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Find pattern to solve regex in one step

I have a problem to find the pattern that solves the problem in onestep.
The string looks like this:
Text1
Text1$Text2$Text3
Text1$Text2$Text3$Text4$Text5$Text6 etc.
What i want to get is: Take up to 4x Text. If there are more than "4xText" take only the last sign.
Example:
Text1$Text2$Text3$Text4$Text5$Text6 -> Text1$Text2$Text3$Text4&56
My current solution is:
First pattern:
^([^\$]*)\$?([^\$]*)\$?([^\$]*)\$?([^\$]*)\$?
After this i will do a substitution with the first pattern
New string: Text5$Text6
second pattern is:
([^\$])\b
result: 56
combine both and get the result:
Text1$Text2$Text3$Text4$56
For me it is not clear why i cant easily put the second pattern after the first pattern into one pattern. Is there something like an anchor that tells the engine to start the pattern from here like it would do if is would be the only pattern ?

You might use an alternation with a positive lookbehind and then concatenate the matches.
(?<=^(?:[^$]+\$){0,3})[^$]+\$?|[^$](?=\$|$)
Explanation
(?<= Positive lookbehind, assert what is on the left is
^(?:[^$]+\$){0,3} Match 0-3 times any char except $ followed by an optional $
) Close lookbehind
[^$]+\$? Match 1+ times any char except $, then match an optional $
| Or
[^$] Match any char except $
(?=\$|$) Positive lookahead, assert what is directly to the right is either $ or the end of the string
.NET regex demo | C# demo
Example
string pattern = #"(?<=^(?:[^$]*\$){0,3})[^$]*\$?|[^$](?=\$|$)";
string[] strings = {
"Text1",
"Text1$Text2$Text3",
"Text1$Text2$Text3$Text4$Text5$Text6"
};
Regex regex = new Regex(pattern);
foreach (String s in strings) {
Console.WriteLine(string.Join("", from Match match in regex.Matches(s) select match.Value));
}
Output
Text1
Text1$Text2$Text3
Text1$Text2$Text3$Text4$56

I strongly believe regular expression isn't the way to do that. Mostly because of the readability.
You may consider using simple algorithm like this one to reach your goal:
using System;
public class Program
{
public static void Main()
{
var input = "Text1$Text2$Text3$Text4$Text5$Text6";
var parts = input.Split('$');
var result = "";
for(var i=0; i<parts.Length; i++){
result += (i <= 4 ? parts[i] + "$" : parts[i].Substring(4));
}
Console.WriteLine(result);
}
}
There are also linq alternatives :
using System;
using System.Linq;
public class Program
{
public static void Main()
{
var input = "Text1$Text2$Text3$Text4$Text5$Text6";
var parts = input.Split('$');
var first4 = parts.Take(4);
var remainings = parts.Skip(4);
var result2 = string.Join("$", first4) + "$" + string.Join("", remainings.Select( r=>r.Substring(4)));
Console.WriteLine(result2);
}
}
It has to be adjusted to the actual needs but the idea is there

Try this code:
var texts = new string[] {"Text1", "Text1$Text2$Text3", "Text1$Text2$Text3$Text4$Text5$Text6" };
var parsed = texts
.Select(s => Regex.Replace(s,
#"(Text\d{1,3}(?:\$Text\d{1,3}){0,3})((?:\$Text\d{1,3})*)",
(match) => match.Groups[1].Value +"$"+ match.Groups[2].Value.Replace("Text", "").Replace("$", "")
)).ToArray();
// parsed is now: string[3] { "Text1$", "Text1$Text2$Text3$", "Text1$Text2$Text3$Text4$56" }
Explanation:
solution uses regex pattern: (Text\d{1,3}(?:\$Text\d{1,3}){0,3})((?:\$Text\d{1,3})*)
(...) - first capturing group
(?:...) - non-capturing group
Text\d{1,3}(?:\$Text\d{1,3} - match Text literally, then match \d{1,3}, which is 1 up to three digits, \$ matches $ literally
Rest is just repetition of it. Basically, first group captures first four pieces, second group captures the rest, if any.
We also use MatchEvaluator here which is delegate type defined as:
public delegate string MatchEvaluator(Match match);
We define such method:
(match) => match.Groups[1].Value +"$"+ match.Groups[2].Value.Replace("Text", "").Replace("$", "")
We use it to evaluate match, so takee first capturing group and concatenate with second, removing unnecessary text.

It's not clear to me whether your goal can be achieved using exclusively regex. If nothing else, the fact that you want to introduce a new character '&' into the output adds to the challenge, since just plain matching would never be able to accomplish that. Possibly using the Replace() method? I'm not sure that would work though...using only a replacement pattern and not a MatchEvaluator, I don't see a way to recognize but still exclude the "$Text" portion from the fifth instance and later.
But, if you are willing to mix regex with a small amount of post-processing, you can definitely do it:
static readonly Regex regex1 = new Regex(#"(Text\d(?:\$Text\d){0,3})(?:\$Text(\d))*", RegexOptions.Compiled);
static void Main(string[] args)
{
for (int i = 1; i <= 6; i++)
{
string text = string.Join("$", Enumerable.Range(1, i).Select(j => $"Text{j}"));
WriteLine(KeepFour(text));
}
}
private static string KeepFour(string text)
{
Match match = regex1.Match(text);
if (!match.Success)
{
return "[NO MATCH]";
}
StringBuilder result = new StringBuilder();
result.Append(match.Groups[1].Value);
if (match.Groups[2].Captures.Count > 0)
{
result.Append("&");
// Have to iterate (join), because we don't want the whole match,
// just the captured text.
result.Append(JoinCaptures(match.Groups[2]));
}
return result.ToString();
}
private static string JoinCaptures(Group group)
{
return string.Join("", group.Captures.Cast<Capture>().Select(c => c.Value));
}
The above breaks your requirement into three different capture groups in a regex. Then it extracts the captured text, composing the result based on the results.

Remove String After Determinate String

I need to remove certain strings after another string within a piece of text.
I have a text file with some URLs and after the URL there is the RESULT of an operation. I need to remove the RESULT of the operation and leave only the URL.
Example of text:
http://website1.com/something Result: OK(registering only mode is on)
http://website2.com/something Result: Problems registered 100% (SOMETHING ELSE) Other Strings;
http://website3.com/something Result: error: "Âíèìàíèå, îáíàðóæåíà îøèáêà - Ìåñòî æèòåëüñòâà ñîäåðæèò íåäîïóñòèìûå ê
I need to remove all strings starting from Result: so the remaining strings have to be:
http://website1.com/something
http://website2.com/something
http://website3.com/something
Without Result: ........
The results are generated randomly so I don't know exactly what there is after RESULT:

One option is to use regular expressions as per some other answers. Another is just IndexOf followed by Substring:
int resultIndex = text.IndexOf("Result:");
if (resultIndex != -1)
{
text = text.Substring(0, resultIndex);
}
Personally I tend to find that if I can get away with just a couple of very simple and easy to understand string operations, I find that easier to get right than using regex. Once you start going into real patterns (at least 3 of these, then one of those) then regexes become a lot more useful, of course.

string input = "Action2 Result: Problems registered 100% (SOMETHING ELSE) Other Strings; ";
string pattern = "^(Action[0-9]*) (.*)$";
string replacement = "$1";
Regex rgx = new Regex(pattern);
string result = rgx.Replace(input, replacement);
You use $1 to keep the match ActionXX.

Use Regex for this.
Example:
var r = new System.Text.RegularExpressions.Regex("Result:(.)*");
var result = r.Replace("Action Result:1231231", "");
Then you will have "Action" in the result.

You can try with this code - by using string.Replace
var pattern = "Result:";
var lineContainYourValue = "jdfhkjsdfhsdf Result:ljksdfljh"; //I want replace test
lineContainYourValue.Replace(pattern,"");

Something along the lines of this perhaps?
string line;
using ( var reader = new StreamReader ( File.Open ( #"C:\temp\test.txt", FileMode.Open ) ) )
using ( var sw = new StreamWriter(File.Open( #"C:\Temp\test.edited.txt", FileMode.CreateNew ) ))
while ( (line = reader.ReadLine()) != null )
if(!line.StartsWith("Result:")) sw.WriteLine(line);

You can use RegEx for this kind of processing.
using System.Text.RegularExpressions;
private string ParseString(string originalString)
{
string pattern = ".*(?=Result:.*)";
Match match = Regex.Match(originalString, pattern);
return match.Value;
}

A Linq approach:
IEnumerable<String> result = System.IO.File
.ReadLines(path)
.Where(l => l.StartsWith("Action") && l.Contains("Result"))
.Select(l => l.Substring(0, l.IndexOf("Result")));

Given your current example, where you want only the website, regex match the spaces.
var fileLine = "http://example.com/sub/ random text";
Regex regexPattern = new Regex("(.*?)\\s");
var websiteMatch = regexPattern.Match(fileLine).Groups[1].ToString();
Debug.Print("!" + websiteMatch + "!");
Repeating for each line in your text file. Regex explained: .* matches anything, ? makes the match ungreedy, (brackets) puts the match into a group, \\s matches whitespace.

Parse and replace string using Regex

i have various strings that look like that:
$(gateway.jms.jndi.ic.url,0,tibjmsnaming, tcp)/topic/$(gateway.destination.prefix)$(gateway.StatusTopicName),$(gateway.jms.jndi.ic.username),$(gateway.jms.jndi.ic.password),abinding,tBinding
i'm trying to figure out a way to extract the $(...) sections and replace them with some other string.
is there anyway in C# to parse those groups and replace one by one with another string?
Thanks

This regular expression will capture those sections:
\$\([^)]+\)
Then replace like this (this example changes each match to it's uppercase equivalent - you can add whatever custom logic you wish):
Regex.Replace(candidate, #"\$\([^)]+\)", delegate(Match m) {
return m.ToString().ToUpper();
});

I am not so good with delegate.s Here is what i came up with using Andrew's regex:
string test1 = #"$(gateway.jms.jndi.ic.url,0,tibjmsnaming, tcp)/topic/$(gateway.destination.prefix)$(gateway.StatusTopicName),$(gateway.jms.jndi.ic.username),$(gateway.jms.jndi.ic.password),abinding,tBinding";
string regex1 = #"\$\([^)]+\)";
var matches = Regex.Matches(test1, regex1);
Console.WriteLine(matches.Count);
foreach (Match match in matches)
{
test1 = test1.Replace(match.Value, "your String");
}
Console.WriteLine(test1);

How can I find a string after a specific string/character using regex

I am hopeless with regex (c#) so I would appreciate some help:
Basicaly I need to parse a text and I need to find the following information inside the text:
Sample text:
KeywordB:***TextToFind* the rest is not relevant but **KeywordB: Text ToFindB and then some more text.
I need to find the word(s) after a certain keyword which may end with a “:”.
[UPDATE]
Thanks Andrew and Alan: Sorry for reopening the question but there is quite an important thing missing in that regex. As I wrote in my last comment, Is it possible to have a variable (how many words to look for, depending on the keyword) as part of the regex?
Or: I could have a different regex for each keyword (will only be a hand full). But still don't know how to have the "words to look for" constant inside the regex

The basic regex is this:
var pattern = #"KeywordB:\s*(\w*)";
\s* = any number of spaces
\w* = 0 or more word characters (non-space, basically)
() = make a group, so you can extract the part that matched
var pattern = #"KeywordB:\s*(\w*)";
var test = #"KeywordB: TextToFind";
var match = Regex.Match(test, pattern);
if (match.Success) {
Console.Write("Value found = {0}", match.Groups[1]);
}
If you have more than one of these on a line, you can use this:
var test = #"KeywordB: TextToFind KeyWordF: MoreText";
var matches = Regex.Matches(test, #"(?:\s*(?<key>\w*):\s?(?<value>\w*))");
foreach (Match f in matches ) {
Console.WriteLine("Keyword '{0}' = '{1}'", f.Groups["key"], f.Groups["value"]);
}
Also, check out the regex designer here: http://www.radsoftware.com.au/. It is free, and I use it constantly. It works great to prototype expressions. You need to rearrange the UI for basic work, but after that it's easy.
(fyi) The "#" before strings means that \ no longer means something special, so you can type #"c:\fun.txt" instead of "c:\fun.txt"

Let me know if I should delete the old post, but perhaps someone wants to read it.
The way to do a "words to look for" inside the regex is like this:
regex = #"(Key1|Key2|Key3|LastName|FirstName|Etc):"
What you are doing probably isn't worth the effort in a regex, though it can probably be done the way you want (still not 100% clear on requirements, though). It involves looking ahead to the next match, and stopping at that point.
Here is a re-write as a regex + regular functional code that should do the trick. It doesn't care about spaces, so if you ask for "Key2" like below, it will separate it from the value.
string[] keys = {"Key1", "Key2", "Key3"};
string source = "Key1:Value1Key2: ValueAnd A: To Test Key3: Something";
FindKeys(keys, source);
private void FindKeys(IEnumerable<string> keywords, string source) {
var found = new Dictionary<string, string>(10);
var keys = string.Join("|", keywords.ToArray());
var matches = Regex.Matches(source, #"(?<key>" + keys + "):",
RegexOptions.IgnoreCase);
foreach (Match m in matches) {
var key = m.Groups["key"].ToString();
var start = m.Index + m.Length;
var nx = m.NextMatch();
var end = (nx.Success ? nx.Index : source.Length);
found.Add(key, source.Substring(start, end - start));
}
foreach (var n in found) {
Console.WriteLine("Key={0}, Value={1}", n.Key, n.Value);
}
}
And the output from this is:
Key=Key1, Value=Value1
Key=Key2, Value= ValueAnd A: To Test
Key=Key3, Value= Something

/KeywordB\: (\w)/
This matches any word that comes after your keyword. As you didn´t mentioned any terminator, I assumed that you wanted only the word next to the keyword.

How can I strip punctuation from a string?

For the hope-to-have-an-answer-in-30-seconds part of this question, I'm specifically looking for C#
But in the general case, what's the best way to strip punctuation in any language?
I should add: Ideally, the solutions won't require you to enumerate all the possible punctuation marks.
Related: Strip Punctuation in Python

new string(myCharCollection.Where(c => !char.IsPunctuation(c)).ToArray());

Why not simply:
string s = "sxrdct?fvzguh,bij.";
var sb = new StringBuilder();
foreach (char c in s)
{
if (!char.IsPunctuation(c))
sb.Append(c);
}
s = sb.ToString();
The usage of RegEx is normally slower than simple char operations. And those LINQ operations look like overkill to me. And you can't use such code in .NET 2.0...

Describes intent, easiest to read (IMHO) and best performing:
s = s.StripPunctuation();
to implement:
public static class StringExtension
{
public static string StripPunctuation(this string s)
{
var sb = new StringBuilder();
foreach (char c in s)
{
if (!char.IsPunctuation(c))
sb.Append(c);
}
return sb.ToString();
}
}
This is using Hades32's algorithm which was the best performing of the bunch posted.

Assuming "best" means "simplest" I suggest using something like this:
String stripped = input.replaceAll("\\p{Punct}+", "");
This example is for Java, but all sufficiently modern Regex engines should support this (or something similar).
Edit: the Unicode-Aware version would be this:
String stripped = input.replaceAll("\\p{P}+", "");
The first version only looks at punctuation characters contained in ASCII.

You can use the regex.replace method:
replace(YourString, RegularExpressionWithPunctuationMarks, Empty String)
Since this returns a string, your method will look something like this:
string s = Regex.Replace("Hello!?!?!?!", "[?!]", "");
You can replace "[?!]" with something more sophiticated if you want:
(\p{P})
This should find any punctuation.

This thread is so old, but I'd be remiss not to post a more elegant (IMO) solution.
string inputSansPunc = input.Where(c => !char.IsPunctuation(c)).Aggregate("", (current, c) => current + c);
It's LINQ sans WTF.

Based off GWLlosa's idea, I was able to come up with the supremely ugly, but working:
string s = "cat!";
s = s.ToCharArray().ToList<char>()
.Where<char>(x => !char.IsPunctuation(x))
.Aggregate<char, string>(string.Empty, new Func<string, char, string>(
delegate(string s, char c) { return s + c; }));

The most braindead simple way of doing it would be using string.replace
The other way I would imagine is a regex.replace and have your regular expression with all the appropriate punctuation marks in it.

Here's a slightly different approach using linq. I like AviewAnew's but this avoids the Aggregate
string myStr = "Hello there..';,]';';., Get rid of Punction";
var s = from ch in myStr
where !Char.IsPunctuation(ch)
select ch;
var bytes = UnicodeEncoding.ASCII.GetBytes(s.ToArray());
var stringResult = UnicodeEncoding.ASCII.GetString(bytes);

If you want to use this for tokenizing text you can use:
new string(myText.Select(c => char.IsPunctuation(c) ? ' ' : c).ToArray())

For anyone who would like to do this via RegEx:
This code shows the full RegEx replace process and gives a sample Regex that only keeps letters, numbers, and spaces in a string - replacing ALL other characters with an empty string:
//Regex to remove all non-alphanumeric characters
System.Text.RegularExpressions.Regex TitleRegex = new
System.Text.RegularExpressions.Regex("[^a-z0-9 ]+",
System.Text.RegularExpressions.RegexOptions.IgnoreCase);
string ParsedString = TitleRegex.Replace(stringToParse, String.Empty);
return ParsedString;

I faced the same issue and was concerned about the performance impact of calling the IsPunctuation for every single check.
I found this post: http://www.dotnetperls.com/char-ispunctuation.
Accross the lines: char.IsPunctuation also handles Unicode on top of ASCII.
The method matches a bunch of characters including control characters. By definiton, this method is heavy and expensive.
The bottom line is that I finally didn't go for it because of its performance impact on my ETL process.
I went for the custom implemetation of dotnetperls.
And jut FYI, here is some code deduced from the previous answers to get the list of all punctuation characters (excluding the control ones):
var punctuationCharacters = new List<char>();
for (int i = char.MinValue; i <= char.MaxValue; i++)
{
var character = Convert.ToChar(i);
if (char.IsPunctuation(character) && !char.IsControl(character))
{
punctuationCharacters.Add(character);
}
}
var commaSeparatedValueOfPunctuationCharacters = string.Join("", punctuationCharacters);
Console.WriteLine(commaSeparatedValueOfPunctuationCharacters);
Cheers,
Andrew

$newstr=ereg_replace("[[:punct:]]",'',$oldstr);

For long strings I use this:
var normalized = input
.Where(c => !char.IsPunctuation(c))
.Aggregate(new StringBuilder(),
(current, next) => current.Append(next), sb => sb.ToString());
performs much better than using string concatenations (though I agree it's less intuitive).

This is simple code for removing punctuation from strings given by the user
Import required library
import string
Ask input from user in string format
strs = str(input('Enter your string:'))
for c in string.punctuation:
strs= strs.replace(c,"")
print(f"\n Your String without punctuation:{strs}")

#include<string>
#include<cctype>
using namespace std;
int main(int a, char* b[]){
string strOne = "H,e.l/l!o W#o#r^l&d!!!";
int punct_count = 0;
cout<<"before : "<<strOne<<endl;
for(string::size_type ix = 0 ;ix < strOne.size();++ix)
{
if(ispunct(strOne[ix]))
{
++punct_count;
strOne.erase(ix,1);
ix--;
}//if
}
cout<<"after : "<<strOne<<endl;
return 0;
}//main