I have a text string with single quotes, I'd like to remove the parenthesis before and after that single quotes by using regular expression. Could anyone suggest me Thank you.
For example,
I have (name equal '('John')') the result that I expect is name equal '('John')'
// Using Regex
string input = "(name equal '('John')')";
Regex rx = new Regex(#"^\((.*?)\)$");
Console.WriteLine(rx.Match(input).Groups[1].Value);
// Using Substring method
String input= "(name equal '('John')')";
var result = input.Substring (1, input.Length-2);
Console.WriteLine(result);
Result:
name equal '('John')'
Try this:
var replaced = Regex.Replace("(name equal '('John')')", #"\((.+?'\)')\)", "${1}");
The Regex class is in the System.Text.RegularExpressions namespace.
Use negative look behind (?<! ) and negative look ahead (?! ) which will stop a match if it encounters the ', such as
(?<!')\(|\)(?!')
The example explains it as a comment:
string pattern =
#"
(?<!')\( # Match an open paren that does not have a tick behind it
| # or
\)(?!') # Match a closed paren tha does not have tick after it
";
var text = "(name equal '('John')')";
// Ignore Pattern whitespace allows us to comment the pattern ONLY, does not affect processing.
var final = Regex.Replace(text, pattern, string.Empty, RegexOptions.IgnorePatternWhitespace);
Result
name equal '('John')'
I am splitting a string with regex using its Split() method.
var splitRegex = new Regex(#"[\s|{]");
string input = "/Tests/ShowMessage { 'Text': 'foo' }";
//second version of the input:
//string input = "/Tests/ShowMessage{ 'Text': 'foo' }";
string[] splittedText = splitRegex.Split(input, 2);
The string is just a sample pattern of the input. There are two different structures of input, once with a space before the { or without the space. I want to split the input on the { bracket in order to get the following result:
/Tests/ShowMessage
{ 'Text': 'foo' }
If there is a space, the string gets splitted there (space gets removed) and i get my desired result. But if there isnt a space i split the string on the {, so the { gets removed, what i dont want though. How can i use Regex.Split() without removing the split condition character?
The square brackets create a character set, so you want it to match exactly one of those inner characters. For your desire start off by removing them.
So to match it a random count of whitespaces you have to add *, the result is this one\s*.
\s is a whitespace
* means zero-or-more
That you don't remove the split condition character, you can use lookahead assertion (?=...).
(?=...) or (?!...) is a lookahead assertion
The combined Regex looks like this: \s*(?={)
This is a really good and detailed documentation of all the different Regex parts, you might have a look at it. Furthermore you can test your Regex easy and for free here.
In order to not include the curly brace in the match you can put it into a look ahead
\s*(?={)
That will match any number of white spaces up to the position before a open curly brace.
You can use regular string split, on "{" and trim the spaces off:
var bits = "/Tests/ShowMessage { 'Text': 'foo' }".Split("{", StringSplitOptions.RemoveEmptyEntries);
bits[0] = bits[0].TrimEnd();
bits[1] = "{" + bits[1];
If you want to use the RegEx route, you can add the { back if you change the regex a bit:
var splitRegex = new Regex(#"\s*{");
string input = "/Tests/ShowMessage { 'Text': 'foo' }";
//second version of the input:
//string input = "/Tests/ShowMessage{ 'Text': 'foo' }";
string[] splittedText = splitRegex.Split(input, 2);
splittedText[1] = "{" + splittedText[1];
It means "split at occurrence of (zero or more whitespace followed by {)" - so the split operation nukes your spaces (you want), and your { (you don't want) but you can put the { back with certainty that it will mean you get what you want
var splitedList = srt.Text.Replace(".", ".#").Replace("?", "?#").Replace("!", "!#").Split(new[] { "#"}, StringSplitOptions.RemoveEmptyEntries).ToList();
This will split text for .!? and will not remove condition chars. For better result just replace # with some uniq char. Like this one for example '®' That is all. Simple as it is. No regex.split which is slow and difficult due to many different task criterias, etc...
passing-> "Hello. I'am dev!"
result (split condition character exist )
"Hello."
"I'am dev!"
I have string of the following format:
string test = "test.BO.ID";
My aim is string that part of the string whatever comes after first dot.
So ideally I am expecting output as "BO.ID".
Here is what I have tried:
// Checking for the first occurence and take whatever comes after dot
var output = Regex.Match(test, #"^(?=.).*?");
The output I am getting is empty.
What is the modification I need to make it for Regex?
You get an empty output because the pattern you have can match an empty string at the start of a string, and that is enough since .*? is a lazy subpattern and . matches any char.
Use (the value will be in Match.Groups[1].Value)
\.(.*)
or (with a lookahead, to get the string as a Match.Value)
(?<=\.).*
See the regex demo and a C# online demo.
A non-regex approach can be use String#Split with count argument (demo):
var s = "test.BO.ID";
var res = s.Split(new[] {"."}, 2, StringSplitOptions.None);
if (res.GetLength(0) > 1)
Console.WriteLine(res[1]);
If you only want the part after the first dot you don't need a regex at all:
x.Substring(x.IndexOf('.'))
I have a string -
xyz":abc,"lmn
I want to extract abc. what will be the regular expression for this ?
I am trying this -
/xyz\":(.*?),\"lmn/
But it is not fetching any result.
In c# you could use
var regex = new Regex(#"(?<=xyz\"":).*?(?=,\""lmn)");
var value = regex.Match(#"xyz"":abc,""lmn").Value;
Note this makes use of the c# verbatim string prefix # that means that \ is not treated as an escape character. You will need to use a double " so that a single " will be included in the string.
This regex makes use of prefix and suffix matching rules so that you can get the match without having to select the specific group from the result.
Alternatively you can use group matching
var regex=new Regex(#"xyz\"":(.*?),\""lmn");
var value = regex.Match(#"xyz"":abc,""lmn").Groups[1].Value;
You can check for the existence of a match by doing the following
var match = regex.Match(#"xyz"":abc,""lmn");
var isMatch = match.Success;
and then follow up with either match.Value or match.Groups[1].Value depending on which regex you used.
EDIT
Actually the escaping the " is not needed in a c# regex so you could use either of the following instead.
var regex = new Regex("(?<=xyz\":).*?(?=,\"lmn)");
var regex = new Regex("xyz\":(.*?),\"lmn");
These two do not use the verbatim string prefix, so the \" is translated into just " in the regex giving an a regex of (?<=xyz":).*?(?=,"lmn) or xyz":(.*?),"lmn
Additionally if the is an entire string match rather than a substring you would want one of the following.
var regex = new Regex("(?<=^xyz\":).*?(?=,\"lmn$)");
var regex = new Regex("^xyz\":(.*?),\"lmn$");
I have a string like
[123,234,321,....]
Can i use a regular expression to extract only the numbers ?
this is the code i am using now
public static string[] Split()
{
string s = "[123,234,345,456,567,678,789,890,100]";
var temp = s.Replace("[", "").Replace("]", "");
char[] separator = { ',' };
return temp.Split(separator);
}
You can use string.Split for this - no need for a regular expression, though your code can be simplified:
var nums = s.Split('[', ']', ',');
Thought you may want to exclude empty entries in the returned array:
var nums = s.Split(new[] { '[', ']', ',' },
StringSplitOptions.RemoveEmptyEntries);
There's an overload to Trim() that takes a character.
You could do this.
string s = "[123,234,345,456,567,678,789,890,100]";
var nums = s.Trim('[').Trim(']').Split(',');
If you want to use a regular expression, try:
string s = "[123,234,345,456,567,678,789,890,100]";
var matches = Regex.Matches(s, #"[0-9]+", RegexOptions.Compiled);
However, regular expressions tend to make your code less readable, so you might stick with your original approach.
Try with using string.Split method;
string s = "[123,234,345,456,567,678,789,890,100]";
var numbers = s.Split('[',']', ',');
foreach(var i in numbers )
Console.WriteLine(i);
Here is a DEMO.
EDIT: As Oded mentioned, you may want to use StringSplitOptions.RemoveEmptyEntries also.
string s = "[123,234,345,456,567,678,789,890,100]";
MatchCollection matches = Regex.Matches(s, #"(\d+)[,\]]");
string[] result = matches.OfType<Match>().Select(m => m.Groups[1].Value).ToArray();
Here the # is used to signify a verbatim string literal and allows the escape character '\' to be used directly in Regular expression notation without escaping itself "\".
\d is a digit, \d+ mean 1 or more digits. The parenthesis signify a group so (\d+) means I want a group of digits. (*See group used a little later)
[,\]] square brackets, in brief, mean choose any one of my element so it will choose either the comma , or a square bracket ] which I had to escape.
So the regular expression will find the expressions of sequential digits followed by a , or ]. The Matches will return the set of matches (which we use because there are multiple set) then we go through each match - with some LINQ - and grab the index 1 group which is the second group, "But we only made one group?" We only specified one group, the first group (index 0) is the entire regular expression match, which in our case, will include the , or ] which we don't want.
while you can and probably should use string.Split as other answers indicate, the question specifically asks if you can do it with regex, and yes, you can :-
var r = new Regex(#"\d+", RegexOptions.Compiled );
var matches = r.Matches("[123,234,345,456,567,678,789,890,100]");