I have the following XML snippet:
<dmFiles>
−
<dmFile dmUpFileGuid="" dmFileDescr="testcase01.pdf" dmFileMetaType="main" dmFileGuid="" dmMimeType="pdf" dmFormat="">
If I create a strongly typed C# class with string properties for the dmFile attributes (eg: dmFileDescr), how can I ensure these attributes will serialize to properties in my c# class?
By using Xml attributes on your class member. Use [XmlAttribute("name")].
Your implementation would look like this:
[XmlRoot("dmFile")]
public class DmFile
{
[XmlAttribute("dmUpFileGuid")]
public String UpFileGuid { get;set; }
...
}
Try this:
[Serializable]
[XmlRoot(ElementName="dmFile")]
public class File
{
[XmlAttribute(AttributeName="dmUpFileGuid")]
public string UploadGuid { get; set; }
[XmlAttribute(AttributeName = "dmFileDescr")]
public string Description { get; set; }
[XmlAttribute(AttributeName = "dmFileMetaType")]
public string MetaType { get; set; }
[XmlAttribute(AttributeName = "dmFileGuid")]
public string FileGuid { get; set; }
[XmlAttribute(AttributeName = "dmMimeType")]
public string MimeType { get; set; }
[XmlAttribute(AttributeName = "dmFormat")]
public string Format { get; set; }
}
And deserialize your XML as follow:
XmlSerializer s = new XmlSerializer(typeof(File));
File file = s.Deserialize(new StringReader(#"<dmFile ... />")) as File;
You can (de)serialize from/to XML with the XmlSerializer and marking up the target class with Attributes provided for Xml-Serialization.
Mark your public properties with the correct attribute. It should be XmlAttributeAttribute.
The enclosing class must map on the dmFile-Element (XmlRootAttribute)
If the property is called differently, or the class is called differently than the XML element, you need to specify the XML-Element/Attribute name.
Related
I am working on deserializing the following XML document into a C# class:
<Station>
<station_id>KMSP</station_id>
<wmo_id>72658</wmo_id>
<latitude>44.88</latitude>
<longitude>-93.23</longitude>
<elevation_m>255.0</elevation_m>
<site>MINNEAPOLIS</site>
<state>MN</state>
<country>US</country>
<site_type>
<METAR />
<TAF />
</site_type>
</Station>
This is the class that it is being deserialized into:
public class Station
{
[XmlElement(ElementName ="station_id")]
public string StationId { get; set; }
[XmlElement(ElementName = "wmo_id")]
public string WmoId { get; set; }
[XmlElement(ElementName ="latitude")]
public double Latitude { get; set; }
[XmlElement(ElementName = "longtitude")]
public double Longtitude { get; set; }
[XmlElement(ElementName="site")]
public string Site { get; set; }
[XmlElement(ElementName ="state")]
public string State { get; set; }
[XmlElement(ElementName ="country")]
public string Country { get; set; }
[XmlElement(ElementName = "site_type")]
public string[] SiteType { get; set; }
}
Everything seems to be deserializng correctly, except for the <site_type> tag. The contents of this tag will vary from Station to Station, but will always contain one or more items of a specific value - essentially from an enum. These tags are always self closing and do not ever contain attributes. They are strictly in the <METAR /> format. When I attempt to deserialize this XML, I get a ReadElementContentAs() error, and I am 99% sure it's that tag that is causing the issue. Would anyone happen to know where I went wrong on this, or have any advice on how to deserialize that kind of element?
Thank you!
Taking your comment on this answer into account
For clarifcation, these type tags in the SiteType will never contain any data like the other tags. If the tag is present, it means that this weather station produces that type of report (METAR, TAF, SIGMENTS, etc)
That SiteType isn't an array of strings, but an array of types, with a different one per report type. All share the same base class.
public abstract class SiteType
{ }
public class Metar : SiteType
{ }
public class Taf : SiteType
{ }
That SiteType property then looks like below
[XmlArray(ElementName = "site_type")]
[XmlArrayItem(typeof(Metar), ElementName ="METAR")]
[XmlArrayItem(typeof(Taf), ElementName = "TAF")]
public SiteType[] SiteType { get; set; }
To check whether a certain report type is supported for a station, you check for the presence of the corresponding type within that SiteType array.
var hasMetar = p.SiteType.Any(o => o.GetType() == typeof(Metar));
You can declare a property as follows:
[XmlAnyElement(Name = "site_type")]
public XmlElement SiteType { get; set; }
After deserialization, there will be a collection of nodes in the property.
foreach(XmlNode node in station.SiteType.ChildNodes)
Console.WriteLine(node.Name);
I am trying to take specific Nodes from an Xml and write it into a class. I have this.
public class TradeMark
{
[XmlElement]
public string MarkVerbalElementText { get; set; }
[XmlElement]
public int MarkCurrentStatusCode { get; set; }
[XmlElement]
public string ExpiryDate { get; set; } = "";
}
static void Main(string[] args)
{
XmlSerializer serializer = new XmlSerializer(typeof(TradeMark));
using (TextReader reader = new StreamReader(pathToImportFile))
{
tradeMark = (TradeMark)serializer.Deserialize(reader);
}
}
In my Xml Data, there are more Node than just these 3. Now when i run the Code it says ...... was not expected. I guess bc. It tries to deserialize everything than only these 3 Infomartionen in Class TradeMark.
Can anyone help?
XML
<?xml version="1.0" encoding="UTF-8"?>
<Transaction xmlns="http://euipo.europa.eu/trademark/data" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://euipo.europa.eu/trademark/data http://euipo.europa.eu/schemas/trademark/EM-TM-TradeMark-V3-2.xsd">
<TransactionHeader>
<SenderDetails>
<RequestProducerDateTime>2018-08-18T15:33:35</RequestProducerDateTime>
</SenderDetails>
</TransactionHeader>
<TradeMarkTransactionBody>
<TransactionContentDetails>
<TransactionIdentifier>017690538</TransactionIdentifier>
<TransactionCode>EM-Trade Mark</TransactionCode>
<TransactionData>
<TradeMarkDetails>
<TradeMark operationCode="Insert">
<RegistrationOfficeCode>EM</RegistrationOfficeCode>
<ApplicationNumber>017690538</ApplicationNumber>
<ApplicationDate>2018-01-16</ApplicationDate>
<RegistrationDate>2018-06-14</RegistrationDate>
<ApplicationLanguageCode>en</ApplicationLanguageCode>
<SecondLanguageCode>es</SecondLanguageCode>
<ExpiryDate>2028-01-16</ExpiryDate>
<MarkCurrentStatusCode milestone="23" status="1">Registered</MarkCurrentStatusCode>
<MarkCurrentStatusDate>2018-06-15</MarkCurrentStatusDate>
<KindMark>Individual</KindMark>
<MarkFeature>Figurative</MarkFeature>
<TradeDistinctivenessIndicator>false</TradeDistinctivenessIndicator>
<WordMarkSpecification>
<MarkVerbalElementText>Tiens</MarkVerbalElementText>
</WordMarkSpecification>
Most likely this happens because your XML has a default namespace and Transaction is within this namespace.
You need to mark your class with XmlRootAttribute like so:
[XmlRootAttribute("TradeMark", Namespace="http://euipo.europa.eu/trademark/data",
IsNullable = false)]
public class TradeMark
XmlIgnore is what you're looking for.
MSDN Docs
See clarification in this answer, as the docs only state XmlIgnore will be ignored on serialize, but will also be ignored when deserializing.
From your example:
public class TradeMark
{
[XmlElement]
public string MarkVerbalElementText { get; set; }
[XmlElement]
public int MarkCurrentStatusCode { get; set; }
[XmlElement]
public string ExpiryDate { get; set; } = "";
[XmlIgnore]
public string IgnoreMe { get; set; } // This will be ignored
}
I know there are several posts out there with this topic, but I can't seem to figure out what is the problem here. I have serialized and deserialized xml several times, and never had this error.
The exception message is:
There is an error in XML document (1, 2).
With InnerException:
<InvoiceChangeRequest xmlns=''> was not expected.
XML file I want to deserialize:
<ns1:InvoiceChangeRequest xmlns:ns1="http://kmd.dk/fie/external_invoiceDistribution">
<CONTROL_FIELDS>
<STRUCTURID>0000000001</STRUCTURID>
<OPERA>GET</OPERA>
<WIID>000050371220</WIID>
</CONTROL_FIELDS>
<HEADER_IN>
<MANDT>751</MANDT>
<BELNR>1234567890</BELNR>
</HEADER_IN>
<ITEMS>
<ITEM_FIELDS_IN>
<BUZEI>001</BUZEI>
<BUKRS>0020</BUKRS>
</ITEM_FIELDS_IN>
</ITEMS>
</ns1:InvoiceChangeRequest>
Class I'm trying to deserialize to:
[XmlRoot(Namespace = "http://kmd.dk/fie/external_invoiceDistribution", IsNullable = false)]
public class InvoiceChangeRequest
{
[XmlElement("CONTROL_FIELDS")] public ControlFields Styrefelter;
[XmlElement("HEADER_IN")] public HeaderIn HeaderfelterInd;
[XmlElement("ITEMS")] public Items Linjer;
}
public class HeaderIn
{
[XmlElement("MANDT")] public string Kommunenummer;
[XmlElement("BELNR")] public string RegnskabsbilagsNummer;
}
public class Items
{
[XmlElement("ITEM_FIELDS_IN")] public Itemfield[] ItemfelterInd;
}
public class Itemfield
{
[XmlElement("BUZEI")] public string Linjenummer;
[XmlElement("BUKRS")] public string Firmakode;
}
Deserialization code:
XmlSerializer serializer = new XmlSerializer(typeof(InvoiceChangeRequest));
var request = serializer.Deserialize(new StringReader(output)) as InvoiceChangeRequest;
In your XML file your root element is the namespace http://kmd.dk/fie/external_invoiceDistribution with prefix ns1.
The element <CONTROL_FIELDS> isn't because it isn't prefixed. Your serialization class doesn't take this into account though. That means that it expects that <CONTROL_FIELDS> and the other elements are ALSO in the ns1 namespace.
To get the serializer parse the elements correctly add the Namespace to the elements, setting it to an empty string:
[XmlRoot(Namespace = "http://kmd.dk/fie/external_invoiceDistribution", IsNullable = false)]
public class InvoiceChangeRequest
{
[XmlElement("CONTROL_FIELDS", Namespace = "")]
public ControlFields Styrefelter { get; set; }
[XmlElement("HEADER_IN", Namespace = "")]
public HeaderIn HeaderfelterInd { get; set; }
[XmlElement("ITEMS", Namespace = "")]
public Items Linjer { get; set; }
}
This will de-serialize the given XML as intended.
In case of de-serialization issues I often create the classes in memory and then serialize that so I can inspect the resulting XML. That often gives clues on what is missing or being added compared to the input document:
var ms = new MemoryStream();
serializer.Serialize(ms, new InvoiceChangeRequest {
Styrefelter = new ControlFields { Opera="test"}
});
var s = Encoding.UTF8.GetString(ms.ToArray());
And then inspect s for differences.
You can replace 'ns1:' with string.Empty.
Below classes should serialize.
public class Item
{
[XmlElement("BUZEI")]
public string Buzei { get; set; }
[XmlElement("BUKRS")]
public string Bukrs { get; set; }
}
public class Header
{
[XmlElement("MANDT")]
public string Mandt { get; set; }
[XmlElement("BELNR")]
public string Belnr { get; set; }
}
public class ControlFields
{
[XmlElement("STRUCTURID")]
public string StructuredId { get; set; }
[XmlElement("OPERA")]
public string Opera { get; set; }
[XmlElement("WIID")]
public string Wild { get; set; }
}
public class InvoiceChangeRequest
{
[XmlElement("CONTROL_FIELDS")]
public ControlFields ControlFields { get; set; }
[XmlElement("HEADER_IN")]
public Header Header { get; set; }
[XmlArray("ITEMS")]
[XmlArrayItem("ITEM_FIELDS_IN")]
public List<Item> Items { get; set; }
}
My XML:
<result>
<document version="2.1.0">
<response type="currency">
<currency>
<code>AMD</code>
<price>85.1366</price>
</currency>
</response>
<response type="currency">
<currency>
<code>AUD</code>
<price>31.1207</price>
</currency>
</response>
</document>
</result>
My Class:
public class CurrencyData
{
public string Code { get; set; }
public string Price { get; set; }
}
My deserializer calling:
RestClient.ExecuteAsync<List<CurrencyData>>...
If i renamed class CurrencyData to Currency then all will been done right. But I want to keep this class name.
Ok, I think I got it,
You can try RestClient.ExecuteAsync<Result>()
[XmlRoot("result")]
public class Result
{
[XmlElement("document")]
public Document Document { get; set; }
}
public class Document
{
[XmlElement("response")]
public Response[] Responses { get; set; }
[XmlAttribute("version")]
public string Version { get; set; }
}
public class Response
{
[XmlElement("currency")]
public CurrencyData Currency { get; set; }
[XmlAttribute("type")]
public string Type { get; set; }
}
public class CurrencyData
{
[XmlElement("code")]
public string Code { get; set; }
[XmlElement("price")]
public decimal Price { get; set; }
}
I had to add a few XmlElement attribute to override the casing without having to name classes and properties in lowercase. but you can drop them if you can change the xml to match the casing
Answer of kay.one is perfect! It works with a any remarks:
public List<Response> Responses { get; set; }
works
public Response[] Responses { get; set; }
don`t works
And
[XmlElement("AnyValue")]
it is from System.Xml.Serialization namespace and don`t work.
Feel free to just delete them.
In this example annotation attributes and properties has same names and serializer understands.
But right annotation attributes are from RestSharp.Deserializers namespace
[DeserializeAs(Name="AnyXmlValue")]
public string AnyModelValue { get; set; }
How to manage deserialization of RestSharp
Then change the xml tag to CurrencyData. Here is the documentation about the xml deserializer: https://github.com/restsharp/RestSharp/wiki/Deserialization
I'm not sure why Kay.one's answer is accepted, it doesn't answer the question.
Per my comment, the default RestSharp deserializer doesn't check for the DeserializeAs attribute when deserializing a list. I'm not sure if that's intentional or a mistake as the author doesn't seem to be very available.
Anyways it's a simple fix.
private object HandleListDerivative(object x, XElement root, string propName, Type type)
{
Type t;
if (type.IsGenericType)
{
t = type.GetGenericArguments()[0];
}
else
{
t = type.BaseType.GetGenericArguments()[0];
}
var list = (IList)Activator.CreateInstance(type);
var elements = root.Descendants(t.Name.AsNamespaced(Namespace));
var name = t.Name;
//add the following
var attribute = t.GetAttribute<DeserializeAsAttribute>();
if (attribute != null)
name = attribute.Name;
I am trying to serialize an object in a particular manner. The main class has a container class that holds some attributes, but really these attributes should be on the main class, from the point of view of the schema. Is there a way to bypass the container class and treat the properties on the container class as properties on the main class, for the purposes of serialization?
I am trying to create XML along the lines of:
<Main foo="3" bar="something">
<Others>etc</Others>
</Main>
from this code:
[System.Xml.Serialization.XmlRootAttribute("Main", Namespace = "")]
public class MainObject
{
public HelperContainer { get; set; }
public string Others { get; set; }
}
public class HelperContainer
{
[System.Xml.Serialization.XmlAttributeAttribute(AttributeName = "foo")]
public int Foo { get; set; }
[System.Xml.Serialization.XmlAttributeAttribute(AttributeName = "bar")]
public string Bar { get; set; }
}
You may want to try implementing IXmlSerializable on MainObject to be able to control what happens when calling serialize. For the read and write xml methods specify the fields to serialize.
Check out msdn: http://msdn.microsoft.com/en-us/library/system.xml.serialization.ixmlserializable.aspx
Something like:
public class MainObject : IXmlSerializable
{
public HelperContainer { get; set; }
public string Others { get; set; }
public void WriteXml (XmlWriter writer)
{
writer.WriteString(Others);
writer.WriteAttributeString("foo", HelperContainer.Foo);
writer.WriteAttributeString("bar", HelperContainer.Bar);
}
public void ReadXml (XmlReader reader)
{
Others = reader.ReadString();
//...
}
}