How can I attach a file to this mailto string?
string mailto = "mailto:" + to + "&SUBJECT=" + subject + "?BODY=" + body +
"&Attachment=" + attachment;
This doesn't work; the file isn't attached.
Remove the quotes at the end of "attachment".
"mailto:" + to + "&SUBJECT=" + subject + "?BODY=" + body + "&Attachment=" + attachment
Where attachment has the attachment link.
Note: This will not work if the users dont have access to the attachment so you can try attaching and sending it through a c# code.
From what I saw on the web (and by trying it to), it is not always possible to do so. Some email client, and by some I mean lots of them, will not let you do this because it is considered a security hole. However, when it is accepted, the syntax provided by Shodan looks good.
Try this
var proc = new System.Diagnostics.Process();
proc.StartInfo.FileName = string.Format("\"{0}\"", Process.GetProcessesByName("OUTLOOK")[0].Modules[0].FileName);
proc.StartInfo.Arguments = string.Format(" /c ipm.note /m {0} /a \"{1}\"", "someone#somewhere.com", #"c:\attachments\file.txt");
proc.Start();
Related
I need to execute Postman collection from within my C# method.
But instead of the data file, I need to pass the data directly from the method output (as List).
Here is my code:
public StringBuilder RunPostmanCall(string collectionPath, string executionFolder, string environmentPath, List<string> inputFilePath = null)
{
StringBuilder runOutputBuilder = new StringBuilder();
string runOutput = null;
ProcessStartInfo psiNpm = new ProcessStartInfo
{
FileName = "cmd",
RedirectStandardOutput = true,
RedirectStandardInput = true,
UseShellExecute = false
};
Process pNpmRun = Process.Start(psiNpm);
pNpmRun.OutputDataReceived += (sender, a) => runOutputBuilder.AppendLine(a.Data);
Console.WriteLine(" - Install Newman ...");
pNpmRun.StandardInput.WriteLine($"npm install -g newman");
Console.WriteLine(" - Execute Postman Script ...");
string value = $"newman run " +
$"\"" + collectionPath + "\" " +
$"--folder \"" + executionFolder + "\" " +
$"--environment \"" + environmentPath + "\" " +
$"-d \"" + inputFilePath + "\" " +
$"--disable-unicode";
pNpmRun.StandardInput.WriteLine(value);
pNpmRun.BeginOutputReadLine();
pNpmRun.StandardInput.WriteLine("exit 0");
I'm getting the following error:
bin\Debug>newman run "../../api/postman_audit.json" --folder "SearchIndex" --environment "../../api/postman_environment.json" -d "System.Collections.Generic.List`1[System.String]" --disable-unicode
I could save the output into the file, and then just use that file location in the command-line. But I would like to avoid creating a file, and read data directly from the memory.
unfortunately with -d you can only refer to a file in your filesystem.
If you are not willing to write this data directly into a file, i would suggest to set the values directly as a global variable from commandline.
Try to add this parameter to your newman run command
--global-var key=value
You can add your data into a string and add it as a global variable. You can parse it in your pre-request or test-script normally.
I would like to use gammu to send text messages with address and message, but I have a problem with the gammu parameters. If I start only the program it runs (string cmd1 = "c:\\G133\\bin\\gammu.exe ";). After adding parameters it gives this failure:
System.ComponentModel.Win32Exception' occurred in System.dll
Additional information: The system cannot find the file specified:
Code:
string[] sms = File.ReadAllLines(#"C:\\temp\\test.txt");
string address = sms[0];
string message = sms[1];
string cmd1 = #"C:\G133\bin\gammu.exe --sendsms TEXT" + " " +
"\"" + address + "\" -text " + " " + "\"" + message + "\"";
System.Diagnostics.Process.Start(cmd1);
Can anyone help me? Thanks in advance.
The output looks well:
Console.WriteLine(cmd1); - result
C:\G133\bin\gammu.exe --sendsms TEXT +12121234567 -text "Hello"
You need to call the overload of Start method which takes two parameters:
First one: the file to run;
Second one: the parameters
And it will looks like:
string app = #"path\to\your\target\app";
string prms = "your parameters";
System.Diagnostics.Process.Start(app, prms);
You should split the application and the arguments:
Process.Start(#"C:\G133\bin\gammu.exe", "--sendsms TEXT +12121234567 -text \"Hello\"");
I've created a GUI app that basically loads a video file, launches 3 processes with arguments in sequential order, (ffmpeg, x264, mp4box) and has the ability to abort if needed.
I'm trying to figure out a way to launch these processes without them stealing focus from whatever program is opened. Not necessarily the original form itself...it could be IE, MS WORD, etc...I know about ProcessWindowStyle, however, all options still take focus away. I do not want to start these processes hidden either.
This is an example of my code for starting a process
Process ffmpegProcess = new Process();
ffmpegProcess.StartInfo.FileName = Settings.Default.ffmpeg;
ffmpegProcess.StartInfo.WindowStyle = ProcessWindowStyle.Minimized;
string outputaud = text2 + "_audio.aac";
string AudioBitrate = this.cBAudiobitrate.GetItemText(this.cBAudiobitrate.SelectedItem);
string ffargs = "-i " + quote + SourceFile + quote + " -filter_complex " + quote + "[0:2][0:3]amerge=inputs=2,pan=stereo|c0=c0+c1|c1=c0+c1[aout]" + quote + " -map " + quote + "[aout]" + quote + " -strict experimental -acodec aac -b:a " + AudioBitrate + "k " + quote + outputaud + quote;
ffmpegProcess.StartInfo.Arguments = ffargs;
ffmpegProcess.Start();
while (!ffmpegProcess.HasExited)
{
if (this.bw404p_withaudio.CancellationPending)
{
ffmpegProcess.Kill();
e.Cancel = true;
return;
}
Thread.Sleep(1000);
}
I know about using the Microsoft.VisualBasic Reference and Shell command with AppWinStyle as it has options for launching with no focus, I just can't seem to figure out how to modify my code to make it work with that.
Any ideas?
Thanks
startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
Is that would you're looking for? More info below
How to start Process hidden?
http://www.dotnetperls.com/process-start
ProcessWindowStyle Enumeration
When I copy paste the javaw.exe -arguments to console it works but, when I launch it like this it doesn't work.
string directory = "C:\\Users\\Can\\AppData\\Roaming\\.minecraft";
string java = #"C:\windows\system32\javaw.exe";
string javaLocation = "C:\\Program Files\\Java\\jre7\\bin\\javaw.exe";
string RAM = "1G";
string username = "namehere";
string token = "--session token:"+tokenGenerated;
string version = "1.6.2";
string launch = "-Xmx" + RAM + " -Djava.library.path={0}\\versions\\1.6.2\\1.6.2-natives-7453523379463 -cp {0}\\libraries\\net\\sf\\jopt-simple\\jopt-simple\\4.5\\jopt-simple-4.5.jar;{0}\\libraries\\com\\paulscode\\codecjorbis\\20101023\\codecjorbis-20101023.jar;{0}\\libraries\\com\\paulscode\\codecwav\\20101023\\codecwav-20101023.jar;{0}\\libraries\\com\\paulscode\\libraryjavasound\\20101123\\libraryjavasound-20101123.jar;{0}\\libraries\\com\\paulscode\\librarylwjglopenal\\20100824\\librarylwjglopenal-20100824.jar;{0}\\libraries\\com\\paulscode\\soundsystem\\20120107\\soundsystem-20120107.jar;{0}\\libraries\\argo\\argo\\2.25_fixed\\argo-2.25_fixed.jar;{0}\\libraries\\org\\bouncycastle\\bcprov-jdk15on\\1.47\\bcprov-jdk15on-1.47.jar;{0}\\libraries\\com\\google\\guava\\guava\\14.0\\guava-14.0.jar;{0}\\libraries\\org\\apache\\commons\\commons-lang3\\3.1\\commons-lang3-3.1.jar;{0}\\libraries\\commons-io\\commons-io\\2.4\\commons-io-2.4.jar;{0}\\libraries\\net\\java\\jinput\\jinput\\2.0.5\\jinput-2.0.5.jar;{0}\\libraries\\net\\java\\jutils\\jutils\\1.0.0\\jutils-1.0.0.jar;{0}\\libraries\\com\\google\\code\\gson\\gson\\2.2.2\\gson-2.2.2.jar;{0}\\libraries\\org\\lwjgl\\lwjgl\\lwjgl\\2.9.0\\lwjgl-2.9.0.jar;{0}\\libraries\\org\\lwjgl\\lwjgl\\lwjgl_util\\2.9.0\\lwjgl_util-2.9.0.jar;{0}\\versions\\1.6.2\\1.6.2.jar net.minecraft.client.main.Main --username " + username + " " + token + " --version " + version + " --gameDir {0} --assetsDir {0}\\assets";
launch = String.Format(launch, directory);
string text = launch;
// WriteAllText creates a file, writes the specified string to the file,
// and then closes the file.
Directory.SetCurrentDirectory(#"C:\windows\system32\");
Process.Start("javaw.exe",
Path.Combine(launch));
What am I doing wrong?
Why do you need to call Path.Combine if your whole path is in one string?
Assuming your javaw.exe is actually in C:\windows\system32\, Process.Start("java.exe", launch); should work as intended.
Source - Path on MSDN: http://msdn.microsoft.com/en-us/library/system.io.path.aspx
Just use Java's real location instead of "javaw" like "c:\programfiles\Java\jre7\bin\javaw.exe"
I have some code that uses a library for a product called Fusion Pro. Based on some config and data files it will generate a PDF file. I have been getting consistent result of a complete lack of output without any thrown exceptions. However when debugging I have been able to get the PDF to generate by attaching the debugger to the code running in my local IIS and stepping through line by line. Nothing is consistent though. It seems to have a higher success rate if I use F11 instead of F10 and going "slow but steady" through each line. Unfortunately it doesn't always produce a PDF even with stepping through the code.
I have never experienced code behaving so inconstantly with the same inputs each time.
The only other relevant bits of information is this code is working in another asmx service without issue, it is running under a specific domain account (requires special security), and it is running in 32bit mode.
DLQueueClient client = new DLQueueClient();
DLQueueJob vdpQueueJob = new DLQueueJob();
string fileName = message.OutputFilePath;
var dataFilePath = CreateDataFile(fileName, message.DefFilePath, message.VariableDataContent, message.QTY);
var pdfFilePath = Path.Combine(new[] { message.OutputFilePath, dataFilePath.Replace(".txt", ".pdf") });
vdpQueueJob.Priority = priority;
vdpQueueJob.Queue = queueName;
string cmd = "\"" + Settings.FusionProExe + "\" \"" + dataFilePath + "\" \""
+ message.DiffFilePath + "\" \"" +
(isProof ? message.ProofConfigFilePath : message.PrintConfigFilePath) + "\" \""
+ pdfFilePath + "\"";
vdpQueueJob.CommandLine = cmd;
client.ConnectRemote(Settings.FusionProServer, Settings.FusionProUser, Settings.FusionProPassword, Settings.FusionProTimeout);
client.SubmitJob(vdpQueueJob, Settings.FusionProTimeout, true);
return pdfFilePath;