Cache delegate of compiled Dynamic Linq Func<> *without* params? - c#

I'm using the Dynamic.ParseLambda method from the Dynamic LINQ library to create expressions, compile each to a Func<>, and cache each in a dictionary:
// parse some dynamic expression using this ParseLambda sig:
Expression<Func<TArgument,TResult>> funcExpr =
System.Linq.Dynamic.ParseLambda<TArgument, TResult>(
expressionString, // string for dyn lambda expression
parameters); // object[] params
// then compile & cache the output of this as a delegate:
Func<TArgument,TResult> func = funcExpr.Compile(); //<-cache this
// then to execute, use:
return func(entityInstance);
The problem is, this forces me to cache a different delegate instance for every distinct set of parameter values. This seems kind of wasteful; all the overhead with Dynamic LINQ is in the parsing and compilation; once created, the delegates are near directly coded lambdas in performance. Is there any way to move the params outside of the expression, so I can pass different values to a common cached delegate in when I call it (instead of when I'm creating it)?
// e.g. with params...
return func(entityInstance,parameters);
// or if params are the issue, multiple signatures are ok:
return func(entityInstance, intValue, stringValue);
I don't see any parameter-free .ParseLambda or .Compile signatures in System.Linq.Dynamic, so my hopes aren't high. Anyone know of a quick way to achieve this?
Thanks!

There is a trick here, that I have used before; you do something like an Expression<Func<object[], object>>, and embed the fetch-by-index and casting inside the expression. Then you have as many parameters as you could want, a single signature, and reasonable performance. It does, however, make writing the lambda a bit tricker.
I don't have my old code for this "to hand", but if I needed to reverse engineer it, I would simply write something typical like the following, and then look in reflector to see what it used:
Expression<Func<object[], object>> func = arr => ((string)arr[0]) + (int)arr[1];
(in particular, paying attention to the indexer usage, the casting from inputs, and the casting to output)

Related

dynamic method invocation in expression tree

When constructing an expression tree, I have to use nodes invoking external methods in order to obtain values the expression could then continue evaluation with.
These methods are supplied as Func<T> and my code has no knowledge of where they originate from.
What is the most correct way of performing the mentioned invocation? I've tried something like this:
private Dictionary<string, Delegate> _externalSymbols;
private Expression _forExternalSymbol(string identifier)
{
Delegate method = _externalSymbols[identifier];
return Expression.Call(method.Method);
}
which works as long as the method fetched from the dictionary was created in compile-time. However, in case of Func<T> being a dynamic method obtained, for instance, by compiling another expression in runtime, this won't work out throwing
ArgumentException: Incorrect number of arguments supplied for call to method 'Int32 lambda_method(System.Runtime.CompilerServices.ExecutionScope)'
The desired effect may be achieved by wrapping the given function into one extra expression, but that seems quite hideous comparing to what it used to look like:
private Expression _forExternalSymbol(string identifier)
{
Delegate method = _externalSymbols[identifier];
Expression mediator = method is Func<double> ?
(Expression)(Expression<Func<double>>)(() => ((Func<double>)method)()) :
(Expression<Func<string>>)(() => ((Func<string>)method)());
return Expression.Invoke(mediator);
}
Also, this is hardly an extensible approach should I need to add support for types other than double and string.
I would like to know if there are better options which would work with dynamically created methods (preferably applicable to .NET 3.5).
which works as long as the method fetched from the dictionary was created in compile-time
No, it works as long as the method is static. For example, it also won't work if the delegate is a lambda that references something from its parent score (i.e. it's a closure).
The correct way to invoke a delegate is to use Expression.Invoke(). To get an Expression that represents your delegate, use Expression.Constant():
Expression.Invoke(Expression.Constant(method)))

Trying to understand what an expression tree is

Both snippets below product the same output.
I understand how Func encapsulates a method with a single parameter, and returns a bool value. And you can either assign it a
method, anonymous method or a lambda expression.
Func<int, bool> deleg = i => i < 5;
Console.WriteLine("deleg(4) = {0}", deleg(4));
Below is using expression trees which I don't fully understand yet. Why would I want to do it this way? Is it more flexible, what advantage does it give me?
System.Linq.Expressions.Expression<Func<int, bool>> expr = i => i < 5;
Func<int, bool> deleg2 = expr.Compile();
Console.WriteLine("deleg2(4) = {0}", deleg2(4));
Basically, the Expression tree is the body of a lambda expression, that allows you to
introspect the expression (see what's in it so to say)
manipulate the expression (simplify, extend (e.g. add new functionality or modify to work on different items).
Once you Compile() the expression, it is just another delegate, which you can only call, not inspect or modify.
Whenever you want to
create expressions dynamically (I mean: construct, not allocate)
operate on expressions dynamically
the Function<> types are not sufficient.
The point of expression trees is that you can do more with them than just compile them to a function. You can inspect them, modify them and compile them to something other than .net functions.
For example Linq2SQL compiles expression trees to SQL code. You couldn't do that with a plain .net function.
In your first example you just have "hardcoded" the body of the function and assigned it to a delegate.
In your second example the assignment constructs an expression-tree which is an object model reprensenting your code in a data structure in memory.
The advantage is that you can modify and inspect that datastructure.
LINQ2SQL for example uses that technique to translate your expressions to another language called SQL.
Expression trees are regular in-memory data structures that can be traversed programmatically and the result of such traversal can be something, like a query you'd like to send to the database. Read more on the ExpressionVisitor class to see how it is done.
On the other hand, the compiled function is nothing more than a sequence of CIL code. You still can inspect it programmatically but you are not inspecting the definition but rather - the compiler output of it.

Calculating expression tree with many parameters

I'm trying to use the Expression tree and Lamdba Expression objects in .Net 3.5 to allow me to dynamically calculate boolean expression entered by a user.
So far a user can create an expression tree consisting of BinarayExpressions that AND and OR values expressed as ParameterExpressions. I was then planning on creating a LambdaExpression based on that tree so that I could compile the expression into a delegate which I could then call. The issue I'm having is that I don't know how many input parameters the user will need so when I come to compile the expression into a delegate I don't know the method what the method signature should be until runtime.
So far I've come up with two possible solutions.
Create a whole bunch of delegates
like the Func<bool, bool, bool...> ones which can
take as many parameters as I think a user might possibly need. This doesn't feel like the most elegant solution but I think it would work, until someone wants to use one more parameter than I've catered for.
Pass in an array of values and somehow assign them to my parameters using the array indexer. I've thought about this but can't work out how it work.
NB: It needs to be quick so no boxing or anything like that.
I did exactly this before, using the array approach (for Finguistics, as it happens). The trick is Expression.ArrayIndex:
var arr = Expression.Parameter(typeof(int[]), "arr");
var body = Expression.ArrayIndex(arr, Expression.Constant(1));
var expr = Expression.Lambda<Func<int[], int>>(body, arr);
var func = expr.Compile();
int[] vals = { 7, 8, 9 };
int i = func(vals);
The advantage of the array approach is that you can keep a strongly typed delegate type (Func<int[],int> or similar, no matter the number of arguments. And typed Invoke is much faster than DynamicInvoke.
If the values aren't all of the same type - that is doable too; let me know and I'll add an example.

Is it possible to cast a delegate instance into a Lambda expression?

Here the context for my question:
A common technique is to declare the parameter of a method as a Lambda expression rather than a delegate. This is so that the method can examine the expression to do interesting things like find out the names of method calls in the body of the delegate instance.
Problem is that you lose some of the intelli-sense features of Resharper. If the parameter of the method was declared as a delegate, Resharper would help out when writing the call to this method, prompting you with the x => x syntax to supply as the argument value to this method.
So... back to my question I would like to do the follow:
MethodThatTakesDelegate(s => s.Length);
}
private void MethodThatTakesDelegate(Func<string, object> func)
{
//convert func into expression
//Expression<Func<string, object>> expr = "code I need to write"
MethodThatTakesExpression(expr);
}
private void MethodThatTakesExpression(Expression<Func<string, object>> expr)
{
//code here to determine the name of the property called against string (ie the Length)
}
Everywhere that you're using the term "lambda expression" you actually mean "expression tree".
A lambda expression is the bit in source code which is
parameters => code
e.g.
x => x * 2
Expression trees are instances of the System.Linq.Expressions.Expression class (or rather, one of the derived classes) which represent code as data.
Lambda expressions are converted by the compiler into either expression trees (or rather, code which generates an expression tree at execution time) or delegate instances.
You can compile an instance of LambdaExpression (which is one of the subclasses of Expression) into a delegate, but you can't go the other way round.
In theory it might be possible to write such a "decompiler" based on the IL returned by MethodBase.GetMethodBody in some situations, but currently there are various delegates which can't be represented by expression trees. An expression tree represents an expression rather than a statement or statement block - so there's no looping, branching (except conditionals), assignment etc. I believe this may change in .NET 4.0, though I wouldn't expect a decompilation step from Microsoft unless there's a really good reason for one.
I don't believe it's possible to achieve what you'd like here. From the comments in your code it looks like you are attempting to capture the name of the property which did the assignment in MethodThatTakesExpression. This requires an expression tree lambda expression which captures the contexnt of the property access.
At the point you pass a delegate into MethodThatTakesDelegate this context is lost. Delegates only store a method address not any context about the method information. Once this conversion is made it's not possible to get it back.
An example of why this is not possible is that there might not even be a named method backing a delegate. It's possible to use ReflectionEmit to generate a method which has no name whatsoever and only exists in memory. It is possible though to assign this out to a Func object.
No, it is not possible.

Confused about LINQ parameters

I am trying to understand LINQ and become confident at using it. What I am struggling with are the parameters asked for. Example:
var sortedWords = words.OrderBy(a=>a.Length)
words is an array collection. OrderBy's intellisense says:
Func<string, TKey> keyselector
A func executes a method, and a string is the value, TKey a key.
In the example http://msdn.microsoft.com/en-us/vcsharp/aa336756.aspx#thenBySimple (ThenBy - Comparer), we compare length by saying a => a.Length. I understand that syntax, but how is that related to what the intellisense is asking for?
I tend to find the method signature and intellisense unreadable because of all the generics.
Thanks.
The type (as displayed by Intellisense) makes sense if you understand the nature of lambda expressions in .NET/C#. Otherwise, it can indeed seem a bit strange to the newcomer. Begin by considering that the type of keySelector, Func<TSource, TKey> is simply a delegate. Before C# 3.0, you would call such a method by passing a delegate as a parameter, for example:
IEnumerable<string> sortedWords = words.OrderBy(new Func<string, int>(mySelectorMethod));
where mySelectorMethod is the name of an ordinary method which takes a string as a parameter and returns an int. (As a side point, I suppose you could use anonymous delegates, but let's not go there for now.) Also, note that this example is purely illustrative, as LINQ is almost always used with .NET 3.5/C# 3.0 (though I believe it can be used with either/both .NET 2.0/C# 2.0 - someone correct me if I'm wrong). Since C# 3.0, methods can be defined inline as lambda expressions, which are intended to be used in precisely such circumstances as these. Read over the MSDN article on lambda expressions (linked above) if you want to get a proper introduction, but here I will simply describe the use in this specific context. As you state, your code (in C# 3.0) is something like the following:
var sortedWords = words.OrderBy(a => a.Length);
The part of the expression that is a => a.Length is the lambda expression, which is really just shorthand for declaring a function inline. The syntax of lambda expressions is quite simple for the most part; to the left of the => the arguments are specified, generally in the form (arg1, arg2, arg3), but since there's only one in this case you can omit the brackets. To the right of the => is the expression that is the return value of the function (lambda expression more accurately). Alternatively you can enclose actual code with a return statement within { and } though this is usually unnecessary. What I believe the C# compiler does is recognises the parameter passed to OrderBy as a lambda expression and then compiles it into a function and creates and passes the delegate for you. Note that lambda expressions can also be converted to System.Linq.Expressions.Expression objects (accessible expression trees) instead of delegates, but this is a much less common usage. Anyway, there's a lot going on behind the scenes here, but hopefully this should at least clarify why the type is Func<TSource, TKey> and how it relates to the lambda expression. As I said, read up on MSDN if you want a deeper understanding of LINQ/lambdas/delegates...
a => a.Length
I understand that syntax, but how is that related to what the intellisense is asking for?
This chunk of code is a lambda expression. A lambda expression is a handy way of generating an Anonymous method (in this case), or a System.Linq.Expressions.Expression . Let's break it down by parts.
The most noticeable feature is the =>, which seperates parameters from a method body.
On the left side of the =>, there is a symbol: a. This is the declaration of a parameter for our anonymous method. The compiler is aware that we are calling OrderBy(), and that OrderBy requires a Func<string, object>. The parameter for such a function is a string, so the compiler determines that a must be a string. The only thing the programmer needed to provide is a name.
On the right side of the =>, there is method body. Since this is a one-liner, the return keyword is implied. The IDE provides intellisense against a as a string, which allows you to use the Length property.
Now, consider this C# 2.0 ...
IEnumerable<string> sortedWords =
Enumerable.OrderBy(words, delegate(string a) {return a.Length;});
With the C# 3.0
IEnumerable<string> sortedWords = words
.OrderBy(a => a.Length);
I think the IntelliSense is actually quite useful, especially for generic methods that take Func<..> type as an argument, because you can see the types and types guide you to understand what the method might do.
For example, the arguments for OrderBy are IEnumerable<string> as a 'this' argument, which means that we have some input containing collection of strings. The first argument keySelector has a type Func<string, TKey>, which means that it is some lambda expression you provide that specifies how to get TKey from string.
This already suggests that the method will probably enumerate over all the items (strings) in the collection and it can use the keySelector to get value of type TKey from every element in the collection. The name TKey already suggests that it will use this value to compare the elements (strings) using this calculated key. However, if you look at the other overload that takes IComparer<TKey> then you can be sure about this - this argument specifies more details about how do you want to compare two values of type TKey, so the function must compare the elements using this key.
... this kind of thinking about types takes some time to get used to, but once you'll learn it, it can be extremely helpful. It is more useful in "functional" style of code, which often uses a lot of generics and lamdba expressions in C# 3.0 (and similar things in functional languages like F# or others)
I never really worry about the Intellisense, to be honest. It was messing me up early in my Linqage. As I spent more time with generics and expressions, it started to make sense, but up until then I just pumped in the syntax.
What it wants is a lambda expression that tells Linq what to look for in order to sort your collection.
I feel you, my brother, hang in there and it will make sense very soon.
OrderBy() takes a delegate for a function that accepts a single parameter (in your case, a string) and returns a value of the type that is substituted for TKey. It may be that the parameter type (string) was already determined since you called the method on an IEnumerable<string> but the delegate type will only be resolved as Func<string, int> after it infers it from the lambda expression when it is fully specified (i.e., a => a.Length). If you haven't given the parser any clues as to what you want as a sort key, it'll just show TKey in IntelliSense until it can determine the intended type.

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