Better way to get the base directory? - c#

I have this code to load a config file and read all the values and it works fine when running the application but of course fails on team city because the appdomain's base directory is where the build script (psake) is started. I know I can change directory to the build dir before executing the tests but I thought it's better to make loading the config file work at all times regardless.
XDocument.Load(Path.Combine(AppDomain.CurrentDomain.BaseDirectory, cfgFile));
Is there another way to get the "BaseDirectory" that really works all times? I tried the below as well with same results:
string path = Path.GetDirectoryName(Assembly.GetExecutingAssembly().CodeBase);
XDocument.Load(Path.Combine(path, cfgFile));
EDIT 1 The problem is the following. My solutions base directory is "C:\Project", all compiled files are copied to "C:\Project\build". Now in the psake build script I have the following code:
task Test -depends PrepareTests {
try {
#$old = pwd
#cd $build_dir
&$mspec $mspec_projects --teamcity
#cd $old
}
catch {
&echo "Error starting test runner"
Exit 1;
}
}
As you can see I commented out the changing of directories which makes the BaseDirectory the location of the build file / solution instead of the build directory regardless of how I try to access it. Kind of confusing if you ask me.
UPDATE I really like to know if it is possible to get the directory of the assembly regardless of what directory the application that started the app domain is located. How?

differents ways to get the base directory
AppDomain.CurrentDomain.BaseDirectory
Directory.GetCurrentDirectory() // not guaranteed to work on Mobile application
Environment.CurrentDirectory // this calls Directory.GetCurrentDirectory()
this.GetType().Assembly.Location // Assembly.location
Application.StartupPath // for windows forms apps
Application.ExecutablePath // same as Application.StartupPath

string origAssemblyLocation = Assembly.GetExecutingAssembly().CodeBase;
Per MSDN:
Assembly.CodeBase Property
Gets the location of the assembly as
specified originally

Your question is a bit unclear. I don't really know if this is what you want.
I typically use AppDomain.CurrentDomain.BaseDirectory
Alternatives
Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location)
Environment.CurrentDirectory

So it sounds/looks like you're attempting to obtain the configuration file for an assembly. The following should accomplish that task by accessing the 'Location' property of the assembly and using it to retrieve the configuration path:
static string GetConfigFileByType(Type type)
{
Configuration config =
ConfigurationManager.OpenExeConfiguration(type.Assembly.Location);
if (config.HasFile)
return config.FilePath;
throw new FileNotFoundException();
}

try this one:
Module[] modules = Assembly.GetExecutingAssembly().GetModules();
return Path.GetDirectoryName(modules[0].FullyQualifiedName);

have you tried getting the FileName of the current process' MainModule?
System.Diagnostics.Process.GetCurrentProcess().MainModule.FileName
Or GetEntryAssembly()?
System.Reflection.Assembly.GetEntryAssembly().Location

I like to make my classes configurable - for example they get the folder name as a parameter in their constructor.
This makes it possible to test with different config files.
In test code we use:
TestContext.TestDeploymentDir
This is the testrun folder, where all assemblies for a test run are copied into, together with the test deployment items. We 'deploy' our unit test config files to the test run folder - this can be specified in the testrunconfig dialog in visual studio.
For our production code we pass
Assembly.GetExecutingAssembly().Location
to the constructor, which works for us.

how about:
Application.StartupPath;

string baseDirectory=Application.StartupPath.Split(Path.DirectorySeparatorChar)[0];
Application startup path will return the path where exe is kept, we will split this using "\" and get the base directory as "C:" for example,

Related

What is the difference between these ways of getting current directory?

They all give the same result, the location of folder that contains the exe that is being executed. I am sure there are no good or bad methods in the .net BCL. They are all appropriate in particular circumstances. Which one is appropriate for which scenario?
var appBaseDir = AppDomain.CurrentDomain.BaseDirectory;
var currentDir = Environment.CurrentDirectory;
var dir = Directory.GetCurrentDirectory();
var path = Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().Location);
They all give the same result
They certainly don’t. currentDir and dir both give you the current working directory – i.e. by default the directory your executable was run from (but it can be changed during the execution).
By contrast, appBaseDir and path get the directory which contains the executing assembly’s file.
To illustrate how they differ, consider that you have an executable which sits in C:\bar\baz.exe. Now I can execute the application by entering the following chain of commands in a terminal:
$ md C:\foo
$ cd C:\foo
$ ..\bar\baz.exe
Now the current working directory is C:\foo but the application’s base directory is C:\bar. There exist analogous means of setting the working directory for other methods of launching an application (e.g. via a shortcut icon or programmatically, such as via Process.Start).
Still, the framework provides different ways of accessing this information:
Environment.CurrentDirectory quite directly conveys the meaning that the execution environment (an environment variable) is queried. Directory.GetCurrentDirectory() may actually do the same internally (I have no idea) but it encapsulates this, and rather focuses on providing the user with a logical API for querying information about directories.
AppDomain.CurrentDomain has information about the current AppDomain (roughly, the executable). Part of that information is, logically, the AppDomain’s path. By contrast, System.Reflection.Assembly gives you general information about assembles – these represent any kind of binary objects in .NET, including DLLs and EXEs. GetExecutingAssembly in particular returns the currently executed assembly. And you can get its path again by querying its Location property, which gives the physical path of an assembly file.
Consider the example above
The myTest.exe file contains the entry point and is at located at D:\myTest.exe. This exe calls via reflection a method in an assembly in F:\. This assembly contains all the find directory code.
In the command prompt I have my current directory set to C:\
Here are the results
AppDomain.CurrentDomain.BaseDirectory
D:\
Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().Location)
F:\
Environment.CurrentDirectory and Directory.GetCurrentDirectory()
C:\
AppDomain.CurrentDomain.BaseDirectory will give you the directory the application is running in.
Environment.CurrentDirectory & Directory.GetCurrentDirectory can change during the execution of an application. You can see the behavior if you get the value at the start of execution, then use something like OpenFileDialog, then then get the value again. You will notice that the value will have changed to where the OpenFileDialog was pointing.
I found with .net 5 that if the application is published as a self-contained single-file EXE, all of these well-known methods to get the EXE location return an empty string:
System.Reflection.Assembly.GetExecutingAssembly().Location
System.Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase
typeof(Program).Assembly.ManifestModule.FullyQualifiedName
However this does work to get the containing folder path:
AppDomain.CurrentDomain.BaseDirectory

C# Unit testing - Weird project directory

I have a situation where I am running a unit test and trying to get the project base path and it is giving me a odd output.
D:\VSCode\Bob.Smith\Projects\MySolution\DEVELOPMENT\MyClasses\MyProject\TestResults\Jacob.Freeman_P1004 2012-11-26 09_21_33\Out
Is this a known issue with VS or just something that I have missed out? I am using the following line with no other code to get the directory information.
string output = null;
output = Environment.CurrentDirectory;
I have tried different various ways to get the directory information such as the following, but it still gives me the same output.
output = System.IO.Directory.GetCurrentDirectory()
Thanks in advance.
As documentation states Environment.CurrentDirectory:
Gets or sets the fully qualified path of the current working directory.
The current working directory is not necessarily the projects base path - It is when you start an exe. While running test this path is set by test runner. This variable can change while program is running.
In application you should use Assembly.GetEntryAssembly().Location to get location of you exe file. This will not work for tests as they are executed by test runner.
If for test purposes you simply need location of tested dll file you can use typeof(SomeTypeThatIsDeclaredInThatDLL).Assembly.Location.
It works as designed. Your tests executes in different directory against bin.

File path for project files?

I am working on a media player in C# but when I want to make my test I have a problem.
I have to create a new object song with the following path:
#"C:\Users\Jesus Antonio\Desktop\JukeboxV2.0\JukeboxV2.0\Datos\ich will.mp3"
It works but when I change the computer I have to rewrite the entire path,
My project is called JukeboxV2.0
In java I remember you can just write the path for example
#"JukeboxV2.0\JukeboxV2.0\Datos\ich will.mp3"
This will save a lot of time because I can take my project to different computers and it works, but here I don't known how to do that, anyone know?
You would do something like this to get the path "Data\ich_will.mp3" inside your application environments folder.
string fileName = "ich_will.mp3";
string path = Path.Combine(Environment.CurrentDirectory, #"Data\", fileName);
In my case it would return the following:
C:\MyProjects\Music\MusicApp\bin\Debug\Data\ich_will.mp3
I use Path.Combine and Environment.CurrentDirectory in my example. These are very useful and allows you to build a path based on the current location of your application. Path.Combine combines two or more strings to create a location, and Environment.CurrentDirectory provides you with the working directory of your application.
The working directory is not necessarily the same path as where your executable is located, but in most cases it should be, unless specified otherwise.
Path.Combine(AppDomain.CurrentDomain.BaseDirectory, #"JukeboxV2.0\JukeboxV2.0\Datos\ich will.mp3")
base directory + your filename
I was facing a similar issue, I had a file on my project, and wanted to test a class which had to deal with loading files from the FS and process them some way. What I did was:
added the file test.txt to my test project
on the solution explorer hit alt-enter (file properties)
there I set BuildAction to Content and Copy to Output Directory to Copy if newer, I guess Copy always would have done it as well
then on my tests I just had to Path.Combine(Environment.CurrentDirectory, "test.txt") and that's it. Whenever the project is compiled it will copy the file (and all it's parent path, in case it was in, say, a folder) to the bin\Debug (or whatever configuration you are using) folder.
Hopes this helps someone

How to get a path from a directory in a C# console application?

Say I have this file structure
Soultion-> Folder1 -> FileIwant.html
So this could be something like C:\Soultion\Folder1\FilterIwant.html
Now I need to read this file into my application. I can't just hardcode it since when I give it to someone else they might put it on F: drive or something.
Or when I create a msi file the path might be completely different. So how can I say maybe take
"Folder1\FilterIwant.html"
and use that to get the folder path regardless of where they put it?
Edit
I tried Path.GetFullPath but I land up in the bin/debug directory. But my file is not in that directory. I think it is a couple directories before. Also if I make a msi file will I have bin/debug directory?
Why is a file which is used as part of your application not in the same folder as the application? It sounds to me like you should set the properties on that file to copy to the output folder when you do a build.
Doing that will make sure your file is in the bin\debug folder.
EDIT:
either that or you should be placing your files in one of the special folders, app data or my documents spring to mind.
When Visual Studio compiles your project, it will be putting the output into the bin\debug directory. Any content files that you want to reference must also be copied to those locations, in order for your app residing in that directory to be able to read that file.
You have two choices:
either you set the Copy to Output Directory property on your FilterIwant.html to Copy if newer; in that case, if the file has changed, it will be copied to the output directory, and you should be able to reference it and load it there
or
you just define a path in your app.config, something like DataPath, and set it to your folder where the file resides. From your app, you then create the full path name for that file as Path.Combine(AppSettings["DataPath"], "FilterIwant.html") - with this approach, you become totally independant of where the file really is and you don't need to move around anything. Also: this gives you the opportunity to create an admin/config utility for your users later on, so that they can pick any directory they like, and your app will find those files there.
In my console app, I started with the debug directory until i found the closest parent folder I wanted.
static void Main(string[] args)
{
Console.WriteLine("Start");
var debugDir = Environment.CurrentDirectory;
DirectoryInfo di = new DirectoryInfo(debugDir);
var searchDir = "";
while (!di.FullName.ToLower().EndsWith("Folder1"))
{
if(di.FullName.ToLower().EndsWith(":")) //if you went too far up as in "D:" then
break;
di = di.Parent;
}
Console.WriteLine(di.FullName);
}
You need the help of System.Io.Path class:
GetFullPath: Returns the absolute path for the specified path string.
Edit:
You might also need the application directory - this is where your application will be installed:
string appPath = Path.GetDirectoryName(Application.ExecutablePath);
Path.GetFullPath
Edit
The bin/Debug path will not be present when you run your installed application (unless you specifically tell the installer to use that subdirectory, of course).
You probably want to pass the full path as a command line argument. You can then get the argument using the args parameter of the Main method. To convert a relative path to an absolute one you can use Path.GetFullPath:
using System;
using System.IO;
public class CommandLine
{
public static void Main(string[] args)
{
// The path is passed as the first argument
string fileName = arg[0];
// get absolute path
fileName = Path.GetFullPath(fileName);
// TODO: do whatever needs to done with the passed file name
}
}

How to find path of active app.config file?

I'm trying to finish this exception handler:
if (ConfigurationManager.ConnectionStrings["ConnectionString"]==null)
{
string pathOfActiveConfigFile = ...?
throw new ConfigurationErrorsException(
"You either forgot to set the connection string, or " +
"you're using a unit test framework that looks for "+
"the config file in strange places, update this file : "
+ pathOfActiveConfigFile);
}
This problem seems to only happen to me when I'm using nUnit.
Try this
AppDomain.CurrentDomain.SetupInformation.ConfigurationFile
Strictly speaking, there is no single configuration file. Excluding ASP.NET1 there can be three configuration files using the inbuilt (System.Configuration) support. In addition to the machine config: app.exe.config, user roaming, and user local.
To get the "global" configuration (exe.config):
ConfigurationManager.OpenExeConfiguration(ConfigurationUserLevel.None)
.FilePath
Use different ConfigurationUserLevel values for per-use roaming and non-roaming configuration files.
1 Which has a completely different model where the content of a child folders (IIS-virtual or file system) web.config can (depending on the setting) add to or override the parent's web.config.
If you mean you are only getting a null return when you use NUnit, then you probably need to copy the ConnectionString value the your app.config of your application to the app.config of your test library.
When it is run by the test loader, the test assembly is loaded at runtime and will look in its own app.config (renamed to testAssembly.dll.config at compile time) rather then your applications config file.
To get the location of the assembly you're running, try
System.Reflection.Assembly.GetExecutingAssembly().Location
Make sure you click the properties on the file and set it to "copy always" or it will not be in the Debug\ folder with your happy lil dll's to configure where it needs to be and add more cowbell
The first time I realized that the Unit testing project referenced the app.config in that project rather then the app.config associated with my production code project (off course, DOH) I just added a line in the Post Build Event of the Prod project that will copy the app.config to the bin folder of the test project.
Problem solved
I haven't noticed any weird side effects so far, but I am not sure that this is the right solution, but at least it seems to work.
One more option that I saw is missing here:
const string APP_CONFIG_FILE = "APP_CONFIG_FILE";
string defaultSysConfigFilePath = (string)AppDomain.CurrentDomain.GetData(APP_CONFIG_FILE);
Depending on the location of your config file System.Reflection.Assembly.GetExecutingAssembly().Location might do what you need.
I tried one of the previous answers in a web app (actually an Azure web role running locally) and it didn't quite work. However, this similar approach did work:
var map = new ExeConfigurationFileMap { ExeConfigFilename = "MyComponent.dll.config" };
var path = ConfigurationManager.OpenMappedExeConfiguration(map, ConfigurationUserLevel.None).FilePath;
The config file turned out to be in C:\Program Files\IIS Express\MyComponent.dll.config. Interesting place for it.

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