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I got problem with draw the bottom part of hourglass. I got code of the middle if the number if not even but i don't paste it. I tried to reverse the top but it doesn't work.
public static void hourglass(int n)
{
// Top
for (int i = 0; i < n / 2; i++)
{
for (int j = 0; j < i; j++)
{
Console.Write(" ");
}
Console.Write("*");
for (int j = 0; j < n - 2 - 2 * i; j++)
{
if (i == 0)
{
Console.Write("*");
}
else
{
Console.Write(" ");
}
}
Console.WriteLine("*");
}
// middle if not even
// Bottom
}
if n = 8 the hourglass should looks like:
********
* *
* *
**
**
* *
* *
********
if n = 7
*******
* *
* *
*
* *
* *
*******
If I understand your Q correctly. I think this is all you need to do :)
Image of console with hourglass
for (int i = 0; i < size; i++)
{
for (int j = 0; j < size; j++)
{
if (i == 0 || i == size - 1)
{
Console.Write("*");
}
else if (j == i || j == size - 1 - i)
{
Console.Write("*");
}
else
{
Console.Write(" ");
}
}
Console.WriteLine();
}
I will try to help the best that I can.
using System;
//First lets draw a cordinate system to see what the values are in each step of the loop (We start from one just to make it easer to see the last row)
DrawMatrix(7);
Console.WriteLine();
DrawMatrix(8);
Console.WriteLine();
Console.WriteLine();
//from the cordinate system we can see that the top and bottom edges are just first (1,...) row and last row (7,...) and since row is the y coordinate the condition is y==1 || y == size
DrawEdge(7);
Console.WriteLine();
DrawEdge(8);
Console.WriteLine();
Console.WriteLine();
// for the left slash we can see that it will be on the position where x == y
DrawLeftToRight(7);
Console.WriteLine();
DrawLeftToRight(8);
Console.WriteLine();
Console.WriteLine();
//fot he other slash the sum of the two will be size -1 so we need to have a x+y == size+1
DrawRightToLeft(7);
Console.WriteLine();
DrawRightToLeft(8);
Console.WriteLine();
Console.WriteLine();
//Now lets combine everything
DrawHourglass(7);
Console.WriteLine();
DrawHourglass(8);
Console.WriteLine();
DrawHourglass(9);
Console.WriteLine();
DrawHourglass(10);
Console.WriteLine();
Console.WriteLine();
void DrawMatrix(ushort size)
{
for(var y = 1; y <= size; y++)
{
for(var x = 1; x <= size; x++)
{
Console.Write($"({y},{x})");
}
Console.WriteLine();
}
}
void DrawEdge(ushort size)
{
for(var y = 1; y <= size; y++)
{
for(var x = 1; x <= size; x++)
{
if(y==1 || y == size)
{
Console.Write('*');
}
else
{
Console.Write(' ');
}
}
Console.WriteLine();
}
}
void DrawLeftToRight(ushort size)
{
for(var y = 1; y <= size; y++)
{
for(var x = 1; x <= size; x++)
{
if(x==y)
{
Console.Write('*');
}
else
{
Console.Write(' ');
}
}
Console.WriteLine();
}
}
void DrawRightToLeft(ushort size)
{
for(var y = 1; y <= size; y++)
{
for(var x = 1; x <= size; x++)
{
if(x+y==size+1)
{
Console.Write('*');
}
else
{
Console.Write(' ');
}
}
Console.WriteLine();
}
}
void DrawHourglass(ushort size)
{
for(var y = 1; y <= size; y++)
{
for(var x = 1; x <= size; x++)
{
if( (y==1 || y == size)
|| (x==y)
|| (x+y==size+1)
)
{
Console.Write('*');
}
else
{
Console.Write(' ');
}
}
Console.WriteLine();
}
}
Here is a dot net fiddle link https://dotnetfiddle.net/i6Bay3
I tried to make as simple as possible to understand so you can play around with this to try to make it work in different ways.
Related
Here's the code of a solid diamond and I want to remove the middle and leave the edges.
From this,
to this,
public void DiamondOne()
{
int i, j, count = 1, number;
Console.Write("Enter number of rows:");
number = int.Parse(Console.ReadLine());
count = number - 1;
for (j = 1; j <= number; j++)
{
for (i = 1; i <= count; i++)
Console.Write(" ");
count--;
for (i = 1; i <= 2 * j - 1; i++)
Console.Write("*");
Console.WriteLine();
}
count = 1;
for (j = 1; j <= number - 1; j++)
{
for (i = 1; i <= count; i++)
Console.Write(" ");
count++;
for (i = 1; i <= 2 * (number - j) - 1; i++)
Console.Write("*");
Console.WriteLine();
}
Console.ReadLine();
}
I would go with something like this:
public void Diamond()
{
Console.WriteLine("Enter number of rows:");
bool isNumber = int.TryParse(Console.ReadLine(), out int rowsNr);
if (!isNumber)
{
Console.WriteLine("Not a number!");
return;
}
// print the upper half
for (int rowIndex = 0; rowIndex < rowsNr - 1; rowIndex++)
{
for (int colIndex = 0; colIndex <= 2 * rowsNr; colIndex++)
{
if (colIndex == Math.Abs(rowsNr - rowIndex) || colIndex == Math.Abs(rowsNr + rowIndex))
{
Console.Write("*");
}
else
{
Console.Write(" ");
}
}
Console.WriteLine();
}
// print the lower half
for (int rowIndex = 1; rowIndex <= rowsNr; rowIndex++)
{
for (int colIndex = 0; colIndex <= 2 * rowsNr; colIndex++)
{
if (colIndex == rowIndex || colIndex == 2 * rowsNr - rowIndex)
{
Console.Write("*");
}
else
{
Console.Write(" ");
}
}
Console.WriteLine();
}
}
Basically you are looking for the x and y coordinates. Each of the 4 edges has its own equation (the upper-left one is x == y for instance) and you check for these while you iterate. I split the code in two parts, one for the upper half and one for the lower half. It's more readable and you don't put together too many if statements and lose the meaning of the code.
This is what I came up with:
// Get the number of rows
int rows;
do
{
Console.WriteLine("Enter number of rows:");
} while (!int.TryParse(Console.ReadLine(), out rows));
// Print diamond
DiamondOne(rows, Console.Out);
// Wait for key press
Console.WriteLine("Press any key to exit");
Console.ReadKey(true);
static void DiamondOne(int rows, TextWriter output)
{
for (int currentRow = 0; currentRow < rows; currentRow++)
{
OutputRow(rows, output, currentRow);
}
for (int currentRow = rows - 2; currentRow >= 0; currentRow--)
{
OutputRow(rows, output, currentRow);
}
}
static void OutputRow(int rows, TextWriter output, int currentRow)
{
int indentation = rows - currentRow - 1;
int diamondCentre = Math.Max((currentRow * 2) - 1, 0);
output.Write(new string(' ', indentation));
output.Write('*');
output.Write(new string(' ', diamondCentre));
if (currentRow != 0) output.Write('*');
output.WriteLine();
}
The problem is to make a program the flips a 2D (2 by 2) array either horizontally(H) or vertically(V), depending on the input the user puts. For example, if the user puts "HHHVVHVHV", it means to flip 5 times horizontally, and 4 times vertically. The code I attached below works, but I am not sure if there is a built-in method in C# to flip arrays or an easier way to do it.
using System;
using System.Linq;
namespace _2019JuniorQ4
{
class Program
{
static void Main(string[] args)
{
//Varables
int[,] grid = new int[2, 2] { { 1, 2 }, { 3, 4 } };
int[,] flippedGrid = new int[2, 2];
string input = "";
int h = 0;
int v = 0;
int flipHorizontal = 0;
int flipVertical = 0;
//Input
input = Console.ReadLine();
//Count number of times
for (int i=0; i<input.Length; i++)
{
if (input[i] == Convert.ToChar("H"))
{
h++;
}
else if(input[i] == Convert.ToChar("V"))
{
v++;
}
}
//Process
flipHorizontal = h % 2;
flipVertical = v % 2;
//Vertical flip
if (flipVertical == 1)
{
for (int y = 0; y < 2; y++)
{
for (int x = 1; x >= 0; x--)
{
flippedGrid[y, Math.Abs(x - 1)] = grid[y,x];
}
}
grid = flippedGrid.Clone() as int[,];
}
//Horizontal Flip
if (flipHorizontal == 1)
{
for (int x = 0; x < 2; x++)
{
for (int y = 1; y >= 0; y--)
{
flippedGrid[Math.Abs(y - 1), x] = grid[y,x];
}
}
grid = flippedGrid.Clone() as int[,];
}
//Output
for (int x=0; x<2; x++)
{
for (int y=0; y<2; y++)
{
Console.Write(grid[x,y]+" ");
}
Console.WriteLine();
}
}
}
}
This program generates random 2d array and calculates maximum in every line. I do have right results, but IndexOutOfRangeException popping up if number of columns does not equals to the number of lines.
Random r = new Random();
int x,y;
Console.WriteLine("lines");
x = int.Parse(Console.ReadLine());
Console.WriteLine("columns");
y = int.Parse(Console.ReadLine());
if ((x < 1) || (y < 1))
{
Console.WriteLine("Error");
Console.ReadLine();
}
else
{
int[,] array1 = new int[x, y];
int[] array2 = new int[y];
for (int i = 0; i < x; i++)
{
for (int j = 0; j < y; j++)
{
array1[i, j] = r.Next(0, 51);
Console.Write(array1[i, j] + " ");
}
Console.WriteLine();
}
for (int j = 0; j < y; j++)
{
int max = array1[j, 0];
for (int i = 1; i < x; i++)
{
if (array1[j, i] > max)
{
max = (array1[j, i]);
}
else
{
}
}
array2[j] = max;
Console.WriteLine();
Console.Write(array2[j]);
}
Console.ReadLine();
}
On your second pass through the data (the one where you go by lines first rather than by columns), this:
if (array1[j, i] > max)
{
max = (array1[j, i]);
}
should look like this:
if (array1[i, j] > max)
{
max = (array1[i, j]);
}
Changing the order in which you process rows and columns doesn't change the dimensions of the array.
Edit: per #csharpfolk's comment, this line also needs fixing:
int max = array1[j, 0];
probably to:
int max = array1[0, j];
So I'm attempting to print a multiplication table in C# however I can't quite figure out how to get what I need.
So far my program outputs the following:
1 2 3
2 4 6
3 6 9
However, I need it to output this:
0 1 2 3
1 1 2 3
2 2 4 6
3 3 6 9
I've tried a lot of different ways to get the second output however I can't quite figure it out. I'm not necessarily asking for an answer but if someone could point me in the right direction it would be much appreciated.
This is the code I have as of now:
static void Main(string[] args)
{
for (int i = 1; i <= 3; i++)
{
for (int j = 1; j <= 3; j++)
{
Console.Write(i * j + "\t");
}
Console.Write("\n");
}
Console.ReadLine();
}
for (int i = 0; i <= 3; i++)
{
Console.Write(i + "\t");
for (int j = 1; j <= 3; j++)
{
if (i>0) Console.Write(i * j + "\t");
else Console.Write(j + "\t");
}
Console.Write("\n");
}
int tbl= int.Parse(Console.ReadLine());
int j = int.Parse(Console.ReadLine());
for (int i=1; i<=10; i++)
{
for (int j=1;j<=10; j++)
{
Console.WriteLine("{0}*{1}={2}", i, j, (i * j));`enter code here`
}
}
Console.ReadLine();
You should skip both 0's.
for (int i = 0; i <= 3; i++)
{
for (int j = 0; j <= 3; j++)
{
Console.Write((i == 0? j : (j == 0? i : i*j)) + "\t");
}
Console.Write("\n");
}
You could try one of this three solutions.
Solution 1 (without if else statement):
static void Main(string[] args)
{
for (int i = 0; i <= 3; i++)
{
Console.Write("{0}\t", i);
for (int j = 1; j <= 3; j++)
{
Console.Write("{0}\t", i * j);
}
Console.WriteLine();
}
Console.ReadLine();
}
Solution 2 (With if else statement):
static void Main(string[] args)
{
for (int i = 0; i <= 3; i++)
{
for (int j = 1; j <= 3; j++)
{
if (i == 0)
{
Console.Write("{0}\t", i);
}
else
{
Console.Write("{0}\t", i * j);
}
}
Console.WriteLine();
}
Console.ReadLine();
}
Solution 3 (With short-hand if else statement):
static void Main(string[] args)
{
for (int i = 0; i <= 3; i++)
{
for (int j = 1; j <= 3; j++)
{
Console.Write("{0}\t", (i == 0) ? i : i * j);
}
Console.WriteLine();
}
Console.ReadLine();
}
for (int i = 0; i <= 3; i++)
{
for (int j = 0; j <= 3; j++)
{
if (i == 0)
{
Console.Write(j);
}
else
{
if(j == 0)
{
Console.Write(i);
}
else
{
Console.Write(i * j);
}
}
}
Console.Write("\n");
}
Console.WriteLine("Enter A Number");
int j = Convert.ToInt32(Console.ReadLine());
for (int i = 0 ; i <= 10; i++) {
Console.WriteLine("{1} X {0} = {2}",i,j,i*j);
Console.ReadLine();
}
public class Program
{
//int num;
public static void Main(string[] args)
{
int num,num1;
Console.WriteLine("enter a any number num");
num = Convert.ToInt32(Console.ReadLine());
Console.WriteLine("enter any second number num1");
num1 = Convert.ToInt32(Console.ReadLine());
for(int i = num;i <= num1; i++)
{
for (int j = 1; j <= 10; j++)
{
Console.Write(i *j+ "\t");
}
}
Console.Write("\n");
}
}
using System;
/*
* Write a console-based application that displays a multiplication table of the product of
* every integer from 1 through 10 multiplied by every integer from 1 through 10. Save the
* file as DisplayMultiplicationTable.cs.
*/
namespace MultiplicationTable
{
class Program
{
static void Main(string[] args)
{
Console.WriteLine("\t\t\t\t\t\t\t\t\tMultiplication Table");
Console.WriteLine("------------------------------------------------------------------------------------------------------------------------------------------------------------");
const int END = 11;
for(int x = 1; x < END; x++)
{
for(int y = 1; y < END; y++)
{
int value = x * y;
Console.Write("{0} * {1} = {2}\t", y, x, value);
}
Console.WriteLine();
}
Console.ReadLine();
}
}
}
Output
Output of Code
I am attempting to complete the above code in a GUI. So far I have come up with the following code; but the output is not like the above output.
My Code for the GUI is as follows:
using System;
using System.Windows.Forms;
namespace DisplayMultiplicationTableGUI
{
public partial class Form1:Form
{
public Form1()
{
InitializeComponent();
}
private void ShowTableButton_Click(object sender, EventArgs e)
{
int a;
int b;
const int STOP = 11;
for(a = 1; a < STOP; a++)
{
for(b = 1; b < STOP; b++)
{
int value = a * b;
multiplicationTableLabel.Text += String.Format("{0} * {1} = {2} ", b, a, value);
}
multiplicationTableLabel.Text += "\n";
}
}
}
}
Hello everyone
I try to solve asterisk tree problem
and found my code is not work correctly and can be improved.
This is output that expected
input : 5
*
* * *
* * * * *
* * *
*
input : 4
* * * *
* *
* * * *
and this is my code
static void Main(string[] args)
{
Console.Write("input:");
char input = Console.ReadKey().KeyChar;
if (char.IsDigit(input))
{
int couter = (int)char.GetNumericValue(input);
Console.WriteLine();
if (couter % 2 != 0)
{
for (int i = 1; i <= couter; i++)
{
for (int j = 3; j > i; j--)
{
Console.Write(" ");
}
for (int k = 1; k <= i; k++)
{
Console.Write(" *");
}
Console.WriteLine();
}
for (int i = couter - 1; i >= 3; i--)
{
for (int j = 1; j <= i; j++)
{
if (j <= couter - i)
{
Console.Write(" ");
}
else
{
Console.Write("* ");
}
}
Console.WriteLine();
}
}
else
{
for (int i = couter; i > 3; i--)
{
for (int j = 1; j <= i; j++)
{
if (couter - i >= j)
{
Console.Write(" ");
}
else
{
Console.Write("* ");
}
}
Console.WriteLine();
}
for (int i = couter - 1; i <= couter; i++)
{
for (int j = 0; j < i; j++)
{
Console.Write("* ");
}
Console.WriteLine();
}
}
}
}
Please could you help me to solve this problem.
Lately, I think I'm poor at algorithms and a little complex problem. Is anybody know useful link or how I can improve this skill, please let me know.
Thanks,
Check this page for input 5 (diamond) : http://www.dreamincode.net/forums/topic/126715-diamond-asterisk/
I've translated it to C# - now it displays diamonds with size that you set in variable 'rows':
int rows = 5;
StringBuilder sb = new StringBuilder();
// top part
for (int i = 1; i <= rows; i++)
{
for (int j = 1; j <= rows - i; j++)
sb.Append(' ');
for (int k = 1; k <= 2 * i - 1; k++)
sb.Append('*');
sb.AppendLine();
}
//bottom part
for (int n = rows - 1; n > 0; n--)
{
for (int l = 1; l <= rows - n; l++)
sb.Append(' ');
for (int m = 1; m <= 2 * n - 1; m++)
sb.Append('*');
sb.AppendLine();
}
Console.Write(sb.ToString());
I was initially reluctant to post it because it definitely smells like homework...
Anyway, here's a piece of working code:
static void Main(string[] args)
{
Console.Write("input:");
char input = Console.ReadKey().KeyChar;
if (char.IsDigit(input))
{
int couter = (int)char.GetNumericValue(input);
Console.WriteLine();
if (couter % 2 != 0)
PrintDiamond(couter);
else
PrintHourGlass(couter);
}
Console.ReadLine();
}
private static void PrintDiamond(int couter)
{
bool moreAsterisks = true;
for (int row = 0; row < couter; row++)
{
int nAsterisks = moreAsterisks ? (2 * row) + 1 : 2 * (couter - row - 1) + 1;
int nSpaces = (couter - nAsterisks) / 2;
if (row == (couter - 1) / 2)
moreAsterisks = false;
for (int i = 0; i < nSpaces; i++)
Console.Write(" ");
for (int i = 0; i < nAsterisks; i++)
Console.Write("*");
for (int i = 0; i < nSpaces; i++)
Console.Write(" ");
Console.WriteLine();
}
}
private static void PrintHourGlass(int couter)
{
bool moreAsterisks = false;
for (int row = 0; row < couter - 1; row++)
{
int nAsterisks = moreAsterisks ? couter - 2 * (couter - row - 2) : couter - (2 * row);
int nSpaces = (couter - nAsterisks) / 2;
if (row == (couter - 2) / 2)
moreAsterisks = true;
for (int i = 0; i < nSpaces; i++)
Console.Write(" ");
for (int i = 0; i < nAsterisks; i++)
Console.Write("*");
for (int i = 0; i < nSpaces; i++)
Console.Write(" ");
Console.WriteLine();
}
}
P.S.:
it works with any number, not just 4-5...
Here's a minified LINQ solution for your problem:
class Program
{
static void Main(string[] args)
{
Console.Write("input: ");
string line = Console.ReadLine();
int n;
if (!int.TryParse(line, out n))
{
Console.WriteLine("Enter a valid integer number.");
return;
}
for (int i = 0; i < n; i++)
{
int l = Math.Abs(n - i * 2 - 1) + 1;
if (n % 2 != 0) l = n - l + 1;
Console.Write(Enumerable.Repeat(" ", n - l).DefaultIfEmpty("").Aggregate((a, b) => a + b));
Console.WriteLine(Enumerable.Repeat("* ", l).DefaultIfEmpty("").Aggregate((a, b) => a + b));
}
}
}
It's pretty simple; inside the loop, first line calculates length of the i-th diamond row if input is even, second one corrects the calculation for odd input. The remaining two lines print i-th row using some LINQ tricks. If you don't like showing off with LINQ, you can replace thoose lines with regular for loops (which is probably going to be faster). Then the code would look like:
class Program
{
static void Main(string[] args)
{
Console.Write("input: ");
string line = Console.ReadLine();
int n;
if (!int.TryParse(line, out n))
{
Console.WriteLine("Enter a valid integer number.");
return;
}
for (int i = 0; i < n; i++)
{
int l = Math.Abs(n - i * 2 - 1) + 1;
if (n % 2 != 0) l = n - l + 1;
//Console.Write(Enumerable.Repeat(" ", n - l).DefaultIfEmpty("").Aggregate((a, b) => a + b));
//Console.WriteLine(Enumerable.Repeat("* ", l).DefaultIfEmpty("").Aggregate((a, b) => a + b));
for (int c = 0; c < n - l; c++) Console.Write(" ");
for (int c = 0; c < l; c++) Console.Write("* ");
Console.WriteLine();
}
}
}