I'm looking for the simplest way to convert a string containing valid XML into an XmlElement object in C#.
How can you turn this into an XmlElement?
<item><name>wrench</name></item>
Use this:
private static XmlElement GetElement(string xml)
{
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
return doc.DocumentElement;
}
Beware!!
If you need to add this element to another document first you need to Import it using ImportNode.
Suppose you already had a XmlDocument with children nodes, And you need add more child element from string.
XmlDocument xmlDoc = new XmlDocument();
// Add some child nodes manipulation in earlier
// ..
// Add more child nodes to existing XmlDocument from xml string
string strXml =
#"<item><name>wrench</name></item>
<item><name>screwdriver</name></item>";
XmlDocumentFragment xmlDocFragment = xmlDoc.CreateDocumentFragment();
xmlDocFragment.InnerXml = strXml;
xmlDoc.SelectSingleNode("root").AppendChild(xmlDocFragment);
The Result:
<root>
<item><name>this is earlier manipulation</name>
<item><name>wrench</name></item>
<item><name>screwdriver</name>
</root>
Use XmlDocument.LoadXml:
XmlDocument doc = new XmlDocument();
doc.LoadXml("<item><name>wrench</name></item>");
XmlElement root = doc.DocumentElement;
(Or in case you're talking about XElement, use XDocument.Parse:)
XDocument doc = XDocument.Parse("<item><name>wrench</name></item>");
XElement root = doc.Root;
You can use XmlDocument.LoadXml() to do this.
Here is a simple examle:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml("YOUR XML STRING");
I tried with this snippet, Got the solution.
// Sample string in the XML format
String s = "<Result> No Records found !<Result/>";
// Create the instance of XmlDocument
XmlDocument doc = new XmlDocument();
// Loads the XML from the string
doc.LoadXml(s);
// Returns the XMLElement of the loaded XML String
XmlElement xe = doc.DocumentElement;
// Print the xe
Console.out.println("Result :" + xe);
If any other better/ efficient way to implement the same, please let us know.
Thanks & Cheers
Related
I am work on some innerxml of an XML document.
I have to concat several parts.
I have this:
<TRANFSERT><GOOD></GOOD></TRANSFERT>
I want to insert another part, <GOOD></GOOD>, before </TRANSFERT>.
I tried this:
int pos = xmldoc.indexOf("</GOOD>");
StringBuilder sb = new StringBuilder(xmlFinal);
sb.Append(xmlModifiee,pos,xmlModifiee.length);
xmlFinal = sb.ToString();
But it doesn't work.
How can I add a small part of XML in other XML?
You shouldn't interact with XML like with ordinary string.
Use provided System.Xml.XmlDocument or System.Xml.Linq.XDocument classes:
Ordinary XmlDocument single node selection and appending new element to it:
XmlDocument xmlDocument = new XmlDocument();
xmlDocument.Load("YourFile.xml");
XmlNode goodNode = xmlDocument.SelectSingleNode("TRANSFERT/GOOD");
XmlNode nodeToInsert = xmlDocument.CreateElement("INSERTEDNODE");
goodNode.AppendChild(nodeToInsert);
Ordinary XmlDocument iterating by nodes to find necessary (be aware for many-childed nodes) and add new child node to it:
XmlDocument xmlDocument = new XmlDocument();
xmlDocument.Load("YourFile.xml");
foreach (XmlNode rootNode in xmlDocument.ChildNodes)
{
if (rootNode.Name == "TRANSFERT")
{
foreach (XmlNode childNode in rootNode.ChildNodes)
{
if (childNode.Name == "GOOD")
{
XmlNode nodeToInsert = xmlDocument.CreateElement("INSERTEDNODE");
childNode.AppendChild(nodeToInsert);
}
}
}
}
Linq to XML variant:
XDocument xDoc = XDocument.Load("YourFIle.xml");
XElement rootElement = xDoc.Element("TRANSFERT");
XElement goodElement = rootElement.Element("GOOD");
goodElement.Add(new XElement("INSERTEDNODE"));
Simplified Linq to XML variant:
XDocument.Load("YourFIle.xml").Element("TRANSFERT").Element("GOOD").Add(new XElement("INSERTEDNODE"));
EDITED: answering the question, example was rewrited from changing InnerText values to Append/Add new child element to GOOD node.
StringBuilder.Append can only be used to add something to the end of the string. To add something inside the string, use StringBuilder.Insert like this:
sb.Insert(pos, xmlModifiee);
I'm getting data from a web service in my phone application and get the response to xmldocument like below.
XmlDocument XmlDoc = new XmlDocument();
XmlDoc.LoadXml(newx2);
Ther result of XmlDoc is like below.now I want to get the values from this.
<root>
<itinerary>
<FareIndex>0</FareIndex>
<AdultBaseFare>4719</AdultBaseFare>
<AdultTax>566.1</AdultTax>
<ChildBaseFare>0</ChildBaseFare>
<ChildTax>0</ChildTax>
<InfantBaseFare>0</InfantBaseFare>
<InfantTax>0</InfantTax>
<Adult>1</Adult>
<Child>0</Child>
<Infant>0</Infant>
<TotalFare>5285.1</TotalFare>
<Airline>AI</Airline>
<AirlineName>Air India</AirlineName>
<FliCount>4</FliCount>
<Seats>9</Seats>
<MajorCabin>Y</MajorCabin>
<InfoVia>P</InfoVia>
<sectors xmlns:json="http://james.newtonking.com/projects/json">
</itinerary>
</root>
I tried with this.
XmlNodeList xnList = XmlDoc.SelectNodes("/root[#*]");
but it gives null result. the count is 0. how can I read the data from this.hope your help with this.thanx.
You can use System.Xml.Linq.XElement to parse an xml:
XElement xRoot = XElement.Parse(xmlText);
XElement xItinerary = xRoot.Elements().First();
// or xItinerary = xRoot.Element("itinerary");
foreach (XElement node in xItinerary.Elements())
{
// Read node here: node.Name, node.Value and node.Attributes()
}
If you want to use XmlDocument you can do like this:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xmlText);
XmlNode itinerary = xmlDoc.FirstChild;
foreach (XmlNode node in itinerary.ChildNodes)
{
string name = node.Name;
string value = node.Value;
// you can also read node.Attributes
}
You can get the value of a particular element like,
var fareIndex = XmlDoc.SelectSingleNode("/root/itinerary/FareIndex").InnerText;
If you want to get the list of all elements that come under root/itinerary -
XmlNodeList xnList = XmlDoc.SelectNodes("/root/itinerary/*");
This link might help you.
I want to save my webpage in XML format. I thought of using XmlDocument to save the values. I tried searching it but I couldn't find a proper way for saving the data entered in a textbox to the xml document.
Is there any way? Although incorrect, but this is what I've done till now.
XmlDocument XDoc = new XmlDocument();
// Create root node.
XmlElement XElemRoot = XDoc.CreateElement("Generate_License");
//Add the node to the document.
XDoc.AppendChild(XElemRoot);
XmlElement Xsource = XDoc.CreateElement("General_Info", txtGInfo.ToString());
XElemRoot.AppendChild(Xsource);
You can try with - based on InnerText property
// Create the xml document containe
XmlDocument doc = new XmlDocument();// Create the XML Declaration, and append it to XML document
XmlDeclaration dec = doc.CreateXmlDeclaration("1.0", null, null);
doc.AppendChild(dec);// Create the root element
XmlElement root = doc.CreateElement("Generate_License");
XmlElement elem= doc.CreateElement("General_Info");
elem.InnerText =txtGInfo.Text;
root.AppendChild(elem);
doc.AppendChild(root);
try this,this is very simple. just that you will need 4.0 .net framework
XDocument doc =
new XDocument(
new XElement("Generate_License",
new XElement("General_Info", txtGInfo.ToString())
)
)
);
How do I get information from an xml document?
I have an xml document at c:\temp\data.xml and am using visual studio.
The closest I can figure is:
XmlDocument xdoc = new XmlDocument();
xdoc.Load(#"C:\temp\data.xml");
date = xdoc.SelectSingleNode("/forcast_informat…
The XML document looks like this:
<?xml version="1.0"?>
-<xml_api_reply version="1">
-<weather section="0" row="0" mobile_zipped="1" mobile_row="0" tab_id="0" module_id="0">
-<forecast_information>
etc etc...
<current_date_time data="2012-08-09 21:53:00 +0000"/>
etc, etc...
All I want to do is grab that date of 2012-08-09 21:53:00 +0000...any suggestions?
This should do the trick:
XmlDocument xdoc = new XmlDocument();
xdoc.Load(#"C:\temp\data.xml");
XmlNode dataAttribute = xdoc.SelectSingleNode("/xml_api_reply/weather/forecast_information/current_date_time/#data");
Console.WriteLine(dataAttribute.Value);
Try this. This will load current date and time for every forecast:
XmlDocument XMLDoc = new XmlDocument();
XMLDoc.Load(XMLDocumentPath);
XmlNodeList NodeList = XMLDoc.SelectNodes("/xml_api_reply/weather/forecast_information/");
foreach(XmlNode Node in NodeList)
{
string DTime = Node["current_date_time"].InnerText;
//Do something with DTime
}
I have XML stored in string variable:
<ItemMasterList><ItemMaster><fpartno>xxx</fpartno><frev>000</frev><fac>Default</fac></ItemMaster></ItemMasterList>
Here I want to change XML tag <ItemMasterList> to <Masterlist>. How can I do this?
System.Xml.XmlDocument and the associated classes in that same namespace will prove invaluable to you here.
XmlDocument doc = new XmlDocument();
doc.LoadXml(yourString);
XmlDocument docNew = new XmlDocument();
XmlElement newRoot = docNew.CreateElement("MasterList");
docNew.AppendChild(newRoot);
newRoot.InnerXml = doc.DocumentElement.InnerXml;
String xml = docNew.OuterXml;
I know i am a bit late, but just have to add this answer as no one seems to know about this.
XDocument doc = XDocument.Parse("<ItemMasterList><ItemMaster><fpartno>xxx</fpartno><frev>000</frev><fac>Default</fac></ItemMaster></ItemMasterList>");
doc.Root.Name = "MasterList";
Which returns the following:
<MasterList>
<ItemMaster>
<fpartno>xxx</fpartno>
<frev>000</frev>
<fac>Default</fac>
</ItemMaster>
</MasterList>
You can use LINQ to XML to parse the XML string, create a new root and add the child elements and attributes of the original root to the new root:
XDocument doc = XDocument.Parse("<ItemMasterList>...</ItemMasterList>");
XDocument result = new XDocument(
new XElement("Masterlist", doc.Root.Attributes(), doc.Root.Nodes()));
Using the XmlDocument way, you can do this as follows (and keep the tree intact):
XmlDocument oldDoc = new XmlDocument();
oldDoc.LoadXml("<ItemMasterList><ItemMaster><fpartno>xxx</fpartno><frev>000</frev><fac>Default</fac></ItemMaster></ItemMasterList>");
XmlNode node = oldDoc.SelectSingleNode("ItemMasterList");
XmlDocument newDoc = new XmlDocument();
XmlElement ele = newDoc.CreateElement("MasterList");
ele.InnerXml = node.InnerXml;
If you now use ele.OuterXml is will return: (you you just need the string, otherwise use XmlDocument.AppendChild(ele) and you will be able to use the XmlDocument object some more)
<MasterList>
<ItemMaster>
<fpartno>xxx</fpartno>
<frev>000</frev>
<fac>Default</fac>
</ItemMaster>
</MasterList>
As pointed by Will A, we can do it that way but for case where InnerXml equals the OuterXml the following solution will work out:
// Create a new Xml doc object with root node as "NewRootNode" and
// copy the inner content from old doc object using the LastChild.
XmlDocument docNew = new XmlDocument();
XmlElement newRoot = docNew.CreateElement("NewRootNode");
docNew.AppendChild(newRoot);
// The below line solves the InnerXml equals the OuterXml Problem
newRoot.InnerXml = oldDoc.LastChild.InnerXml;
string xmlText = docNew.OuterXml;