My application creates files with a ".mhm" extension.
I'd like for my application to open and process these files when I double-click them. Current behavior is that when I double-click the file, my application opens but does not process the file.
How can I read the args parameter of Main() method in C# 2008?
"Hi
My Application creates files with the .MHM file extension.
I would like my application to be associated with this file extension so that when a MHM file is executed, my application is too, with the file path as the arguments for the main method of my application."
That's what I understood.
Grzenio has the right idea -
public void static Main(string args[])
{
...
}
but to push your application into the shell would take extra research, you'd have to look into integrating your application into the Shell (using the registry).
See here: script-to-associate-an-extension-to-a-program
EDIT: Thanks for the edit of the question Chris, trying to see things a bit wider here... Perhaps the arguments solution was all the OP needed.
If I understand your question correctly you just use:
public void static Main(string args[])
{
...
}
Related
Looking how to run the program.cs file from a winform as I'm trying to run it, hide it and display the text in the textbox but I cannot find a way to run the console separately once the winform has started up!
A .cs file is just plaintext as far as I'm aware - You probably need to to actually be executable - From there you can use IPC to communicate between the two processes.
If you have somehow made the program.cs run (Black magic?) you could also get one process to write to a text file, then get the "winform" process to read from it (And then delete it!).
You might try elaborating on your problem, method and environment in your question - There's not a lot to work off here.
Make a console application and add a WinForm to do. Show the winform with .ShowDialog() and you will have both the console and the winform showing at the same time.
class Program
{
static void Main(string[] args)
{
var dlg = new Form1();
dlg.ShowDialog();
}
}
I am will be using this class to set file associations for my program. How would i fetch the path of which file was opened to launch the application? I searched that class for one, and didn't spot one anywhere, and I have searched google and MSDN for the last few hours with no results. I don't have any sample code as I have absolutely no clue.
Any help is thanked and will be welcome.
The filename for the file that was selected, causing your application to open, will be passed as a command line parameter. If this is a program where you're writing the Main function, the array of strings passed to the function will contain the information you need.
public static void Main(string[] args)
Another option, if you aren't writing Main yourself, is to call
Environment.GetCommandLineArgs
See this page http://msdn.microsoft.com/en-us/library/system.environment.getcommandlineargs.aspx for more information about how to use this function.
in my application I've registered a file type (.asm) with my application (it's a tabbed notepad application), and when those files are double-clicked they open with my application through the arguments passed when it's loaded:
static void Main(string[] args)
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Main(args));
}
Now the problem is, while this does work, if one instance of my application is already running, whenever a file is opened, a new instance of it is created rather than a new tab being opened in the current instance which I don't want. So I thought of checking if the program is already running, and if it is then I would call a separate function in the main form to load that document instead. But the problem is, I don't know how you call a function in Main.cs from Program.cs, how do we do that?
It's more complicated than just calling a function in Main.cs from Program.cs because the OS will launch a second process for you at the time you double-click your registered files. You need some way to find out if there is another existing process running already and then communicate with that existing process, if there is one.
Fortunately, there is a class in the .NET Framework that already does all of the hard work for you:
Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase
See this blog for a complete example:
http://windowsclient.net/blogs/suryahg/archive/2008/08/20/use-of-microsoft-visualbasic-applicationservices-part-2.aspx
The technique in this question might help:
C# : how to - single instance application that accepts new parameters?
I've written a log parser, with some generous and insightful help from the SO community:
Keeping the UI responsive while parsing a very large logfile
Now, I'd like to be able to right click one of these logs, select "MyNewLogParser" from "Open With.." and see it open in my new program.
This would require me to
Change something about my XP installation to show my program in the dropdown list
Change the program so that it knows to open the selected file and run the parsing.
What do you call these things, and how is it done? I don't know what to search for...
To open the selected file, you need to implement command-line parameters. Take a look at your Program.cs file and the Main function.
You want its signature to look something like this:
static void Main(string[] args)
{
}
The args array will be the array of command-line params passed to your application. So if you ran MyNewLogParser myLog.txt, the contents of args[0] would be myLog.txt.
For the OpenWith... menu, you'll need to modify the registry. Search for the "OpenWith" key in Regedit and you'll find it. On my machine (Windows 7), it's in HKEY_CURRENT_USER\Software\Microsoft\Windows\CurrentVersion\Explorer\FileExts. I'm not sure on the exact details of how it works, but Google should be able to help you out from there.
If you don't want to do it programmatically, I'm pretty sure there's some menu item that allows you to select the application that will open a file. Don't recall what it is on XP, though. Alternatively, you can associate a file extension with your application through a tab in the Folder Options dialog, so that double-clicking it opens your application.
Assuming that your file logs have specific file extension, you need to add OpenWithList keys in the registry. See this MSDN page for more information:
http://msdn.microsoft.com/en-us/library/bb166549%28VS.80%29.aspx
When you double-click on a Word document, Word is automatically run and the document is loaded.
What steps are needed to do the same thing with my C# application?
In other words, assume my application uses ".XYZ" data files. I know how to tell Windows to start my application when a .XYZ data file is double clicked. But how do I find out within my application what data file was chosen so I can load it?
Granted this is a VB.NET solution, but this article has details on how to create the file association for your application in the registry and how to retrieve the command arguments when your application is fired up to do the proper file handling.
It looks easy enough to port over to C#.
The arguments should contain the path to the data file.
You can tweak this behavior and pass additional arguments. Look at the example in this image. Here the file path is passed with %1.
Quicktime File Association Dialog
I think what you are looking for is command-line arguments. If you look at the Open action for .doc for example you'll probably see something like this 'word.exe %1'. Windows will take the name of the file and substitute it in for %1 and then execute the command 'word.exe whatever.doc'. Then from within the application you can see what was passed as an argument into the program see this MSDN article for more details.
I believe it is just a command-line argument that gets passed into your app. Then you can read it with Environment.GetCommandLineArgs. I know that is the case if you drag-and-drop a file onto your app. I have not done what you are describing myself but I assume it works the same way.
I did this in a project I was working on awhile ago and don't have the source code handy, but I believe it really came down to this:
//program.cs
[STAThread]
static void Main(string[] args)
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
if (args.Length > 0)
{
//launch same form as normal or different
Application.Run(new Form1(args));
}
else
{
Application.Run(new Form1());
}
}
args is empty when the application is normally started, but when you've properly linked in the association to your .xyz file, when one of those files is selected, your application will be launched with the file location as the first element of the string[]. Certainly either in program.cs or your launch form, I would add validation, but at the base level I believe this is what you need to do.