Where and when to use "this" keyword [duplicate] - c#

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Closed 11 years ago.
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When do you use the “this” keyword?
Hi All,
I am just wondering when and where using the keyword is a MUST? Because sometimes if I dont "this" or even I delete "this" the program just runs fine. So what will happen if you dont use it? or if you USE it in a wrong place.
Some explict examples would be appriciated.

The this keyword is often used to disambiguate between member variables and local variables:
...
{
int variable = 10;
this.variable = 1; // modifies a member variable.
variable = 1; // modifies the local variable.
}
....
The other use of this is to pass a reference to the current object so:
....
DoSomethingWithAnObject( this );
....
Another use (Thanks to HadleyHope ) is to disambiguate when method parameters are assigned to member variables with the same name:
void Initialise( int variable )
{
this.variable = variable;
}

You can't use this when calling static members. The compiler will just not let you. When you use "this" you are explicitly calling the current instance. I like to prefix current instance members with "this" even if this is not mandatory but just for clarity. That way I distinguish local scope variables from members.
Cheers

Microsoft recommend using camelCase for member variables, i.e.
public class MyClass
{
private int myInt;
private void SetMyInt(int myInt)
{
this.myInt = myInt;
}
}
So if you didn't have the 'this' keyword, there would be confusion between the private member and the parameter.
Personally I prefer prefixing my private members with an underscore to avoid this confusion.
private int _myInt;
So the only real use I find for it is to pass a reference of the current object to something else
MyStaticClass.MyStaticMethod(this);

public class People{
private String name;
private int age;
public People(String name, int age){
this.name = name;
this.age = age; //use this to declare that the age is the field in People class
}
}
One way to use this, hope it can help you.

You can use this when you have a member variable and a local variable of the same name in the same scope - the "this" will then make clear which one you mean.
Consider this:
class Person
{
private string name;
public string Name
{
get
{
return name;
}
set
{
name = value;
}
}
public Person(string name)
{
this.name = name; // "this" is necessary here to disambiguate between the name passed in and the name field.
this.Name = name; // "this" is not necessary, as there is only one Name in scope.
Name = name; // See - works without "this".
}
}

Personally I use this whenever I'm accessing a member variable or method. 99% of the time it's not necessary, but I think it improves clarity and makes the code more readable - a quality well worth the extra effort of typing 4 characters and a dot.

This is a bit subjective, but if you are using a proper naming convention (I use _camelCase for member variables) you will never need to use this.
Except this exception: =)
When you want to call an extension method from inside the class that the extension method is for:
public class HomeController : Controller
{
public ActionResult Index()
{
// won't work
return MyCustomResult();
}
public ActionResult List()
{
// will work
return this.MyCustomResult();
}
}
public static class MyExtensions
{
public static MyResult MyCustomResult(this Controller instance)
{
return new SomeResult(instance.ActionName);
}
}

You don't have to use "this" keyword every time in your member method, it is useful in this case:
class human
{
private int age;
...
void func(int age)
{
this.age = age;
}
...
}
it can solve the confusion which age you mean

Related

Get property name C#

I have a class :
class Sample
{
...
}
and define a property like this:
Sample sampleParam =new Sample(...);
and have a function :
private void Func(Sample s)
{}
and use it like:
Func(sampleParam);
can I get the 's' name in the function? I mean can I get "sampleParam"(the name of param)?
It sounds odd; but I need the name of the passed param.
and sorry for this type of asking; I just wanted to ask my question as simple as possible
public string GetParamName(System.Reflection.MethodInfo method,int index)
{
string strParameterName = string.Empty;
if (method != null && method.GetParameters().Length > index)
strParameterName = method.GetParameters()[index].Name;
return retVal;
}
Yes there is a way to achieve this through Reflection...
You should never reference variable or property names from called methods - it's bad manners and bad design (mostly the latter).
There is nameof operator in C# 6.0, but it wasn't designed for this.
You could use expression trees, which would slightly change your syntax. If sampleParam is not a property but a variable, you can't really access it, because compiler does not store any references to that name in generated dll file.
This isn't exactly what you're asking for, but is perhaps closer to what you want, but you could take a look at System.Environment.StackTrace.
I think it is not possible to get the name for a variable which value is passed to a method. But there is the compiler service CallerMemberNameAttribute which copies the name of the caller method (here the get accessor of our property Name) to the calling method if not specified:
class Person {
static void Main(string[] args) {
Person bart = new Person();
bart.Name = "Bart";
Console.ReadKey();
}
private string _name;
public string Name {
get {
return _name;
} set {
_name = value;
PropertyChanged(); //no need to fill in `Name` here! :)
}
}
//automatically copy caller's name to `propertyName`, at compile time
private void PropertyChanged([CallerMemberName] string propertyName = "") {
object propertyValue = this.GetType().GetProperty(propertyName).GetValue(this);
Console.WriteLine("Property '" + propertyName + "' changed the value to '" + propertyValue + "'");
}
}
Prints:
Property 'Name' changed the value to 'Bart'
If you mean can you get the name 'sampleParam' from INSIDE func? The the answer is no. There is nameof() in C#6.0 but 'sampleParam' inside not in scope inside the func. The variable s (of type Sample) is crated and assigned a ref to sampleParam.
You can get the name "s" inside Func.
You can get the name "sampleParam" in the calling class (outside Func).
Example (available on dotnetfiddle)
using System;
public class Program
{
public static Sample sampleParam {get; set;} =new Sample();
public static void Main()
{
Console.WriteLine($"Name of property: {nameof(sampleParam)}");
Func(sampleParam);
}
private static void Func(Sample s)
{
Console.Write($"Name of parameter: {nameof(s)}");
}
}
public class Sample
{
}
Output:
Name of property: sampleParam
Name of parameter: s
Now this is a rather simplistic example. Func exists in the same class as sampleParam and there is only one property so one could derive the name but my assumption is despite your question stating it this way you are looking for a more generalized solution. The problem is that inside func the calling parameter name is not in scope. You could capture it via nameof in the calling method and pass it into func but you shouldn't that would be horrible code for a variety of reasons.
As described what you are doing is intentionally building fragile tightly coupled code which is something developers work very hard to prevent. The caller is not going to know the name of the parameter passed into func is important and shouldn't. This leads me to believe this an xy problem.

C# Get property value without creating instance?

Is it possible to get value without creating an instance ?
I have this class:
public class MyClass
{
public string Name{ get{ return "David"; } }
public MyClass()
{
}
}
Now I need get the value "David", without creating instance of MyClass.
Real answer: no. It's an instance property, so you can only call it on an instance. You should either create an instance, or make the property static as shown in other answers.
See MSDN for more information about the difference between static and instance members.
Tongue-in-cheek but still correct answer:
Is it possible to get value without creating an instance ?
Yes, but only via some really horrible code which creates some IL passing in null as this (which you don't use in your property), using a DynamicMethod. Sample code:
// Jon Skeet explicitly disclaims any association with this horrible code.
// THIS CODE IS FOR FUN ONLY. USING IT WILL INCUR WAILING AND GNASHING OF TEETH.
using System;
using System.Reflection.Emit;
public class MyClass
{
public string Name { get{ return "David"; } }
}
class Test
{
static void Main()
{
var method = typeof(MyClass).GetProperty("Name").GetGetMethod();
var dynamicMethod = new DynamicMethod("Ugly", typeof(string),
Type.EmptyTypes);
var generator = dynamicMethod.GetILGenerator();
generator.Emit(OpCodes.Ldnull);
generator.Emit(OpCodes.Call, method);
generator.Emit(OpCodes.Ret);
var ugly = (Func<string>) dynamicMethod.CreateDelegate(
typeof(Func<string>));
Console.WriteLine(ugly());
}
}
Please don't do this. Ever. It's ghastly. It should be trampled on, cut up into little bits, set on fire, then cut up again. Fun though, isn't it? ;)
This works because it's using call instead of callvirt. Normally the C# compiler would use a callvirt call even if it's not calling a virtual member because that gets null reference checking "for free" (as far as the IL stream is concerned). A non-virtual call like this doesn't check for nullity first, it just invokes the member. If you checked this within the property call, you'd find it's null.
EDIT: As noted by Chris Sinclair, you can do it more simply using an open delegate instance:
var method = typeof(MyClass).GetProperty("Name").GetGetMethod();
var openDelegate = (Func<MyClass, string>) Delegate.CreateDelegate
(typeof(Func<MyClass, string>), method);
Console.WriteLine(openDelegate(null));
(But again, please don't!)
You can make that property static
public static string Name{ get{ return "David"; } }
Usage:
MyClass.Name;
You requirements do seem strange, but I think you're looking for some kind of metadata. You can use an attribute to achieve this:
public class NameAttribute : Attribute {
public string Name { get; private set; }
public NameAttribute(string name) {
Name = name;
}
}
[Name("George")]
public class Dad {
public string Name {
get {
return NameGetter.For(this.GetType());
}
}
}
[Name("Frank")]
public class Son : Dad {
}
public static class NameGetter {
public static string For<T>() {
return For(typeof(T));
}
public static string For(Type type) {
// add error checking ...
return ((NameAttribute)type.GetCustomAttributes(typeof(NameAttribute), false)[0]).Name;
}
}
Now this code can get names with and without instances:
Console.WriteLine(new Dad().Name);
Console.WriteLine(new Son().Name);
Console.WriteLine(NameGetter.For<Dad>());
Console.WriteLine(NameGetter.For<Son>());
You can make your property static, as pointed out by many others.
public static string Name{ get{ return "David"; } }
Be aware that this means your instances of MyClass will no longer have their own Name property, since static members belong to the class, not the individual object instances of it.
Edit:
In a note, you mentioned that you want to override the Name property in subclasses. At the same time, you want to be able to access it at the class level (access it without creating an instance of your class).
For the static properties, you would simply create a new Name property in each class. Since they are static, you're always (almost always, yay reflection) going to access them using a specific class, so you'd be specifying which version of Name you want to get. If you want to try and hack polymorphism in there and get the name from any given subclass of MyClass, you could do so using reflection, but I wouldn't recommend doing so.
Using the example from your comment:
public class Dad
{
public static string Name { get { return "George"; }
}
public class Son : Dad
{
public static string Name { get{ return "Frank"; }
}
public static void Test()
{
Console.WriteLine(Dad.Name); // prints "George"
Console.WriteLine(Son.Name); // prints "Frank"
Dad actuallyASon = new Son();
PropertyInfo nameProp = actuallyASon.GetType().GetProperty("Name");
Console.WriteLine(nameProp.GetValue(actuallyASon, null)); // prints "Frank"
}
As a side note, since you are declaring a property that has only a getter and it is returning a constant value, I recommend possibly using a const or static readonly variable instead.
public const string Name = "David";
public static readonly string Name = "David";
Usage for both would be the same:
string name = MyClass.Name;
The main benefit (and drawback) of const is that all references to it are actually replaced by its value when the code is compiled. That means it will be a little faster, but if you ever change its value, you will need to recompile ALL code that references it.
Whenever you write C# code, always check if your method and property getter/setter code does anything at all with other instance members of the class. If they don't, be sure to apply the static keyword. Certainly the case here, it trivially solves your problem.
The reason I really post to this question is that there's a bit of language bias at work in some of the answers. The C# rule that you can't call an instance method on a null object is a specific C# language rule. It is without a doubt a very wise one, it really helps to troubleshoot NullReferenceExceptions, they are raised at the call site instead of somewhere inside of a method where it gets very hard to diagnose that the this reference is null.
But this is certainly not a requirement to the CLR, nor of every language that run on the CLR. In fact, even C# doesn't enforce it consistently, you can readily bypass it in an extension method:
public static class Extensions {
public static bool IsNullOrEmpty(this string obj) {
return obj != null && obj.Length > 0;
}
}
...
string s = null;
bool empty = s.IsNullOrEmpty(); // Fine
And using your property from a language that doesn't have the same rule works fine as well. Like C++/CLI:
#include "stdafx.h"
using namespace System;
using namespace ClassLibrary1; // Add reference
int main(array<System::String ^> ^args)
{
MyClass^ obj = nullptr;
String^ name = obj->Name; // Fine
Console::WriteLine(name);
return 0;
}
Create a static property:
public class MyClass
{
public static string Name { get { return "David"; } }
public MyClass()
{
}
}
Get it like so:
string name1 = MyClass.Name;
That is not possible. As Name is an instance property, you can only get its value if you have an instance.
Also, note that you are not talking about a parameter, but about a property.
Create a static class or a static property, and you don't have to explicitly instantiate it.

Why is this field declared as private and also readonly?

In the following code:
public class MovieRepository : IMovieRepository
{
private readonly IHtmlDownloader _downloader;
public MovieRepository(IHtmlDownloader downloader)
{
_downloader = downloader;
}
public Movie FindMovieById(string id)
{
var idUri = ...build URI...;
var html = _downloader.DownloadHtml(idUri);
return ...parse ID HTML...;
}
public Movie FindMovieByTitle(string title)
{
var titleUri = ...build URI...;
var html = _downloader.DownloadHtml(titleUri);
return ...parse title HTML...;
}
}
I asked for something to review my code, and someone suggested this approach. My question is why is the IHtmlDownloader variable readonly?
If it's private and readonly, the benefit is that you can't inadvertently change it from another part of that class after it is initialized. The readonly modifier ensures the field can only be given a value during its initialization or in its class constructor.
If something functionally should not change after initialization, it's always good practice to use available language constructs to enforce that.
On a related note, C# 9 introduces the init accessor method for properties, which indicates the property value can only be set during object construction, e.g.:
class InitExample
{
private double _seconds;
public double Seconds
{
get { return _seconds; }
init { _seconds = value; }
}
}
This ensures that the value of _downloader will not be changed after the constructor was executed. Fields marked as readonly can only be assigned a value from within the constructor(s) of a class.
A readonly field is useful for modelling data that should not change after it has been initialized. You can assign a value to a readonly field by using a initializer when you declare it or in a constructor, but thereafter you cannot change it.

Accessing members in your own class: use (auto)properties or not?

I've created this "question" as a community-wiki, because there is no right or wrong answer. I only would like to know how the community feels about this specific issue.
When you have a class with instance variables, and you also created properties that are simply getters and setters for these instance variables, should you use the properties inside your own class, or should you always use the instance variable?
Having auto-properties in C# 3.0 made this an even harder decision.
Using properties:
public class MyClass
{
private string _name;
// could be an auto-property of-course
public string Name { get { return _name; } set { _name = value; } }
public void Action()
{
string localVar = Name;
// ...
Name = "someValue";
// ...
}
}
Using instance variables:
public class MyClass
{
private string _name;
public string Name { get { return _name; } set { _name = value; } }
public void Action()
{
string localVar = _name;
// ...
_name = "someValue";
// ...
}
}
(for those who hate member prefixes, I apologize)
Personally, I always use the latter (instance variables), because I feel that properties should only be used by other classes, not yourself. That's why I mostly stay away from auto-properties as well.
Of course, things change when the property setter (or getter) does a little more than just wrapping the instance variable.
Are there compelling reasons to pick one or the other?
I always use instance variables as well. The reason is because properties might be doing stuff like validating arguments (like in a setter) for not null or not empty. If you're using the variable inside your class code, there's no need to go through the extra overhead of those checks (assuming you know the variable value is valid). The properties could be doing other things as well (logging, for example), that are important for the public API, but not for internal usage, so again, it's better to avoid the overhead and just use the instance variable in my opinion.
I think it becomes more difficult to change the internal implementation if the code uses its own public interface.
Difficult to explain but consider these expressions:
mTotalPrice = mPrice * mQuantity;
mTotalPrice = Price * Quantity;
What to do in the second expression if I need to change the internals to express all prices in € instead of $ (without affecting the public interface which still uses $)?
One solution is to make the expression more complex by adding the opposite of the change in the property.
mTotalPrice = Price / Rate * Quantity
The other solution is to start to use the private field instead.
mTotalPrice = mPrice * Quantity
In the end you get a mix of private and public use. The only way to get consistent use is to always use the private field.
I don't like prefixing members either, but actually I find I can write something like this accidently and not spot it until run time. Which kinda tempts me to avoid using properties where they're not necessary... but I still do, currently!
Public String MyString
{
{ get { return this.MyString; } } //<== Stack Overflow
{ set { this.myString = value; } }
}
private String myString;
I think that there is no difference between these two approaches.
Auto-implemented properties is just a quick way to access private members which are created any way.
Example from MSDN:
class Customer
{
// Auto-Impl Properties for trivial get and set
public double TotalPurchases { get; set; }
public string Name { get; set; }
public int CustomerID { get; set; }
// Constructor
public Customer(double purchases, string name, int ID)
{
TotalPurchases = purchases;
Name = name;
CustomerID = ID;
}
// Methods
public string GetContactInfo() {return "ContactInfo";}
public string GetTransactionHistory() {return "History";}
// .. Additional methods, events, etc.
}
99% of the time I use the property rather then the instance variable. In the past, I've worked with a lot of code that used the instance variable and when there was a bug associated with that variable, I had to put a breakpoint on every line of code that referenced it.
I decided to use properties instead, either public or private, to wrap around the instance variable. Doing this means that I only have to put a breakpoint in the getter/setter of the property if I need to debug an issue with the instance variable, rather then having (potentially) a lot of breakpoints scattered all over the code.

Can I pass parameters by reference in Java?

I'd like semantics similar to C#'s ref keyword.
Java is confusing because everything is passed by value. However for a parameter of reference type (i.e. not a parameter of primitive type) it is the reference itself which is passed by value, hence it appears to be pass-by-reference (and people often claim that it is). This is not the case, as shown by the following:
Object o = "Hello";
mutate(o)
System.out.println(o);
private void mutate(Object o) { o = "Goodbye"; } //NOT THE SAME o!
Will print Hello to the console. The options if you wanted the above code to print Goodbye are to use an explicit reference as follows:
AtomicReference<Object> ref = new AtomicReference<Object>("Hello");
mutate(ref);
System.out.println(ref.get()); //Goodbye!
private void mutate(AtomicReference<Object> ref) { ref.set("Goodbye"); }
Can I pass parameters by reference in
Java?
No.
Why ? Java has only one mode of passing arguments to methods: by value.
Note:
For primitives this is easy to understand: you get a copy of the value.
For all other you get a copy of the reference and this is called also passing by value.
It is all in this picture:
In Java there is nothing at language level similar to ref. In Java there is only passing by value semantic
For the sake of curiosity you can implement a ref-like semantic in Java simply wrapping your objects in a mutable class:
public class Ref<T> {
private T value;
public Ref(T value) {
this.value = value;
}
public T get() {
return value;
}
public void set(T anotherValue) {
value = anotherValue;
}
#Override
public String toString() {
return value.toString();
}
#Override
public boolean equals(Object obj) {
return value.equals(obj);
}
#Override
public int hashCode() {
return value.hashCode();
}
}
testcase:
public void changeRef(Ref<String> ref) {
ref.set("bbb");
}
// ...
Ref<String> ref = new Ref<String>("aaa");
changeRef(ref);
System.out.println(ref); // prints "bbb"
From James Gosling in "The Java Programming Language":
"...There is exactly one parameter passing mode in Java - pass by value - and that keeps things simple.
.."
I don't think you can. Your best option might be to encapsulate the thing you want to pass "by ref" onto another class instance, and pass the (outer) class's reference (by value). If you see what I mean...
i.e. your method changes the internal state of the object it is passed, which is then visible to the caller.
Java is always pass by value.
When you pass a primitive it's a copy of the value, when you pass an object it's a copy of the reference pointer.
Another option is to use an array, e.g.
void method(SomeClass[] v) { v[0] = ...; }
but 1) the array must be initialized before method invoked, 2) still one cannot implement e.g. swap method in this way...
This way is used in JDK, e.g. in java.util.concurrent.atomic.AtomicMarkableReference.get(boolean[]).
Check out my response in: http://stackoverflow.com/a/9324155/1676736
In there I used a simpler version of the wrapper class idea.
I don't like setters/getters as a standard. When there is no reason to bury a field I make it 'public'. Especially in something like this.
However, this would work for all but the primitive, or multi-parameter/type returns:
public class Ref<T> {
public T val;
}
Although, I suppose you could just add more type parameters. But I think that creating an inner static class fit-for-purpose would be easier:
public static class MyReturn {
public String name;
public int age;
public double salary;
}
this would be for use when you don't need it for other reasons.
MyReturn mRtn = new MyReturn();
public void myMethod(final MyReturn mRtn){
mRtn.name = "Fred Smith";
mRtn.age = 32;
mRtn.salary = 100000.00;
}
System.out.println(mRtn.name + " " +mRtn.age + ": $" + mRtn.salary);

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