(C# / WindowsMobile 6)
Let's take an application with 3 STATIC forms: Form1, Form2, Form3, where Form1 opens Form2 by calling Form2.Show(), and Form2 does the same with Form3. Form2 and Form3 have a "Exit" button, that just hides the form (not "close", just hide).
So, we execute these steps:
open the application;
go to Form2, by clicking "Form2" button on Form1;
go to Form3, by clicking "Form3" button on Form2;
open File Explorer, and "re-open" application by clicking on it's file. Form3 appears;
hide Form3 by clicking on "Exit" button on Form3 ( this.Hide() ). That's the problem: file explorer appears instead Form2.
I don't want to call "callingform".Show() every time I hide a form. This "works", but file explorer screen appears after "this.Hide()" and before "callinform.Show()" and I need to "control" who's calling who.
How to solve this? Is there any way to bring all application's form to foreground in the same order they appeared?
Thanks in advance.
There really isn't a way. You could implement a way to store forms in a similar way to the first answer, but when you switch you need to do:
"callingform".BringToFront();
"callingform".Show();
That will put all of your forms in front of Explorer.
You might need to do some investigation into this, but off the top of my head you could try looking at the Application.Forms[] collection.
Maybe someone can confirm or deny this but I think usually, Application.OpenForms[0] will be the main/initial form with subsequent Form appearances being in Application.OpenForms[1], Application.OpenForms[2], etc...
So you could simply try navigating backwards through this Forms collections.
Something like (or a variation of),
public void BringLastOpenedFormToFront()
{
if(Application.OpenForms.Count > 0)
{
Form form = Application.OpenForms[Application.OpenForms.Count - 1];
BringToFront(form); // your bring to front method.
}
}
This would allow you to ensure the last Form that appeared was brought to the front and immediately visible to the user. Let me know if you need any clarification.
Link to MSDN:
http://msdn.microsoft.com/en-us/library/system.windows.forms.application.openforms.aspx
Related
My apps use a timer that display a form after some seconds.
When I minimize my apps to do other stuff, the timer is still active (I'm ok with that) and the form bring to front over all my windows with focus on it (normal behavior).
I want that the new form open above my main apps but not above all my windows.
In the main form, I call the new form like this :
MRIS.EVENT_BOX form1 = new MRIS.EVENT_BOX();
form1.Owner = this;
form1.ShowDialog();
I manage to remove the focus problem by adding this in the EVENT_BOX :
protected override bool ShowWithoutActivation { get { return true; } }
I also check that TopMost is set to false in the new form.
But the new form is still show above all the others (without focus this time...).
I check some other questions but cannot manage to find something useful.
Some people talk about visible form ?
If you can help me ?
Thanks
You need to call form1.Show(); if you don't want to bring it to front
form1.Show();
//form1.BringToFront() You may need to call this if you want to being it to front
form1.ShowDialog() shows the form as dialog which means it will be shown on top of parent form. You can check more details on this here
In Form1 I'm enabling IsMdiContainer and I added a MenuStrip. In Form1_Load I "new" Form2 and I'm assiging Form2.MdiParent to this which is Form1. I'm also maximizing Form2 and this operation works well.
In Form2 I have a treeView on the left side of the form and on the right side of the form I would like to display a number of different forms with various editing capabilities which will be dependent upon the node or level selected in the treeView.
I would like to create a number of different forms for editing data that would be displayed in Form2 depending on the selection from the treeView. I can't seem to add a form to the MdiChild and I've been seeing some posts where adding a form to a form may create some programming problems which I'm not sure about.
I really don't have any code to paste into this post because nothing seemed to work except for the Mdi Parent and Child relationship which was pretty simple.
Thanks in advance for any help.
There is a lot of information on this subject, but some documentation can be difficult to understand for some new developers. Follow these steps:
Open Visual Studio
Create a Windows Form Application
Click your Form
Go to Properties for that Form
Minimum Size : 1366 pixels by 768 pixels.
Launch Maximized
The important element is IsMdiContainer
Open your Toolbox.
Go to Menus
Drag FileMenu onto your Form
Build your Menu
Then go to Solution Explorer
Right-Click Add Item
Add another Form
I left mine as Form2 (In a real program, not a good name).
So within those fifteen steps, we have all that we need to accomplish our goal. So what we will do to finish our task is:
Go back to our First Form
Go to our FileMenu
Double Click on the menu button you wish to link.
It will load a code view, inside the area put this:
Form2 newFrm = new Form2();
newFrm.MdiParent = this;
newFrm.Show();
What this code is doing is three distinct things:
Line 1: It is actually calling our object, in this case a second form. It is actually building our object for us.
Line 2: Is actually linking our second form to our current form, this is physically turning our second form into a Child Form.
Line 3: This is actually physically showing our second form when the button is clicked.
That is all you need to physically show a Form.
In regards to your second question, I'm not entirely sure what your attempting to accomplish. It sounds like your trying to have a tree, then as a Node is selected the right hand side of the Form changes to specific context.
Now this isn't the nicest example, but do you mean something like this?
TreeNode node = treeView1.SelectedNode;
if (node.Text.Contains("XP"))
{
TextBox one = new TextBox();
Panel i = new Panel();
i.Dock = DockStyle.Right;
i.BackColor = Color.Black;
i.Controls.Add(one);
i.Show();
TreeFrm.ActiveForm.Controls.Add(i);
}
Not sure if that is what you are seeking. Obviously you'd want to implement a FlowLayoutPanel to make the positioning not a pain for you. Keep in mind an MDI Parent, with a Child Form acting as a MDI Parent will not work very well. As most things will default to MDI Parent Forms Docking / Positioning. This example is not pretty, but I'm not entirely sure of what your asking.
Are you trying to dock other forms or components on the same form?
I have A and B forms.
when i run A form will display all the values in datagridview by clicking start button.In this same form one labellink is there.Once i click the labelink B form will display with combobox and one button.
now i choose one option and click the button which i want to see the values in datagridview of A Form.
My issue is when i selected choice in B form, the results should come in already opened A form but where as in my case it will open up another new A form and shows the result.I dont want to open again A Form and process the result.
How can i do this? simple solution to acheive it?
Pass instance of FormA to FormB
public class FormB{
public FormB(FormA formA){
this.FormA=formA;
}
private void UpdateFormA(){
formA.SetResult(...);
}
}
Use an MVC architecture, where the controller 'knows' which forms are open. That way form B tells the controller to display form A, the controller decides one form A is already open, and advises form A to update itself.
As suggested by AISki use MVC else use events and delegates. Fire event from FORM B and subscribe it in FORM A.
I have a large application with several forms, any of them could get a MessageBox (MessageBox.Show()) that is modal and locks the form.
On activation of another form I now need to find this MessageBox and bring the form that has this MessageBox to front. Is there any way to check this?
I know about the Application.OpenForms property, maybe there is something like this for MessageBox?
Edit1 : For example, say that we open Winform1, then a event in Winform1 will go to the mainController that opens Winform2. Lateron Winform1 is getting a MessageBox.Show, But its fully possible to bring Winform2 to front(above Winform1). So now I need to react to the Winform.Activated to check if there is any MessageBox.Show and if so, bring this form that holds the MessageBox to front.
You could find them by using Application.OpenForms like this:
foreach (Form f in Application.OpenForms)
{
if (f.Visible && ! f.CanFocus)
{
// whatever...
}
}
Or: use a different approach altogether:
Make all your forms handle Application.EnterThreadModal and Application.LeaveThreadModal, so that when the app goes modal while that form is current, you add that form onto a list so you can keep track of it, and remove it from the list when it leaves modal...
Then all you need to do is query that list to see if any forms have a modal dialog box open.
Try using one of the Show methods that takes an owner:
MessageBox.Show(this, "My Message");
I tested this on .NET 4 / Windows 7, and when the message box is opened it brings its owner to the front.
Thinking about this for an About dialog but I'm sure it's applicable in other places (say a find box)
Sorry if this is a dupe, but I couldn't find this or how to articulate the last part about it only being on top of the parent. How do you make a form that is always on top of the parent form, but is non-modal, but doesn't cover up other apps?
Try this to open your dialog:
FindDialog fd = new FindDialog();
fd.Show(this);
The key is to assign dialog's owner.
Not sure exactly what you mean; Form.ShowDialog is only modal with respect to the parent, not the application, unless the application is single threaded.
For example, I made an app to test this which was organized like the following:
mainform:
2 buttons, each of which begins a thread that creates a frmDialog1 and calls ShowDialog
frmDialog1:
single button which creates a frmDialog2 and calls ShowDialog on it.
frmDialog2:
does nothing (ie. blank)
when they were all running I could access/drag mainform. I could also do the same with frmDialog1 (both versions) only if I hadn't clicked the button that shows dialog 2.