How to find whether a string array contains some part of string?
I have array like this
String[] stringArray = new [] { "abc#gmail.com", "cde#yahoo.com", "#gmail.com" };
string str = "coure06#gmail.com"
if (stringArray.Any(x => x.Contains(str)))
{
//this if condition is never true
}
i want to run this if block when str contains a string thats completely or part of any of array's Item.
Assuming you've got LINQ available:
bool partialMatch = stringArray.Any(x => str.Contains(x));
Even without LINQ it's easy:
bool partialMatch = Array.Exists(stringArray, x => str.Contains(x));
or using C# 2:
bool partialMatch = Array.Exists(stringArray,
delegate(string x) { return str.Contains(x)); });
If you're using C# 1 then you probably have to do it the hard way :)
If you're looking for if a particular string in your array contains just "#gmail.com" instead of "abc#gmail.com" you have a couple of options.
On the input side, there are a variety of questions here on SO which will point you in the direction you need to go to validate that your input is a valid email address.
If you can only check on the back end, I'd do something like:
emailStr = "#gmail.com";
if(str.Contains(emailStr) && str.length == emailStr.length)
{
//your processing here
}
You can also use Regex matching, but I'm not nearly familiar enough with that to tell you what pattern you'd need.
If you're looking for just anything containing "#gmail.com", Jon's answer is your best bets.
Related
I'm using this code to check if the string (oCode/ originalCode) exists in the array (the string is written by user):
if (dic.cs.Any(code.Contains)) //dic.cs is in another class (cs is the array), the code variable is what I look for in the array
{
//I want to get the string was found in the array with the "Contains" function
}
I want to get the string that was found in the array with the Contains() function.
If it's possible to have multiple matches, then use this:
var foundCodes = dic.cs.Where(code.Contains);
foreach(var foundCode in foundCodes)
{
}
Otherwise:
var foundCode = dic.cs.FirstOrDefault(code.Contains);
if (!String.IsNullOrEmpty(foundCode))
{
}
You need a lambda expression in the Any method:
https://code.msdn.microsoft.com/LINQ-Quantifiers-f00e7e3e#AnySimple
var answer = yourArray.any(a => a == "WhatYouAreLookingFor");
if answer is true, then you found it.
I believe what you need is the array IndexOf method. https://msdn.microsoft.com/en-us/library/system.array.indexof(v=vs.110).aspx
Please note, the 'C#' tag was included intentionally, because I could accept C# syntax for my answer here, as I have the option of doing this both client-side and server-side. Read the 'Things You May Want To Know' section below. Also, the 'regex' tag was included because there is a strong possibility that the use of regular expressions is the best approach to this problem.
I have the following highlight Plug-In found here:
http://johannburkard.de/blog/programming/javascript/highlight-javascript-text-higlighting-jquery-plugin.html
And here is the code in that plug-in:
/*
highlight v4
Highlights arbitrary terms.
<http://johannburkard.de/blog/programming/javascript/highlight-javascript-text-higlighting-jquery-plugin.html>
MIT license.
Johann Burkard
<http://johannburkard.de>
<mailto:jb#eaio.com>
*/
jQuery.fn.highlight = function(pat) {
function innerHighlight(node, pat) {
var skip = 0;
if (node.nodeType == 3) {
var pos = node.data.toUpperCase().indexOf(pat);
if (pos >= 0) {
var spannode = document.createElement('span');
spannode.className = 'highlight';
var middlebit = node.splitText(pos);
var endbit = middlebit.splitText(pat.length);
var middleclone = middlebit.cloneNode(true);
spannode.appendChild(middleclone);
middlebit.parentNode.replaceChild(spannode, middlebit);
skip = 1;
}
}
else if (node.nodeType == 1 && node.childNodes && !/(script|style)/i.test(node.tagName)) {
for (var i = 0; i < node.childNodes.length; ++i) {
i += innerHighlight(node.childNodes[i], pat);
}
}
return skip;
}
return this.length && pat && pat.length ? this.each(function() {
innerHighlight(this, pat.toUpperCase());
}) : this;
};
jQuery.fn.removeHighlight = function() {
return this.find("span.highlight").each(function() {
this.parentNode.firstChild.nodeName;
with (this.parentNode) {
replaceChild(this.firstChild, this);
normalize();
}
}).end();
};
This plug-in works pretty easily.
If I wanted to highlight all instances of the word "Farm" within the following element...(cont.)
<div id="#myDiv">Farmers farm at Farmer's Market</div>
...(cont.) all I would need to do is use:
$("#myDiv").highlight("farm");
And then it would highlight the first four characters in "Farmers" and "Farmer's", as well as the entire word "farm" within the div#myDiv
No problem there, but I would like it to use this:
$("#myDiv").highlight("Farmers");
And have it highlight both "Farmers" AND "Farmer's". The problem is, of course, that I don't know the value of the search term (The term "Farmers" in this example) at runtime. So I would need to detect all possibilities of no more than one apostrophe at each index of the string. For instance, if I called $("#myDiv").highlight("Farmers"); like in my code example above, I would also need to highlight each instance of the original string, plus:
'Farmers
F'armers
Fa'rmers
Far'mers
Farm'ers
Farme'rs
Farmer's
Farmers'
Instances where two or more apostrophes are found sid-by-side, like "Fa''rmers" should, of course, not be highlighted.
I suppose it would be nice if I could include (to be highlighted) words like "Fa'rmer's", but I won't push my luck, and I would be doing well just to get matches like those found in my bulleted list above, where only one apostrophe appears in the string, at all.
I thought about regex, but I don't know the syntax that well, not to mention that I don't think I could do anything with a true/false return value.
Is there anyway to accomplish what I need here?
Things You May Want To Know:
The highlight plug-in takes care of all the case insensitive requirements I need, so no need to worry about that, at all.
Syntax provided in JavaScript, jQuery, or even C# is acceptable, considering the hidden input fields I use the values from, client-side, are populated, server-side, with my C# code.
The C# code that populates the hidden input fields uses Razor (i.e., I am in a C#.Net Web-Pages w/ WebMatrix environment. This code is very simple, however, and looks like this:
for (var n = 0; n < searchTermsArray.Length; n++)
{
<input class="highlightTerm" type="hidden" value="#searchTermsArray[n]" />
}
I'm copying this answer from your earlier question.
I think after reading the comments on the other answers, I've figured out what it is you're going for. You don't need a single regex that can do this for any possible input, you already have input, and you need to build a regex that matches it and its variations. What you need to do is this. To be clear, since you misinterpreted in your question, the following syntax is actually in JavaScript.
var re = new RegExp("'?" + "farmers".split("").join("'?") + "'?", "i")
What this does is take your input string, "farmers" and split it into a list of the individual characters.
"farmers".split("") == [ 'f', 'a', 'r', 'm', 'e', 'r', 's' ]
It then stitches the characters back together again with "'?" between them. In a regular expression, this means that the ' character will be optional. I add the same particle to the beginning and end of the expression to match at the beginning and end of the string as well.
This will create a regex that matches in the way you're describing, provided it's OK that it also matches the original string.
In this case, the above line builds this regex:
/'?f'?a'?r'?m'?e'?r'?s'?/
EDIT
After looking at this a bit, and the function you're using, I think your best bet will be to modify the highlight function to use a regex instead of a straight string replacement. I don't think it'll even be that hard to deal with. Here's a completely untested stab at it.
function innerHighlight(node, pat) {
var skip = 0;
if (node.nodeType == 3) {
var matchResult = pat.exec(node.data); // exec the regex instead of toUpperCase-ing the string
var pos = matchResult !== null ? matchResult.index : -1; // index is the location of where the matching text is found
if (pos >= 0) {
var spannode = document.createElement('span');
spannode.className = 'highlight';
var middlebit = node.splitText(pos);
var endbit = middlebit.splitText(matchResult[0].length); // matchResult[0] is the last matching characters.
var middleclone = middlebit.cloneNode(true);
spannode.appendChild(middleclone);
middlebit.parentNode.replaceChild(spannode, middlebit);
skip = 1;
}
}
else if (node.nodeType == 1 && node.childNodes && !/(script|style)/i.test(node.tagName)) {
for (var i = 0; i < node.childNodes.length; ++i) {
i += innerHighlight(node.childNodes[i], pat);
}
}
return skip;
}
What I'm attempting to do here is keep the existing logic, but use the Regex that I built to do the finding and splitting of the string. Note that I'm not doing the toUpper call anymore, but that I've made the regex case insensitive instead. As noted, I didn't test this at all, but it seems like it should be pretty close to a working solution. Enough to get you started anyway.
Note that this won't get you your hidden fields. I'm not sure what you need those for, but this will (if it's right) take care of highlighting the string.
Good Morning,
In an if statement if we want to check if a string contains a value, we have :
if (string.Contains("Value1"))
{
}
How can we make the string compare with more values in an if statement without keep writing the whole statement? For example to avoid the below statement
if ((string.Contains("Value1") && (string.Contains("Value2")) && (string.Contains("Value3")))
{
}
Thank you
So, basically, you want to check if all of your values are contained in the string . Fortunately (with the help of LINQ), this can by translated almost literally into C#:
var values = new String[] {"Value1", "Value2", "Value3"};
if (values.All(v => myString.Contains(v))) {
...
}
Similarly, if you want to check if any value is contained in the string, you'd substitute All by Any.
Well, you could use LINQ:
string[] requiredContents = { "Foo", "Bar", "Baz" };
if (requiredContents.All(x => text.Contains(x))
{
...
}
Note that just like the short-circuiting && operator, All will stop as soon as it finds a value which doesn't satisfy the condition. (If you want to use Any in a similar way elsewhere, that will stop as soon as it finds a value which does satisfy the condition.)
I wouldn't bother for only a reasonably small number though. Without the extraneous brackets, it's really not that bad:
if (text.Contains("foo") && text.Contains("bar") && text.Contains("Baz"))
{
}
I would only start using the more general form if either there were genuinely quite a few values (I'd probably draw the line at about 5) or if the set of values was being passed in as a parameter, or varied in some other way.
As you need "your" string to contains all values:
var values = new String[] {"Value1", "Value2", "Value3"};
var s = yourString;
if (values.Count(v => s.Contains(v)) == values.Length) {
...
}
Is this the best solution? Probably not. Is it readable and extendable? Yes.
var matches = {"string1", "string2", "string3","string-n"};
var i = 0;
foreach(string s in matches)
{
if(mystring.Contains(s))
{
i++;
}
}
if(i == matches.Length)
{
//string contains all matches.
}
if(stringArray.Any(s => stringToCheck.Contains(s)))
If you want to ensure that it contains all the substrings, change Any to All:
if(stringArray.All(s => stringToCheck.Contains(s)))
Lets say I have several short string:
string[] shortStrings = new string[] {"xxx","yyy","zzz"};
(this definition can change length on array and on string too, so not a fixed one)
When a given string, I like to check if it combines with the shortStrings ONLY, how?
let say function is like bool TestStringFromShortStrings(string s)
then
TestStringFromShortStrings("xxxyyyzzz") = true;
TestStringFromShortStrings("xxxyyyxxx") = true;
TestStringFromShortStrings("xxxyyy") = true;
TestStringFromShortStrings("xxxxxx") = true;
TestStringFromShortStrings("xxxxx") = false;
TestStringFromShortStrings("xxxXyyyzzz") = false;
TestStringFromShortStrings("xxx2yyyxxx") = false;
Please suggest a memory not tense and relatively fast method.
[EIDT] What this function for?
I will personally use this function to test if a string is a combination of a PINYIN ok, some Chinese stuff. Following Chinese are same thing if you cannot read it.
检测一个字符串是否为汉语拼音（例如检测是否拼音域名）
所有的汉语拼音字符串有：
(To detect whether a string is Hanyu Pinyin (e.g. detect the phonetic domain) of the Pinyin string:)
Regex PinYin = new Regex(#"^(a|ai|an|ang|ao|ba|bai|ban|bang|bao|bei|ben|beng|bi|bian|biao|bie|bin|bing|bo|bu|ca|cai|can|cang|cao|ce|cen|ceng|cha|chai|chan|chang|chao|che|chen|cheng|chi|chong|chou|chu|chua|chuai|chuan|chuang|chui|chun|chuo|ci|cong|cou|cu|cuan|cui|cun|cuo|da|dai|dan|dang|dao|de|den|dei|deng|di|dia|dian|diao|die|ding|diu|dong|dou|du|duan|dui|dun|duo|e|ei|en|eng|er|fa|fan|fang|fei|fen|feng|fo|fou|fu|ga|gai|gan|gang|gao|ge|gei|gen|geng|gong|gou|gu|gua|guai|guan|guang|gui|gun|guo|ha|hai|han|hang|hao|he|hei|hen|heng|hong|hou|hu|hua|huai|huan|huang|hui|hun|huo|ji|jia|jian|jiang|jiao|jie|jin|jing|jiong|jiu|ju|juan|jue|jun|ka|kai|kan|kang|kao|ke|ken|keng|kong|kou|ku|kua|kuai|kuan|kuang|kui|kun|kuo|la|lai|lan|lang|lao|le|lei|leng|li|lia|lian|liang|liao|lie|lin|ling|liu|long|lou|lu|lv|luan|lue|lve|lun|luo|ma|mai|man|mang|mao|me|mei|men|meng|mi|mian|miao|mie|min|ming|miu|mo|mou|mu|na|nai|nan|nang|nao|ne|nei|nen|neng|ni|nian|niang|niao|nie|nin|ning|niu|nong|nou|nu|nv|nuan|nuo|nun|ou|pa|pai|pan|pang|pao|pei|pen|peng|pi|pian|piao|pie|pin|ping|po|pou|pu|qi|qia|qian|qiang|qiao|qie|qin|qing|qiong|qiu|qu|quan|que|qun|ran|rang|rao|re|ren|reng|ri|rong|rou|ru|ruan|rui|run|ruo|sa|sai|san|sang|sao|se|sen|seng|sha|shai|shan|shang|shao|she|shei|shen|sheng|shi|shou|shu|shua|shuai|shuan|shuang|shui|shun|shuo|si|song|sou|su|suan|sui|sun|suo|ta|tai|tan|tang|tao|te|teng|ti|tian|tiao|tie|ting|tong|tou|tu|tuan|tui|tun|tuo|wa|wai|wan|wang|wei|wen|weng|wo|wu|xi|xia|xian|xiang|xiao|xie|xin|xing|xiong|xiu|xu|xuan|xue|xun|ya|yan|yang|yao|ye|yi|yin|ying|yo|yong|you|yu|yuan|yue|yun|za|zai|zan|zang|zao|ze|zei|zen|zeng|zha|zhai|zhan|zhang|zhao|zhe|zhei|zhen|zheng|zhi|zhong|zhou|zhu|zhua|zhuai|zhuan|zhuang|zhui|zhun|zhuo|zi|zong|zou|zu|zuan|zui|zun|zuo)+$");
用下面的正则表达式方法，试过了，最简单而且效果非常好，就是有点慢:(
递归的方式对长字符串比较麻烦，容易内存溢出
(Tried it with the regular expression: it's the most simple and gives very good results, but it's a bit slow. The recursive way on the long string is too much trouble, it's too easy to overflow the stack.)
Edit: Simplified this a lot thanks to L.B and millimoose.
Regular Expressions to the rescue! Using System.Text.RegularExpressions.Regex, we get:
public static bool TestStringFromShortStrings(string checkText, string[] pieces) {
// Build the expression. Ultimate result will be
// of the form "^(xxx|yyy|zzz)+$".
var expr = "^(" +
String.Join("|", pieces.Select(Regex.Escape)) +
")+$";
// Check whether the supplied string matches the expression.
return Regex.IsMatch(checkText, expr);
}
This should be able to properly handle cases that have multiple repeated patterns of different lenghts. E.g. if you the list of possible pieces includes strings "xxx" and "xxxx".
Copy the target string to string builder. For each string in shortstring array, remove all occurences from target. If u end up in zero length string, true else false.
Edit:
This approach is not correct. Please refer to comments. Keeping this answer still here as it may look reasonably correct initially.
You could compare the start of the input string with each of the short strings. As soon as you have a match, you take the rest of the string and repeat. As soon as you have no more string left, you're done. For example:
string[] shortStrings = new string[] { "xxx", "yyy", "zzz" };
bool Test(string input)
{
if (input.Length == 0)
return true;
foreach (string shortStr in shortStrings)
{
if (input.StartsWith(shortStr))
{
if (Test(input.Substring(shortStr.Length)))
return true;
}
}
return false;
}
You might optimize this by removing the recursion, or by sorting the short strings and do a binary instead of a linear search.
Here is a non-recursive version, that uses a Stack object instead. No chance of getting a StackOverflowException:
string[] shortStrings = new string[] { "xxx", "yyy", "zzz" };
bool Test(string input)
{
Stack<string> stack = new Stack<string>();
stack.Push(input);
while (stack.Count > 0)
{
string str = stack.Pop();
if (str.Length == 0)
return true;
foreach (string shortStr in shortStrings)
{
if (str.StartsWith(shortStr))
stack.Push(str.Substring(shortStr.Length));
}
}
return false;
}
I have a list that needs ordering say:
R1-1
R1-11
R2-2
R1-2
this needs to be ordered:
R1-1
R1-2
R1-11
R2-2
Currently I am using the C# Regex.Replace method and adding a 0 before the occurance of single numbers at the end of a string with something like:
Regex.Replace(inString,#"([1-9]$)", #"0$2")
I'm sure there is a nicer way to do this which I just can't figure out.
Does anyone have a nice way of sorting letter and number strings with regex?
I have used Greg's method below to complete this and just thought I should add the code I am using for completeness:
public static List<Rack> GetRacks(Guid aisleGUID)
{
log.Debug("Getting Racks with aisleId " + aisleGUID);
List<Rack> result = dataContext.Racks.Where(
r => r.aisleGUID == aisleGUID).ToList();
return result.OrderBy(r => r.rackName, new NaturalStringComparer()).ToList();
}
I think what you're after is natural sort order, like Windows Explorer does? If so then I wrote a blog entry a while back showing how you can achieve this in a few lines of C#.
Note: I just checked and using the NaturalStringComparer in the linked entry does return the order you are looking for with the example strings.
You can write your own comparator and use regular expressions to compare the number between "R" and "-" first, followed by the number after "-", if the first numbers are equal.
Sketch:
public int Compare(string x, string y)
{
int releaseX = ...;
int releaseY = ...;
int revisionX = ...;
int revisionY = ...;
if (releaseX == releaseY)
{
return revisionX - revisionY;
}
else
{
return releaseX - releaseY;
}
}