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Convert from String to BigInteger in C# without cutting off leading zero's.

Working on a project where I need to do a bitwise & between two similar 168 character bitarrays. I am working in C# and when I attempt to convert from String to BigInteger, the leading zero's are being truncated. Is there anything I can do to save these characters?
Basically:
string bits = "000000000000000000000000000000000000000000000000000000000000000000001111111000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000"
BigInteger bigIntBits = BigInteger.Parse(bits);
// I am being returned 1111111000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000"
Anything will help. Thank you in advance.

You can simply do this:
string bits = "000000000000000000000000000000000000000000000000000000000000000000001111111000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000";
// convert to big integer
var bigIntBits = BigInteger.Parse(bits);
int index = bits.IndexOf('1');
string backToString = new string('0', index) + bigIntBits.ToString();

Convert double to string, keep format - C#

Hi all. I have a double number (Ex: 0.000006). I want convert it to string type. But result is "6E-06". I dont want it, i want 0.000006".Thanks you so much
double a = 0.000006;
string resultString = a.toString();
I don't know many number after "." character

It's simple that if you want to show a number as exactly as what it looks, we can cast it to decimal and use the default ToString() like this:
var s = ((decimal)yourNumber).ToString();
//if yourNumber = 0.00000000000000000000000006
//just append the M after it:
var s = (0.00000000000000000000000006M).ToString();

Please check this article and find the format which suits your needs: http://www.csharp-examples.net/string-format-double/
Looks like this one is good enough:
String.Format("{0:0.00}", 123.4567);

Use String.Format() with the format specifier.
double a = 0.000006;
string formatted = String.Format("{0:F6}", a);

Try with the Roundtrip 'R' format specifier:
double a = 0.000006;
string resultString = a.ToString("R");

Double Rate_USD = Convert.ToDouble(txtRateUsd.Text);
string Rate_USD = txtRateUsd.Text;

Number increment from string value

I my application due to some reason I have two numbers in 5 digits.
The following code give you brief idea.
string s = "00001"; // Initially stored somewhere.
//Operation start
string id = DateTime.Now.ToString("yy") + DateTime.Now.AddYears(-1).ToString("yy") + s;
//Operation end
//Increment the value of s by 1. i.e 00001 to 00002
This can be done easily by convert the value of s to int and increment it by 1 but after all that I have to also store the incremented value of s in 5 digit so it will be "00002".
This think give me a pain...

use
string s = "00001";
int number = Convert.ToInt32(s);
number += 1;
string str = number.ToString("D5");
to get atleast 5 digits.
The "D" (or decimal) format specifier
If required, the number is padded with zeros to its left to produce the number of digits given by the precision specifier. If no
precision specifier is specified, the default is the minimum value
required to represent the integer without leading zeros.

This seems to work for me.
string s = "00001";
int i = Int32.Parse(s);
i++;
s = i.ToString("D" + s.Length);

So I think you want to know how to convert an int to a 5 digit string.
You can do this:
int i = 1;
string s = i.ToString("D5");
//s = "00001"
There are plenty of format examples here.

Use String.Format() to achieve this:
string str = String.Format({0:#####}, s);
Look here.

This works using the PadLeft function:
int i = 1; // Initially stored somewhere.
//Operation start
string id = DateTime.Now.ToString("yy") + DateTime.Now.AddYears(-1).ToString("yy") + i.ToString().PadLeft(5, '0');
//Operation end

Convert alphabetic string into Integer in C#

Is it possible to convert alphabetical string into int in C#? For example
string str = "xyz";
int i = Convert.ToInt32(str);
I know it throws an error on the second line, but this is what I want to do.
So how can I convert an alphabetical string to integer?
Thanks in advance

System.Text.Encoding ascii = System.Text.Encoding.ASCII;
string str = "xyz";
Byte[] encodedBytes = ascii.GetBytes(str);
foreach (Byte b in encodedBytes)
{
return b;
}
this will return each characters ascii value... its up to you what you want to do with them

To answer the literal questions that you have asked
Is it possible to convert alphabetical string into int in C#?
Simply put... no
So how can I convert an alphabetical string to integer?
You cannot. You can simply TryParse to see if it will parse, but unless you calculate as ASCII value from the characters, there is no built in method in c# (or .NET for that matter) that will do this.

You can check whether a string contains a valid number using Int32.TryParse (if your questions is about avoiding an exception to be thrown):
int parsed;
if (!Int32.TryParse(str, out parsed))
//Do Something

Convert int (number) to string with leading zeros? (4 digits) [duplicate]

This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Number formatting: how to convert 1 to "01", 2 to "02", etc.?
How can I convert int to string using the following scheme?
1 converts to 0001
123 converts to 0123
Of course, the length of the string is dynamic. For this sample, it is:
int length = 4;
How can I convert like it?

Use String.PadLeft like this:
var result = input.ToString().PadLeft(length, '0');

Use the formatting options available to you, use the Decimal format string. It is far more flexible and requires little to no maintenance compared to direct string manipulation.
To get the string representation using at least 4 digits:
int length = 4;
int number = 50;
string asString = number.ToString("D" + length); //"0050"

Use the ToString() method - standard and custom numeric format strings. Have a look at the MSDN article How to: Pad a Number with Leading Zeros.
string text = no.ToString("0000");

val.ToString("".PadLeft(length, '0'))