In C# should try-catch be used for is-numeric testing? - c#

I have heard that using exception trapping is not a recommended practice for number testing.
For example:
bool isnumeric
try
{
int i = int.parse(textbox1.text);
isnumeric = true;
}
catch {isnumenric=false}
Is there some other way that I could test for numbers in C#?

Yes try using
int i;
bool success = Int32.TryParse(textBox1.text, out i);
The TryParse method basically does what you are doing above.

Use the built-in TryParse
E.g.
int number;
bool result = Int32.TryParse(value, out number);

Yes. Use int.TryParse, double.TryParse, etc. instead, which all return a boolean.
Alternately, there's an IsNumeric function buried in the VB assemblies (in the Microsoft.VisualBasic namespace in Microsoft.VisualBasic.dll) that you can also call from your C# code:
bool Microsoft.VisualBasic.Information.IsNumeric(value)

TryParse()
int i;
if(Int32.TryParse(someString,out i))
{
//now use i because you know it is valid
//otherwise, TryParse would have returned false
}

int result = -1;
bool isNumeric = Int32.TryParse(text, out result);
isNumeric will be true if the number is numeric, false otherwise; if the number is numeric, result will have the numeric value of the number.

bool TryParse(string, out int)
It will return a bool that is true if it was able to parse the integer, and the out parameter will contain the integer (if it was successful with the parsing).

If you just need to do number testing and do not need the integer number, you may use the function below. This is faster than Int32.TryParse(...) methods.
Edit for Barry Fandango: Handles negative numbers now. This is only for testing integers.
public static bool IsNumber(string s)
{
if (s == null || s.Length == 0)
{
return false;
}
if (s[0] == '-')
{
for (int i = 1; i < s.Length; i++)
{
if (!char.IsDigit(s[i]))
{
return false;
}
}
}
else
{
foreach (char c in s)
{
if (!char.IsDigit(c))
{
return false;
}
}
}
return true;
}

If you want the integer then Int32.TryParse(...) is what you want else
Information.IsNumeric(...) (From the Microsoft.VisualBasic.dll) if you don't care what the actual integer is.

Related

IDE0059 Unnecessary assignment of a value to 'number'

I got an assignment where I have a few user inputs. My goal is that the user is only allowed to enter an integer. The program works as I want it to, but this message is messing with me.
What is the problem there, and how do I fix it?
static int Check_input(string input)
{
bool is_valid = Int32.TryParse(input, out int number);
if (is_valid)
{
number = 1;
}
else
{
number = 0;
}
return (number);
}
In the first line of your method bool is_valid = Int32.TryParse(input, out int number); you create a new variable number and assign a value to it. But you never use this value, because you immediately assign either the value 1 or 0 to it. Actually, you can shorten your code
static int Check_input(string input)
{
bool is_valid = Int32.TryParse(input, out _);
if (is_valid)
{
return 1;
}
else
{
return 0;
}
}
Here, you discard the out parameter of TryParse and only investigate its return value to check which value your method should return.
But actually, you should return a bool value to see whether the user entered a valid number, which would make your method look like this:
static bool Check_input(string input)
{
return Int32.TryParse(input, out _);
}
This is even simpler and it is easier to work with a boolean variable then with an integer that might be 1 or 0. Compare this:
if(Check_input("test") == 1)
{
Console.WriteLine("good input");
}
else
{
Console.WriteLine("bad input");
}
with
if(Check_input("test"))
{
Console.WriteLine("good input");
}
else
{
Console.WriteLine("bad input");
}
You wouldn't need to asign number with out int number, because you are setting it to 0 or 1 later anyway.
To be more accurate your if, else is useless anyway. You are already setting the number to either 1 or 0 or you wouldn't be able to set it equal to a bool anyway.
Fixed Code:
static bool Check_input(string input) {
bool is_valid = Int32.TryParse(input, out _);
return (is_valid);
}

How To Check a double value whether is Int or double

Is That Any calculation or method allow me to check whether a double value is Int or Double in c# code
Example
Double NumberOne = 55.00 // Return False
Double NumberTwo = 55.10 // Return True
Use Math.Floor
if (Math.Floor(number) == number) {
// yay, an "int"
}
private bool IsDoubleNotAnInt(double num)
{
if ((num % 1) == 0)
{
return false;
}
else
{
return true;
}
}
You could check
n % 1 == 0
to determine this.
You could compare it with value without fractional part:
Math.Floor(n) != n

How can I check if a string is a number?

I'd like to know on C# how to check if a string is a number (and just a number).
Example :
141241 Yes
232a23 No
12412a No
and so on...
Is there a specific function?
Look up double.TryParse() if you're talking about numbers like 1, -2 and 3.14159. Some others are suggesting int.TryParse(), but that will fail on decimals.
string candidate = "3.14159";
if (double.TryParse(candidate, out var parsedNumber))
{
// parsedNumber is a valid number!
}
EDIT: As Lukasz points out below, we should be mindful of the thread culture when parsing numbers with a decimal separator, i.e. do this to be safe:
double.TryParse(candidate, NumberStyles.AllowDecimalPoint, CultureInfo.InvariantCulture, out var parsedNumber)
If you just want to check if a string is all digits (without being within a particular number range) you can use:
string test = "123";
bool allDigits = test.All(char.IsDigit);
Yes there is
int temp;
int.TryParse("141241", out temp) = true
int.TryParse("232a23", out temp) = false
int.TryParse("12412a", out temp) = false
Hope this helps.
Use Int32.TryParse()
int num;
bool isNum = Int32.TryParse("[string to test]", out num);
if (isNum)
{
//Is a Number
}
else
{
//Not a number
}
MSDN Reference
Use int.TryParse():
string input = "141241";
int ouput;
bool result = int.TryParse(input, out output);
result will be true if it was.
Yep - you can use the Visual Basic one in C#.It's all .NET; the VB functions IsNumeric, IsDate, etc are actually static methods of the Information class. So here's your code:
using Microsoft.VisualBasic;
...
Information.IsNumeric( object );
int value;
if (int.TryParse("your string", out value))
{
Console.WriteLine(value);
}
This is my personal favorite
private static bool IsItOnlyNumbers(string searchString)
{
return !String.IsNullOrEmpty(searchString) && searchString.All(char.IsDigit);
}
Perhaps you're looking for the int.TryParse function.
http://msdn.microsoft.com/en-us/library/system.int32.tryparse.aspx
Many datatypes have a TryParse-method that will return true if it managed to successfully convert to that specific type, with the parsed value as an out-parameter.
In your case these might be of interest:
http://msdn.microsoft.com/en-us/library/system.int32.tryparse.aspx
http://msdn.microsoft.com/en-us/library/system.decimal.tryparse.aspx
int result = 0;
bool isValidInt = int.TryParse("1234", out result);
//isValidInt should be true
//result is the integer 1234
Of course, you can check against other number types, like decimal or double.
You should use the TryParse method for the int
string text1 = "x";
int num1;
bool res = int.TryParse(text1, out num1);
if (res == false)
{
// String is not a number.
}
If you want to validate if each character is a digit and also return the character that is not a digit as part of the error message validation, then you can loop through each char.
string num = "123x";
foreach (char c in num.ToArray())
{
if (!Char.IsDigit(c))
{
Console.WriteLine("character " + c + " is not a number");
return;
}
}
int.TryPasrse() Methode is the best way
so if the value was string you will never have an exception , instead of the TryParse Methode return to you bool value so you will know if the parse operation succeeded or failed
string yourText = "2";
int num;
bool res = int.TryParse(yourText, out num);
if (res == true)
{
// the operation succeeded and you got the number in num parameter
}
else
{
// the operation failed
}
string str = "123";
int i = Int.Parse(str);
If str is a valid integer string then it will be converted to integer and stored in i other wise Exception occur.
Starting with C# 7.0, you can declare the out variable in the argument
list of the method call, rather than in a separate variable
declaration. This produces more compact, readable code, and also
prevents you from inadvertently assigning a value to the variable
before the method call.
bool isDouble = double.TryParse(yourString, out double result);
https://learn.microsoft.com/en-us/dotnet/csharp/language-reference/keywords/out-parameter-modifier
You could use something like the following code:
string numbers = "numbers you want to check";
Regex regex = new Regex("^[0-9]+$"));
if (regex.IsMatch(numbers))
{
//string value is a number
}
public static void Main()
{
string id = "141241";
string id1 = "232a23";
string id2 = "12412a";
validation( id, id1, id2);
}
public static void validation(params object[] list)
{
string s = "";
int result;
string _Msg = "";
for (int i = 0; i < list.Length; i++)
{
s = (list[i].ToString());
if (string.IsNullOrEmpty(s))
{
_Msg = "Please Enter the value";
}
if (int.TryParse(s, out result))
{
_Msg = "Enter " + s.ToString() + ", value is Integer";
}
else
{
_Msg = "This is not Integer value ";
}
}
}
Try This
here i perform addition of no and concatenation of string
private void button1_Click(object sender, EventArgs e)
{
bool chk,chk1;
int chkq;
chk = int.TryParse(textBox1.Text, out chkq);
chk1 = int.TryParse(textBox2.Text, out chkq);
if (chk1 && chk)
{
double a = Convert.ToDouble(textBox1.Text);
double b = Convert.ToDouble(textBox2.Text);
double c = a + b;
textBox3.Text = Convert.ToString(c);
}
else
{
string f, d,s;
f = textBox1.Text;
d = textBox2.Text;
s = f + d;
textBox3.Text = s;
}
}
I'm not a programmer of particularly high skills, but when I needed to solve this, I chose what is probably a very non-elegant solution, but it suits my needs.
private bool IsValidNumber(string _checkString, string _checkType)
{
float _checkF;
int _checkI;
bool _result = false;
switch (_checkType)
{
case "int":
_result = int.TryParse(_checkString, out _checkI);
break;
case "float":
_result = Single.TryParse(_checkString, out _checkF);
break;
}
return _result;
}
I simply call this with something like:
if (IsValidNumber("1.2", "float")) etc...
It means that I can get a simple true/false answer back during If... Then comparisons, and that was the important factor for me. If I need to check for other types, then I add a variable, and a case statement as required.
use this
double num;
string candidate = "1";
if (double.TryParse(candidate, out num))
{
// It's a number!
}
int num;
bool isNumeric = int.TryParse("123", out num);
namespace Exception
{
class Program
{
static void Main(string[] args)
{
bool isNumeric;
int n;
do
{
Console.Write("Enter a number:");
isNumeric = int.TryParse(Console.ReadLine(), out n);
} while (isNumeric == false);
Console.WriteLine("Thanks for entering number" + n);
Console.Read();
}
}
}
Regex.IsMatch(stringToBeChecked, #"^\d+$")
Regex.IsMatch("141241", #"^\d+$") // True
Regex.IsMatch("232a23", #"^\d+$") // False
Regex.IsMatch("12412a", #"^\d+$") // False
The problem with some of the suggested solutions is that they don't take into account various float number formats. The following function does it:
public bool IsNumber(String value)
{
double d;
if (string.IsNullOrWhiteSpace(value))
return false;
else
return double.TryParse(value.Trim(), System.Globalization.NumberStyles.Any,
System.Globalization.CultureInfo.InvariantCulture, out d);
}
It assumes that the various float number styles such es decimal point (English) and decima comma (German) are all allowed. If that is not the case, change the number styles paramater. Note that Any does not include hex mumbers, because the type double does not support it.

How to validate user input for whether it's an integer?

It tells me that it can't convert int to bool.
Tried TryParse but for some reason the argument list is invalid.
Code:
private void SetNumber(string n)
{
// if user input is a number then
if (int.Parse(n))
{
// if user input is negative
if (h < 0)
{
// assign absolute version of user input
number = Math.Abs(n);
}
else
{
// else assign user input
number = n;
}
}
else
{
number = 0; // if user input is not an int then set number to 0
}
}
You were probably very close using TryParse, but I'm guessing you forgot the out keyword on the parameter:
int value;
if (int.TryParse(n, out value))
{
}
Just use this:
int i;
bool success = int.TryParse(n, out i);
if the parse was successful, success is true.
If that case i contain the number.
You probably got the out argument modifier wrong before. It has the out modifier to indicate that it is a value that gets initialized within the method called.
You can try with some simple regular expression :
bool IsNumber(string text)
{
Regex regex = new Regex(#"^[-+]?[0-9]*\.?[0-9]+$");
return regex.IsMatch(text);
}
private void SetNumber(string n)
{
int nVal = 0;
if (int.TryParse(n, out nVal))
{
if (nVal < 0)
number = Math.Abs(nVal);
else
number = nVal;
}
else
number = 0;
}
There are a lot of problems with this code:
Using VB-style line comments (') instead of C# slashes
Parse for integer returns an int and not a bool
You should use TryParse with an out value
h does not seem to be valid at all. Is it a type for n?
There are variables that do not seem to be defined in function scope (number) are they defined at class scope?
But try this:
private void SetNumber(string n)
{
int myInt;
if (int.TryParse(n, out myInt)) //if user input is a number then
{
if (myInt < 0) //if user input is negative
number = Math.Abs(n); //assign absolute version of user input
else //else assign user input
number = n;
}
else number = 0; //if user input is not an int then set number to 0
}
You could try something like below using int.TryParse..
private void SetNumber(string n)
{
int parsed = -1;
if (int.TryParse(n, out parsed)) //if user input is a number then
...
The reason there are complaints that it cannot convert an int to a bool is because the return type of int.Parse() is an int and not a bool and in c# conditionals need to evaluate bool values.
int.Parse will give you back an integer rather than a boolean.
You could use int.TryParse as you suggested.
int parsedValue;
if(int.TryParse(n, out parsedValue))
{
}
Well for one thing the inner if statement has an 'h' instead of an 'n' if(h < 0). But TryParse should work there assuming that 'number' is a class variable.
private void SetNumber(string n)
{
int temp;
bool success = Int32.TryParse(n, out temp);
// If conversion successful
if (success)
{
// If user input is negative
if (temp < 0)
number = Math.Abs(temp); // Assign absolute version of user input
else // Assign user input
number = temp;
}
else
{
number = 0;
}
}
int.Parse will convert a string to an integer. Current you have it within an if statement, so its treating the returned value of int.Parse as a bool, which its not.
Something like this will work:
private void SetNumber(string n)
{
int num = 0;
try{
num = int.Parse(n);
number = Math.Abs(num);
}catch(Exception e){
number = 0;
}
}
I did this in the simplest way I knew how.
static void Main(string[] args)
{
string a, b;
int f1, f2, x, y;
Console.WriteLine("Enter two inputs");
a = Convert.ToString(Console.ReadLine());
b = Console.ReadLine();
f1 = find(a);
f2 = find(b);
if (f1 == 0 && f2 == 0)
{
x = Convert.ToInt32(a);
y = Convert.ToInt32(b);
Console.WriteLine("Two inputs r number \n so tha additon of these text box is= " + (x + y).ToString());
}
else
Console.WriteLine("One or tho inputs r string \n so tha concadination of these text box is = " + (a + b));
Console.ReadKey();
}
static int find(string s)
{
string s1 = "";
int f;
for (int i = 0; i < s.Length; i++)
for (int j = 0; j <= 9; j++)
{
string c = j.ToString();
if (c[0] == s[i])
{
s1 += c[0];
}
}
if (s==s1)
f= 0;
else
f= 1;
return f;
}

Convert string to integer

I need help with my code. I would like to write only numbers/integers in my textbox and would like to display that in my listbox.
Is my code below in order? This seems to give an error.
int yourInteger;
string newItem;
newItem = textBox1.Text.Trim();
if (newItem == Convert.ToInt32(textBox1.Text))
{
listBox1.Items.Add(newItem);
}
====
Update:
This is how my code looks like now. My question is, can listBox handle the data type "long"? Because when I entered the number 20,000,000 I just got an hour glass for 20 minutes. But when I tried this one with the console, I got the answer. So I'm not sure what kind of element can handle data type "long".
string newItem;
newItem = textBox1.Text.Trim();
Int64 num = 0;
if(Int64.TryParse(textBox1.Text, out num))
{
for (long i = 2; i <= num; i++)
{
//Controls if i is prime or not
if ((i % 2 != 0) || (i == 2))
{
listBox1.Items.Add(i.ToString());
}
}
}
private void btnClear_Click(object sender, EventArgs e)
{
listBox1.Items.Clear();
}
int result = int.Parse(textBox1.Text.Trim());
If you want to check for validity:
int result;
if (int.TryParse(textBox1.Text.Trim(), out result)) // it's valid integer...
// int is stored in `result` variable.
else
// not a valid integer
Use this:
int yourInteger;
string newItem;
newItem = textBox1.Text.Trim();
Int32 num = 0;
if ( Int32.TryParse(textBox1.Text, out num))
{
listBox1.Items.Add(newItem);
}
else
{
customValidator.IsValid = false;
customValidator.Text = "You have not specified a correct number";
}
This assumes you have a customValidator.
Use int.TryParse() to check if string contains integer value.
textBox1.Text may not contain a valid string representation of an integer (or is just an empty string). To work around that, use Int32.TryParse().
You can do:
Convert.ToInt32(input);
For a longer function using this you can look at:
http://msdn.microsoft.com/en-us/library/bb397679.aspx
Basically it checks if the string is null, then it will call int.Parse. This will work under WindowsCE also, which doesn't have int.TryParse.
To be specific as to why your code fails to compile it is because you are comparing a string (newItem) against the result of Convert.ToInt32, which is an integer, which it wont let you do. Also Convert.ToInt32 will raise an exception it the string passed in is not a number.
You can try using int.TryParse, or alternatively write a simple regular expression to validate your input:
int i;
bool isInteger = int.TryParse(textBox1.Text,out i);
or
bool isInteger = System.Text.RegularExpressions.Regex.IsMatch("^\d+$", textBox1.Text);
Are you checking for an empty string?
int yourInteger;
string newItem;
newItem = textBox1.Text.Trim();
if(newItem != string.Empty)
{
if ( newItem == Convert.ToInt32(textBox1.Text))
{
listBox1.Items.Add(newItem);
}
}

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