Some sample code:
var psi = new ProcessStartInfo();
psi.FileName = "path to update.exe";
psi.Arguments = "arguments for update.exe";
psi.Verb = "runas";
var process = new Process();
process.StartInfo = psi;
process.Start();
process.WaitForExit();
Ref: 0xA3.
Programmatically in code what type of objects if possible could you pass into the '.Arguments' property? Typically you can pass an int or a string type. I want to know if you could pass in a more complicated type like a DirectoryInfo[] or a FileInfo[]? Would anyone know if this is possible? If not i'll have to come up with something else?
Why? I am trying to remove some problem code from a very large background worker and the only solution is to pass the data I require into a process that will handle the work I need doing in a completey different process. Problem this problem code always throws up on permissions - permissions the app does not have.
Serialize the data then you can "pipe" the resulting string into the other process's standard input. See example of "Process.StandardInput Property" help topic at http://msdn.microsoft.com/en-us/library/system.diagnostics.process.standardinput.aspx
Serialize the data, store into a file then have other process read this file, passing the path to the file in Arguments.
- Allocate the object into global memory then pass the resulting IntPtr, in Arguments, to the other process.
The arguments are exactly what you'd type (with leading and trailing quotes), if you were running the .exe from the command prompt.
Use strings.
As defined the Arguments property is of type string so you could only pass space delimited arguments to the process the same way you would when calling it at the command line.
No, this isn't possible.
You should consider making a new AppDomain in your existing process.
Related
Have been searching, but surprisingly could not find this specific question:
With C# I want (by clicking a button in a form) to run a certain file, with an certain application.
When using "Process.start(variable)" I can only pick one of the two.
And by using "Process.startinfo.filename" (like: https://learn.microsoft.com/en-us/dotnet/api/system.diagnostics.processstartinfo.filename?view=net-5.0) this also seems to be the case.
Isn't is possible to just combine both in some "easy" way?
Thanks.
Typically you would run a file with an application using a command argument (i.e. 'notepad.exe file.txt').
If that is possible with the application(s) you are attempting to launch, then you would simply need to set the Filename property of StartInfo to the name, if in the PATH, or the full path of the application and the Arguments property to the path of the file.
var process = new Process();
process.StartInfo.FileName = "notepad.exe";
process.StartInfo.Arguments = "C:\\{pathToFile}\\file.txt";
process.Start();
The above code would launch notepad opening file.txt. You can simply replace the FileName and Arguments with variables containing the paths to the application and file.
I need help in trying to execute an executable from my C# application.
Suppose the path is cPath, the EXE is HHTCtrlp.exe and the parameter that has to be passed is cParams.
How would I go about this?
The reason why the path is a variable is that there are 3 different EXE files to run and the path will change depending on which one will run, same with the parameter string.
Any help would be greatly appreciated.
To start the process with parameters, you can use following code:
string filename = Path.Combine(cPath,"HHTCtrlp.exe");
var proc = System.Diagnostics.Process.Start(filename, cParams);
To kill/exit the program again, you can use following code:
proc.CloseMainWindow();
proc.Close();
System.Diagnostics.Process.Start("PATH to exe", "Command Line Arguments");
ProcessStartInfo startInfo = new ProcessStartInfo(string.Concat(cPath, "\\", "HHTCtrlp.exe"));
startInfo.Arguments =cParams;
startInfo.UseShellExecute = false;
System.Diagnostics.Process.Start(startInfo);
I looked around for a while and didn't find many promising articles on the question I have.
I am attempting to write a program that will query users for the path to a file using the openFileDialog and saving the output to a string in C#. What I want to do with it, is use said path in a command script that will copy the file to another part of the computer for use by the program that I am writing.
I am pretty new to C#, so the dummy version, if possible, would be appreciated. I so far understand that I have to set up a new process to run batch commands in general, but I never could find good examples of how to pass C# strings to the batch script.
Thanks
Why not just use .NET's built in Copy method? You can use a Backgroundworker or a Task to make this occur on a different thread, also.
If you must spin up a separate process, then you can use Process.Start with ProcessInfo set up to the path and pass the arguments in that way.
If your script is long, I would use a StringBuilder then write the string to a file:
// set srcFilename and xcopyOptions (like /Y, for example)
var sb = new StringBuilder();
sb.Append( "XCOPY " )
.Append( xcopyOptions )
.Append( " " )
.Append( srcFilename )
.Append( " " )
.AppendLine( dstDir );
// repeat for as many copy commands as you want
// ...
File.WriteAllText( scriptFilename, sb.ToString() );
In addition to already available post, if you really want to use a batch, to pass a variable to it is the same like a pass arguments to an executable.
instance process , where "ececutable" is a batch file
assign arguments, which will be passed like a parameters to the variables of the batch.
Process thisProcess = new Process();
thisProcess.StartInfo.CreateNoWindow = true; //NO NEED OF WINDOW
thisProcess.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
thisProcess.StartInfo.WorkingDirectory = #"DirectoryOfTheBacth";
thisProcess.StartInfo.FileName = "BatchFileName";
thisProcess.StartInfo.Arguments = "parameters";
thisProcess.StartInfo.UseShellExecute = false; //NO SHELL EXECUTE
thisProcess.StartInfo.RedirectStandardOutput = true; //STDO REDIRECTION, SO WE CAN READ WHAT IS HAPPENNING
thisProcess.Start(); // FINALLY, START PROCESS
How to pass parameter from C# to a batch file?
I have an Console application which runs as background process and there is an exe which needs to be called.This exe takes complete fill path as parameter and then encrypts that file.
I did this way :
Process.Start( "myapp.exe" );
But what i want is this :
Process.Start( "myapp.exe file1.txt" ); // File1 is parameter of that exe
But this is not working.
Looking for help & advice.
Thanks :)
You want to use the ProcessStartInfo class.
See http://msdn.microsoft.com/en-us/library/system.diagnostics.process.startinfo.aspx and http://msdn.microsoft.com/en-us/library/system.diagnostics.processstartinfo.aspx for an example on how to use this.
Use the Arguments property to set your arguments.
Use something like this:
Process p = new Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.FileName = "myApp.exe";
p.StartInfo.Arguments = "file1.txt";
p.Start();
Try Process.Start("myapp.exe", "file1.txt");
Process.Start("[drive]:\[directory]\myapp.exe", "file1.txt");
Substitute the actual drive and directory where indicated
Process.Start(<the nameof the process>,<the parameters>)
In your case
Process.Start("myapp.exe","file1.txt")
I am trying to launch the default application registered for an extension specifying an additional argument:
ProcessStartInfo p = new ProcessStartInfo();
p.Arguments = "myargument";
p.FileName = "file.ext";
Process.Start(p);
The application starts correctly opening the specified file.
The problem is that it is getting just one parameter (the name of the file), totally ignoring the additional "Arguments".
Is it possible to do what I want?
Am I doing something wrong?
Thanks in advance for any help,
Paolo
I believe this is expected. Behind the scenes, Windows is finding the default application in the registry and creating a new process and passing your file name to it. I get the same behavior if I go to a command prompt and type "filename.ext argument", that my arguments are not passed to the application.
What you probably need to do is find the default application yourself by looking in the registry. Then you can start that process with arguments, instead of trying to start by filetype association. There is an answer here on how to find the default application in the registry:
Finding the default application for opening a particular file type on Windows
what exactly is your "argument", does it have spaces, backslash, etc?
Process process = new Process();
process.StartInfo.FileName = #"C:\process.exe";
process.StartInfo.Arguments = #"-r -d something else";
process.StartInfo.CreateNoWindow = false;
process.StartInfo.UseShellExecute = false;
process.Start();
Is there any reason why you cant start the app, then use the extension and arguments in your arguments?
I think an easier method is using the cmd command
void LaunchAssociatedProgram(string filename) {
Process.Start( #"cmd.exe", "/C start "+ filename );
}
EDIT:
I don't know if it works with arguments, but it is what I was looking for to launch an associated program...