(C#) How to draw an "a" with Tahoma with height = 6 - c#

I've been trying to do this, but for some reason this is just giving me weird results:
int bpp = Screen.PrimaryScreen.BitsPerPixel;
string fontName = "Tahoma";
Font font = new Font(fontName, 10 * bpp, GraphicsUnit.Point);
Bitmap bm = new Bitmap(20 * bpp, 20 * bpp);
Graphics g = Graphics.FromImage(bm);
TextRenderer.DrawText(g, "a", font, new Rectangle(0, 0, 5 * bpp, 6 * bpp), Color.Black);
g.Flush();
pictureBox1.Image = bm;
What am I doing wrong here? I don't see anything printed on the picture. If I remove all bpp references, I can see it, but it's pretty small.

You are aware that BitsPerPixel describes the color depth (the number of memory bits that are used to describe the color of a pixel), and has nothing to do with resolution?
I assume that what you want to do is to draw the text in a size that is related to the resolution, which you can do by referring to the DpiX and DpiY properties of the Graphics object.
Update
I am not sure if yo need to bring Dpi into the calculation for this. All you need to do is to create a Rectangle that defines the desired size of your text, and then calculate the correct font size to make the text fit inside the rectangle. The following does that (but maximizes the text size both vertical and horizontal direction). It might give you some pointers to solve your problem:
Bitmap bm = new Bitmap(50, 50);
using (Font font = new Font(fontName, 10, GraphicsUnit.Point))
using (Graphics g = Graphics.FromImage(bm))
{
g.TextRenderingHint = System.Drawing.Text.TextRenderingHint.AntiAlias;
StringFormat stringFormat = new StringFormat()
{
Alignment = StringAlignment.Center,
LineAlignment = StringAlignment.Near
};
Rectangle rect = new Rectangle(0, 0, bm.Width, bm.Height);
// measure how large the text is on the Graphics object with the current font size
SizeF s = g.MeasureString(text, font);
// calculate how to scale the font to make the text fit
float fontScale = Math.Max(s.Width / rect.Width, s.Height / rect.Height);
using (Font fontForDrawing = new Font(font.FontFamily, font.SizeInPoints / fontScale, GraphicsUnit.Point))
{
g.DrawString(text, fontForDrawing, Brushes.Black, rect, stringFormat);
}
}
And if you want to print the text with a given point size, you don't need to go about measuring; just set the font size:
Bitmap bm = new Bitmap(20, 20);
using (Font font = new Font(fontName, 6, GraphicsUnit.Point))
using (Graphics g = Graphics.FromImage(bm))
{
g.TextRenderingHint = System.Drawing.Text.TextRenderingHint.AntiAlias;
StringFormat stringFormat = new StringFormat()
{
Alignment = StringAlignment.Center,
LineAlignment = StringAlignment.Near
};
Rectangle rect = new Rectangle(0, 0, bm.Width, bm.Height);
g.DrawString(text, font, Brushes.Black, rect, stringFormat);
}

I would try:
int ImgQual = 600;
int Width = 50;
int Height = 50;
Font TextFont = New Font("Tahoma", 14, FontStyle.Bold)
Bitmap bmp = New Bitmap(Width, Height);
bmp.SetResolution(ImgQual, ImgQual);
System.Drawing.Graphics g = Graphics.FromImage(bmp);
System.Drawing.StringFormat sf = New System.Drawing.StringFormat();
sf.Alignment = StringAlignment.Center;
g.DrawString("a", NumberTextFont, Brushes.Black, New RectangleF(0, 0, Width, Height), sf);
return bmp;

There are two primary reasons the "a" is small:
The height of a font is measured using a point size (which is 1/72nd of a inch, quite different from a number of pixels because different computer screens have different numbers of pixels per inch).
Font height is measured from the top of a line of text to the bottom. As some letters have ascenders (the tall bar in "h") and others have descenders (the dangly bit of a "g"), an "a" will occupy only about a third of the height of the font.
If you wish your "a" to fill the image, then you will need to draw it into a larger rectangle and "clip off" the empty regions above and below the "a". If you're not too worried about screen DPI on different computers, then you can just experiment until you find a font size (and position to draw at) that works.

Related

Is it posble create text on image with higher quality in .net

I need to create some kind of graph in .net desktop application.
I use .Net Framework 4.7.2 and System.Drawing library.
The scenario looked like this.
In the console application I create a bitmap with X and Y axes and some simple lines and some text on those lines, nothing complicated.
After creating the bitmap, I save it as .bmp file.
The problem is that the letters and numbers I create are bad and look furry, I tried with different fonts and different settings but the result was always the same.
The picture looks like this:
and under a magnifyer it looks like this:
This is my sample code:
// create new bitmap
Bitmap bitmap = new Bitmap(900, 700, System.Drawing.Imaging.PixelFormat.Format32bppPArgb);
Graphics g = Graphics.FromImage(bitmap);
g.Clear(Color.LightGray);
// set attr
g.SmoothingMode = SmoothingMode.AntiAlias;
g.InterpolationMode = InterpolationMode.Bicubic;
// draw X and Y axes
Pen pen = new Pen(Color.Black, 1);
g.DrawLine(pen, new Point(100, 100), new Point(100,600));
g.DrawLine(pen, new Point(100, 600), new Point(800, 600));
SolidBrush brush = new SolidBrush(Color.Black);
Font font = new Font("Lucida Console", 14, FontStyle.Bold);
g.SmoothingMode = SmoothingMode.AntiAlias;
g.InterpolationMode = InterpolationMode.Bicubic;
// grid numbeers on x axis
for (int i = 0; i < 8; i++)
{
g.DrawString(i.ToString(), font, brush, 100 * (i+1), 620);
}
// grid numbeers on y axis
for (int i = 0; i < 6; i++)
{
g.DrawString(i.ToString(), font, brush, 70, 600 - (100 * i));
}
// label 1
font = new Font("Lucida Console", 14, FontStyle.Bold);
g.DrawString("Line - X axis", font, brush, 100, 650);
// label 2
font = new Font("Lucida Console", 32, FontStyle.Bold);
g.DrawString("PORCO El.01", font, brush, 550, 150);
// label 3
font = new Font("Lucida Console", 24, FontStyle.Regular);
g.DrawString("PORCO El.01", font, brush, 550, 200);
// save as .bmp file
bitmap.Save(Path.Combine(picturePath, "sample.bmp"));
Is it possible to get better text quality? Is there maybe another 3rd party library that can achieve better results?
Thanks in advance!

Draw rectangle box for letters

My code. Output:
Bitmap bitmap = new Bitmap(600, 300, PixelFormat.Format32bppArgb);
Graphics g = Graphics.FromImage(bitmap);
GraphicsPath path = new GraphicsPath();
StringFormat format = new StringFormat();
Rectangle rect = new Rectangle(0, 0, 600, 300);
SolidBrush Brush = new SolidBrush(Color.White);
g.FillRectangle(Brush, rect);
g.SmoothingMode = SmoothingMode.AntiAlias;
format.Alignment = StringAlignment.Center;
format.LineAlignment = StringAlignment.Center;
path.AddString(textBox1.Text, FontFamily.GenericSansSerif, (int)FontStyle.Bold, 128, rect, format);
Brush = new SolidBrush(Color.Blue);
g.FillPath(Brush, path);
float x = path.GetBounds().X;
float y = path.GetBounds().Y;
float w = path.GetBounds().Width / textBox1.Text.Length;
float h = path.GetBounds().Height;
Pen redPen = new Pen(Color.Red, 2);
for (int i = 0; i < textBox1.Text.Length+1; i++)
{
rect = new Rectangle((int)x, (int)y, (int)w*i, (int)h);
g.DrawRectangle(redPen, rect);
}
pictureBox1.Image = bitmap;
I am getting the wrong result in the output because I cannot get the corners of the letters and am using the wrong way.
But i need get correct pixels of letter corners, draw rectangle and fill it.
Like this:
This line made me find one error in your code:
for (int i = 0; i < textBox1.Text.Length+1; i++)
It should be:
for (int i = 0; i < textBox1.Text.Length; i++)
But then indeed only 3 red boxes seem to appear.
The reason for that is the first rectangle (with your code) is very small, because the width is (int)w*i. That should be (int)w*(i+1).
Now back to the place where you are drawing rectangles.
If you take the text 'WWWW', you will see that your solution seems pretty OK.
But if you test with 'IIII', ten you should note that the left-most 'I' is left aligned in the red box, and the right-most 'I' is right aligned in the red box.
You are drawing 4 equal boxes round 4 letters with different with.
A solution could be to draw the letters with a monospaced font.
or, if you do not want a monospaced font, look at How to measure width of character precisely?

How to build a string that have a fixed length, and append data to it at specific starting positions?

How to build a string that have a fixed length of pixels, and append three variables to it at specific starting positions in pixels, variables data constantly changes but their starting positions are constant within the string.
// Below is what am trying to accomplish if I were to use Graphics DrawString
Bitmap bmp = new Bitmap(656, 5);
using (Graphics g = Graphics.FromImage(bmp))
{
Font font = new Font("Arial", 14, FontStyle.Regular, GraphicsUnit.Point);
g.Clear(Color.White);
g.DrawString(first_number, font, Brushes.Black, 10, 1;
g.DrawString(full_name, font, Brushes.Black, 150, 1);
g.DrawString(second_number, font, Brushes.Black, 550, 1);
}

DrawEllipse: Ellipse goes outside of the Bitmap size

I want to draw a circle with DrawEllipse on a specified Bitmap, with the same size of the Bitmap, but the result is that the circle appears clipped at the edges.
Why this problem?
Bitmap layer = new Bitmap(80, 80);
using (Graphics g = Graphics.FromImage(layer))
{
using (Pen p = new Pen(Color.Black, 4))
{
g.DrawEllipse(p, new Rectangle(0, 0, layer.Width, layer.Height));
}
}
pictureBox3.Size = new Size(100, 100);
pictureBox3.Image = layer;
By default a Pen has a PenAlignment.Center.
This means that half of its widh will draw outside the bounding rectangle.
You can simply avoid the issue by changing it to PenAlignment.Inset:
using (Pen p = new Pen(Color.Black, 4) { Alignment = PenAlignment.Inset})
{
g.DrawEllipse(p, new Rectangle(0, 0, layer.Width, layer.Height));
}
Update: If you want to turn on smoothing for the Graphics object you will need 1 or 2 extra pixels on both sides of the pen stroke for the anti-aliasing pixels. Using a smaller bounding rectanlge can't be avoided now. But..:
Rectangle rect = new Rectangle(Point.Empty, layer.Size);
rect.Inflate(-1, -1); // or -2
..should do..

Adapt Rectangle's region to a different size

Under Windows Forms, I take a full size screenshot of a specific window that has a specific window size, I save it into a Bitmap object, then, I declared a Rectangle structure to crop a region of that Bitmap, because later I need to manipulate only a very specific part/region of the screenshot...
To make things simpler for this question, lets say the window and bitmap size is 640x480, the Rectangle's X,Y is: 436,150 and the Width,Height is: 146,170, and what I crop from the screenshot (the bitmap) is a balloon image. The window is a videogame.
The problem is that when the window size increase, the balloon image increase too, as obvious, so the x,y and width/height of my rectangle for a window size of 640x480 will not properly capture/crop the entire balloon image when the window of the game has a bigger size...
I need to know how can I calculate the x,y width/height that my rectangle should have to properly crop the balloon image when the window size changes. I need to adapt the rectangle.
So, if this is the predefined size and rectangle I have:
{ new Size(640, 480), new Rectangle(436, 150, 146, 170) }
From that, the approximated adapted values that the rectangle should have to properly crop the same equivalent area in a window size of 800x600 and 1280x768 it would be more or less these:
{ new Size(800, 600), new Rectangle(546, 186, 186, 212) }
{ new Size(1280, 768), new Rectangle(830, 232, 240, 274) }
...are just approximated values, but not perfect, because I did it manually since Im not sure which is the way to calculate and automate this math operation.
I hope my question and problem was understood. Thankyou in advance.
Maybe you're over-thinking it, but all you need to do is capture the percentage change between the original size and the new size (for both X and Y), and then apply that percentage to the properties of the original rectangle to get the new rectangle.
For example:
public static Rectangle GetNewRectangle(Size oldSize, Rectangle oldRectangle,
Size newSize)
{
var percentChangeX = (double)newSize.Width / oldSize.Width;
var percentChangeY = (double)newSize.Height / oldSize.Height;
return new Rectangle
{
X = (int)(oldRectangle.X * percentChangeX),
Y = (int)(oldRectangle.Y * percentChangeY),
Width = (int)(oldRectangle.Width * percentChangeX),
Height = (int)(oldRectangle.Height * percentChangeY)
};
}
Example usage:
// Helper method to display size and rectangle properties
private static string GetDisplayValues(Size size, Rectangle rect)
{
return $" - size: {size.Width} x {size.Height}\n" +
$" - rect: {rect.X}, {rect.Y} : {rect.Width} x {rect.Height}\n";
}
private static void Main()
{
var size = new Size(640, 480);
var rect = new Rectangle(436, 150, 146, 170);
Console.WriteLine($"Original:\n{GetDisplayValues(size, rect)}");
var newSize = new Size(800, 600);
var newRect = GetNewRectangle(size, rect, newSize);
Console.WriteLine($"Resized:\n{GetDisplayValues(newSize, newRect)}");
GetKeyFromUser("\nDone! Press any key to exit...");
}
Output
Try this:
if width 640:
X = 436 / 640 = 0.68125 (68.125%)
W = 146 / 640 = 0.22125 (22.125%)
if heigth 480:
Y = 150 / 480 = 0.3125 (31.25%)
H = 170 / 480 = 0.3541666666666666666666666667 (35.41666666666666666666666667%)
Considering the size of the form as this.Width, and the height as this.Height:
decimal pX = 0.68125;
decimal pW = 0.22125;
decimal pY = 0.3125;
decimal pH = 0.3541666666666666666666666667;
Rectangle rect = new Rectangle(this.Width * pX, this.Height * pY, this.Width * pW, this.Height * pH);
Given a source Bitmap and a selection Rectangle inside its boundaries:
RectangleF SourceRect = new Rectangle(Point.Empty, SourceBitmap.Size);
Rectangle SelectionRect = new Rectangle([Point], [Size]);
When the SourceBitmap changes its size, the new size of the selection rectangle is calculated using the scale factor given by the relation between the old size and the new size of the SourceBitmap:
RectangleF DestinationRect = new RectangleF(Point.Empty, InflatedBitmap.Size);
SizeF ScaleFactor = new SizeF(DestinationRect.Width / SourceRect.Width,
DestinationRect.Height / SourceRect.Height);
PointF NewPosition = new PointF(SelectionRect.X * ScaleFactor.Width, SelectionRect.Y * ScaleFactor.Height);
SizeF NewSize = new SizeF(SelectionRect.Width * ScaleFactor.Width, SelectionRect.Height * ScaleFactor.Height);
RectangleF InflatedSelection = new RectangleF(NewPosition, NewSize);
With a SourceBitmap and a selection rectangle sized as:
RectangleF SourceRect = new RectangleF(0, 0, 640, 480);
RectangleF SelectionRect = new RectangleF(436, 150, 146, 170);
If the inflated bitmaps are sized as:
RectangleF DestinationRect1 = new RectangleF(0, 0, 800, 600);
RectangleF DestinationRect2 = new RectangleF(0, 0, 1280, 768);
The Inflated selection with a scale factor of (1.25, 1.25) and (2, 1.6) will be (rounded down):
RectangleF InflatedSelection1 = new RectangleF(545, 187, 182, 212);
RectangleF InflatedSelection2 = new RectangleF(872, 240, 292, 272);

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