Currently have a working rounding model within my c# code and is perfectly rounding numbers that have more than 2 decimal places down to 2 decimal places which is great. However, when i have lets say double value = 100.6, and i put that into double dollar_value = Math.Round(value, 2), it still returns as 100.6.
I was wondering if there was a way to transform a 1 decimal place value to 2 decimal places?
Numbers are not stored with extra zeroes (As it is a waste of memory to do so, being the numbers are the same with or without). In order to represent a number this way you will either need to display or store it as a string.
string str = value.ToString("#.00", CultureInfo.InvariantCulture);
Now str will always have 2 decimal places.
I don't know the C# method, but in C++ I'd use one of these two methods:
double value = 23.666666 ; // example
value = 0.01 * floor ( value * 100.0 ) ; // There's a "floor" function in C# too
^ See https://msdn.microsoft.com/en-us/library/e0b5f0xb(v=vs.110).aspx
Or
double value = 23.666666 ; // example
value = 0.01 * (double) ( (int)(value*100.0) ) ;
Or
double value = 23.666666 ; // example
value = 0.01 * double ( int ( value*100.0 ) ) ; // same as previous, but more C++ like
The other answers are probably better if you're looking to "print a dollar amount with two decimal places." However, if you want to transform the number to use internally, this is a way to do it.
If you want the string representation to have two decimal points use:
yourNumber.ToString ("0.00");
The number itself is always stored as a ~29 digit number regardless of its string representation.
Your value just needs to be formatted when it's display - for example value.ToString("N2") will convert it to a string with two decimal places. Check out the Standard Numeric Format Strings on MSDN to see a broader list of formatting strings.
Additionally, I'd only convert to a string when you're ready display the value to a user and would keep it as a numeric type (e.g. double) if you're passing it around between methods or planning to do any further calculations on it. Otherwise you'll be unnecessarily converting the value to and from a string multiple times.
I want to convert float value to string.
Below is the code which i am using for the conversion.
static void Main(string[] args)
{
string s =string.Format("{0:G}", value);
Console.Write(s);
Console.ReadLine();
}
and it outputs as 2.5
But my problem is i want to get the value as 2.50 because i want to compare it with original value later in my project.
so please suggest me if there are any ways to do it?
You should be using {0:N2} to format to two decimal places.
string.Format("{0:N2}", 2.50)
For 3 decimal places:
string.Format("{0:N3}", 2.50)
And so on.
You can also store the value in a string this way without worrying about precision and then convert your value where you are testing for comparison as string:
string strDecimalVal = Convert.ToString( 2.5000001);
because i want to compare it with original value later in my project.
...then you will need to store the number of decimal places the original value had. Once the value is a float, this information is lost. The float representations of 2.5, 2.50 and 2.500 are exactly the same.
So, basically, you have the following possibilities (in order of preference):
Don't do a string comparison between the old and the new value. Convert both values to float and then compare them (with a margin of error since floats are not precise).
Store the number of decimal places of the old value and then use myFloat.ToString("F" + numDecimals.ToString()) to convert it to a string.
Store the value as a string instead of a float. Obviously, you won't be able to do math on that value.
Alternatively, if you do not insist on using floats, decimals might suit your purpose: The do store the number of significant digits:
decimal x = Decimal.Parse("2.50", CultureInfo.InvariantCulture);
decimal y = Decimal.Parse("2.500", CultureInfo.InvariantCulture);
Console.WriteLine(x.ToString()); // prints 2.50
Console.WriteLine(y.ToString()); // prints 2.500
Try this
Console.WriteLine("{0:F2}", 2.50);
Console.WriteLine("{0:0.00}", 2.50);
Console.WriteLine("{0:N2}", 2.50);
Version 1 and 2 are almost similar, but 3 is different. 3 will include number separators when number is large.
For example the following outputs 454,542.50
Console.WriteLine("{0:N2}", 454542.50);
More on MSDN
I'm struggling to find a better way to preserve the 2 digit precision for decimal variable.
Here I have divided the question in 2 steps:
Step1: SQL Query
Inorder to get a 2 digit precision in a SQL query, I'm using
CONVERT(DECIMAL(10,2), .....) // to get 2 digit precision
On execution, I'm able to achieve the 2 digit precision in my SSMS.
NET_TOTAL
---------
10.00
12.50
14.25
Step2: via C# code
Whereas in my C# code, when I tried to store the value in my C# code it is not preserving the 2 digit precision.
NET_TOTAL
---------
10 //lost my precision
12.5 //lost my precision
14.25
Following is my variable declaration.
public decimal? NET_TOTAL { get; set; }
But I can smell a workaround using properties, but I'm not able to get it.
I'm using
dapper.net for database operations.
FileHelper.dll for converting the query list to a CSV file.
I would like to know the reason and a way to solve this problem.
Any help is much appreciated.
Thanks in advance.
Trailing zeros to the right of the decimal is not precision.
It is just presentation.
decimal d;
d = 10;
System.Diagnostics.Debug.WriteLine(string.Format("{0:N2}",d));
You can use
decimal.Round(value,decimalPoints);
This will return a decimal rounded upto decimalPoints.
You are confusing precision with representation. What you see in SSMS is a formatted number (a string). What you have in C# (and inside the DB) is a "true" number. In a true normally ending 0 after the decimal point aren't included.
If you want to format it you can do something like NET_TOTAL.ToString("0.00")
Note that there could be another problem:
NET_TOTAL = 1.245;
decimal sum = NET_TOTAL + NET_TOTAL;
the sum will be 2.29, but after a roundtrip to the DB NET_TOTAL will be 1.24 or 1.25 (depending on how the DB rounded 1.245) and the recalculated sum will be 2.28 or 2.3 .
is this acceptable:
private decimal? _netTotal;
public decimal? NET_TOTAL{
get{
return _netTotal;
}
set
{
if (value.HasValue)
{
_netTotal = Math.Truncate(value.Value, 2); // or rounding
}else{
_netTotal = value;
}
}
}
if you want to keep the original value but present it with 2 decimal places, then you could modify the getter instead: return Math.Truncate(value.Value, 2);
I am working with a decimal type in my application and have to submit that value as a string to a legacy web service which accepts values as strings. Its a payment value, so:
1000 => "100000" (1000 dollars and 00 cents)
131.11 => "13111"
I thought I'd multiply by 100 initially but ran into some cases that don't work as expected.
EDIT:
OK I will clarify:
decimal val = 145.99m;
Console.WriteLine((val * 100).ToString());
results in:
14599.00
but I really need 14599 without the decimal points, since the value the other side is expecting is 145 dollars and 99 cents.
I was thinking there may be a different way rather than doing something like String.Replace(".00", string.Empty) or is this the only way?
If you want it to be 0 decimal places, you can do myDecimal.ToString("0");.
For example:
decimal myDecimal = 25.99m;
(myDecimal*100m).ToString("0"); // 2599
While if your decimal had more decimal places:
decimal myDecimal = 3.14159m;
(myDecimal*100m).ToString("0"); // 314
EDIT: If your decimal has extra decimal places, it performs an .5 away round. (in my experience, VS2008).
You could simply convert to float, divide by 100, and convert to string then (supposing you store the number as an integer).
You could multiply by 100 then cast it to an integer based (integer in the mathematical sense) to truncate the decimal portion, and then ToString() the result.
decimal x = 45.13m;
string output = ((long)(x * 100)).ToString();
When displaying the value of a decimal currently with .ToString(), it's accurate to like 15 decimal places, and since I'm using it to represent dollars and cents, I only want the output to be 2 decimal places.
Do I use a variation of .ToString() for this?
decimalVar.ToString("#.##"); // returns ".5" when decimalVar == 0.5m
or
decimalVar.ToString("0.##"); // returns "0.5" when decimalVar == 0.5m
or
decimalVar.ToString("0.00"); // returns "0.50" when decimalVar == 0.5m
I know this is an old question, but I was surprised to see that no one seemed to post an answer that;
Didn't use bankers rounding
Keeps the value as a decimal.
This is what I would use:
decimal.Round(yourValue, 2, MidpointRounding.AwayFromZero);
http://msdn.microsoft.com/en-us/library/9s0xa85y.aspx
decimalVar.ToString("F");
This will:
Round off to 2 decimal places eg. 23.456 → 23.46
Ensure that there
are always 2 decimal places eg. 23 → 23.00; 12.5 → 12.50
Ideal for displaying currency.
Check out the documentation on ToString("F") (thanks to Jon Schneider).
If you just need this for display use string.Format
String.Format("{0:0.00}", 123.4567m); // "123.46"
http://www.csharp-examples.net/string-format-double/
The "m" is a decimal suffix. About the decimal suffix:
http://msdn.microsoft.com/en-us/library/364x0z75.aspx
Given decimal d=12.345; the expressions d.ToString("C") or String.Format("{0:C}", d) yield $12.35 - note that the current culture's currency settings including the symbol are used.
Note that "C" uses number of digits from current culture. You can always override default to force necessary precision with C{Precision specifier} like String.Format("{0:C2}", 5.123d).
If you want it formatted with commas as well as a decimal point (but no currency symbol), such as 3,456,789.12...
decimalVar.ToString("n2");
There's a very important characteristic of Decimal that isn't obvious:
A Decimal 'knows' how many decimal places it has based upon where it came from
The following may be unexpected :
Decimal.Parse("25").ToString() => "25"
Decimal.Parse("25.").ToString() => "25"
Decimal.Parse("25.0").ToString() => "25.0"
Decimal.Parse("25.0000").ToString() => "25.0000"
25m.ToString() => "25"
25.000m.ToString() => "25.000"
Doing the same operations with Double will result in zero decimal places ("25") for all of the above examples.
If you want a decimal to 2 decimal places there's a high likelyhood it's because it's currency in which case this is probably fine for 95% of the time:
Decimal.Parse("25.0").ToString("c") => "$25.00"
Or in XAML you would use {Binding Price, StringFormat=c}
One case I ran into where I needed a decimal AS a decimal was when sending XML to Amazon's webservice. The service was complaining because a Decimal value (originally from SQL Server) was being sent as 25.1200 and rejected, (25.12 was the expected format).
All I needed to do was Decimal.Round(...) with 2 decimal places to fix the problem regardless of the source of the value.
// generated code by XSD.exe
StandardPrice = new OverrideCurrencyAmount()
{
TypedValue = Decimal.Round(product.StandardPrice, 2),
currency = "USD"
}
TypedValue is of type Decimal so I couldn't just do ToString("N2") and needed to round it and keep it as a decimal.
Here is a little Linqpad program to show different formats:
void Main()
{
FormatDecimal(2345.94742M);
FormatDecimal(43M);
FormatDecimal(0M);
FormatDecimal(0.007M);
}
public void FormatDecimal(decimal val)
{
Console.WriteLine("ToString: {0}", val);
Console.WriteLine("c: {0:c}", val);
Console.WriteLine("0.00: {0:0.00}", val);
Console.WriteLine("0.##: {0:0.##}", val);
Console.WriteLine("===================");
}
Here are the results:
ToString: 2345.94742
c: $2,345.95
0.00: 2345.95
0.##: 2345.95
===================
ToString: 43
c: $43.00
0.00: 43.00
0.##: 43
===================
ToString: 0
c: $0.00
0.00: 0.00
0.##: 0
===================
ToString: 0.007
c: $0.01
0.00: 0.01
0.##: 0.01
===================
Math.Round Method (Decimal, Int32)
Very rarely would you want an empty string if the value is 0.
decimal test = 5.00;
test.ToString("0.00"); //"5.00"
decimal? test2 = 5.05;
test2.ToString("0.00"); //"5.05"
decimal? test3 = 0;
test3.ToString("0.00"); //"0.00"
The top rated answer is incorrect and has wasted 10 minutes of (most) people's time.
Mike M.'s answer was perfect for me on .NET, but .NET Core doesn't have a decimal.Round method at the time of writing.
In .NET Core, I had to use:
decimal roundedValue = Math.Round(rawNumber, 2, MidpointRounding.AwayFromZero);
A hacky method, including conversion to string, is:
public string FormatTo2Dp(decimal myNumber)
{
// Use schoolboy rounding, not bankers.
myNumber = Math.Round(myNumber, 2, MidpointRounding.AwayFromZero);
return string.Format("{0:0.00}", myNumber);
}
None of these did exactly what I needed, to force 2 d.p. and round up as 0.005 -> 0.01
Forcing 2 d.p. requires increasing the precision by 2 d.p. to ensure we have at least 2 d.p.
then rounding to ensure we do not have more than 2 d.p.
Math.Round(exactResult * 1.00m, 2, MidpointRounding.AwayFromZero)
6.665m.ToString() -> "6.67"
6.6m.ToString() -> "6.60"
The top-rated answer describes a method for formatting the string representation of the decimal value, and it works.
However, if you actually want to change the precision saved to the actual value, you need to write something like the following:
public static class PrecisionHelper
{
public static decimal TwoDecimalPlaces(this decimal value)
{
// These first lines eliminate all digits past two places.
var timesHundred = (int) (value * 100);
var removeZeroes = timesHundred / 100m;
// In this implementation, I don't want to alter the underlying
// value. As such, if it needs greater precision to stay unaltered,
// I return it.
if (removeZeroes != value)
return value;
// Addition and subtraction can reliably change precision.
// For two decimal values A and B, (A + B) will have at least as
// many digits past the decimal point as A or B.
return removeZeroes + 0.01m - 0.01m;
}
}
An example unit test:
[Test]
public void PrecisionExampleUnitTest()
{
decimal a = 500m;
decimal b = 99.99m;
decimal c = 123.4m;
decimal d = 10101.1000000m;
decimal e = 908.7650m
Assert.That(a.TwoDecimalPlaces().ToString(CultureInfo.InvariantCulture),
Is.EqualTo("500.00"));
Assert.That(b.TwoDecimalPlaces().ToString(CultureInfo.InvariantCulture),
Is.EqualTo("99.99"));
Assert.That(c.TwoDecimalPlaces().ToString(CultureInfo.InvariantCulture),
Is.EqualTo("123.40"));
Assert.That(d.TwoDecimalPlaces().ToString(CultureInfo.InvariantCulture),
Is.EqualTo("10101.10"));
// In this particular implementation, values that can't be expressed in
// two decimal places are unaltered, so this remains as-is.
Assert.That(e.TwoDecimalPlaces().ToString(CultureInfo.InvariantCulture),
Is.EqualTo("908.7650"));
}
You can use system.globalization to format a number in any required format.
For example:
system.globalization.cultureinfo ci = new system.globalization.cultureinfo("en-ca");
If you have a decimal d = 1.2300000 and you need to trim it to 2 decimal places then it can be printed like this d.Tostring("F2",ci); where F2 is string formating to 2 decimal places and ci is the locale or cultureinfo.
for more info check this link
http://msdn.microsoft.com/en-us/library/dwhawy9k.aspx
https://msdn.microsoft.com/en-us/library/dwhawy9k%28v=vs.110%29.aspx
This link explains in detail how you can handle your problem and what you can do if you want to learn more. For simplicity purposes, what you want to do is
double whateverYouWantToChange = whateverYouWantToChange.ToString("F2");
if you want this for a currency, you can make it easier by typing "C2" instead of "F2"
The most applicable solution is
decimalVar.ToString("#.##");
Double Amount = 0;
string amount;
amount=string.Format("{0:F2}", Decimal.Parse(Amount.ToString()));
If you need to keep only 2 decimal places (i.e. cut off all the rest of decimal digits):
decimal val = 3.14789m;
decimal result = Math.Floor(val * 100) / 100; // result = 3.14
If you need to keep only 3 decimal places:
decimal val = 3.14789m;
decimal result = Math.Floor(val * 1000) / 1000; // result = 3.147
var arr = new List<int>() { -4, 3, -9, 0, 4, 1 };
decimal result1 = arr.Where(p => p > 0).Count();
var responseResult1 = result1 / arr.Count();
decimal result2 = arr.Where(p => p < 0).Count();
var responseResult2 = result2 / arr.Count();
decimal result3 = arr.Where(p => p == 0).Count();
var responseResult3 = result3 / arr.Count();
Console.WriteLine(String.Format("{0:#,0.000}", responseResult1));
Console.WriteLine(String.Format("{0:#,0.0000}", responseResult2));
Console.WriteLine(String.Format("{0:#,0.00000}", responseResult3));
you can put as many 0 as you want.