I want to serialize a ReportDocument using XML serialization but in vain, that's my code:
public String serialiser (ReportDocument rd)
{
StringWriter sw= new StringWriter();
System.Xml.Serialization.XmlSerializer xs = new System.Xml.Serialization.XmlSerializer(typeof(ReportDocument));
xs.Serialize(sw, rd);
return sw.ToString();
}
NB: CrystalDecisions.CrystalReports.Engine.ReportDocument.
I got the following error:
An error occurred during the reflection of the type 'CrystalDecisions.CrystalReports.Engine.ReportDocument'.
How could I serialize it?!
My guess is that type is not marked as serializable. Have you tried doing binary serialization?
public static byte[] SerializeToBytes<T>(T original)
{
byte[] results;
using (MemoryStream stream = new MemoryStream())
{
BinaryFormatter binaryFormatter = new BinaryFormatter();
binaryFormatter.Serialize(stream, original);
stream.Seek(0, SeekOrigin.Begin);
results = stream.ToArray();
}
return results;
}
Related
I seem to be getting some junk at the head of my serialized XML string. I have a simple extension method
public static string ToXML(this object This)
{
DataContractSerializer ser = new DataContractSerializer(This.GetType());
var settings = new XmlWriterSettings { Indent = true };
using (MemoryStream ms = new MemoryStream())
using (var w = XmlWriter.Create(ms, settings))
{
ser.WriteObject(w, This);
w.Flush();
return UTF8Encoding.Default.GetString(ms.ToArray());
}
}
and when I apply it to my object I get the string
<?xml version="1.0" encoding="utf-8"?>
<RootModelType xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.datacontract.org/2004/07/WeinCad.Data">
<MoineauPump xmlns:d2p1="http://schemas.datacontract.org/2004/07/Weingartner.Numerics">
<d2p1:Rotor>
<d2p1:Equidistance>0.0025</d2p1:Equidistance>
<d2p1:Lobes>2</d2p1:Lobes>
<d2p1:MajorRadius>0.04</d2p1:MajorRadius>
<d2p1:MinorRadius>0.03</d2p1:MinorRadius>
</d2p1:Rotor>
</MoineauPump>
</RootModelType>
Note the junk at the beginning. When I try to deserialize this
I get an error. If I copy paste the XML into my source minus
the junk prefix I can deserialize it. What is the junk text
and how can I remove it or handle it?
Note my deserialization code is
public static RootModelType Load(Stream data)
{
DataContractSerializer ser = new DataContractSerializer(typeof(RootModelType));
return (RootModelType)ser.ReadObject(data);
}
public static RootModelType Load(string data)
{
using(var stream = new MemoryStream(Encoding.UTF8.GetBytes(data))){
return Load(stream);
}
}
This fix seems to work
public static string ToXML(this object obj)
{
var settings = new XmlWriterSettings { Indent = true };
using (MemoryStream memoryStream = new MemoryStream())
using (StreamReader reader = new StreamReader(memoryStream))
using(XmlWriter writer = XmlWriter.Create(memoryStream, settings))
{
DataContractSerializer serializer =
new DataContractSerializer(obj.GetType());
serializer.WriteObject(writer, obj);
writer.Flush();
memoryStream.Position = 0;
return reader.ReadToEnd();
}
}
I am writing an xml file but am missing some value for specific field. I check that when the object comes which contains the value that specific value exist, but after writing the xml the value doesn't exist.
This is the code that I use, I think XmlTextWriter could be the cause of the wrong xml.
There is another method which could be used for it, that is TextWriter but it failed to convert into memorystream.
string xmlString = null;
MemoryStream memoryStream = new MemoryStream();
XmlSerializer xs = new XmlSerializer(typeof(T));
// XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.ASCII);
TextWriter xmlTextWriter=new StreamWriter(memoryStream,Encoding.ASCII);
xs.Serialize(xmlTextWriter, obj);
memoryStream =(MemoryStream)xmlTextWriter.
//(MemoryStream)xmlTextWriter.BaseStream;
xmlString = ASCIIByteArrayToString(memoryStream.ToArray());
return `xmlString;`
Any idea how I can know why and where the problem occurs.
I think you are over-complicating it with the memory stream. You can serialize to a StringWriter (which derives from TextWriter) then call ToString() if you want to get the XML string.
XmlSerializer xs = new XmlSerializer(typeof(T));
StringWriter sw = new StringWriter();
xs.Serialize(sw, obj);
return sw.ToString();
Try disposing properly your IDisposable resources by wrapping them in using statements:
public string SerializeToXml<T>(T obj)
{
using (var stream = new MemoryStream())
{
var xs = new XmlSerializer(typeof(T));
xs.Serialize(stream, obj);
return Encoding.UTF8.GetString(stream.ToArray());
}
}
I'm trying to do custom serialization/deserialization of an object as well as compressing/decompressing the serialized data with DeflateStreams. I originally did this for more complex objects but cut it down to try and figure out the problem, however it just became more puzzling as it is still there. Here is the class to be serialized/deserialized:
[Serializable]
public class RandomObject : ISerializable
{
public String Name { get; set; }
public String SavePath { get; set; }
public RandomObject()
{
}
public RandomObject(String name, String savepath)
{
Name = name;
SavePath = savepath;
}
public RandomObject(SerializationInfo info, StreamingContext context)
: this(info.GetString("name"), info.GetString("savepath"))
{
}
[SecurityPermissionAttribute(SecurityAction.Demand, SerializationFormatter = true)]
public void GetObjectData(SerializationInfo info, StreamingContext context)
{
info.AddValue("name", Name);
info.AddValue("savepath", SavePath);
}
}
And here is the code that is supposed to serialize it(which seems to work):
BinaryFormatter bf = new BinaryFormatter();
using (MemoryStream ms = new MemoryStream())
{
bf.Serialize(ms, profile);
using (DeflateStream ds = new DeflateStream(ms, CompressionMode.Compress))
{
try
{
using (FileStream fs = File.Create(path))
{
ds.Flush();
Miscellaneous.CopyStream(ds.BaseStream, fs);
fs.Flush();
fs.Close();
}
}
catch (IOException e)
{
MessageBox.Show(e.Message);
success = false;
}
ds.Close();
}
ms.Close();
}
And here is the deserialization:
RandomObject profile = null;
using (FileStream fs = File.OpenRead(path))
{
using (DeflateStream ds = new DeflateStream(fs, CompressionMode.Decompress))
{
BinaryFormatter bf = new BinaryFormatter();
ds.Flush();
using (MemoryStream ms = new MemoryStream())
{
Miscellaneous.CopyStream(ds.BaseStream, ms);
profile = bf.Deserialize(ms) as RandomObject;
profile.SavePath = path;
ms.Close();
}
ds.Close();
}
fs.Close();
}
Now, to the problem. Deserialization throws a SerializationException with the message {"No map for object '201326592'."} I have no idea how to troubleshoot or figure out what exactly is causing the problem. Very basic serialization works when I just run BinaryFormatter's Serialize and Deserialize methods on the same MemoryStream.
I tried removing the DeflateStream stuff from both methods, but it's still the same problem. When I look at the examples at MSDN and other places it looks like I'm doing it just right, and googling for the exception message doesn't give any meaningful results(or perhaps I'm just bad at searching).
PS. As you can see I use Miscellaneous.CopyStream(src, dest) which is a basic stream copier, as I can't get src.CopyTo(dest) to work at all, so any hints on that is welcome as well.
Below is a link to the whole VS2010 project if you would like to look at it more closely:
http://www.diredumplings.com/SerializationTesting.zip
UPDATE:
The_Smallest: I tried using the Compress method you posted on my serialization:
BinaryFormatter bf = new BinaryFormatter();
using (MemoryStream stream = new MemoryStream())
{
bf.Serialize(stream, profile);
byte[] array = Compress(stream);
using (MemoryStream ms = new MemoryStream(array))
{
using (FileStream fs = File.Create(path))
{
ms.WriteTo(fs);
fs.Flush();
}
}
}
However, it seems to give me the same problems that I had with srcStream.CopyTo(destStream) earlier, which is that it doesn't seem to get written to the stream. The result is a 0 kb file when I try to save it to disk. Any ideas?
Pieter: I removed the MemoryStream from the deserialization method and it seems have the same functionality as before. However I'm not sure how to implement the serialization the way you suggested. Is this what you had in mind?
BinaryFormatter bf = new BinaryFormatter();
using (FileStream fs = File.Create(path))
{
using (DeflateStream ds = new DeflateStream(fs, CompressionMode.Compress))
{
bf.Serialize(ds, profile);
fs.Flush();
ds.Close();
}
fs.Close();
}
Thanks to both of you!
I dowloaded you example and digged a little in there. See changes for your project below:
Replace LoadFromFile in Loader.cs
private static RandomObject LoadFromFile(string path)
{
try
{
var bf = new BinaryFormatter();
using (var fileStream = File.OpenRead(path))
using (var decompressed = new MemoryStream())
{
using (var deflateStream = new DeflateStream(fileStream, CompressionMode.Decompress))
deflateStream.CopyTo(decompressed);
decompressed.Seek(0, SeekOrigin.Begin);
var profile = (RandomObject)bf.Deserialize(decompressed);
profile.SavePath = path;
return profile;
}
}
catch (IOException e)
{
MessageBox.Show(e.Message);
return null;
}
}
Replace Save in Saver.cs as follows:
public static bool Save(RandomObject profile, String path)
{
try
{
var bf = new BinaryFormatter();
using (var uncompressed = new MemoryStream())
using (var fileStream = File.Create(path))
{
bf.Serialize(uncompressed, profile);
uncompressed.Seek(0, SeekOrigin.Begin);
using (var deflateStream = new DeflateStream(fileStream, CompressionMode.Compress))
uncompressed.CopyTo(deflateStream);
}
return true;
}
catch (IOException e)
{
MessageBox.Show(e.Message);
return false;
}
}
You should serialize into the DeflateStream, not the base (MemoryStream) stream.
For serializing: begin with the File.Create. Then around that stream, create the DeflateStream. Then to the DefaulteStream, serialize your objects.
For deserializing: do not create the MemoryStream and deserialize directly from the DeflateStream.
I believe there is no need for the added MemoryStream. If however you do have problems writing directly to/reading directly from the file streams, just change the serialize routine to write to the DeflateStream instead of the MemoryStream.
That should solve your issues.
There is error in streams logics, while compressing you should write to CompressStream, which writes to MemoryStream, after this you will have result in MemoryStream (not in CompressStream)
Here is example how to compress and decompress bytes
private static byte[] Compress(Stream stream)
{
using (var resultStream = new MemoryStream())
{
using (var gzipStream = new DeflateStream(resultStream, CompressionMode.Compress))
stream.CopyTo(gzipStream);
return resultStream.ToArray();
}
}
private static byte[] Decompress(byte[] bytes)
{
using (var readStream = new MemoryStream(bytes))
using (var resultStream = new MemoryStream())
{
using (var gzipStream = new DeflateStream(readStream, CompressionMode.Decompress))
gzipStream.CopyTo(resultStream);
return resultStream.ToArray();
}
}
I had a quick question regarding the datacontractserializer. Maybe it's more of a stream question. I found a piece of code that writes the xml to a filestream. I basically don't want the file and just need the string output.
public static string DataContractSerializeObject<T>(T objectToSerialize)
{
var fs = new FileStream("test.xml", FileMode.OpenOrCreate);
var serializer = new DataContractSerializer(typeof(T));
serializer.WriteObject(fs, objectToSerialize);
fs.Close();
return fs.ToString();
}
fs.ToString() is obviously not what I'm looking for. What stream or writer etc, can I use just to return the proper string and not create a file? I did look at the XML the filestream created and it's exactly what I'm looking for. The XmlSerializer wrote the XML a bit strange and I prefer the output of the DataContractSerializer in this case. Can anyone point me in the right direction?
Something like this - put your output into a MemoryStream and then read that back in:
public static string DataContractSerializeObject<T>(T objectToSerialize)
{
using(MemoryStream memStm = new MemoryStream())
{
var serializer = new DataContractSerializer(typeof(T));
serializer.WriteObject(memStm, objectToSerialize);
memStm.Seek(0, SeekOrigin.Begin);
using(var streamReader = new StreamReader(memStm))
{
string result = streamReader.ReadToEnd();
return result;
}
}
}
Thanks to #xr280xr for pointing out my forgotten StringWriter disposal in the first draft.
/// <summary>
/// Converts this instance to XML.
/// </summary>
/// <returns>XML representing this instance.</returns>
public string ToXml()
{
var serializer = new DataContractSerializer(this.GetType());
using (var output = new StringWriter())
using (var writer = new XmlTextWriter(output) { Formatting = Formatting.Indented })
{
serializer.WriteObject(writer, this);
return output.GetStringBuilder().ToString();
}
}
And even easier:
var serializer = new DataContractSerializer(typeof(T));
var sb = new StringBuilder();
using (var writer = XmlWriter.Create(sb))
{
serializer.WriteObject(writer, objectToSerialize);
writer.Flush();
return sb.ToString();
}
I suggest combining the methods given by Pat and marc_s:
public static string DataContractSerializeObject<T>(T objectToSerialize)
{
using (var output = new StringWriter())
using (var writer = new XmlTextWriter(output) {Formatting = Formatting.Indented})
{
new DataContractSerializer(typeof (T)).WriteObject(writer, objectToSerialize);
return output.GetStringBuilder().ToString();
}
}
A variant of #root's answer:
var serializer = new DataContractSerializer(typeof(T));
var sb = new StringBuilder();
using (var writer = XmlWriter.Create(sb))
{
serializer.WriteObject(writer, objectToSerialize);
}
return sb.ToString();
I am writing common functions to serialize the given object and List<object> as follows
public string SerializeObject(Object pObject)// for given object
{
try
{
String XmlizedString = null;
MemoryStream memoryStream = new MemoryStream();
XmlSerializer xs = new XmlSerializer(typeof(pObject));
XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.UTF8);
xs.Serialize(xmlTextWriter, pObject);
memoryStream = (MemoryStream)xmlTextWriter.BaseStream;
XmlizedString = UTF8ByteArrayToString(memoryStream.ToArray());
return XmlizedString;
}
catch (Exception e) { System.Console.WriteLine(e); return null; }
}
public string SerializeObject(List<Object> pObject)// for given List<object>
{
try
{
String XmlizedString = null;
MemoryStream memoryStream = new MemoryStream();
XmlSerializer xs = new XmlSerializer(typeof(pObject));
XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.UTF8);
xs.Serialize(xmlTextWriter, pObject);
memoryStream = (MemoryStream)xmlTextWriter.BaseStream;
XmlizedString = UTF8ByteArrayToString(memoryStream.ToArray());
return XmlizedString;
}
catch (Exception e) { System.Console.WriteLine(e); return null; }
}
first one is working fine. If I pass any type, it is successfully returning xml string.
CORRECTION: Compilation error has occurred for second one (Error: cannot convert from List<MyType> to List<object>.
I rewrite the second one as follows which solves my problem. Now it is serializing the given List<generic types>.
private string SerializeObject<T>(T source)
{
MemoryStream memoryStream = new MemoryStream();
XmlSerializer xs = new XmlSerializer(typeof(T));
XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.UTF8);
xs.Serialize(xmlTextWriter, source);
memoryStream = (MemoryStream)xmlTextWriter.BaseStream;
string XmlizedString = UTF8ByteArrayToString(memoryStream.ToArray());
return XmlizedString;
}
https://weblogs.asp.net/rajbk/Contents/Item/Display/345
The relevant code from the article:
private static string SerializeObject<T>(T source)
{
var serializer = new XmlSerializer(typeof(T));
using (var sw = new System.IO.StringWriter())
using (var writer = XmlWriter.Create(sw))
{
serializer.Serialize(writer, source);
return sw.ToString();
}
}
I have tried your two functions without much trouble. The only thing I changed was this line:
XmlSerializer xs = new XmlSerializer(typeof(pObject));
to this:
XmlSerializer xs = new XmlSerializer(pObject.GetType());
typeof() requires an actual type whereas GetType() returns the type of the object.