Pattern is
Regex splRegExp = new System.Text.RegularExpressions.Regex(#"[\,#,+,\,?,\d,%,.,?,*,&,^,$,(,!,),#,-,_]");
All characters work except '-'. Please advise.
Use
#"[,#+\\?\d%.*&^$(!)#_-]"
No need for all those commas.
If you place a - inside a character class, it means a literal dash only if it's at the start or end of the class. Otherwise it denotes a range like A-Z. As Damien put it, the range ,-, is indeed rather small (and doesn't contain the -, of course).
'-' has to be the first charater in your regex.
Regex splRegExp = new System.Text.RegularExpressions.Regex(#"[-,\,#,+,\,?,\d,%,.,?,*,&,^,$,(,!,),#,_]");
You need to escape the -character for it to work (it's a regular expression syntax)
Try this:
"[\,#,+,\,?,\d,%,.,?,*,&,^,$,(,!,),#,\-,_]"
Related
I'm using C# 2012 and I can not solve this regular expression.
I need to validate the text so that points or traces are Mandatory to separate the numbers in the input text :
[0-9]{9}(-|.)[\s]?[0-9]{4}(-|.)[0-9]{4}(-|.)0-9[0-9]{2}(-|.)[0-9]{4}
A valid text should be as follows:
0706570-39.2014.8.02.0001
but the expression above returns true to the text below although it should be false:
...Certidão de Casamento nº 00287301551
982200032250000901391 - Cartório Privativo....
^[0-9]{9}(-|\.)[\s]?[0-9]{4}(-|\.)[0-9]{4}(-|\.)0-9[0-9]{2}(-|\.)[0-9]{4}$
Add anchors ^...$ to denote start and end of string. Also escape ..
You need to use the following regex:
\b[0-9]{7}[-.][0-9]{2}[-.][0-9]{4}[-.][0-9][.-][0-9]{2}[-.][0-9]{4}\b
See demo
If the expression must match individual full strings, replace \b...\b with ^...$.
Note that (-|.) is really pointless as . matches -, so your intention was to match a literal .. To match a literal ., you need to escape it (as vks shows), or put it into a character class [.]. A character class is a bit more efficient solution here since there is much less backtracking than with alternation | operator. Anyway, the original expression is matching different digit groups (see [0-9]{7}(-|\.)\s?[0-9]{2}(-|\.)[0-9]{4}(-|\.)[0-9]{1}(-|\.)[0-9]{2}(-|\.)[0-9]{4} just for a demo sake that is a "fixed" version.)
My Regex is for a canadian postal code and only allowing the valid letters:
Regex pattern = new Regex("^[ABCEGHJKLMNPRSTVXY][0-9][ABCEGHJKLMNPRSTVWXYZ][/s][0-9][ABCEGHJKLMNPRSTVWXYZ][0-9]$");
The problem I am having is that I want to allow for a space to be put in between the each set but cannot find the correct character to use.
You've got a forward-slash instead of a backslash in your regular expression for whitespace (\s). The following regex should work.
#"^[ABCEGHJKLMNPRSTVXY][0-9][ABCEGHJKLMNPRSTVWXYZ][\s][0-9][ABCEGHJKLMNPRSTVWXYZ][0-9]$"
If you are simply searching for space use \s
To provide the escape sequence character \ use # verbitm literal character as below in the given example.
Regex pattern = new Regex(#"^[ABCEGHJKLMNPRSTVXY][0-9]\s[ABCEGHJKLMNPRSTVWXYZ[0-9]\s[ABCEGHJKLMNPRSTVWXYZ][0-9]$");
As pointed out in the comments, if space is optional you can use ? quantifier as below.
Regex pattern = new Regex(#"^[ABCEGHJKLMNPRSTVXY][0-9]\s?[ABCEGHJKLMNPRSTVWXYZ[0-9]\s?[ABCEGHJKLMNPRSTVWXYZ][0-9]$");
Use the \s token for whitespace instead of /s.
Some handy tools to speed up regex development:
regexr.com helps with syntax and provides realtime testing
regexpr.com (yes I know :)) visualizes your expression.
As per other answers....
Use \s instead of /s
You shouldn't need to square bracket the [\s], because it already implies a complete class of characters.
Also...
In most languages, you probably don't want to use double quotes "..." as delimiters to the Regex, since this might be interpolating the \s before the pattern is applied. It's certainly worth a try.
Use a trailing quantifier \s* or \s? to allow the space to be optional.
May I know what \? means in a regular expression? For example, what is its significance in this expression.
I have used this for validating 7 digit telephone no
Any help is highly appreciated.
"\?" means "?" itself. "\" - is escape character. "?" is quantifier and "\" is used to escape it.
I have used this for validating 7 digit telephone no
"[[:number:]]\{3\}[ -]\?[[:number:]]\{4\}"
Looking at your example, it seems that you are talking about BRE, then the \ (escaping) gave ? special meaning: one or zero[ -]
If it is ERE/PCRE, the \ will take that speical meaning away from ?, that is, \? means literal question mark: ?
The properly-escaped "?" will match that exact character, the "?", as it appears in the text.
For instance, if you do
Regex re = new Regex(#"\d{3}-\?\d{4}");
, you will be able to get a positive match for 123-?1234.
If you want to get a positive match for 1231234 OR 123-1234, you can use the special character "?" without escape, like this:
Regex re = new Regex(#"\d{3}-?\d{4}");
P.S. for C# .NET, I find the best regex-testing place online is MyRegexTester. If you use it for C#, don't forget to check the appropriate "C# .NET" checkbox.
P.P.S. as per the comment, putting "\s*" into the regex will match any length white space (spaces and tabs included), "\ ?" will match an optional space, and "[ ]" will match exactly one space (no less).
"\?" escapes "?" that have a special meaning in the regex (0 or 1 match) so "\?" escapes it and identifies the literal "?"
your regex looks strange to me, it looks that all the special character are escaped (also "{" ) and doesn't appear to be valid from what i know.
i think you want to write
"\d{3}[ -]?\d{4}"
if you want to match something that respect the pattern or
"^\d{3}[ -]?\d{4}$"
if you want to have a match something that is exactly the pattern
I have a problem with that regular expression [^%()*+-\/=?#[\\]ªº´¿'.]*` .
I want to avoid the characters inside. the regular expression it is working but when I set something like DAVID, SC I can save the form because it has a comma but this character it is not inside the regular expression.
Could you help me please?
You are not accounting for the special meaning of - inside a character class [.....].
You must either place the dash at the very end, or else escape it with a backslash:
[^%()*+\/=?#\[\]ªº´¿'.-]*
In your original regex, +-\/ disallows any characters between + and / in the ASCII table; these are the comma, dot and dash. Your example input contains a comma so the regex did not match all of the input at once.
I have also fixed the escaping for the [] characters from [\\] to \[\], which I presume was a mistake.
Because you're using * in [^%()*+\/=?#[\\]ªº´¿'.-]* with line start/end anchors. * means match 0 or more of preceding group/pattern in character class and your regex can even match an empty string.
Use this regex:
^[^%()*+\/=?#[\\-]ªº´¿'.]+$
PS: Hyphen - should be either or first OR at last position in character class to avoid escaping.
Rubular Demo
I'm currently facing a (little) blocking issue. I'd like to replace a substring by one another using regular expression. But here is the trick : I suck at regex.
Regex.Replace(contenu, "Request.ServerVariables("*"))",
"ServerVariables('test')");
Basically I'd like to replace whatever is between the " by "test". I tried ".{*}" as a pattern but it doesn't work.
Could you give me some tips, I'd appreciate it!
There are several issues you need to take care of.
You are using special characters in your regex (., parens, quotes) -- you need to escape these with a slash. And you need to escape the slashes with another slash as well because we 're in a C# string literal, unless you prefix the string with # in which case the escaping rules are different.
The expression to match "any number of whatever characters" is .*. In this case, you would want to match any number of non-quote characters, which is [^"]*.
In contrast to (1) above, the replacement string is not a regular expression so you don't want any slashes there.
You need to store the return value of the replace somewhere.
The end result is
var result = Regex.Replace(contenu,
#"Request\.ServerVariables\(""[^""]*""\)",
"Request.ServerVariables('test')");
Based purely on my knowledge of regex (and not how they are done in C#), the pattern you want is probably:
"[^"]*"
ie - match a " then match everything that's not a " then match another "
You may need to escape the double-quotes to make your regex-parser actually match on them... that's what I don't know about C#
Try to avoid where you can the '.*' in regex, you can usually find what you want to get by avoiding other characters, for example [^"]+ not quoted, or ([^)]+) not in parenthesis. So you may just want "([^"]+)" which should give you the whole thing in [0], then in [1] you'll find 'test'.
You could also just replace '"' with '' I think.
Taryn Easts regex includes the *. You should remove it, if it is just a placeholder for any value:
"[^"]"
BTW: You can test this regex with this cool editor: http://rubular.com/r/1MMtJNF3kM