Class<type> in C# - c#

I have a class and want to work with it as Lists: e.g. List<int>, List<string>, ... , List<T>
I have a class Randomizor which will take the collection data type that will be shuffled. How can I do so?
class Randomizor<T>
{
public Randomizor()
{
}
public Array Shuffle(Array toShuffle)
{
}
}

Create a generic class like so:
class Randomizer<TList, TType> where TList : IList<TType>
{
public TList Randomize(TList list)
{
// ...
}
}
Or like so:
class Randomizer<T>
{
public IList<T> Randomize(IList<T> list)
{
// ...
}
}

Not very clear question... do you mean something like this?
public static class Randomizer<T>
{
public static T GetRandom(List<T> list)
{
T value = default(T);
// Perform some random logic.
return value;
}
}

EDIT: I found two superior impementations after a little digging so I would suggest those in preference.
An extension method for this purpose and already been suggested previously here
I include the code paraphrased to Shuffle below.
public static IEnumerable<T> Shuffle<T> (this IEnumerable<T> source)
{
Random random = new Random ();
T [] copy = source.ToArray ();
for (int i = copy.Length - 1; i >= 0; i--)
{
int index = random.Next (i + 1);
yield return copy [index];
copy [index] = copy [i];
}
}
And an interesting solution adapted from this linq approach
public static IEnumerable<T> Shuffle<T> (this IEnumerable<T> source)
{
Random random = new Random ();
return source.OrderBy(i => Random.Next()).AsEnumerable();
}
The orignal answer but slower than the edits
public static IEnumerable<T> Shuffle<T>(this IEnumerable<T> sequence)
{
Random random = new Random();
List<T> copy = sequence.ToList();
while (copy.Count > 0)
{
int index = random.Next(copy.Count);
yield return copy[index];
copy.RemoveAt(index);
}
}
If you like one of these you should up vote the linked answer.
If you are very concerned about randomness, you could upgrade to one of the RNG algorithms from the Crypto API and seed it with some non deterministic value, like somthing generated from recent mouse activity. I suspect that would be overkill and it would degrade performance.

class Randomizor<T>
{
public Randomizor()
{
}
public List<T> Shuffle(List<T> toShuffle)
{
}
}

class Randomizer<T>
{
public Randomizer(ICollection<T> collection)
{
//Do something with collection using T as the type of the elements
}
}
However you may want to go for a generic extension method
static class Randomizer
{
public static void Randomize<T>(this ICollection<T> collection)
{
//randomize the collection
}
}
and the usage:
List<int> list = new List<int> { 1, 2, 3, 4, 5 };
list.Randomize();

Maybe like this:
public List<T> Shuffle<T>(List<T> toShuffle)
{
return toShuffle.OrderBy(x => Guid.NewGuid()).ToList();
}
Or as an extension method
public static class Extensions
{
public static List<T> Shuffle<T>(this List<T> toShuffle)
{
return toShuffle.OrderBy(x => Guid.NewGuid()).ToList();
}
}

Related

concrete implemantation of IEnumerable<T> that is not ICollection<T>

I would like to know if any of the classes in the .net framework that implement IEnumerable doesn't implement the ICollection interface.
I'm asking it because I can't get 100% code coverage in the following extension method that I wrote:
public static int GetSafeCount<T>(this IEnumerable<T> nullableCollaction)
{
if (nullableCollaction == null)
{
return 0;
}
var collection = nullableCollaction as ICollection<T>;
if (collection != null)
{
return collection.Count;
}
return nullableCollaction.Count();
}
The last line is not covered in any of my tests and I can't find the correct class to instantiate in order to cover it.
my test code is:
[Test]
public void GetSafeCount_NullObject_Return0()
{
IEnumerable<string> enumerable=null;
Assert.AreEqual(0, enumerable.GetSafeCount());
}
[Test]
public void GetSafeCount_NonICollectionObject_ReturnCount()
{
IEnumerable<string> enumerable = new string[]{};
Assert.AreEqual(0, enumerable.GetSafeCount());
}
Just use any LINQ operation, e.g. Where:
[Test]
public void GetSafeCount_NonICollectionObject_ReturnCount()
{
IEnumerable<string> enumerable = new string[0].Where(x => x.Length == 0);
Assert.AreEqual(0, enumerable.GetSafeCount());
}
However, you can simplify your implementation by just deferring to Enumerable.Count(), which I'd expect to be optimized every way you'd like it to be:
public static int GetSafeCount<T>(this IEnumerable<T> nullableCollection)
=> nullableCollection == null ? 0 : nullableCollection.Count();
Or:
public static int GetSafeCount<T>(this IEnumerable<T> nullableCollection)
=> nullableCollection?.Count() ?? 0;
(Both assume C# 6...)
At that point, it makes sense to only have two tests: one for a null argument, one for a non-null argument.
You can use the Stack<T> class, it implements ICollection and IEnumerable<T> but not ICollection<T>.
Here is how the class is defined:
public class Stack<T> : IEnumerable<T>, IEnumerable, ICollection,
IReadOnlyCollection<T>
He's an example of a IEnumerable<T> that is not a ICollection<T>:
public class MyClass : IEnumerable<int>
{
public List<int> ints = new List<int> { 1, 2, 3, 4, 5 };
public IEnumerator<int> GetEnumerator()
{
foreach (var i in ints)
{
yield return i;
}
}
IEnumerator IEnumerable.GetEnumerator()
{
return this as IEnumerator;
}
}
Now you can do this:
foreach(var item in new MyClass())
{
// do something
}
But can't do this, since it's not an ICollection
var coll = new MyClass() as ICollection<int>; // null!!!

C# Enumerable.Take with default value

What is the best way to get exactly x values from an Enumerable in C#.
If i use Enumerable .Take() like this:
var myList = Enumerable.Range(0,10);
var result = myList.Take(20);
The result will only have 10 elements.
I want to fill the missing entries with a default value.
Something like this:
var myList = Enumerable.Range(0,10);
var result = myList.TakeOrDefault(20, default(int)); //Is there anything like this?
Is there such a function in C# and if not, what would be the best way to achieve this?
You could do something like:
var result = myList.Concat(Enumerable.Repeat(default(int), 20)).Take(20);
And it would be easy to turn this into an extension method:
public static IEnumerable<T> TakeOrDefault<T>(this IEnumerable<T> list, int count, T defaultValue)
{
return list.Concat(Enumerable.Repeat(defaultValue, count)).Take(count);
}
But there is a subtle gotcha here. This would work perfectly fine for value types, for a reference type, if your defaultValue isn't null, you are adding the same object multiple times. Which probably isn't want you want. For example, if you had this:
var result = myList.TakeOrDefault(20, new Foo());
You are going to add the same instance of Foo to pad your collection. To solve that problem, you'd need something like this:
public static IEnumerable<T> TakeOrDefault<T>(this IEnumerable<T> list, int count, Func<T> defaultFactory)
{
return list.Concat(Enumerable.Range(0, count).Select(i => defaultFactory())).Take(count);
}
Which you'd call like this:
var result = myList.TakeOrDefault(20, () => new Foo())
Of course, both methods can co-exist, so you could easily have:
// pad a list of ints with zeroes
var intResult = myIntList.TakeOrDefault(20, default(int));
// pad a list of objects with null
var objNullResult = myObjList.TakeOrDefault(20, (object)null);
// pad a list of Foo with new (separate) instances of Foo
var objPadNewResult = myFooList.TakeOrDefault(20, () => new Foo());
Its not there by default, but it's easy enough to write as an extension method
public static IEnumerable<T> TakeOrDefault<T>(this IEnumerable<T> items, int count, T defaultValue)
{
var i = 0;
foreach(var item in items)
{
i++;
yield return item;
if(i == count)
yield break;
}
while(i++<count)
{
yield return defaultValue;
}
}
Live example: http://rextester.com/XANF91263
What you're looking for is a general-purpose PadTo method, which extends the collection's length if needed using a given value.
public static IEnumerable<T> PadTo<T>(this IEnumerable<T> source, int len)
{
return source.PadTo(len, default(T));
}
public static IEnumerable<T> PadTo<T>(this IEnumerable<T> source, int len, T elem)
{
return source.PadTo(len, () => elem);
}
public static IEnumerable<T> PadTo<T>(this IEnumerable<T> source, int len, Func<T> elem)
{
int i = 0;
foreach(var t in source)
{
i++;
yield return t;
}
while(i++ < len)
yield return elem();
}
You can now express:
myList.Take(20).PadTo(20);
This is analogous to Scala's List[A].padTo
You could use Concat for this purpose. You can use a simple helper method to join this all together:
public IEnumerable<T> TakeSpawn(this IEnumerable<T> #this, int take, T defaultElement)
{
return #this.Concat(Enumerable.Repeat(defaultElement, take)).Take(take);
}
The idea is that you always append another enumerable on the end of the original enumerable, so if the input doesn't have enough elements, it will start enumerating from the Repeat.
There isn't anything in the .NET Framework, not that I'm aware of. This can be achieved easily using an extension method though and it works for all types if you supply a default value yourself:
public static class ListExtensions
{
public static IEnumerable<T> TakeOrDefault<T>(this List<T> list, int count, T defaultValue)
{
int missingItems = count - list.Count;
List<T> extra = new List<T>(missingItems);
for (int i = 0; i < missingItems; i++)
extra.Add(defaultValue);
return list.Take(count).Concat(extra);
}
}
I wrote a quick extension for this which depends on T being a value type.
public static class Extensions
{
public static IEnumerable<T> TakeOrDefault<T>(this IEnumerable<T> list, int totalElements)
{
List<T> finalList = list.ToList();
if (list.Count() < totalElements)
{
for (int i = list.Count(); i < totalElements; i++)
{
finalList.Add(Activator.CreateInstance<T>());
}
}
return finalList;
}
}
Why not just write an extension method that checks the count and returns the default value for remaining entries:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication3
{
class Program
{
static void Main(string[] args)
{
List<int> values = new List<int>{1, 2, 3, 4};
IEnumerable<int> moreValues = values.TakeOrDefault(3, 100);
Console.WriteLine(moreValues.Count());
moreValues = values.TakeOrDefault(4, 100);
Console.WriteLine(moreValues.Count());
moreValues = values.TakeOrDefault(10, 100);
Console.WriteLine(moreValues.Count());
}
}
public static class ExtensionMethods
{
public static IEnumerable<T> TakeOrDefault<T>(this IEnumerable<T> enumerable, int count, T defaultValue)
{
int returnedCount = 0;
foreach (T variable in enumerable)
{
returnedCount++;
yield return variable;
if (returnedCount == count)
{
yield break;
}
}
if (returnedCount < count)
{
for (int i = returnedCount; i < count; i++)
{
yield return defaultValue;
}
}
}
}
}

Non-0 based arrays in C# with traditional [ ] array syntax?

I'd like to be able to create an array in C# with an arbitrary range of index bounds, e.g., a 16 element array with indices of 100-115.
Native arrays in C# are 0-based, but I'm told (e.g., in Luaan's comment here), that the C# Array class allows arbitrary lower and upper bounds. But in the examples I've seen elements in the Array class are accessed via myArray.GetValue() and myArray.SetValue() instead of conventional array syntax like myArray [ foo ].
Array arr = Array.CreateInstance(typeof(string), new[]{16}, new[]{100});
Console.WriteLine(arr.Length); // 16
arr.SetValue("foo", 100);
Console.WriteLine(arr.GetValue(100)); // foo
Is there any way to make an array with some arbitrary starting index, like [100] that I can access with traditional [ ] syntax in C#?
You could create a class that implements the decorator pattern: just implement the IList interface (wich is also implemented by Array) and do whatever shifting you want on the this [int index] property.
The decorator pattern is described here:
http://www.codeproject.com/Articles/479635/UnderstandingplusandplusImplementingplusDecoratorp
The Array class does not support this, but you can write your own array class with one-based indices:
public class OneBasedArray<T>
{
public T[] InnerArray;
public T this[int i]
{
get { return InnerArray[i-1]; }
set { InnerArray[i-1] = value; }
}
}
And then use it like this:
var myArray = new OneBasedArray<int> { InnerArray = new int[]{ 1, 2, 3, 4, 5 } };
for(int i = 1; i <=5; i++)
{
Console.WriteLine(myArray[i]);
}
This code is only to get the idea, such a class would of course need a nicer interface.
You can only use an array's indexer when it's a 0-indexed array.
You can use an indexer for a custom, non-array, type, and use whatever logic you want for it, such as making it non-zero-indexed, but that's not an option for arrays.
I think Lukas' answer is probably the easiest way to handle this, but if, for some reason, you really wanted to use Array.CreateInstance (not sure why you would - maybe some external library might insist on it?), you could wrap it in a class like this:
public class NonZeroArray<T>
{
private readonly Array array;
public T this[int i]
{
get { return (T)array.GetValue(i); }
set { array.SetValue(value, i); }
}
public NonZeroArray(int length, int lowerBounds = 0)
{
array = Array.CreateInstance(typeof(T), new int[] { length}, new int[] { lowerBounds } );
}
}
You could obviously make this a lot prettier (and easier to work with) by having it implement the rest of IList<T>. And if you really need the native array, you could implement a property with a getter to expose it when needed.
Using it would be simply:
var myNonZeroArray = new NonZeroArray<string>(16,100);
myNonZeroArray[100] = "foo";
Console.WriteLine(myNonZeroArray[100]); // prints "foo"
Here's a custom class that extends IList<T> to provide functionality for starting at a non-zero index:
public class NonZeroList<T> : IList<T>
{
private int startIndex;
private List<T> inner;
public NonZeroList(int startIndex, IEnumerable<T> content)
{
this.startIndex = startIndex;
inner = content.ToList();
}
public NonZeroList(int startIndex)
{
this.startIndex = startIndex;
inner = new List<T>();
}
public T this[int i]
{
get
{
return inner[i - startIndex];
}
set
{
inner[i - startIndex] = value;
}
}
public IEnumerator<T> GetEnumerator()
{
foreach (T i in inner)
yield return i;
yield break;
}
System.Collections.IEnumerator System.Collections.IEnumerable.GetEnumerator()
{
return inner.GetEnumerator();
}
public int IndexOf(T item)
{
return inner.IndexOf(item) + startIndex;
}
public void Insert(int index, T item)
{
inner.Insert(index - startIndex, item);
}
public void RemoveAt(int index)
{
inner.RemoveAt(index - startIndex);
}
public void Add(T item)
{
inner.Add(item);
}
public void Clear()
{
inner.Clear();
}
public bool Contains(T item)
{
return inner.Contains(item);
}
public void CopyTo(T[] array, int arrayIndex)
{
inner.CopyTo(array, arrayIndex);
}
public int Count
{
get { return inner.Count; }
}
public bool IsReadOnly
{
get { return false; }
}
public bool Remove(T item)
{
return inner.Remove(item);
}
}
To use it, you initialize it just as you would a normal List<T>, but with the start index specified (e.g. NonZeroList<int> myList = new NonZeroList<int>(20) { 0, 1, 2, 3 };). You can then use it just as you would a normal List<T> or T[].
If you want to use it as an array instead of a list, then you can simply add bounds checking or implement IEnumerable<T> instead of IList<T>, and create utility functions yourself.

How should I use properties when dealing with read-only List<T> members

When I want to make a value type read-only outside of my class I do this:
public class myClassInt
{
private int m_i;
public int i {
get { return m_i; }
}
public myClassInt(int i)
{
m_i = i;
}
}
What can I do to make a List<T> type readonly (so they can't add/remove elements to/from it) outside of my class? Now I just declare it public:
public class myClassList
{
public List<int> li;
public myClassList()
{
li = new List<int>();
li.Add(1);
li.Add(2);
li.Add(3);
}
}
You can expose it AsReadOnly. That is, return a read-only IList<T> wrapper. For example ...
public ReadOnlyCollection<int> List
{
get { return _lst.AsReadOnly(); }
}
Just returning an IEnumerable<T> is not sufficient. For example ...
void Main()
{
var el = new ExposeList();
var lst = el.ListEnumerator;
var oops = (IList<int>)lst;
oops.Add( 4 ); // mutates list
var rol = el.ReadOnly;
var oops2 = (IList<int>)rol;
oops2.Add( 5 ); // raises exception
}
class ExposeList
{
private List<int> _lst = new List<int>() { 1, 2, 3 };
public IEnumerable<int> ListEnumerator
{
get { return _lst; }
}
public ReadOnlyCollection<int> ReadOnly
{
get { return _lst.AsReadOnly(); }
}
}
Steve's answer also has a clever way to avoid the cast.
There is limited value in attempting to hide information to such an extent. The type of the property should tell users what they're allowed to do with it. If a user decides they want to abuse your API, they will find a way. Blocking them from casting doesn't stop them:
public static class Circumventions
{
public static IList<T> AsWritable<T>(this IEnumerable<T> source)
{
return source.GetType()
.GetFields(BindingFlags.Public |
BindingFlags.NonPublic |
BindingFlags.Instance)
.Select(f => f.GetValue(source))
.OfType<IList<T>>()
.First();
}
}
With that one method, we can circumvent the three answers given on this question so far:
List<int> a = new List<int> {1, 2, 3, 4, 5};
IList<int> b = a.AsReadOnly(); // block modification...
IList<int> c = b.AsWritable(); // ... but unblock it again
c.Add(6);
Debug.Assert(a.Count == 6); // we've modified the original
IEnumerable<int> d = a.Select(x => x); // okay, try this...
IList<int> e = d.AsWritable(); // no, can still get round it
e.Add(7);
Debug.Assert(a.Count == 7); // modified original again
Also:
public static class AlexeyR
{
public static IEnumerable<T> AsReallyReadOnly<T>(this IEnumerable<T> source)
{
foreach (T t in source) yield return t;
}
}
IEnumerable<int> f = a.AsReallyReadOnly(); // really?
IList<int> g = f.AsWritable(); // apparently not!
g.Add(8);
Debug.Assert(a.Count == 8); // modified original again
To reiterate... this kind of "arms race" can go on for as long as you like!
The only way to stop this is to completely break the link with the source list, which means you have to make a complete copy of the original list. This is what the BCL does when it returns arrays. The downside of this is that you are imposing a potentially large cost on 99.9% of your users every time they want readonly access to some data, because you are worried about the hackery of 00.1% of users.
Or you could just refuse to support uses of your API that circumvent the static type system.
If you want a property to return a read-only list with random access, return something that implements:
public interface IReadOnlyList<T> : IEnumerable<T>
{
int Count { get; }
T this[int index] { get; }
}
If (as is much more common) it only needs to be enumerable sequentially, just return IEnumerable:
public class MyClassList
{
private List<int> li = new List<int> { 1, 2, 3 };
public IEnumerable<int> MyList
{
get { return li; }
}
}
UPDATE Since I wrote this answer, C# 4.0 came out, so the above IReadOnlyList interface can take advantage of covariance:
public interface IReadOnlyList<out T>
And now .NET 4.5 has arrived and it has... guess what...
IReadOnlyList interface
So if you want to create a self-documenting API with a property that holds a read-only list, the answer is in the framework.
JP's answer regarding returning IEnumerable<int> is correct (you can down-cast to a list), but here is a technique that prevents the down-cast.
class ExposeList
{
private List<int> _lst = new List<int>() { 1, 2, 3 };
public IEnumerable<int> ListEnumerator
{
get { return _lst.Select(x => x); } // Identity transformation.
}
public ReadOnlyCollection<int> ReadOnly
{
get { return _lst.AsReadOnly(); }
}
}
The identity transformation during enumeration effectively creates a compiler-generated iterator - a new type which is not related to _lst in any way.
Eric Lippert has a series of articles on Immutability In C# on his blog.
The first article in the series can be found here.
You might also find useful Jon Skeet's answer to a similar question.
public List<int> li;
Don't declare public fields, it's generally considered bad practice... wrap it in a property instead.
You can expose your collection as a ReadOnlyCollection :
private List<int> li;
public ReadOnlyCollection<int> List
{
get { return li.AsReadOnly(); }
}
public class MyClassList
{
private List<int> _lst = new List<int>() { 1, 2, 3 };
public IEnumerable<int> ListEnumerator
{
get { return _lst.AsReadOnly(); }
}
}
To check it
MyClassList myClassList = new MyClassList();
var lst= (IList<int>)myClassList.ListEnumerator ;
lst.Add(4); //At this point ypu will get exception Collection is read-only.
public static IEnumerable<T> AsReallyReadOnly<T>(this IEnumerable<T> source)
{
foreach (T t in source) yield return t;
}
if I add to Earwicker's example
...
IEnumerable<int> f = a.AsReallyReadOnly();
IList<int> g = f.AsWritable(); // finally can't get around it
g.Add(8);
Debug.Assert(a.Count == 78);
I get InvalidOperationException: Sequence contains no matching element.

How to access random item in list?

I have an ArrayList, and I need to be able to click a button and then randomly pick out a string from that list and display it in a messagebox.
How would I go about doing this?
Create an instance of Random class somewhere. Note that it's pretty important not to create a new instance each time you need a random number. You should reuse the old instance to achieve uniformity in the generated numbers. You can have a static field somewhere (be careful about thread safety issues):
static Random rnd = new Random();
Ask the Random instance to give you a random number with the maximum of the number of items in the ArrayList:
int r = rnd.Next(list.Count);
Display the string:
MessageBox.Show((string)list[r]);
I usually use this little collection of extension methods:
public static class EnumerableExtension
{
public static T PickRandom<T>(this IEnumerable<T> source)
{
return source.PickRandom(1).Single();
}
public static IEnumerable<T> PickRandom<T>(this IEnumerable<T> source, int count)
{
return source.Shuffle().Take(count);
}
public static IEnumerable<T> Shuffle<T>(this IEnumerable<T> source)
{
return source.OrderBy(x => Guid.NewGuid());
}
}
For a strongly typed list, this would allow you to write:
var strings = new List<string>();
var randomString = strings.PickRandom();
If all you have is an ArrayList, you can cast it:
var strings = myArrayList.Cast<string>();
You can do:
list.OrderBy(x => Guid.NewGuid()).FirstOrDefault()
Or simple extension class like this:
public static class CollectionExtension
{
private static Random rng = new Random();
public static T RandomElement<T>(this IList<T> list)
{
return list[rng.Next(list.Count)];
}
public static T RandomElement<T>(this T[] array)
{
return array[rng.Next(array.Length)];
}
}
Then just call:
myList.RandomElement();
Works for arrays as well.
I would avoid calling OrderBy() as it can be expensive for larger collections. Use indexed collections like List<T> or arrays for this purpose.
Create a Random instance:
Random rnd = new Random();
Fetch a random string:
string s = arraylist[rnd.Next(arraylist.Count)];
Remember though, that if you do this frequently you should re-use the Random object. Put it as a static field in the class so it's initialized only once and then access it.
I'll suggest different approach, If the order of the items inside the list is not important at extraction (and each item should be selected only once), then instead of a List you can use a ConcurrentBag which is a thread-safe, unordered collection of objects:
var bag = new ConcurrentBag<string>();
bag.Add("Foo");
bag.Add("Boo");
bag.Add("Zoo");
The EventHandler:
string result;
if (bag.TryTake(out result))
{
MessageBox.Show(result);
}
The TryTake will attempt to extract an "random" object from the unordered collection.
Why not:
public static T GetRandom<T>(this IEnumerable<T> list)
{
return list.ElementAt(new Random(DateTime.Now.Millisecond).Next(list.Count()));
}
ArrayList ar = new ArrayList();
ar.Add(1);
ar.Add(5);
ar.Add(25);
ar.Add(37);
ar.Add(6);
ar.Add(11);
ar.Add(35);
Random r = new Random();
int index = r.Next(0,ar.Count-1);
MessageBox.Show(ar[index].ToString());
I have been using this ExtensionMethod for a while:
public static IEnumerable<T> GetRandom<T>(this IEnumerable<T> list, int count)
{
if (count <= 0)
yield break;
var r = new Random();
int limit = (count * 10);
foreach (var item in list.OrderBy(x => r.Next(0, limit)).Take(count))
yield return item;
}
I needed to more item instead of just one. So, I wrote this:
public static TList GetSelectedRandom<TList>(this TList list, int count)
where TList : IList, new()
{
var r = new Random();
var rList = new TList();
while (count > 0 && list.Count > 0)
{
var n = r.Next(0, list.Count);
var e = list[n];
rList.Add(e);
list.RemoveAt(n);
count--;
}
return rList;
}
With this, you can get elements how many you want as randomly like this:
var _allItems = new List<TModel>()
{
// ...
// ...
// ...
}
var randomItemList = _allItems.GetSelectedRandom(10);
Printing randomly country name from JSON file.
Model:
public class Country
{
public string Name { get; set; }
public string Code { get; set; }
}
Implementaton:
string filePath = Path.GetFullPath(Path.Combine(Environment.CurrentDirectory, #"..\..\..\")) + #"Data\Country.json";
string _countryJson = File.ReadAllText(filePath);
var _country = JsonConvert.DeserializeObject<List<Country>>(_countryJson);
int index = random.Next(_country.Count);
Console.WriteLine(_country[index].Name);
Why not[2]:
public static T GetRandom<T>(this List<T> list)
{
return list[(int)(DateTime.Now.Ticks%list.Count)];
}

Categories

Resources