In C# it is possible to create weak references to objects as described here:
WeakReference Class
In .net some classes also implement the IDisposable interface. Calling the Dispose method of this interface is performed to manually dispose of any managed or unmanaged resources currently being held onto. An example might be a Bitmap object or class.
If I assign an object that implements IDisposable to a weak reference, will Dispose be called if the weak reference collects the object?
In general, the answer is indeed No.
However, a properly implemented class that implements IDisposable using the IDisposable pattern (hopefuly all .NET classes do this). Would also implement finalizer which is called when the object is garbage collected and inside the finalizer, it would call Dispose. So, for all proper implementations of IDisposable, the Dispose method will be called.
(Note: the counter-example by Fernando is not implementing IDisposable properly)
GC does not ever call Dispose. Dispose must be called by user code.
No. Simple like that ;)
No. Check this test:
class Program {
static void Main(string[] args) {
Test test = new Test();
Console.WriteLine(test.Disposable == null);
GC.Collect();
Console.WriteLine(test.Disposable == null);
Console.ReadLine();
}
}
public class Test {
private WeakReference disposable = new WeakReference(new WeakDisposable());
public WeakDisposable Disposable {
get { return disposable.Target as WeakDisposable; }
}
}
public class WeakDisposable : IDisposable {
~WeakDisposable() {
Console.WriteLine("Destructor");
}
public void Dispose() {
Console.WriteLine("Dispose");
}
}
The output is:
False
True
Destructor
As you can see, the execution never hits the Dispose method.
Related
This question already has answers here:
Proper use of the IDisposable interface
(20 answers)
Closed 2 years ago.
I've gone through many article which says the purpose of IDisposable is to close the unmanaged objects like DB connections and Third party reports.But my question is why should I define Dispose method if I can handle the unmanaged objects in my methods without defining Dispose() method?
For an example,
class Report : IDisposable
{
public void GenerateReport()
{
Report rpt=new Report() //unmanaged object created
rpt.Dispose(); // Disposing the unmanaged object
}
private void Dispose()
{
//not sure why this block is needed
}
}
Is my understanding correct?
You're correct that you wouldn't need the implement IDisposable in your example. The example where you would is if you're keeping a long lived object for the life of the class you've written. So say you had this:
public class Report : IDisposable
{
private Stream _reportStream; // This variable lives a long time.
public void WriteToStream(byte[] data)
{
_reportStream.Write(data, 0, data.Length);
}
public void Dispose()
{
_reportStream?.Dispose();
}
}
This is a fairly simple example, but it shows that _reportStream lives for the length of the class and needs to get cleaned up and garbage collected at the same time as the class. There's nothing stopping you from creating a public method called CleanupObject() to do the same thing, but then people can't use a using block to have the Runtime call the Dispose() automatically:
using (var myReport = new Report())
{
// do a bunch of things with myReport;
} // Here the runtime will call myReport.Dispose() for you.
// myReport isn't accessible from here, as it was declared in the using block
The class that implements the IDisposable interface can be used in the using block. A big plus of this solution is that after leaving the block the Dispose method will be automatically called on the object created in this area. That way, we can only use classes that implement the IDisposable interface.
//example :
using(var dClean= new DisposableClean())
{
//after leaving this using dClean will be automatically destroyed
}
The object that you've created needs to expose some method, not necessary named Dispose(). You could also call it Clean(). Dispose() is the conventional name.
Garbage Collector(GC), available throughout the .Net framwork, works well enough to be easily forgotten. However, it is worth learning to work with him well and use his possibilities. For this purpose, the correct implementation of the IDisposable interface is necessary, the basic form of which is sometimes insufficient if we consider the proper release of managed and unmanaged resources.
This is extanded version which can be very useful in this case.
In a way an answer to you question:
public class DisposableExtended: IDisposable
{
private bool isDisposed = false;
public void Dispose ()
{
this.Dispose (true);
GC.SupressFinalize (this);
}
protected void Dispose (bool disposing)
{
if (! this.isDisposed)
{
if (disposing)
{
// here we release managed resources (standard classes)
}
// here we release unmanaged resources (e.g. streams, etc..)
{
}
}
this .isDisposed = true;
}
~ DisposableExtended ()
{
this.Dispose (false);
}
Yes, you can define your own way to release resources but many existing code use this way. If you share your code to people, remember to tell them to dispose in your way.
One "profit" of implementing IDisposable is that you can call Dispose indirectly by use a language construct such as using.
For example:
using(Stream s = File.OpenRead("HelloWorld.bin"))
{
//Do stuffs
}
I have a question about IDisposable Method parameters.
Assume i have got a class which implements the IDisposable Interface, such as "TestClass":
class TestClass : IDisposable
{
public void TestMethod()
{
Console.WriteLine("I am a Test Method");
}
public void Dispose()
{
Console.WriteLine("Test Method was disposed!");
}
}
Suppose I want to put a instance of IDisposable Class (e.g. DB Context) into a method to perform context dependent actions.
Usually we use this like in the following example:
static void Main(string[] args)
{
using (var context = new TestClass())
{
X(context);
}
}
public static void X(TestClass context)
{
context.TestMethod();
}
The result is, as expected, that the Dispose() method is called. (Debugger attached, or displayed "Test Method was disposed!" on Console)
So the question is:
If i will write something like this:
static void Main(string[] args)
{
X(new TestClass());
}
I cannot see any indicator that the Dispose method has been called? Is the TestClass() context automatically disposed of if the execution of the method was successful / finished.
Is the dispose method called when the garbage collector cleans this up?
I am concerned that resource-intensive contexts will still be open?
The garbage collector can only clean up managed resources (things created with new). Classes that work with unmanaged resources typically implement a finalizer/destructor, that calls Dispose() for you when you haven't already. The garbage collector does call the finalizer. See here for an example and more information.
If you don't explicitly call Dispose() and your class does not have a destructor, Dispose() won't be called at all. This shouldn't be a problem, because at that point the garbage collector is already cleaning up anyway.
So for classes that do not own unmanaged resources, Dispose() just gives control over when resources are to be freed.
I'm coding in C# and I created a class that I would like to use in a 'using' block.
Is this possible and if so, how should I proceed and what to I need to add to my class?
The using keyword can be used on any object that implements IDisposable. To implement IDisposable, include a Dispose method in your class.
It's usually important to also include the Dispose functionality in your class's finalizer in case users of your library don't (or forget to) call Dispose.
For example:
class Email : IDisposable {
// The only method defined for the 'IDisposable' contract is 'Dispose'.
public void Dispose() {
// The 'Dispose' method should clean up any unmanaged resources
// that your class uses.
}
~Email() {
// You should also clean up unmanaged resources here, in the finalizer,
// in case users of your library don't call 'Dispose'.
}
}
void Main() {
// The 'using' block can be used with instances of any class that implements
// 'IDisposable'.
using (var email = new Email()) {
}
}
public class MyClass : IDisposable
{
public void Dispose()
{
}
}
That's all there is to it! In calling code you'd be able to do the following:
using(var mc = new MyClass())
{
}
I am using C#. Is it advised to unit test dispose methods? If so why, and how should one test these methods?
Yes, but it might be hard. There are two things that can generally happen in Dispose implementation:
Unmanaged resources are released.
In this case it's pretty hard to verify that the code called, for example, Marshal.Release. A possible solution is to inject an object that can do the disposing and pass a mock to it during testing. Something to this effect:
interface ComObjectReleaser {
public virtual Release (IntPtr obj) {
Marshal.Release(obj);
}
}
class ClassWithComObject : IDisposable {
public ClassWithComObject (ComObjectReleaser releaser) {
m_releaser = releaser;
}
// Create an int object
ComObjectReleaser m_releaser;
int obj = 1;
IntPtr m_pointer = Marshal.GetIUnknownForObject(obj);
public void Dispose() {
m_releaser.Release(m_pointer);
}
}
//Using MOQ - the best mocking framework :)))
class ClassWithComObjectTest {
public DisposeShouldReleaseComObject() {
var releaserMock = new Mock<ComObjectReleaser>();
var target = new ClassWithComObject(releaserMock);
target.Dispose();
releaserMock.Verify(r=>r.Dispose());
}
}
Other classes' Dispose method is called
The solution to this might not be as simple as above. In most cases, implementation of Dispose is not virtual, so mocking it is hard.
One way is to wrap up those other objects in a mockable wrapper, similar to what System.Web.Abstractions namespace does for HttpContext class - i.e. defines HttpContextBase class with all virtual methods that simply delegates method calls to the real HttpContext class.
For more ideas on how to do something like that have a look at System.IO.Abstractions project.
Certainly can't hurt. Client code may try to use an object of your class after it has disposed of it. If your class is composed of other IDisposable objects, you should always be throwing the ObjectDisposedException exception if it is in a state which it is no longer usable.
Of course, you should only be testing the external state of your object. In the example below, I've made the property Disposed external to give me the state.
Consider:
internal class CanBeDisposed : IDisposable
{
private bool disposed;
public bool Disposed
{
get
{
if (!this.disposed)
return this.disposed;
throw new ObjectDisposedException("CanBeDisposed");
}
}
public void Dispose()
{
this.Dispose(true);
GC.SuppressFinalize(this);
}
protected virtual void Dispose(bool disposing)
{
if (!this.disposed)
{
if (disposing)
{
//// Dispose of managed resources.
}
//// Dispose of unmanaged resources.
this.disposed = true;
}
}
}
So how I would test this is thus:
CanBeDisposed cbd;
using (cbd = new CanBeDisposed())
{
Debug.Assert(!cbd.Disposed); // Best not be disposed yet.
}
try
{
Debug.Assert(cbd.Disposed); // Expecting an exception.
}
catch (Exception ex)
{
Debug.Assert(ex is ObjectDisposedException); // Better be the right one.
}
If your class creates and works with unmanaged resources, then you should definitely ensure that Dispose works as you expect it to - although it could be argued it is more of an integration test due to the type of hoops you're going to have to jump through.
If your class only creates / uses managed resources ( i.e. they implement IDisposable ) then all you really need to ensure is that the Dispose method on these resources is invoked at the correct time - if you are using some form of DI then you can inject a mock and assert that Dispose was called.
Look at the complexity of your dispose methods - if they are only a couple of lines long with maybe 1 condition, ask yourself if there really is a benefit in unit testing them.
Big yes - if your situation requires you to implement a Dispose function - you better make sure it does what you think!
For example, we have classes that coordinate database tasks (think SSIS packages, but with SqlConnection and SqlCommand and SqlBulkCopy etc.).
If I don't properly implement my Dispose, I could have an uncommitted SqlTransaction, or dangling SqlConnection. This would be VERY bad if I were running multiple instances of these database tasks in series.
As a practical tip (because yes, you should test Dispose()) my experience has been that there are two ways to do so without too much hassle.
IDisposer
The first follows Igor's accepted answer - inject something like an IDisposer, so that you can call
public void Dispose()
{
_disposer.Release(_disposable);
}
where
public interface IDisposer
{
void Release(IDisposable disposable);
}
Then all you need to do is mock the IDisposer and assert that it's called once and you're golden.
Factory
The second, and my personal favourite, is to have a factory that creates the thing you need to test disposal of. This only works when the factory produces a mockable type (interface, abstract class), but hey, that's almost always the case, especially for something that's to be disposed. For testing purposes, mock the factory but have it produce a mock implementation of the thing you want to test disposal of. Then you can assert calls to Dispose directly on your mock. Something along the lines of
public interface IFooFactory
{
IFoo Create(); // where IFoo : IDisposable
}
public class MockFoo : IFoo
{
// ugly, use something like Moq instead of this class
public int DisposalCount { get; privat set; }
public void Dispose()
{
DisposalCount++;
}
}
public class MockFooFactory
{
public MockFoo LatestFoo { get; private set; }
public IFoo Create()
{
LatestFoo = new MockFoo();
return LatestFoo;
}
}
Now you can always ask the factory (which will be available in your test) to give you the latest MockFoo, then you dispose of the outer thing and check that DisposalCount == 1 (although you should use a test framwork instead, e.g. Moq).
Edit - New Question
Ok lets rephrase the question more generically.
Using reflection, is there a way to dynamically call at runtime a base class method that you may be overriding. You cannot use the 'base' keyword at compile time because you cannot be sure it exists. At runtime I want to list my ancestors methods and call the ancestor methods.
I tried using GetMethods() and such but all they return are "pointers" to the most derived implementation of the method. Not an implementation on a base class.
Background
We are developing a system in C# 3.0 with a relatively big class hierarchy. Some of these classes, anywhere in the hierarchy, have resources that need to be
disposed of, those implement the IDisposable interface.
The Problem
Now, to facilitate maintenance and refactoring of the code I would like to find a way, for classes implementing IDisposable,
to "automatically" call base.Dispose(bDisposing) if any ancestors also implements IDisposable. This way, if some class higher up in the hierarchy starts implementing
or stops implementing IDisposable that will be taken care of automatically.
The issue is two folds.
First, finding if any ancestors implements IDisposable.
Second, calling base.Dispose(bDisposing) conditionally.
The first part, finding about ancestors implementing IDisposable, I have been able to deal with.
The second part is the tricky one. Despite all my
efforts, I haven't been able to call base.Dispose(bDisposing) from a derived class. All my attempts failed. They either caused
compilation errors or called the wrong Dispose() method, that is the most derived one, thus looping forever.
The main issue is that you cannot actually refer to base.Dispose() directly in your code if there is no such thing as an
ancestor implementing it (be reminded that there might have no ancestors yet implementing IDisposable, but I want the derived code to be ready when and if such
a thing happens in the future). That leave us with the Reflection mechanisms, but I did not find a proper way of doing it. Our code is quite filled with
advanced reflection techniques and I think I did not miss anything obvious there.
My Solution
My best shot yet was to have some conditional code using in commented code. Changing the IDisposable hierarchy would either break the build
(if no IDisposable ancestor exists) or throw an exception (if there are IDisposable ancestors but base.Dispose is not called).
Here is some code I am posting to show you what my Dispose(bDisposing) method looks like. I am putting this code at the end of all the Dispose()
methods throughout the hierarchy. Any new classes are created from templates that also includes this code.
public class MyOtherClassBase
{
// ...
}
public class MyDerivedClass : MyOtherClassBase, ICalibrable
{
private bool m_bDisposed = false;
~MyDerivedClass()
{
Dispose(false);
}
public void Dispose()
{
Dispose(true);
GC.SuppressFinalize(this);
}
protected virtual void Dispose(bool bDisposing)
{
if (!m_bDisposed) {
if (bDisposing) {
// Dispose managed resources
}
// Dispose unmanaged resources
}
m_bDisposed = true;
Type baseType = typeof(MyDerivedClass).BaseType;
if (baseType != null) {
if (baseType.GetInterface("IDisposable") != null) {
// If you have no ancestors implementing base.Dispose(...), comment
// the following line AND uncomment the throw.
//
// This way, if any of your ancestors decide one day to implement
// IDisposable you will know about it right away and proceed to
// uncomment the base.Dispose(...) in addition to commenting the throw.
//base.Dispose(bDisposing);
throw new ApplicationException("Ancestor base.Dispose(...) not called - "
+ baseType.ToString());
}
}
}
}
So, I am asking is there a way to call base.Dispose() automatically/conditionally instead?
More Background
There is another mechanism in the application where all objects are registered with a main class. The class checks if they implement IDisposable.
If so, they are disposed of properly by the application. This avoids having the code using the classes to deal with
calling Dispose() all around by themselves. Thus, adding IDisposable to a class that has no ancestor history of IDisposable still works perfectly.
The standard pattern is for your base class to implement IDisposable and the non-virtual Dispose() method, and to implement a virtual Dispose(bool) method, which those classes which hold disposable resources must override. They should always call their base Dispose(bool) method, which will chain up to the top class in the hierarchy eventually. Only those classes which override it will be called, so the chain is usually quite short.
Finalizers, spelled ~Class in C#: Don't. Very few classes will need one, and it's very easy to accidentally keep large object graphs around, because the finalizers require at least two collections before the memory is released. On the first collection after the object is no longer referenced, it's put on a queue of finalizers to be run. These are run on a separate, dedicated thread which only runs finalizers (if it gets blocked, no more finalizers run and your memory usage explodes). Once the finalizer has run, the next collection that collects the appropriate generation will free the object and anything else it was referencing that isn't otherwise referenced. Unfortunately, because it survives the first collection, it will be placed into the older generation which is collected less frequently. For this reason, you should Dispose early and often.
Generally, you should implement a small resource wrapper class that only manages the resource lifetime and implement a finalizer on that class, plus IDisposable. The user of the class should then call Dispose on this when it is disposed. There shouldn't be a back-link to the user. That way, only the thing that actually needs finalization ends up on the finalization queue.
If you are going to need them anywhere in the hierarchy, the base class that implements IDisposable should implement the finalizer and call Dispose(bool), passing false as the parameter.
WARNING for Windows Mobile developers (VS2005 and 2008, .NET Compact Framework 2.0 and 3.5): many non-controls that you drop onto your designer surface, e.g. menu bars, timers, HardwareButtons, derive from System.ComponentModel.Component, which implements a finalizer. For desktop projects, Visual Studio adds the components to a System.ComponentModel.Container named components, which it generates code to Dispose when the form is Disposed - it in turn Disposes all the components that have been added. For the mobile projects, the code to Dispose components is generated, but dropping a component onto the surface does not generate the code to add it to components. You have to do this yourself in your constructor after calling InitializeComponent.
Personally, I think you might be better off handling this with something like FxCop. You should be able to write a rule that check so see if when an object is created that implements IDisposable that you use a using statement.
It seems a little dirty (to me) to automatically dispose an object.
There is not an "accepted" way of doing this. You really want to make your clean up logic (whether it runs inside of a Dispose or a finalizer) as simple as possible so it won't fail. Using reflection inside of a dispose (and especially a finalizer) is generally a bad idea.
As far as implementing finalizers, in general you don't need to. Finalizers add a cost to your object and are hard to write correctly as most of the assumptions you can normally make about the state of the object and the runtime are not valid.
See this article for more information on the Dispose pattern.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace TestDisposeInheritance
{
class Program
{
static void Main(string[] args)
{
classC c = new classC();
c.Dispose();
}
}
class classA: IDisposable
{
private bool m_bDisposed;
protected virtual void Dispose(bool bDisposing)
{
if (!m_bDisposed)
{
if (bDisposing)
{
// Dispose managed resources
Console.WriteLine("Dispose A");
}
// Dispose unmanaged resources
}
}
public void Dispose()
{
Dispose(true);
GC.SuppressFinalize(this);
Console.WriteLine("Disposing A");
}
}
class classB : classA, IDisposable
{
private bool m_bDisposed;
public void Dispose()
{
Dispose(true);
base.Dispose();
GC.SuppressFinalize(this);
Console.WriteLine("Disposing B");
}
protected override void Dispose(bool bDisposing)
{
if (!m_bDisposed)
{
if (bDisposing)
{
// Dispose managed resources
Console.WriteLine("Dispose B");
}
// Dispose unmanaged resources
}
}
}
class classC : classB, IDisposable
{
private bool m_bDisposed;
public void Dispose()
{
Dispose(true);
base.Dispose();
GC.SuppressFinalize(this);
Console.WriteLine("Disposing C");
}
protected override void Dispose(bool bDisposing)
{
if (!m_bDisposed)
{
if (bDisposing)
{
// Dispose managed resources
Console.WriteLine("Dispose C");
}
// Dispose unmanaged resources
}
}
}
}
If you wanted to use [basetype].Invoke("Dispose"...) then you could implement the function call without the debugger complaining. Then later when the base type actually implements the IDisposable interface it will execute the proper call.
If you wanted to use [basetype].Invoke("Dispose"...) then you could implement the function call without the debugger complaining. Then later when the base type actually implements the IDisposable interface it will execute the proper call.
Try this. It's a one-line addition to the Dispose() method, and calls the ancestor's dispose, if it exists. (Note that Dispose(bool) is not a member of IDisposable)
// Disposal Helper Functions
public static class Disposing
{
// Executes IDisposable.Dispose() if it exists.
public static void DisposeSuperclass(object o)
{
Type baseType = o.GetType().BaseType;
bool superclassIsDisposable = typeof(IDisposable).IsAssignableFrom(baseType);
if (superclassIsDisposable)
{
System.Reflection.MethodInfo baseDispose = baseType.GetMethod("Dispose", new Type[] { });
baseDispose.Invoke(o, null);
}
}
}
class classA: IDisposable
{
public void Dispose()
{
Console.WriteLine("Disposing A");
}
}
class classB : classA, IDisposable
{
}
class classC : classB, IDisposable
{
public void Dispose()
{
Console.WriteLine("Disposing C");
Disposing.DisposeSuperclass(this);
}
}
public class MyVeryBaseClass {
protected void RealDispose(bool isDisposing) {
IDisposable tryme = this as IDisposable;
if (tryme != null) { // we implement IDisposable
this.Dispose();
base.RealDispose(isDisposing);
}
}
}
public class FirstChild : MyVeryBaseClasee {
//non-disposable
}
public class SecondChild : FirstChild, IDisposable {
~SecondChild() {
Dispose(false);
}
public void Dispose() {
Dispose(true);
GC.SuppressFinalize(this);
base.RealDispose(true);
}
protected virtual void Dispose(bool bDisposing) {
if (!m_bDisposed) {
if (bDisposing) {
}// Dispose managed resources
} // Dispose unmanaged resources
}
}
That way, you are responsible to implement right only the first class which is IDisposable.