Develop Reference

Return XML response with metadata from asp .net core Web API

How can I return an XML response from webAPI written in .net core to have the metadata information at the top.
Required response :
<?xml version="1.0" encoding="UTF-8"?>
<dataset xmlns="http://developer.cognos.com/schemas/xmldata/1/"
xmlns:xs="http://www.w3.org/2001/XMLSchema-instance">
<metadata>
<item name="AsOfDate" type="xs:string" length="12"/>
<item name="RateOfReturn" type="xs:double"/>
<item name="FamAcctIndex" type="xs:string" length="3"/>
<item name="RowID" type="xs:string" length="1"/>
<item name="BrM" type="xs:string" length="1"/>
<item name="ProductLineCode" type="xs:int"/>
</metadata>
<data>
<row>
<value>Apr 26, 2002</value>
<value>0.210066429</value>
<value>JA1</value>
<value>F</value>
<value>B</value>
<value>1</value>
</row>
<row>
<value>Apr 27, 2002</value>
<value>0.1111111</value>
<value>BBB</value>
<value>G</value>
<value>B</value>
<value>2</value>
</row>
</data>
</dataset>
I have added the following code to accept xml type :
services.AddMvc().AddXmlSerializerFormatters();
My API method returns XML without the metadata if I use Accept : application/xml

How parse XML with metadata in C#?

I have a problem with parsing above XML code. It doesn't look like normal XML structure - in the top of document is schema, which describe fields. Is there any simple method for parsing it?
<metadata>
<item name="number" type="xs:string" length="42"/>
<item name="artist" type="xs:string" length="62"/>
<item name="title" type="xs:string" length="502"/>
<item name="title supplement" type="xs:string" length="502"/>
<item name="price" type="xs:decimal" scale="2" precision="12"/>
</metadata>
<data>
<row>
<value>88697562032</value>
<value>1979 Revival Cast Recording</value>
<value>Oklahoma!</value>
<value>Softpack</value>
<value>25</value>
</row>
(...)
<row>
<value>88697919802</value>
<value>2CELLOS (Sulic & Hauser)</value>
<value>2CELLOS</value>
<value>Three Language Booklet Version</value>
<value>39.6</value>
</row>
</data>

Validating XML against XSD with <xs:any/> - Warning : Could not find schema information for the element

I am trying to validate my XML files against an XSD to check if the files have the correct format.
In my XSd file I want the Row element to contain as many and whatever element possible, thus the any element.
With an online validator, I checked that the validity of XSD and checked my Schema on one of the files I want to check. Everything was valid.
The online validator is this one: http://www.utilities-online.info/xsdvalidation/
I based my parsing code on this topic : c# XML Schema validation
I get that my files are not valid: Could not find schema information for the element <MYELEMENT>
The elements that are not found are the ones in my in the content of my Row element.
The complete .XSD is :
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="Root">
<xs:complexType>
<xs:sequence>
<xs:element name="Row" minOccurs="0" maxOccurs="unbounded">
<xs:complexType>
<xs:sequence>
<xs:any minOccurs='1' maxOccurs='unbounded' processContents="lax" />
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:sequence>
</xs:complexType>
The XML I tested with is :
<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<Root>
<Row>
<MODE_SAISIE_CT>'DEGRADE'</MODE_SAISIE_CT>
<MODE_STATUT>'F'</MODE_STATUT>
<MODE_LIBELLE>'Dégradé'</MODE_LIBELLE>
<DATE_MODE_DEGRADE>'17/08/2011 15:28:17'</DATE_MODE_DEGRADE>
</Row>
<Row>
<MODE_SAISIE_CT>'STANDARD'</MODE_SAISIE_CT>
<MODE_STATUT>'V'</MODE_STATUT>
<MODE_LIBELLE>'Standard'</MODE_LIBELLE>
<DATE_MODE_DEGRADE>'17/08/2011 15:53:06'</DATE_MODE_DEGRADE>
</Row>
</Root>
How can I manage the parsing if I have an any element in my schema ?

Without seeing a complete XSD and input XML that exhibit the issue, it's unclear what to recommend, but perhaps this working example will help you identify your problem:
This input XML:
<?xml version="1.0" encoding="utf-8"?>
<root>
<Row>
<MYELEMENT/>
</Row>
</root>
Is valid against this XSD:
<?xml version="1.0" encoding="utf-8"?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<xsd:element name="root">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="Row">
<xsd:complexType>
<xsd:sequence>
<xsd:any processContents="lax" maxOccurs="unbounded"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:schema>

How do you generate xsd namespace prefixes in the resulting output file?

I've gone over multiple topics and solutions that talk specifically about this issue. None have worked or I fail to understand what I am doing wrong.
I would like for the namespace prefixes to accompany the element names in the resulting xml output file.
I'm am using the XSD command with Visual Studio 2008 from the VS Command Prompt
Here's my xsd schema for Trial.xsd
<?xml version="1.0" encoding="utf-8"?>
<xs:schema id="Junk"
targetNamespace="http://www.opengis.net/kml/2.2"
xmlns="http://www.opengis.net/kml/2.2"
xmlns:gx="http://www.google.com/kml/ext/2.2"
xmlns:kml="http://www.opengis.net/kml/2.2"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
elementFormDefault="qualified">
<xs:import namespace="http://www.google.com/kml/ext/2.2" schemaLocation="TestSchema.xsd" />
<!-- Start LookType -->
<xs:complexType name="LookType">
<xs:sequence>
<xs:element ref="gx:TimeSpan" minOccurs="0" />
<xs:element name="longitude" type="xs:string" />
</xs:sequence>
</xs:complexType>
<!-- End LookType -->
<xs:element name="Te" type="LookType" />
</xs:schema>
Here's my xsd schema for TestSchema.xsd
<?xml version="1.0" encoding="utf-8"?>
<xs:schema id="TestSchema"
targetNamespace="http://www.google.com/kml/ext/2.2"
xmlns="http://www.google.com/kml/ext/2.2"
xmlns:gx="http://www.google.com/kml/ext/2.2"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
elementFormDefault="qualified">
<xs:element name="TimeSpan" type="gx:GXTimeSpanType" />
<!-- Start GXTimeSpanType -->
<xs:complexType name="GXTimeSpanType">
<xs:sequence>
<xs:element name="begin" type="xs:string" />
<xs:element name="end" type="xs:string" />
</xs:sequence>
</xs:complexType>
<!-- End GXTimeSpanType -->
</xs:schema>
I´m generating the resulting class file Trial.cs by using xsd TestSchema.xsd ./Trial.xsd /c /l:cs /n:T
In a program I assign these junk values and write them to file using XmlDocument, XmlSerializer and FileStream
T.LookType te = new T.LookType();
te.longitude = "34.444";
te.TimeSpan = new T.GXTimeSpanType();
te.TimeSpan.begin = "2010-02-26T20:22:00Z";
te.TimeSpan.end = "2010-02-26T20:23:42Z";
I've excluded the method that saves out the file using XmlDocument, XmlSerializer and FileStream as it is a little thicker then I'd like to post unless that is part of the problem.
This is what I get in the resulting file
<?xml version="1.0" encoding="utf-16"?>
<Te xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns="http://www.opengis.net/kml/2.2">
<TimeSpan xmlns="http://www.google.com/kml/ext/2.2">
<begin>2010-02-26T20:22:00Z</begin>
<end>2010-02-26T20:23:42Z</end>
</TimeSpan>
<longitude>34.444</longitude>
</Te>
This is what I want in the resulting file. Notice the gx:TimeSpan element and the xmlns:gx namespace definition being added to the main Te element.
<?xml version="1.0" encoding="utf-16"?>
<Te xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns="http://www.opengis.net/kml/2.2"
xmlns:gx="http://www.google.com/kml/ext/2.2">
<gx:TimeSpan>
<begin>2010-02-26T20:22:00Z</begin>
<end>2010-02-26T20:23:42Z</end>
</gx:TimeSpan>
<longitude>34.444</longitude>
</Te>

It doesn't matter on which element the prefixes are declared on, as long as they're declared before they are used. Any code that doesn't like this is broken.
Perhaps because it doesn't matter, XML Schema has no way to influence on which element the prefixes are declared, or which prefix is used.

XML to LINQ with metadata

I'm very new to both XML and LINQ. I've read several XML to LINQ tutorials, but none of the XML documents seem to be formatted the way mine is. I'm not sure if (and how) it changes things.
All the examples I've read on the internet seem to follow this format:
<data>
<row>
<Term>201320</Term>
<Subj>ACCT</Subj>
<Subj_desc>Accounting</Subj_desc>
</row>
<row>
<Term>201320</Term>
<Subj>ACCT</Subj>
<Subj_desc>Accounting</Subj_desc>
</row>
</data>
If I wanted to read that I think the code would look something like this:
XDocument document = XDocument.Load("URLHERE.xml");
var term = from row in document.Descendants("row")
select new
{
Term = row.Element("Term").Value,
Subject = row.Element("Subj").Value,
Subject_Description = row.Element("Subj_desc").Value,
};
Here's the problem: my XML document doesn't follow the same format. Instead of repeating the different tags for each term, it has a set of metadata at the top and then uses the SAME tag for each set of data.
Here's a sample of my XML document:
<metadata>
<item name="TERM" type="xs:string" length="128"/>
<item name="SUBJ" type="xs:string" length="128"/>
<item name="SUBJECT_DESC" type="xs:string" length="512"/>
</metadata>
<data>
<row>
<value>201320</value>
<value>ACCT</value>
<value>Accounting</value>
</row>
<row>
<value>201320</value>
<value>ACCT</value>
<value>Accounting</value>
</row>
</data>
How would I extract data from it?
var term = from row in document.Descendants("row")
select new
{
Term = row.Element("value").Value,
Subject = row.Element("value").Value,
};
Doesn't seem right. I'm using C# BTW (not sure if I need to say that or if the tag's sufficient).

Your XML is not properly formatted, you need a root element that encapsulates the entire document. such as
<?xml version='1.0' encoding='utf-8'?>
<root>
<metadata>
<item name="TERM" type="xs:string" length="128"/>
<item name="SUBJ" type="xs:string" length="128"/>
<item name="SUBJECT_DESC" type="xs:string" length="512"/>
</metadata>
<data>
<row>
<value>201320</value>
<value>ACCT</value>
<value>Accounting</value>
</row>
<row>
<value>201320</value>
<value>ACCT</value>
<value>Accounting</value>
</row>
</data>
</root>
Then using XDocument you could load the file
var doc = XDocument.Load("file.xml");
then you can extract the data, kinda depends what you want to extract, you never specified. example of getting the metadata
var item = doc.Descendants("metadata");
getting rows, containing an IEnumerable of values
XDocument document = XDocument.Load("c:\\tmp\\test.xml");
var rows = from i in document.Descendants("row")
select new {values = i.Elements("value").Select(a=>a.Value)};