Develop Reference

Append to the second to last line in a text file

So I'm making a program to type what's in my clipboard into a text file, I plan on later transporting this information into an AHK script, but I want to do this all in one program, so if possible it will append to the .ahk file, but instead of it appending to the very last line, I need it to append to the line before return, which is the final line of the file.
Send ::redeem N4E2vzCEp {enter}
Sleep 1000
return
That's the end of the file, if possible I want my program to do something like:
string pasted = Clipboard.GetText();
sw.WriteLine.SecondLastLine("Send ::redeem " + pasted + " {enter}");
sw.WriteLine.SecondLastLine("Sleep 1000"); //Fully aware that secondlastline is not a valid command
But I don't know what the proper way of actually coding this would be.
Current code:
private void paste_Click(object sender, EventArgs e)
{
string path = #"c:\users\john\desktop\auths.txt";
using (StreamWriter sw = File.AppendText(path))
{
string pasted = Clipboard.GetText();
sw.WriteLine("Send ::redeem " + pasted + " {enter}");
sw.WriteLine("Sleep 1000");
}
}

What you can do is reading all lines into a List and then insert the new line at a specific position and write the lines back to the file.
List<string> lines = File.ReadAllLines("your file").ToList();
lines.Insert(lines.Count - 2, "new line");
File.WriteAllLines("your file", lines);

How can i write multiple lines in a textfile to different textboxes?

What i did to write from the boxes to the txt file
private void save2_Click(object sender, EventArgs e)
{
Stream myStream;
SaveFileDialog sfd = new SaveFileDialog();
sfd.Filter = "Textdokument|*.txt";
sfd.FilterIndex = 1;
sfd.RestoreDirectory = true;
if (sfd.ShowDialog() == DialogResult.OK)
{
if ((myStream = sfd.OpenFile()) != null)
{
StreamWriter sw = new StreamWriter(myStream);
sw.WriteLine(TextBoxCardname1.Text);
sw.WriteLine(TextBoxCardname2.Text);
sw.WriteLine(TextBoxCardname3.Text);
sw.WriteLine(TextBoxCardname4.Text);
sw.WriteLine(TextBoxCardname5.Text);
sw.WriteLine(TextBoxCardname6.Text);
sw.WriteLine(TextBoxCardname7.Text);
sw.WriteLine(TextBoxCardname8.Text);
sw.WriteLine(TextBoxCardname9.Text);
sw.WriteLine(TextBoxCardname10.Text);
sw.WriteLine(TextBoxCardname11.Text);
sw.WriteLine(TextBoxCardname12.Text);
sw.WriteLine(TextBoxCardname13.Text);
sw.WriteLine(TextBoxCardname14.Text);
sw.WriteLine(TextBoxCardname15.Text);
sw.WriteLine(TextBoxCardname16.Text);
sw.WriteLine(TextBoxCardname17.Text);
sw.WriteLine(TextBoxCardname18.Text);
sw.WriteLine(TextBoxCardname19.Text);
sw.WriteLine(TextBoxCardname20.Text);
sw.WriteLine(TextBoxCardname21.Text);
sw.WriteLine(TextBoxCardname22.Text);
sw.WriteLine(TextBoxCardname23.Text);
sw.WriteLine(TextBoxCardname24.Text);
sw.WriteLine(TextBoxCardname25.Text);
sw.WriteLine(TextBoxCardname26.Text);
sw.WriteLine(TextBoxCardname27.Text);
sw.WriteLine(TextBoxCardname28.Text);
sw.WriteLine(TextBoxCardname29.Text);
sw.WriteLine(TextBoxCardname30.Text);
sw.Close();
myStream.Close();
}
}
}

Assuming what you meant by your question is that you want to take the contents of each line of a textfile and write it to its corresponding textbox.text; this should work for you:
TextBoxCardname1.Text = System.IO.File.ReadLines("Your Text File").Skip(0).Take(1).First();
TextBoxCardname2.Text = System.IO.File.ReadLines("Your Text File").Skip(1).Take(1).First();
TextBoxCardname3.Text = System.IO.File.ReadLines("Your Text File").Skip(2).Take(1).First();
//...etc
For each line you're reading, you specify how many lines you want to skip, and how many lines you want to read (ie. Skip(1), Take (1) means you would skip the first line in the text file, and read the second line).
If you're trying to get the textbox.text and write it to your textfile (it's kind of hard to tell from your question) This is a simple, yet messy, and labor-intensive method:
var lines = System.IO.File.ReadAllLines("Your text file");
lines[0] = TextBoxCardname1.text);
System.IO.File.WriteAllLines("Your text file", lines);
var lines = System.IO.File.ReadAllLines("Your text file");
lines[1] = TextBoxCardname2.text);
System.IO.File.WriteAllLines("Your text file", lines);
var lines = System.IO.File.ReadAllLines("Your text file");
lines[2] = TextBoxCardname3.text);
System.IO.File.WriteAllLines("Your text file", lines);
//...etc
This method is a very simple way to write to a certain line in a text file. lines[3] would denote the 4th line in the text file, since the line numbering starts at zero [0] (The first line in the text file).

How to create a text file, and naming it with a text box or variable

Hi im very new to c# so apologies for this.
Im trying to create a text file to save customers details. But i want to name the text file by the surname. I.e myfile.txt.
Im sure im close, but missing something when it comes to changing the surname.text to a variable then making it the name of my created new file.
I have put 2 ** around the problem area.
private void button1_Click(object sender, EventArgs e)
{
try
{
if ((tb_firstname.Text == "") || (tb_surname.Text == "") || (tb_postcode.Text == ""))
{
MessageBox.Show("Missing values from textboxes!");
}
else if (
****string myfile.txt = (tb_surname.Text);
File.Exists("myfile.txt"));****
{
if (MessageBox.Show("Warning: file already exists. " +
"Contents will be replaced - " +
"do you want to continue?", "File Demo",
MessageBoxButtons.YesNo, MessageBoxIcon.Question,
MessageBoxDefaultButton.Button1,
MessageBoxOptions.DefaultDesktopOnly) ==
DialogResult.Yes)
{
//write lines of text to file
StreamWriter outputStream = File.CreateText(myfile.txt);
outputStream.WriteLine(tb_firstname.Text);
outputStream.WriteLine(tb_surname.Text);
outputStream.WriteLine(tb_surname.Text);
outputStream.Close();
MessageBox.Show("Text written to file successfully!");
this.Close();
}
else
{
MessageBox.Show("Action cancelled existing file contents not replaced!");
this.Close();
}
}
else
{
//write lines of text to file
StreamWriter outputStream = File.CreateText("myFile.txt");
outputStream.WriteLine(tb_firstname.Text);
outputStream.WriteLine(tb_surname.Text);
outputStream.WriteLine(tb_postcode.Text);
outputStream.Close();
MessageBox.Show("Text written to file successfully!");
this.Close();
}
}
catch (Exception problem)
{
MessageBox.Show("Program has caused an error - " + problem.ToString());
}
}
any help would be great!

You are creating a file called myfile.txt every time
StreamWriter outputStream = File.CreateText("myFile.txt");
That's a string literal you are using.
You have the line:
string myfile.txt = (tb_surname.Text)
which reads the contents of the text box into a variable called myfile.txt. You then need to use that in the file creation code:
StreamWriter outputStream = File.CreateText(myFile.txt);
Note that there are no quotes.
This will overwrite the file if it already exists - if you want to append you will need to use the following method:
StreamWriter outputStream = File.AppendText(myFile.txt);

I believe you are trying to save the surname as part of the file name. You can generate the filename and check if it exists with the code below:
First generate the filename:
string fileName = string.Format("{0}File.txt", tb_surname.Text);
And then check it using the variable:
File.Exists(fileName);

Text file doesn't get saved but no errors (C#)

I've been looking on many websites now for the answer, but all working answers only work for the richTextbox, and I'm using the normal textbox. I'm trying to save the contents of the textbox to a file of choice, but for some reason the file doesn't get saved, and I have no idea what the problem is. This is the code of the 'save' menu item:
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveFileDialog ofd = new SaveFileDialog();
ofd.Title = "Save";
ofd.Filter = "Txt Documents (.txt)|*.txt|All files (*.*)|*.*";
if (ofd.ShowDialog() == DialogResult.OK)
{
try
{
//I don't know what to make of this, because clearly this doesn't work
File.WriteAllText(#"./TestFile.txt", MainTextbox.Text);
}
catch (Exception ex)
{
MainTextbox.Text += ex;
}
}
}
There is no error.

You should be saving to the file selected in your SaveFileDialog, as retrieved by OpenFile(). This example worked for me:
SaveFileDialog ofd = new SaveFileDialog();
ofd.Title = "Save";
ofd.Filter = "Txt Documents (.txt)|*.txt|All files (*.*)|*.*";
if (ofd.ShowDialog() == DialogResult.OK)
{
using (var fileStream = ofd.OpenFile())
using (var sw = new StreamWriter(fileStream))
sw.WriteLine("Some text");
}
In your code, you let the user select a file to save to, then ignore that and write it to a hardcoded location. It's possible your app didn't have permissions to do this, but it should have permissions to write to a location the user selected.

First off, saving the file has nothing to do with where the text is coming from, rich text box or normal text box.
As Brian S. said in a comment, it is likely there is an exception because you're writing to the C drive. You should use a relative path: "./MyTest.txt"

I think its access denied issue.. try with 'D' drive ...
This is working example.. .WriteAllText works when file already exists and if file already exists then use AppendAllText
using System;
using System.IO;
using System.Text;
class Test
{
public static void Main()
{
string path = #"c:\temp\MyTest.txt";
// This text is added only once to the file.
if (!File.Exists(path))
{
// Create a file to write to.
string createText = "Hello and Welcome" + Environment.NewLine;
File.WriteAllText(path, createText);
}
// This text is always added, making the file longer over time
// if it is not deleted.
string appendText = "This is extra text" + Environment.NewLine;
File.AppendAllText(path, appendText);
// Open the file to read from.
string readText = File.ReadAllText(path);
Console.WriteLine(readText);
}
}

Use a try { } catch (Exception ex) { } block How to: Use the Try/Catch Block to Catch Exceptions

How to replace a data from a file if already exists and write a new data

Hi all i write a code to write my last row of datagrid view to a file as follows
private void Save_Click(object sender, EventArgs e)
{
if (dataGridView1.Rows.Count > 0)
{
List<string> lstContent = new List<string>();
foreach (DataGridViewRow row in dataGridView1.Rows)
{
if ((string)row.Cells[0].Value == "FileControl")
{
lstContent.Add((string)row.Cells[1].Value);
string mydata = string.Join(",", lstContent.ToArray());
using (StreamWriter sw = new StreamWriter(Append.FileName, true))
{
sw.WriteLine();
sw.Write(mydata);
}
}
}
}
}
But if i click multiple times on save this is writing that line multiple times what i need is if already that line exists in the file i have to replace that line with new line. Any help please

Your StreamWriter is explicitly using the file with append = true. Change the second parameter of the constructor to false if you want to overwrite the file each time. Docs are here. Quote:
append
Type: System.Boolean
Determines
whether data is to be appended to the
file. If the file exists and append is
false, the file is overwritten. If the
file exists and append is true, the
data is appended to the file.
Otherwise, a new file is created.
Revised code:
using (StreamWriter sw = new StreamWriter(Append.FileName, false))
{
sw.WriteLine();
sw.Write(mydata);
}
Replacing a given line in your file rather than just overwriting the whole file is a lot more difficult - this code is not going to get it done. StreamWriter is not great for this, you need random access and the ability to replace one data segment (line) by a different data segment of different length, which is an expensive operation on disk.
You might want to keep the files in memory as a container of Strings and do your required line replacement within the container, then write out the file to disk using File.WriteAllLines - that's if the file is not too big.