here is my code
// Read the data from the file
XmlSerializer serializer = new XmlSerializer(typeof(HighScoreData));
data = (HighScoreData)serializer.Deserialize(stream);
im currently doing a saving highscore for my game. but it get an error of "there is an error in xml document (0, 0).
care to help or enlighten?
i have had this problem before and a byte order mark was present at the beginning of the file. Check your XML file in a hex editor and see if there are three characters at the beginning. You could simply do something like the following with your raw xml
if (xml.StartsWith(ByteOrderMarkUtf8))
{
xml = xml.Remove(0, ByteOrderMarkUtf8.Length);
}
then read that into the stream
or you could do something like this when creating your stream
byte[] bytes = Encoding.UTF8.GetBytes(xml);
MemoryStream stream = new MemoryStream(bytes);
hopefully that helps
Related
I'm trying to make a config file from an XML file, but I can't figure out how to save the file after I add to it. I can read from the file fine, so I know it's not an issue with where it's located, but I still don't know how to save it.
I've looked around for about 2 hours and can't figure out the problem. I'm know my way around c# but am completely new to XML.
public async Task CreateReaction(string name, DiscordMessage message, DiscordEmoji emoji, DiscordRole role)
{
string path = #"E:\Visual Studio\repos\JustHangoutBot\bin\Debug\netcoreapp1.1\configs\reactions.xml";
XDocument doc = XDocument.Load(path);
await message.CreateReactionAsync(emoji);
XElement root = new XElement(name);
root.Add(new XElement("MessageID", message.Id));
root.Add(new XElement("ReactionID", emoji.Id));
root.Add(new XElement("RoleID", role.Id));
doc.Element("Reactions").Add(root);
byte[] byteArray = Encoding.UTF8.GetBytes(path);
MemoryStream stream = new MemoryStream(byteArray);
doc.Save(stream);
}
I think the problem is somewhere in the last three lines. I've seen tutorials of people saving the file by just using doc.Save("reactions.xml") for example, but I get the error of not being able to convert from string to Stream.
Any help would be appreciated. Thank you in advance!
This will do it:
using (var fileStream = System.IO.File.OpenWrite("path to the file you want to write"))
{
doc.Save(fileStream);
}
When you do this:
byte[] byteArray = Encoding.UTF8.GetBytes(path);
MemoryStream stream = new MemoryStream(byteArray);
doc.Save(stream);
What's happening is
You're opening the file at path and reading it into a byte array.
You're creating a MemoryStream that has those bytes as its content
You're saving that document to the MemoryStream.
Under the hood a MemoryStream is just an array of bytes in memory. So it's writing the file to memory, not to a file.
File.OpenWrite(path) opens a FileStream with the specified path. If the file doesn't exist it creates it. If the file does exist it will overwrite it.
So when you call doc.Save(fileStream) you're writing to the file.
I am creating an XML file on the fly.
One of it's nodes contains a ZIP file encoded as a BASE64 string.
I then create another ZIP file.
I add this XML file and a few other JPEG files.
I output the file to the browser.
I am unable to open the FINAL ZIP file.
I get: "Windows cannot open the folder. The Compressed(zipped) Folder'c:\path\file.zip' is invalid."
I am able to save my original XML file to the file system.
I can open that XML file, decode the ZIP node and save to the file system.
I am then able to open that Zip file with no problems.
I can create the final ZIP file, OMIT my XML file, and the ZIP file opens no problem.
I seem to only have an issue with I attempt to ZIP an XML file that has a node with ZIP content encoded as a BASE64 string.
Any ideas? Code snipets are below. Heavily edited.
XDocument xDoc = new XDocument();
XDocument xDocReport = new XDocument();
XElement xNodeReport;
using (FileStream fsData = new FileStream(strFullFilePath, FileMode.Open, FileAccess.Read)) {
xDoc = XDocument.Load(fsData);
xNodeReport = xDoc.Element("Data").Element("Reports").Element("Report");
//SNIP
//create XDocument xDocReport
//SNIO
using (MemoryStream zipInMemoryReport = new MemoryStream()) {
using (ZipArchive zipFile = new ZipArchive(zipInMemoryReport, ZipArchiveMode.Update)) {
//Add REPORT to ZIP file
ZipArchiveEntry entryReport = zipFile.CreateEntry("data.xml");
using (StreamWriter writer = new StreamWriter(entryReport.Open())) {
writer.Write(xDocReport.ToString());
} //END USING report entry
}
xNodeReport.Value = System.Convert.ToBase64String(zipInMemoryReport.GetBuffer());
//I am able to write this file to disk and manipulate it no problem.
//File.WriteAllText("c:\\users\\snip\\desktop\\Report.xml",xDoc.ToString());
}
//create ZIP for response
using (MemoryStream zipInMemory = new MemoryStream()) {
using (ZipArchive zipFile = new ZipArchive(zipInMemory, ZipArchiveMode.Update)) {
//Add REPORT to ZIP file
ZipArchiveEntry entryReportWrapper = zipFile.CreateEntry("Report.xml");
//THIS IS THE STEP THAT makes the Zip "invalid". Although i can open and manipulate this source file no problem.
//********
using (StreamWriter writer = new StreamWriter(entryReportWrapper.Open())) {
xDoc.Save(writer);
}
//Add JPEG(s) to report
//Create Charts
if (chkDLSalesPrice.Checked) {chartDownloadSP.SaveImage(entryChartSP.Open(), ChartImageFormat.Jpeg);}
if (chkDLSalesDOM.Checked) {chartDownloadDOM.SaveImage(entryChartDOM.Open(), ChartImageFormat.Jpeg);}
if (chkDLSPLP.Checked) {chartDownloadSPLP.SaveImage(entryChartSPLP.Open(), ChartImageFormat.Jpeg);}
if (chkDLSPLP.Checked) {chartDownloadLP.SaveImage(entryChartLP.Open(), ChartImageFormat.Jpeg);}
} // END USING ziparchive
Response.Clear();
Response.AppendHeader("content-disposition", "attachment; filename=file.zip");
Response.ContentType = "application/zip";
Response.BinaryWrite(zipInMemory.GetBuffer());
Response.End();
Without a good, minimal, complete code example, it's impossible to know for sure what bugs are in the code. But there are at least two apparent errors in the code snippet you posted, one of which could easily be responsible for the "invalid .zip" error:
In the statement writer.Write(xDocReport.ToString());, the variable xDocReport has not been initialized to anything useful, at least not in the code you posted. So you'll get an empty XML document in the archive.
Since the code example is incomplete, it's possible you just omitted from the code example in your question the initialization of that variable to something else. In any case, even if you didn't that would just lead to an empty XML document in the archive, not an invalid archive.
More problematic though…
You are calling GetBuffer() on your MemoryStream objects, instead of ToArray(). You want the latter. The former gets the entire backing buffer for the MemoryStream object, including the uninitialized bytes past the end of the valid stream. Since a valid .zip file includes a CRC value at the end of the file, adding extra data beyond that causes anything trying to read the file as a .zip archive to miss the correct CRC, reading the uninitialized data instead.
Replace your calls to GetBuffer() with calls to ToArray() instead.
If the above does not lead to a solution for your problem, you should edit your post, to provide a better code example.
One last comment: there is no point in initializing a variable like xDoc to an empty XDocument object when you're going to just replace that object with a different one (e.g. by calling XDocument.Load()).
This is pretty odd. I have a configuration file which is well formed XML. I create a stream from the file and serialize it using what seems to be pretty typical code:
TextWriter tw = new StreamWriter(tempFile);
I use a serializer created as follows:
XmlSerializer ConfigSettingSerializer = new XmlSerializer(typeof(ConfigSettings));
Where ConfigSettings is just a container class containing string variables and values.
I then take the serialized stream and stash it away as a configuration using the ConfigurationManager class and AppSettings. I then retrieve the serialized data from appSettings and attempt to convert the stream back to the original class:
string configXml = ConfigurationManager.AppSettings[Id];
using (StringReader reader = new StringReader(configXml))
{
retVal = (ConfigSettings)MVHelper.ConfigSettingSerializer.Deserialize(reader);
}
This all works perfectly well until I switch from Debug to Release, when I get an error on the Deserialize call about invalid XML, complaining about the very last character in the document: There is an error in XML document (92, 18). The inner exception is: "Data at the root level is invalid. Line 92, position 18". The document is identical to the one generated in debug mode, and it renders fine in any browser. My guess is that there maybe something else going on and that the real error is somehow being masked, but so far I don't see it. Any advice would be greatly appreciated.
Thanks,
Gary
Load the XML file in a hex editor or other binary editor and check for unprintable characters like an encoding preamble.
I need to generate a huge xml file from different sources (functions). I decide to use XmlTextWriter since it uses less memory than XmlDocument.
First, initiate an XmlWriter with underlying MemoryStream
MemoryStream ms = new MemoryStream();
XmlTextWriter xmlWriter = new XmlTextWriter(ms, new UTF8Encoding(false, false));
xmlWriter.Formatting = Formatting.Indented;
Then I pass the XmlWriter (note xml writer is kept open until the very end) to a function to generate the beginning of the XML file:
xmlWriter.WriteStartDocument();
xmlWriter.WriteStartElement();
// xmlWriter.WriteEndElement(); // Do not write the end of root element in first function, to add more xml elements in following functions
xmlWriter.WriteEndDocument();
xmlWriter.Flush();
But I found that underlying memory stream is empty (by converting byte array to string and output string). Any ideas why?
Also, I have a general question about how to generate a huge xml file from different sources (functions). What I do now is keeping the XmlWriter open (I assume the underlying memory stream should open as well) to each function and write. In the first function, I do not write the end of root element. After the last function, I manually add the end of root element by:
string endRoot = "</Root>";
byte[] byteEndRoot = Encoding.ASCII.GetBytes(endRoot);
ms.Write(byteEndRoot, 0, byteEndRoot.Length);
Not sure if this works or not.
Thanks a lot!
Technically you should only ask one question per question, so I'm only going to answer the first one because this is just a quick visit to SO for me at the moment.
You need to call Flush before attempting to read from the Stream I think.
Edit
Just bubbling up my second hunch from the comments below to justify the accepted answer here.
In addition to the call to Flush, if reading from the Stream is done using the Read method and its brethren, then the position in the stream must first be reset back to the start. Otherwise no bytes will be read.
ms.Position = 0; /*reset Position to start*/
StreamReader reader = new StreamReader(ms);
string text = reader.ReadToEnd();
Console.WriteLine(text);
Perhaps you need to call Flush() on the xml stream before checking the memory streazm.
Make sure you call Flush on the XmlTextWriter before checking the memory stream.
I'm importing data from XML files containing this type of content:
<FirstName>™MšR</FirstName><MiddleName/><LastName>HšNER™Z</LastName>
The XML is loaded via:
XmlDocument doc = new XmlDocument();
try
{
doc.Load(fullFilePath);
}
When I execute this code with the data contained on top I get an exception about an illegal character. I understand that part just fine.
I'm not sure which encoding this is or how to solve this problem. Is there a way I can change the encoding of the XmlDocument or another method to make sure the above content is parsed correctly?
Update: I do not have any encoding declaration or <?xml in this document.
I've seen some links say to add it dynamically? Is this UTF-16 encoding?
It appears that:
The name was ÖMÜR HÜNERÖZ (or possibly ÔMÜR HÜNERÔZ or ÕMÜR HÜNERÕZ; I don't know what language that is).
The XML file was encoded using the DOS "OEM" code page, probably 437 or 850.
But it was decoded using windows-1252 (the "ANSI" code page).
If you look at the file with a hex editor (HXD or Visual Studio, for instance), what exactly do you see?
Is every character from the string you posted represented by a single byte? Does the file have a byte-order mark (a bunch of non-printable bytes at the start of the file)?
The ™ and š seem to indicate that something went pretty wrong with encoding/conversion along the way, but let's see... I guess they both correspond with a vowel (O-M-A-R H-A-NER-O-Z, maybe?), but I haven't figured out yet how they ended up looking like this...
Edit: dan04 hit the nail on the head. ™ in cp-1252 has hex value 99, and š is 9a. In cp-437 and cp-850, hex 99 represents Ö, and 9a Ü.
The fix is simple: just specify this encoding when opening your XML file:
XmlDocument doc = new XmlDocument();
using (var reader = new StreamReader(fileName, Encoding.GetEncoding(437)))
{
doc.Load(reader);
}
From here:
Encoding encoding;
using (var stream = new MemoryStream(bytes))
{
using (var xmlreader = new XmlTextReader(stream))
{
xmlreader.MoveToContent();
encoding = xmlreader.Encoding;
}
}
You might want to take a look at this: How to best detect encoding in XML file?
For actual reading you can use StreamReader to take care of BOM(Byte order mark):
string xml;
using (var reader = new StreamReader("FilePath", true))
{ // ↑
xml= reader.ReadToEnd(); // detectEncodingFromByteOrderMarks
}
Edit: Removed the encoding parameter. StreamReader will detect the encoding of a file if the file contains a BOM. If it does not it will default to UTF8.
Edit 2: Detecting Text Encoding for StreamReader
Obviously you provided a fragment of the XML document since it's missing a root element, so I'll assume that was your intention. Is there an xml processing instruction at the top like <?xml version="1.0" encoding="UTF-8" ?>?