How can I just get the base filename from this C# code? - c#

I have the following code:
string[] files = Directory.GetFiles(#"C:\Notes", "*.txt", SearchOption.TopDirectoryOnly);
foreach(string file in files)
When I check the contents of file it has the directory path and extension. Is there a way I can just get the filename out of that?

You can use the FileInfo class:
FileInfo fi = new FileInfo(file);
string name = fi.Name;
If you want just the file name - quick and simple - use Path:
string name = Path.GetFileName(file);

You can use the following method: Path.GetFileName(file)

System.IO.FileInfo f = new System.IO.FileInfo(#"C:\pagefile.sys"); // Sample file.
System.Windows.Forms.MessageBox.Show(f.FullName); // With extension.
System.Windows.Forms.MessageBox.Show(System.IO.Path.GetFileNameWithoutExtension(f.FullName)); // What you wants.

If you need to strip away the extension, path, etc. you should fill this string into a FileInfo and use its properties or use the static methods of the Path class.

Related

GetFiles with spaces in filename

I use the following code to take all the files from a directory and search for a specific file:
string [] fileEntries = Directory.GetFiles("C:\\uploads");
foreach(string fileName in fileEntries)
if (fileName.Contains(name))
PicturePath = fileName;
where "name" is a string which I get from DB.
It seems to work to an extend but if my file contains a space in fileName it only takes the first string from fileName which is the first string before the white space, ignoring th rest. How can i take the full fileName (as well as the path to that file accordingly).
For example: I have a file named "ALEXANDRU ALINA.jpg" inside uploads and in name i have the string "ALEXANDRU ALINA". When I run that code (writing the PicturePath) it displays just "ALEXANDRU".
This might be what you're looking for:
string[] fileEntries = Directory.GetFiles("C:\\uploads");
foreach (string fileName in fileEntries)
{
FileInfo fi = new FileInfo(fileName);
if (fi.Name.Equals(name, StringComparison.CurrentCultureIgnoreCase)) PicturePath = fileName;
}
What you're attempting to do is find the target file name within the whole path, but the method you're using could produce errors (what if the name is contained within part of the folder path?). By using the System.FileInfo class and its Name property, which is the file name only (not the full file path which includes the containing folder path), you won't be needlessly searching any part of the folder path.

How to get files with desired name in C# using Directory.Getfile?

I am trying to obtain a file of name "fileName.wav" from the directory whose path has been specified im not able to get the desired function .. any help in this regard is appreciated.
static void Main(string[] args)
{
string[] fileEntries = Directory.GetFiles(
#"D:\project\Benten_lat\BentenPj_000_20141124_final\Testing\DPCPlus\Ref\Generated_Ref_Outputs_MSVS", "*.wav");
foreach (string fileName in fileEntries)
{
string[] fileEntries1 = Directory.GetFiles(
#"D:\project\older versions\dpc_latest\Testing\DPCPlus\input");
foreach (string fileName1 in fileEntries1)
{
Console.WriteLine(Path.GetFileName(fileName1));
}
}
}
This Code will search for all .xml extension files with matches abCd name from C:\\SomeDir\\ folder.
string cCId ="abCd";
DirectoryInfo di = new DirectoryInfo("C:\\SomeDir\\");
FileInfo[] orderFiles = di.GetFiles("*" + cCId + "*.xml", SearchOption.TopDirectoryOnly);
You should change this code according to your needs.
Hope this helps you.
If you want to extract name and extension from a file-path, you can use following code:
string result = Path.GetFileName(yourFilePath); // result will be filename.wav
You can not use GetFiles method for a file path!
Directory.GetFiles(#"D:\project\Benten_lat\BentenPj_000_20141124_final\Testing\DPCPlus\Ref\Generated_Ref_Outputs_MSVS\filename.wav") //Error
The input for this method should be a directory!
Assumptions based on your question (please correct me if I am wrong):
You know the folder (e.g. the user entered it)
You know the file name (e.g. it is hard coded because it must be the same always)
In this case you do not really need to search the file.
Solution:
string folderPath = #"D:\somewhere";
string fileName = "file.wav";
string filePath = Path.Combine(folderPath, fileName);
if (File.Exists(filePath))
{
// continue reading the file, etc.
}
else
{
// handle file not found
}

get full filename

I have a path "C:\Users\Web References"
Under the "Web References" folder, i have *.wsdl file
I want to get the full filename of the *.wsdl file
Thanks!
Something like this:
var files = Directory.GetFiles("C:\\Users\\Web References", "*.wsdl", SearchOption.AllDirectories);
This will return a collection of files - there could be more than one wsdl file in the directory. Take the first:
var wsdlFile = files.FirstOrDefault();
Seeing that no-one is mentioning it: Path.GetFullPath()
First, you have to find it:
var files = Directory.GetFiles(path, "*.wsdl");
and now files will contain full paths to all WSDL files (if any) in path.
// find files by filter
var result = Directory.GetFiles("C:\\Users\\Web References\\", "*.wsdl");
//if you have only one file
return System.IO.Path.GetFileName(result[0]); // "my.wsdl"
The Path class will help you extract just the filename from a file path:
string path = #"C:\Users\Web References";
string[] files = Directory.GetFiles(path, "*.wsdl");
foreach (string filePath in files) {
string filename = Path.GetFileName(filePath); // e.g. myFile.wsdl
}
or using linq
var files = from f in Directory.GetFiles((#"C:\Users\Web References")
where f.EndsWith(".wsdl")
select f;
foreach (var file in files)
...

How do I get the directory from a file's full path?

What is the simplest way to get the directory that a file is in? I'm using this to set a working directory.
string filename = #"C:\MyDirectory\MyFile.bat";
In this example, I should get "C:\MyDirectory".
If you've definitely got an absolute path, use Path.GetDirectoryName(path).
If you might only get a relative name, use new FileInfo(path).Directory.FullName.
Note that Path and FileInfo are both found in the namespace System.IO.
System.IO.Path.GetDirectoryName(filename)
Path.GetDirectoryName(filename);
You can use System.IO.Path.GetDirectoryName(fileName), or turn the path into a FileInfo using FileInfo.Directory.
If you're doing other things with the path, the FileInfo class may have advantages.
You can use Path.GetDirectoryName and just pass in the filename.
MSDN Link
If you are working with a FileInfo object, then there is an easy way to extract a string representation of the directory's full path via the DirectoryName property.
Description of the FileInfo.DirectoryName Property via MSDN:
Gets a string representing the directory's full path.
Sample usage:
string filename = #"C:\MyDirectory\MyFile.bat";
FileInfo fileInfo = new FileInfo(filename);
string directoryFullPath = fileInfo.DirectoryName; // contains "C:\MyDirectory"
Link to the MSDN documentation.
You can get the current Application Path using:
string AssemblyPath = Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().Location).ToString();
First, you have to use System.IO namespace. Then;
string filename = #"C:\MyDirectory\MyFile.bat";
string newPath = Path.GetFullPath(fileName);
or
string newPath = Path.GetFullPath(openFileDialog1.FileName));
You can use Path.GetFullPath for most of the case.
But if you want to get the path also in the case of the file name is relatively located then you can use the below generic method:
string GetPath(string filePath)
{
return Path.GetDirectoryName(Path.GetFullPath(filePath))
}
For example:
GetPath("C:\Temp\Filename.txt") return "C:\Temp\"
GetPath("Filename.txt") return current working directory like "C:\Temp\"
In my case, I needed to find the directory name of a full path (of a directory) so I simply did:
var dirName = path.Split('\\').Last();

How to get the name of File in a directory in C#

Directory.GetFiles(targetDirectory);
Using the above code we get the names(i.e full path) of all the files in the directory. but i need to get only the name of the file and not the path. So how can I get the name of the files alone excluding the path? Or do I need to do the string operations in removing the unwanted part?
EDIT:
TreeNode mNode = new TreeNode(ofd.FileName, 2, 2);
Here ofd is a OpenFileDialog and ofd.FileName is giving the the filename along with it's Path but I need the file name alone.
You could use:
Path.GetFileName(fullPath);
or in your example:
TreeNode mNode = new TreeNode(Path.GetFileName(ofd.FileName), 2, 2);
Use DirectoryInfo and FileInfo if you want to get only the filenames without doing any manual string editing.
DirectoryInfo dir = new DirectoryInfo(dirPath);
foreach (FileInfo file in dir.GetFiles())
Console.WriteLine(file.Name);
Use:
foreach(FileInfo fi in files)
{
Response.Write("fi.Name");
}

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