I'm using BitConverter.ToInt32 to pack 3 byte values into an int, like so:
byte R = 0;
byte G = 0;
byte B = 0;
int i = BitConverter.ToInt32(new byte[] { R, G, B, 0 }, 0);
Is there a faster way to do this that doesn't involve the creation of a new int each time? Getting the bytes out of an int is easy:
int i = 34234;
byte B = (byte)(i >> 0);
byte G = (byte)(i >> 8);
byte R = (byte)(i >> 16);
Is there a simple way to reverse this process and use bit-shifting to write the RGB bytes back over an existing int?
int i = (B << 0) | (G << 8) | (R << 16);
You ought to consider the Color structure. It has R, G and B properties and FromArgb() and ToArgb() methods.
Related
I have an array of audio data, which is a lot of Int32 numbers represented by array of bytes (each 4 byte element represents an Int32) and i want to do some manipulation on the data (for example, add 10 to each Int32).
I converted the bytes to Int32, do the manipulation and convert it back to bytes as in this example:
//byte[] buffer;
for (int i=0; i<buffer.Length; i+=4)
{
Int32 temp0 = BitConverter.ToInt32(buffer, i);
temp0 += 10;
byte[] temp1 = BitConverter.GetBytes(temp0);
for (int j=0;j<4;j++)
{
buffer[i + j] = temp1[j];
}
}
But I would like to know if there is a better way to do such manipulation.
You can check the .NET Reference Source for pointers (grin) on how to convert from/to big endian.
class intFromBigEndianByteArray {
public byte[] b;
public int this[int i] {
get {
i <<= 2; // i *= 4; // optional
return (int)b[i] << 24 | (int)b[i + 1] << 16 | (int)b[i + 2] << 8 | b[i + 3];
}
set {
i <<= 2; // i *= 4; // optional
b[i ] = (byte)(value >> 24);
b[i + 1] = (byte)(value >> 16);
b[i + 2] = (byte)(value >> 8);
b[i + 3] = (byte)value;
}
}
}
and sample use:
byte[] buffer = { 127, 255, 255, 255, 255, 255, 255, 255 };//big endian { int.MaxValue, -1 }
//bool check = BitConverter.IsLittleEndian; // true
//int test = BitConverter.ToInt32(buffer, 0); // -129 (incorrect because little endian)
var fakeIntBuffer = new intFromBigEndianByteArray() { b = buffer };
fakeIntBuffer[0] += 2; // { 128, 0, 0, 1 } = big endian int.MinValue - 1
fakeIntBuffer[1] += 2; // { 0, 0, 0, 1 } = big endian 1
Debug.Print(string.Join(", ", buffer)); // "128, 0, 0, 0, 1, 0, 0, 1"
For better performance you can look into parallel processing and SIMD instructions - Using SSE in C#
For even better performance, you can look into Utilizing the GPU with c#
How about the following approach:
struct My
{
public int Int;
}
var bytes = Enumerable.Range(0, 20).Select(n => (byte)(n + 240)).ToArray();
foreach (var b in bytes) Console.Write("{0,-4}", b);
// Pin the managed memory
GCHandle handle = GCHandle.Alloc(bytes, GCHandleType.Pinned);
for (int i = 0; i < bytes.Length; i += 4)
{
// Copy the data
My my = (My)Marshal.PtrToStructure<My>(handle.AddrOfPinnedObject() + i);
my.Int += 10;
// Copy back
Marshal.StructureToPtr(my, handle.AddrOfPinnedObject() + i, true);
}
// Unpin
handle.Free();
foreach (var b in bytes) Console.Write("{0,-4}", b);
I made it just for fun.
Not sure that's less ugly.
I don't know, will it be faster? Test it.
Is their any way to convert 2 bytes to signed int? I know we can convert a byte to signed int in following way
byte B1= 0xFF;
int r = Convert.ToSbyte((sbyte)B1);
but what about 2 bytes to signed int? For example -260 is 0xFC, 0xFE
Assuming the first byte is the msb:
byte b1 = 0xff;
byte b2 = 0xff;
var test = BitConverter.ToInt16(new byte[] { b1, b2 }, 0);
Otherwise:
byte b1 = 0xff;
byte b2 = 0xff;
var test = BitConverter.ToInt16(new byte[] { b2, b1 }, 0);
Edit: "signed"
In case of one byte, just assign:
byte B1 = 0xFF;
int r = B1;
In case of two bytes - add shift and assign:
byte B1 = 0xFE;
byte B2 = 0xFC;
int r = (B1 << 8) | B2;
in case Int16 is wanted then cast:
// -260
short s = unchecked((short) ((B1 << 8) | B2));
Take a look at BitConverter class and its ToInt32() method.
Good morning all,
I am making an Image Steganography project for college.
While hiding data in image. I am writing the "Text Length" which is an Int32 in a pixel. As Int32 is of 4 bytes. I thought I could write it in the 4 bytes of Alpha,Red,Green,Blue, as each color is of 1 byte.
Then I save the image in bmp format.
I used single stepping and data get properly distributed and set in the pixel.
The problem arise when I read back the pixel. R,G,B have their value as i had set them. But the alpha is always 255 no matter what it was set.
Code that I am using for distributing Int32 into 4 bytes are
byte R, G, B, A;
int colorValue = messageLength;
int first = colorValue & 255;
//R contains bit 0-7 means the least significant 8 bits
R = (byte)first;
colorValue = colorValue - first;
int second = colorValue & 65535;
colorValue = colorValue - second;
second = second >> 8;
//G contains 8-15
G = (byte)second;
int third = colorValue & 16777215;
colorValue = colorValue - third;
third = third >> 16;
//B contains 16-23
B = (byte)third;
colorValue = colorValue >> 24;
//A contains 24-31
A = (byte)colorValue;
pixelColor = Color.FromArgb(A, R, G, B);
bitmap.SetPixel(location.X, location.Y, pixelColor);
Code for getting the values back is
byte R, G, B, A;
R = pixelColor.R;
G = pixelColor.G;
B = pixelColor.B;
A = pixelColor.A;
messageLength = A;
messageLength = messageLength << 8;
messageLength += B;
messageLength = messageLength << 8;
messageLength += G;
messageLength = messageLength << 8;
messageLength += R;
Is there something I am missing. Is it that BMP does not allow alpha value to persist???
Please help.
Thanks.
Sorry to say that Bitmap doesn't support an alpha value.
I am currently using BitConverter to package two unsigned shorts inside a signed int. This code executes millions of times for different values and I am thinking the code could be optimized further. Here is what I am currently doing -- you can assume the code is C#/NET.
// to two unsigned shorts from one signed int:
int xy = 343423;
byte[] bytes = BitConverter.GetBytes(xy);
ushort m_X = BitConverter.ToUInt16(bytes, 0);
ushort m_Y = BitConverter.ToUInt16(bytes, 2);
// convet two unsigned shorts to one signed int
byte[] xBytes = BitConverter.GetBytes(m_X);
byte[] yBytes = BitConverter.GetBytes(m_Y);
byte[] bytes = new byte[] {
xBytes[0],
xBytes[1],
yBytes[0],
yBytes[1],
};
return BitConverter.ToInt32(bytes, 0);
So it occurs to me that I can avoid the overhead of constructing arrays if I bitshift. But for the life of me I can't figure out what the correct shift operation is. My first pathetic attempt involved the following code:
int xy = 343423;
const int mask = 0x00000000;
byte b1, b2, b3, b4;
b1 = (byte)((xy >> 24));
b2 = (byte)((xy >> 16));
b3 = (byte)((xy >> 8) & mask);
b4 = (byte)(xy & mask);
ushort m_X = (ushort)((xy << b4) | (xy << b3));
ushort m_Y = (ushort)((xy << b2) | (xy << b1));
Could someone help me? I am thinking I need to mask the upper and lower bytes before shifting. Some of the examples I see include subtraction with type.MaxValue or an arbitrary number, like negative twelve, which is pretty confusing.
** Update **
Thank you for the great answers. Here are the results of a benchmark test:
// 34ms for bit shift with 10M operations
// 959ms for BitConverter with 10M operations
static void Main(string[] args)
{
Stopwatch stopWatch = new Stopwatch();
stopWatch.Start();
for (int i = 0; i < 10000000; i++)
{
ushort x = (ushort)i;
ushort y = (ushort)(i >> 16);
int result = (y << 16) | x;
}
stopWatch.Stop();
Console.WriteLine((int)stopWatch.Elapsed.TotalMilliseconds + "ms");
stopWatch.Start();
for (int i = 0; i < 10000000; i++)
{
byte[] bytes = BitConverter.GetBytes(i);
ushort x = BitConverter.ToUInt16(bytes, 0);
ushort y = BitConverter.ToUInt16(bytes, 2);
byte[] xBytes = BitConverter.GetBytes(x);
byte[] yBytes = BitConverter.GetBytes(y);
bytes = new byte[] {
xBytes[0],
xBytes[1],
yBytes[0],
yBytes[1],
};
int result = BitConverter.ToInt32(bytes, 0);
}
stopWatch.Stop();
Console.WriteLine((int)stopWatch.Elapsed.TotalMilliseconds + "ms");
Console.ReadKey();
}
The simplest way is to do it using two shifts:
int xy = -123456;
// Split...
ushort m_X = (ushort) xy;
ushort m_Y = (ushort)(xy>>16);
// Convert back...
int back = (m_Y << 16) | m_X;
Demo on ideone: link.
int xy = 343423;
ushort low = (ushort)(xy & 0x0000ffff);
ushort high = (ushort)((xy & 0xffff0000) >> 16);
int xxyy = low + (((int)high) << 16);
I'm trying to convert 3 bytes to signed integer (Big-endian) in C#.
I've tried to use BitConverter.ToInt32 method, but my problem is what value should have the lats byte.
Can anybody suggest me how can I do it in different way?
I also need to convert 5 (or 6 or 7) bytes to signed long, is there any general rule how to do it?
Thanks in advance for any help.
As a last resort you could always shift+add yourself:
byte b1, b2, b3;
int r = b1 << 16 | b2 << 8 | b3;
Just swap b1/b2/b3 until you have the desired result.
On second thought, this will never produce negative values.
What result do you want when the msb >= 0x80 ?
Part 2, brute force sign extension:
private static int Bytes2Int(byte b1, byte b2, byte b3)
{
int r = 0;
byte b0 = 0xff;
if ((b1 & 0x80) != 0) r |= b0 << 24;
r |= b1 << 16;
r |= b2 << 8;
r |= b3;
return r;
}
I've tested this with:
byte[] bytes = BitConverter.GetBytes(p);
int r = Bytes2Int(bytes[2], bytes[1], bytes[0]);
Console.WriteLine("{0} == {1}", p, r);
for several p.
The last value should be 0 if it isn't set for a positive number, 256 for a negative.
To know what you should pass in, you can try converting it the other way:
var bytes = BitConverter.GetBytes(i);
int x = BitConverter.ToInt32(bytes, 0);
To add to the existing answers here, there's a bit of a gotcha in that Bitconverter.ToInt32() will throw an ArgumentException if the array is less than sizseof(int) (4) bytes in size;
Destination array is not long enough to copy all the items in the collection. Check array index and length.
Given an array less than sizeof(int) (4) bytes in size, you can compensate for left/right padding like so;
Right-pad
Results in positive Int32 numbers
int intByteSize = sizeof(int);
byte[] padded = new byte[intByteSize];
Array.Copy(sourceBytes, 0, padded, 0, sourceBytes.Length);
sourceBytes = padded;
Left-pad
Results in negative Int32 numbers, assuming non-zero value at byte index sourceBytes.Length - 1.
int intByteSize = sizeof(int);
byte[] padded = new byte[intByteSize];
Array.Copy(sourceBytes, 0, padded, intByteSize - sourceBytes.Length, sourceBytes.Length);
sourceBytes = padded;
Once padded, you can safely call int myValue = BitConverter.ToInt32(sourceBytes, 0);.