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How to set a while loop? [closed]

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I'm trying to set my code for counting math games, all math operations are fine except for division. I don't know how to set the while loop correctly. There is a problem with division, such that I would like the division to be residual, so I came up with one method which is given below. It is all in WPF Application. I would like to count only single-digit numbers.
Random number = new Random();
int maxValue = 10;
int total = 0;
int firstNumber = number.Next(1, maxValue);
int secondNumber = number.Next(1, firstNumber);
while (firstNumber % secondNumber != 0);
{
secondNumber++;
}
total = firstNumber / secondNumber;
Why does it still show me the values ​​that have a residual division?
Thank you for any advice

The semi colon at the end of line:
while (firstNumber % secondNumber != 0);
...ends the while loop. The code in the remaining block is executed without any condition (as it in fact is a anonymous block):
{
secondNumber++;
}

C# loop on fraction [closed]

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I need someone to give me an idea on how to go on about this problem.Using a loop to calculate the fraction , There is no common value.I want to get the sum
Eg for fraction :
1 1/5 1/10 1/15 1/20 … 1/290 1/295 1/300
code snippet:-
int sum=0;
for(int i=1;i<=60 ;i++)
{
int sum=1
}

These sort of problems are actually surprisingly non-trivial due to issues with working with floating point, and decimal types for that matter.
Accepting that you want a loop solution for this (a closed form solution for n terms does exist), first note that your series can be written as
1 + 1/5(1 + 1/2 + 1/3 + ... + 1/60)
Then note that a good rule of thumb when working with floating point types is to add the small terms first.
So an algorithm would be of the form
double sum = 0.0;
for (int i = 60; i >= 1; --i){
sum += 1.0 / i;
}
sum = sum / 5 + 1;
Note the 1.0 in the numerator; that's there to defeat integer division.
Reference: Is floating point math broken?

͏Since you asked for a hint:
float sum = 1.0;
for (int i = 5; i <= ??; i += ??) {
sum += 1.0/i;
}
What goes in place of the ??s?

try this code:
double sum=1;
for(int i=5; i<=300; i+=5)
sum += (double) 1 / i;
The value of sum will be 1.93597408259035

Making 2 ints merge but with the highest number in first spot and the lowest in the back [closed]

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I would like to make my 2 ints get together in one number but where the biggest of the 2 get in the front and the other one in the back
I have a var named num1 and one named num2.
The numbers of those 2 are getting assigned thru a random.
I would like to make them into one number but with the highest number first and the other one after it. I don't want to + them together but make a big number.
For example num1 = 5 and num2 = 6 my whole number should then be 65.
Thx in advance I tried googling this but I could not really find what I was. Looking for sry for bad English

Utilise Math.Max and Math.Min to find the largest and smallest of the two numbers, then concatenate and parse to an int.
int result = int.Parse(Math.Max(num1, num2) + ""+ Math.Min(num1, num2));
or if the number can get large after concatenation then use the long data type.
long result = long.Parse(Math.Max(num1, num2) + ""+ Math.Min(num1, num2));

It sounds like you wish to randomly generate the digits separately, then combine the digits to form a two-digit number. So:
var num1 = 5;
var num2 = 6;
var bigNumber = num1 + 10 * num2; //65

I found a solution i used a little of both of your answers
This is what it ended like
num1 = randomNum.Next(1, 7);
num2 = randomNum.Next(1, 7);
maxNum = Math.Max(num1, num2);
minNum = Math.Min(num1, num2);
wholeNum = minNum + 10 * maxNum;`

Get Number from Random String [closed]

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How to get the whole number of this random.
Finally, I get a Debug.Log () to display my 757 number

You need to build up the whole number:
Random random = new Random();
int hundred = 100 * random.Next(1, 10);
int ten = 10 * random.Next(0, 10);
int one = random.Next(0, 10);
int result = hundred + ten + one;
Lets assume, the first random gives you 7, the second gives you 5 and the third gives you 7 again. you would end up with:
hundred = 100 * 7 = 700
ten = 10 * 5 = 50
one = 5
result = 700 + 50 + 7 = 757
Then just log result

What you describe is random 3 digit number. So simply:
Random.Range(100, 1000);

Retrieving a value that is stored as MB [closed]

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I have a table that stores the amount of RAM a server has in a biginit column with values such as 2470208.
But how I can apply a data annotation or other validations to show only 2 instead of s470208. ?
I mean to always divide by 1 million and get the number on the left side of the digit ?

1) Use this for automatic thousands-unit:
string GetByteString(long n) {
int k=0;
string u=" kMGTEP";
while(n>1024) {
n>>=10;
k++;
}
return n.ToString() + u[k];
}
Call:
string s= GetByteString(1234567890123);
Debug.WriteLine(s);
2) But if you simply always want MB just shift by 20:
long n = 123456789;
string MB = (n>>20).ToString();
But this will show 0 if n goes below 1MB.
Reason:
1 kB = 2^10 = 1<<10 = 1024;
1 MB = 2^20 = 1<<20 = 1024*1024 = 1048576;
1 GB = 2^30 = 1<<30 = 1024*1024*1024 = 1073741824;

You tagged C# but mentioned a bigint column so it isn't clear whether you're looking for a database or C# solution. The following C# method will take the number of bytes as an integer and return a formatted string...
public string FormattedBytes(long bytes)
{
string units = " kMGT";
double logBase = Math.Log((double)bytes, 1024.0);
double floorBase = Math.Floor(logBase);
return String.Format("{0:N2}{1}b",
Math.Pow(1024.0, logBase - floorBase),
units.Substring((int)floorBase, 1));
}