True
3452.434.43=> False
2342f43.34 => False
svasad.324 => False
3215.afa => False
Hope this helps
string myString = "abc";
double num;
bool isNumber = double.TryParse(myString , out num);
if isNumber
{
//string is number
}
else
{
//string is not a number
}
Pull in a reference to Visual Basic in your project and use its Information.IsNumeric method such as shown below and be able to capture floats as well as integers unlike the answer above which only catches ints.
// Using Microsoft.VisualBasic;
var txt = "ABCDEFG";
if (Information.IsNumeric(txt))
Console.WriteLine ("Numeric");
IsNumeric("12.3"); // true
IsNumeric("1"); // true
IsNumeric("abc"); // false
All the Answers are Useful. But while searching for a solution where the Numeric value is 12 digits or more (in my case), then while debugging, I found the following solution useful :
double tempInt = 0;
bool result = double.TryParse("Your_12_Digit_Or_more_StringValue", out tempInt);
Th result variable will give you true or false.
Here is the C# method.
Int.TryParse Method (String, Int32)
bool is_number(string str, char delimiter = '.')
{
if(str.Length==0) //Empty
{
return false;
}
bool is_delimetered = false;
foreach (char c in str)
{
if ((c < '0' || c > '9') && (c != delimiter)) //ASCII table check. Not a digit && not delimeter
{
return false;
}
if (c == delimiter)
{
if (is_delimetered) //more than 1 delimiter
{
return false;
}
else //first time delimiter
{
is_delimetered = true;
}
}
}
return true;
}
I am using Visual Studio 2010.I want to check whether a string is numeric or not.Is there any built in function to check this or do we need to write a custom code?
You could use the int.TryParse method. Example:
string s = ...
int result;
if (int.TryParse(s, out result))
{
// The string was a valid integer => use result here
}
else
{
// invalid integer
}
There are also the float.TryParse, double.TryParse and decimal.TryParse methods for other numeric types than integers.
But if this is for validation purposes you might also consider using the built-in Validation controls in ASP.NET. Here's an example.
You can do like...
string s = "sdf34";
Int32 a;
if (Int32.TryParse(s, out a))
{
// Value is numberic
}
else
{
//Not a valid number
}
You can use Int32.TryParse()
http://msdn.microsoft.com/en-us/library/f02979c7.aspx
Yes there is: int.TryParse(...) check the out bool param.
Have a look at this question:
What is the C# equivalent of NaN or IsNumeric?
You can use built in methods Int.Parse or Double.Parse methods. You can write the following function and call where ever necessary to check it.
public static bool IsNumber(String str)
{
try
{
Double.Parse(str);
return true;
}
catch (Exception)
{
return false;
}
}
The problem with all the Double/Int32/... TryParse(...) methods is that with a long enough numeric string, the method will return false;
For example:
var isValidNumber = int.TryParse("9999999999", out result);
Here, isValidNumber is false and result is 0, although the given string is numeric.
If you don't need to use the string as int, I would go with regular expressions validation on this one:
var isValidNumber = Regex.IsMatch(input, #"^\d+$")
This will only match integers. "123.45" for example, will fail.
If you need to check for floating point numbers:
var isValidNumber = Regex.IsMatch(input, #"^[0-9]+(\.[0-9]+)?$")
Note: try to create a single Regex object and send it to your int testing method for better performance.
Try this:
string Str = textBox1.Text.Trim();
double Num;
bool isNum = double.TryParse(Str, out Num);
if (isNum)
MessageBox.Show(Num.ToString());
else
`enter code here`MessageBox.Show("Invalid number");
Use IsNumeric() to check whether given string is numeric or not. It always return True for numeric value regardless whether it is Int or Double.
string val=...;
bool b1 = Microsoft.VisualBasic.Information.IsNumeric(val);
using System;
namespace ConsoleApplication1
{
class Test
{
public static void Main(String[] args)
{
bool check;
string testStr = "ABC";
string testNum = "123";
check = CheckNumeric(testStr);
Console.WriteLine(check);
check = CheckNumeric(testNum);
Console.WriteLine(check);
Console.ReadKey();
}
public static bool CheckNumeric(string input)
{
int outPut;
if (int.TryParse(input, out outPut))
return true;
else
return false;
}
}
}
This will work for you!!
Try This-->
String[] values = { "87878787878", "676767676767", "8786676767", "77878785565", "987867565659899698" };
if (Array.TrueForAll(values, value =>
{
Int64 s;
return Int64.TryParse(value, out s);
}
))
Console.WriteLine("All elements are integer.");
else
Console.WriteLine("Not all elements are integer.");
private int FindNumber(string sPar)
{
// Get the last number
int len = sPar.Length;
string s = sPar.Substring(len-1);
return new (int)Decimal(s);
}
In this I am getting the error ; required . Can any ine help me on this.
Thank You!
Change your code to this:
private int FindNumber(string sPar)
{
int len = sPar.Length;
string s = sPar.Substring(len - 1);
return Convert.ToInt32(s);
}
Or, even shorter:
private int FindNumber(string sPar)
{
return Convert.ToInt32(sPar.Substring(sPar.Length - 1));
}
I'm not 100% what you are trying to do here, but if you want to get 4 as the result from the string "17894" i guess you want to write it like this with minimum number of changes:
private int FindNumber(string sPar) {
// Get the last number
int len = sPar.Length;
string s = sPar.Substring(len-1);
return int.Parse(s);
}
No reason to include a decimal and parse it to an int if you are only taking one char of the string anyway.
Note that this will give an exception if the last char of the string for any reason is not a number.
what is Decimal(s)? If you mean "parse as a decimal, then cast to int":
return (int)decimal.Parse(s);
If it is known to be an integer, just:
return int.Parse(s);
Actually, since you are only interested in the last digit, you could cheat:
private static int FindNumber(string sPar)
{
char c = sPar[sPar.Length - 1];
if (c >= '0' && c <= '9') return (int)(c - '0');
throw new FormatException();
}
Decimal(s) is not a valid call since Decimal is a type. Try Decimal.Parse(s) instead if you are certain that s is a valid decimal, stored as a string. If not, use Decimal.TryParse instead.
Please take into account different Culture related problems also, check out the overload that takes an IFormatProvider (I think, not sure about the exact name)
Do you just want to parse the digit from the last position in the string?
private int FindNumber(string sPar)
{
return int.Parse(sPar.Substring(sPar.Length - 1));
}
Note that this will fail if (a) the string is null, (b) the string is empty, or (c) the last character of the string isn't a digit. You should add some checking to your method if these situations are likely to be a problem.
The last line is completely wrong.
Your code takes the last char of a string(that i presume is always a number) and cast it to an int.
Do the following
try{
return Int32.Parse(s);
}
catch(Exception e)
{
// manage conversion exception here
}
I suppose you want to convert string to decimal as your code is not very clear.
you can use
Decimal d1;
if(Decimal.TryParse(sPar,out d1))
{
return d1
}
else
{
return 0;
}
I need to check if a string contains only digits. How could I achieve this in C#?
string s = "123" → valid
string s = "123.67" → valid
string s = "123F" → invalid
Is there any function like IsNumeric?
double n;
if (Double.TryParse("128337.812738", out n)) {
// ok
}
works assuming the number doesn't overflow a double
for a huge string, try the regexp:
if (Regex.Match(str, #"^[0-9]+(\.[0-9]+)?$")) {
// ok
}
add in scientific notation (e/E) or +/- signs if needed...
Taken from MSDN (How to implement Visual Basic .NET IsNumeric functionality by using Visual C#):
// IsNumeric Function
static bool IsNumeric(object Expression)
{
// Variable to collect the Return value of the TryParse method.
bool isNum;
// Define variable to collect out parameter of the TryParse method. If the conversion fails, the out parameter is zero.
double retNum;
// The TryParse method converts a string in a specified style and culture-specific format to its double-precision floating point number equivalent.
// The TryParse method does not generate an exception if the conversion fails. If the conversion passes, True is returned. If it does not, False is returned.
isNum = Double.TryParse(Convert.ToString(Expression), System.Globalization.NumberStyles.Any, System.Globalization.NumberFormatInfo.InvariantInfo, out retNum );
return isNum;
}
You can use double.TryParse
string value;
double number;
if (Double.TryParse(value, out number))
Console.WriteLine("valid");
else
Console.WriteLine("invalid");
This should work no matter how long the string is:
string s = "12345";
bool iAllNumbers = s.ToCharArray ().All (ch => Char.IsDigit (ch) || ch == '.');
Using regular expressions is the easiest way (but not the quickest):
bool isNumeric = Regex.IsMatch(s,#"^(\+|-)?\d+(\.\d+)?$");
As stated above you can use double.tryParse
If you don't like that (for some reason), you can write your own extension method:
public static class ExtensionMethods
{
public static bool isNumeric (this string str)
{
for (int i = 0; i < str.Length; i++ )
{
if ((str[i] == '.') || (str[i] == ',')) continue; //Decide what is valid, decimal point or decimal coma
if ((str[i] < '0') || (str[i] > '9')) return false;
}
return true;
}
}
Usage:
string mystring = "123456abcd123";
if (mystring.isNumeric()) MessageBox.Show("The input string is a number.");
else MessageBox.Show("The input string is not a number.");
Input :
123456abcd123
123.6
Output:
false
true
I think you can use Regular Expressions, in the Regex class
Regex.IsMatch( yourStr, "\d" )
or something like that off the top of my head.
Or you could use the Parse method int.Parse( ... )
If you are receiving the string as a parameter the more flexible way would be to use regex as described in the other posts.
If you get the input from the user, you can just hook on the KeyDown event and ignore all keys that are not numbers. This way you'll be sure that you have only digits.
This should work:
bool isNum = Integer.TryParse(Str, out Num);