I want to create a gadget. when opening windows they appear on the shell tray as:
how can I prevent a window from showing on that tray. I already know how to send a window to the back to make it appear as a gadget. I found that example in here. It will be nice if that menu does not show up meanwhile the window is active and open.
Use the Window property ShowInTaskbar to restrict or allow your Window to appear in the taskbar.
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GoodDay, Here i want to minimize the WPF Window, While user clicking outside of the window.
I can easily minimize the window by this code
mywindow.WindowState= WindowState.Minimized;
but i want minimize the window at the time of clicking outside of the window.
i searched about that. But i can only got the output of various events like, FocusChanged,MouseMove,MouseDown like that. those are not solve my issue
You could use the Deactivatedevent. Have a look at the MSDN for further information.
A window is deactivated (becomes a background window) when:
A user switches to another window in the current application.
A user switches to the window in another application by using ALT+TAB or by using Task Manager.
A user clicks the taskbar button for a window in another application.
I've created a winforms application. All is running fine, also the taskbar button is created and shown in taskbar including the correct icon.
Whenever I move the form from one display to the second display, the taskbar button stays at the display from where the form was initial start.
I also compared the settings with another winforms application where the behaviour is correct. Means, the button is moving/switching/whatever to the active display where the form is moved to.
Hopefully it is just a small thing, but I came not across with it.
It is an OS feature.
For windows 7 there is no built-in support to show taskbar for your second monitor and your taskbar buttons will always show on first monitor taskbar.
For windows 8 you can open Taskbar properties and in Multiple displays settings, check Show taskbar on all displays and then set the value of Show taskbar bottons on: to Taskbar where window is open
I am in a need of hiding the console window, which I quickly resolved by P/Invoking ShowWindow. However, the call hides the console window as well as the taskbar button of the console window. I need the taskbar button to remain visible. I am not, however, looking for a way to minimize the console window. Clicking the taskbar button show not do anything. I tried to use SetWinEventHook and hide the window every time it was activated, but to no avail, as the window calling this function must run message loop in order to receive the events (and my console window didn't, no matter if I set OutOfContext or InContext flag).
Is there a way I can make my console application run, show itself in taskbar, then hide itself (or never show itself in a first place) and just keep running with no window but taskbar button visible?
The normal way to get a button on the taskbar is to create a visible unowned top-level window. So that's no use to you. One possible alternative is to use ITaskbarList::AddTab to add a button. I don't know whether or not this will do anything for an invisible window. Either way you'd need to run a message loop for your window. Even if you could do this the net result would not feel very nice for the user.
I am using C# and WinForms to create UI of my application.
I have main window and dialog, which is shown modal to the main window. Dialog window is not shown in task bar. I go to another application and return back by clicking at the main window task bat icon. I can see locked main window but cannot see dialog unless I select it in Alt-Tab. This is confusing for an application user.
How can I ensure showing modal window in this situation? I can see similar but unfortunately unsolved question ALT+TAB in Vista activates main window instead of previously active child window which regards to Vista (and I have Windows 7).
This is probably because you don't use the ShowDialog(owner) overload. You should fret a little bit about the exact reason that ShowDialog() cannot find an owner by itself and picked the desktop window instead. It isn't healthy. I cannot guess why from your post. See what explicitly setting the owner buys you.
Oh, this will happen when the dialog runs on its own thread. In which case ShowDialog(owner) is going to bomb.
It sounds like your dialog is not properly owned by the main window. Make sure you have assigned the main window to the dialog object's Owner property before showing the modal dialog.
I have a window that opens another window. I want that when this window it's opened i can't do anything on the parent window. (I'm not allowed to click buttons for example)
How I can do that?
Thanks.
You need to call the ShowDialog method instead of Show to show the second window as a modal dialog.
You want a modal window instead of a modeless window. A modal window means that the parent window is not usable while the child window is open.
You can open a modal window with ShowDialog.
You can open a modeless window with just Show.
I Recommend you to use MDI scenario behaving as child and parent windows but for instance according to the point you can use code below.
NewWindow.ShowDialog() method instead of NewWindow.Show() as it will disable background window
but that's not good practice we should implement MDI.
I've never seen a desktop application opening on multiple windows and disabling older ones.