Hello I would like to send image of screen by udp but I got error with buffer length in client side. How Can I compress image to send it or change udp byte[] limit?? I already tried to compress it by deflate & change image size but quality of picture was bad (I used code from other post for quality it not work). I want to show this image in picture box in the other app.
static Rectangle bounds = Screen.GetBounds(Point.Empty);
static UdpClient socket = new UdpClient();
static void Main(string[] args)
{
Console.WriteLine(GetScreenShot().Length);
socket.Connect(new IPEndPoint(IPAddress.Parse("myServerAddress"), 6665));
while (true)
{
byte[] arr = GetScreenShot();
socket.Send(arr, arr.Length);
}
}
static byte[] GetScreenShot()
{
using (MemoryStream ms = new MemoryStream())
{
using (Bitmap bitmap = new Bitmap(bounds.Width, bounds.Height))
{
using (Graphics g = Graphics.FromImage(bitmap))
{
g.CopyFromScreen(Point.Empty, Point.Empty, bounds.Size);
}
bitmap.Save(ms,ImageFormat.Jpeg);
}
return Compress(ms.ToArray());
}
}
static byte[] Compress(byte[] b)
{
using(MemoryStream ms = new MemoryStream())
{
using(DeflateStream deflateStream = new DeflateStream(ms, CompressionMode.Compress))
{
deflateStream.Write(b, 0, b.Length);
}
return ms.ToArray();
}
}```
Related
I am using WCF for communication between client and server program on the same machine. Earlier I used Bitmaps to transfer video frames to the client. It was successful with WCF, but I only have 6 megabytes / sec LAN. Transferring 1.2Mb every second would block the LAN. I decided to JPEG encode the captured Bitmaps from the camera. It is possible to save a JPEG on the disk from a bitmap, or to a Memorystream. I created a
[MessageContract]
public class RemoteResponse
{
[MessageBodyMember(Order = 1)]
public System.IO.MemoryStream jpegImage;
}
I return this back from the (I)LiveImageService.
As I get it out in the client: RemoteResponse ret = client.GetLiveImage();
MemoryStream returnedImage = returnedResponse.jpegImage;
returnedImage.Position = 0L;
returnedImage.Seek(0, SeekOrigin.Begin);
args.image = returnedImage;
I do this in the event handler:
args.image.Position = 0L;
args.image.Seek(0, SeekOrigin.Begin);
//bitmap = new Bitmap(args.image);
bitmap = (Bitmap)Image.FromStream(args.image);
It gives me a "parameter is not valid" exception.
I have read that this is a buggy solution of Microsoft. Actually the
retreived stream is believed to be 21 bytes long because there is a trailing
zero \0 at the end of the leading "System.Drawing.Bitmap"\0. That is why the
processing of the image is stopped.
I have read a solution that avoids this:
byte[] arr = PdfReader.FlateDecode(PdfReader.GetStreamBytesRaw((PRStream)obj), true);
System.Drawing.Bitmap bmp = new System.Drawing.Bitmap(width, height, pixelFormat);
System.Drawing.Imaging.BitmapData bmd = bmp.LockBits(new System.Drawing.Rectangle(0, 0, width, height), System.Drawing.Imaging.ImageLockMode.WriteOnly, pixelFormat);
Marshal.Copy(arr, 0, bmd.Scan0, arr.Length);
bmp.UnlockBits(bmd);
using (MemoryStream ms = new MemoryStream())
{
bmp.Save(ms, System.Drawing.Imaging.ImageFormat.Png); // here it is the trick
arr = ms.GetBuffer(); // now I replace my incorrect image format bytes for the correct ones
System.Drawing.Image image = System.Drawing.Image.FromStream(ms);
image.Save(path, System.Drawing.Imaging.ImageFormat.Png);
}
How does the last arr = ... have any effect? It is not used anymore later?
So I don't understand.
update:
On a Microsoft website: https://social.msdn.microsoft.com/Forums/vstudio/en-US/f9e39595-04ca-42ae-a353-eb1a08602631/resolved-creating-image-file-parameter-is-not-valid?forum=netfxbcl
I rewrote the example so:
public static Bitmap DecodeJPEGFromMemoryStream(MemoryStream stream, int width, int height, PixelFormat pixelFormat)
{
string content = System.Text.Encoding.UTF8.GetString(stream.ToArray());
byte[] arr = Encoding.UTF8.GetBytes(content);
//byte[] arr = PdfReader.FlateDecode(PdfReader.GetStreamBytesRaw((PRStream)obj), true);
System.Drawing.Bitmap bmp = new System.Drawing.Bitmap(width, height, pixelFormat);
System.Drawing.Imaging.BitmapData bmd = bmp.LockBits(new
System.Drawing.Rectangle(0, 0, width, height),
System.Drawing.Imaging.ImageLockMode.WriteOnly, pixelFormat);
Marshal.Copy(arr, 0, bmd.Scan0, arr.Length);
bmp.UnlockBits(bmd);
using (MemoryStream ms = new MemoryStream())
{
bmp.Save(ms, System.Drawing.Imaging.ImageFormat.Jpeg); // here it is the trick
arr = ms.GetBuffer(); // now I replace my incorrect image format bytes for the correct ones
System.Drawing.Image image = System.Drawing.Image.FromStream(ms);
Bitmap ret = new Bitmap(image);
return ret;
}
}
I can see the image in the Picturebox, but it has only 2 lines, flickering.
If I obscure the camera I see that it darkens. So the data comes through now. But I cannot reconstruct my JPEG live data.
I was able to decode the JPEG data, only with saving it to disk.
So I've got the image without error. I tried to save the image only
temporarily and delete after.
public static Bitmap DecodeJPEGFromMemoryStream(MemoryStream stream, int width, int height, PixelFormat pixelFormat)
{
try
{
if(File.Exists("c:\\imagecache.jpg") == true)
File.Delete("c:\\imagecache.jpg");
//using (FileStream file = new FileStream("c:\\imagecache.jpg", FileMode.CreateNew, System.IO.FileAccess.ReadWrite))
using (FileStream file = File.Open("c:\\imagecache.jpg", FileMode.CreateNew, FileAccess.Write, FileShare.ReadWrite))
{
stream.WriteTo(file);
//JpegBitmapDecoder decoder = new JpegBitmapDecoder(file, BitmapCreateOptions.PreservePixelFormat, BitmapCacheOption.Default);
file.Close();
file.Dispose();
}
System.GC.Collect();
System.GC.WaitForPendingFinalizers();
//BitmapSource bitmapSource = decoder.Frames[0];
Bitmap jpeg;
{
{
FileInfo info = new FileInfo("c:\\imagecache.jpg");
if (info.Length == 0)
{
File.Delete("c:\\imagecache.jpg");
return null;
}
}
System.GC.Collect();
System.GC.WaitForPendingFinalizers();
jpeg = (Bitmap)Image.FromFile("c:\\imagecache.jpg"); //the process cannot access the file...
}
System.GC.Collect();
System.GC.WaitForPendingFinalizers();
if (File.Exists("c:\\imagecache.jpg") == true)
File.Delete("c:\\imagecache.jpg");
return jpeg;
}
catch(Exception ex)
{
return null;
}
}
I get the exception: The process cannot access the file "imagecache.jpg",
because it is being used by another process. Exception comes at the FromFile.
System.GC.Collect();
System.GC.WaitForPendingFinalizers();
Bitmap retImage = (Bitmap)jpeg.Clone();
jpeg.Dispose();
if (File.Exists("c:\\imagecache.jpg") == true)
{
System.IO.FileInfo fi = new System.IO.FileInfo("c:\\imagecache.jpg");
fi.Delete();
}
return retImage;
}
catch (Exception ex)
{
return null;
}
finally
{
stream.Dispose();
}
It is fixed so. Image.FromFile: the File remains locked until the Image is disposed.
So I cloned my Image and disposed the old one.
Before I've seen my Image, now nothing is visible.
I need to convert a BitmapImage in a byte[] but I don't find how to do it in C# web.
I found examples but none of them work (JpegBitmapEncoder doesn't exist, BitmapImageObject.StreamSource doesn't exist, there isn't WriteableBitmap constructor with BitmapImage as parameter, Extensions.SaveJpeg(parameters) doesn't exist ...).
Examples I found:
Constructor new WriteableBitmap(bitmapImage) doesn't exist.
public static byte[] ConvertToBytes(this BitmapImage bitmapImage)
{
byte[] data;
// Get an Image Stream
using (MemoryStream ms = new MemoryStream())
{
WriteableBitmap btmMap = new WriteableBitmap(bitmapImage);
// write an image into the stream
Extensions.SaveJpeg(btmMap, ms,
bitmapImage.PixelWidth, bitmapImage.PixelHeight, 0, 100);
// reset the stream pointer to the beginning
ms.Seek(0, 0);
//read the stream into a byte array
data = new byte[ms.Length];
ms.Read(data, 0, data.Length);
}
//data now holds the bytes of the image
return data;
}
new WriteableBitmap(img), System.Windows.Media.Imaging.Extensions.SaveJpeg don't exist.
public static byte[] ImageToBytes(BitmapImage img)
{
using (MemoryStream ms = new MemoryStream())
{
WriteableBitmap btmMap = new WriteableBitmap(img);
System.Windows.Media.Imaging.Extensions.SaveJpeg(btmMap, ms, img.PixelWidth, img.PixelHeight, 0, 100);
img = null;
return ms.ToArray();
}
}
imageSource.StreamSource doesn't exist.
public static byte[] ImageToByte(BitmapImage imageSource)
{
Stream stream = imageSource.StreamSource;
Byte[] buffer = null;
if (stream != null && stream.Length > 0)
{
using (BinaryReader br = new BinaryReader(stream))
{
buffer = br.ReadBytes((Int32)stream.Length);
}
}
return buffer;
}
JpegBitmapEncoder doesn't exist.
byte[] data;
JpegBitmapEncoder encoder = new JpegBitmapEncoder();
encoder.Frames.Add(BitmapFrame.Create(bitmapImage));
using(MemoryStream ms = new MemoryStream())
{
encoder.Save(ms);
data = ms.ToArray();
}
Try with the using statement to a namespace in the beginning of your code.
Otherwise there should be some Nuget packages which you could install to achieve your goal.
using System.Drawing;
In Main method
Image img = Image.FromFile("path to the file");
var byteArray = ImageToByte(img);
public static byte[] ImageToByte(Image img)
{
ImageConverter converter = new ImageConverter();
return (byte[])converter.ConvertTo(img, typeof(byte[]));
}
Try this
I think this will help...
public byte[] ConvertBitMapToByteArray(Bitmap bitmap)
{
byte[] result = null;
if (bitmap != null)
{
MemoryStream stream = new MemoryStream();
bitmap.Save(stream, bitmap.RawFormat);
result = stream.ToArray();
}
return result;
}
byte[] foo = System.IO.File.ReadAllBytes("bitmap path");
Or
byte[] foo;
Object obj = YourBitmap;
BinaryFormatter bf = new BinaryFormatter();
using (var ms = new MemoryStream())
{
bf.Serialize(ms, obj);
foo = ms.ToArray();
}
Or
ImageConverter foocon = new ImageConverter();
byte[] foo = (byte[])foocon.ConvertTo(YourBitmap, typeof(byte[]));
Or
MemoryStream ms = new MemoryStream();
Bitmap.Save(ms, YourBitmap.RawFormat);
byte[] foo = ms.ToArray();
Finally, it seems that, obviously, it missed some libraries but we are limited with our application, so we decided to recover our pictures by another way. Anyway, thank you all.
I try to receive a desktop screen capture from my PC using WPF (Client and server side WPF)
here is my code
private void ViewReceivedImage(byte[] buffer)
{
try
{
using (MemoryStream memoryStream = new MemoryStream(buffer))
{
BitmapImage imageSource = new BitmapImage();
imageSource.BeginInit();
imageSource.StreamSource = memoryStream;
imageSource.EndInit();
// Assign the Source property of your image
MyImage.Source = imageSource;
}
//MemoryStream ms = new MemoryStream(buffer);
//BitmapImage bi = new BitmapImage();
//bi.SetSource = ms;
//MyImage.Source = bi;
//ms.Close();
}
catch (Exception) { }
finally
{
StartReceiving();
}
}
The commented line above are for Windows phone app, I have already tested it and it works with WP8(Client Side), I have the problem only on WPF Client Side.
WPF Server Side and WP8 Client Side works
WPF Client Side not working but connection is successful
this method sends the image
void StartSending()
{
while (!stop)
try
{
System.Drawing.Image oldimage = scr.Get_Resized_Image(wToCompare, hToCompare, scr.GetDesktopBitmapBytes());
//Thread.Sleep(1);
System.Drawing.Image newimage = scr.Get_Resized_Image(wToCompare, hToCompare, scr.GetDesktopBitmapBytes());
byte[] buffer = scr.GetDesktop_ResizedBytes(wToSend, hToSend);
//float difference = scr.difference(newimage, oldimage);
//if (difference >= 1)
//{
SenderSocket.Send(buffer);
//}
}
catch (Exception) { }
}
and this Get_Resized_Image
public Image Get_Resized_Image(int w, int h, byte[] image)
{
MemoryStream ms = new MemoryStream(image);
Image bt = Image.FromStream(ms);
try
{
Size sizing = new Size(w, h);
bt = new System.Drawing.Bitmap(bt, sizing);
}
catch (Exception) { }
return bt;
}
edited
this is the output
I am developing a program to grab images from four cameras and turn them into one picture only in style quad, 4 images in one. And it generate a .avi
AVIReader reader = new AVIReader();
List<byte[]> ImagemMainb = new List<byte[]>();
reader.Open(_rootPath + Path.GetFileName(_arqsCam01[i]));
while (reader.Position - reader.Start < reader.Length)
{
Bitmap aux = reader.GetNextFrame();
Bitmap r = new Bitmap(aux.Width * 2, aux.Height * 2, System.Drawing.Imaging.PixelFormat.Format24bppRgb);
using (var g = Graphics.FromImage(r))
{
g.DrawImage(aux, new Rectangle(0, 0, aux.Width, aux.Height));
ImagemMainb.Add(ImageToByte(r));
}
}
reader.Close();
reader.Dispose();
And here is the method ImageToByte
public static byte[] ImageToByte(Image img)
{
byte[] byteArray = new byte[0];
using (MemoryStream stream = new MemoryStream())
{
img.Save(stream, System.Drawing.Imaging.ImageFormat.Png);
stream.Close();
byteArray = stream.ToArray();
}
return byteArray;
}
Using these codes takes too long to finish the process!
When I have a list of 84000 bitmaps in that case are 280 videos with frame rate = 5, size = 320x240, it takes forever.
Would have any problem in this code or have a better way?
i found the answer.
AVIReader reader = new AVIReader();
List<Bitmap> ImagemMain = new List<byte[]>();
reader.Open(_rootPath + Path.GetFileName(_arqs[0]));
while (reader.Position - reader.Start < reader.Length)
{
using (var aux = reader.GetNextFrame())
{
using (var r = new Bitmap(640, 480))
{
using (var g = Graphics.FromImage(r))
{
g.DrawImage(aux, new Rectangle(0, 0, aux.Width, aux.Height));
ImagemMain.Add((Bitmap)r.Clone());
}
}
}
}
Every video uploaded AVIWriter I open the file .avi and add bitmap.
With this is much more fast and does not take up almost no memory.
I have a file transfer program. The program (Client) does following operations to send a bitmap via TCP socket: get screenshot -> grab Bitmap from memory -> convert to stream -> send
MemoryStream Fs = new MemoryStream();
//////////////11111
Bitmap bmp = TakeScreen();
///////////////2222
//Bitmap bmp = new Bitmap(#"C:\temp\001.bmp");
bmp.Save(Fs, ImageFormat.Bmp);
Byte[] buffer = Fs.ToArray();
Fs.Read(buffer, 0, buffer.Length);
TcpClient socket = new TcpClient("192.168.0.131", 1095);
NetworkStream nw = socket.GetStream();
nw.Write(buffer, 0, buffer.Length);
nw.Close();
Fs.Dispose();
socket.Close();
bmp.Dispose();
If I choose to transfer image directly from memory - no errors.
If I try to load Bitmap from file first - getting "Parameter is not valid" error on a server's side.
here is the server side:
NetworkStream Nw = new NetworkStream(handlerSocket.Client);
int thisRead = 0;
int Blocksize = 1024;
Byte[] dataByte = new Byte[Blocksize];
Bitmap screen = getScreen(Nw, dataByte, thisRead, Blocksize);
Nw.Close();
and
private Bitmap getScreen(NetworkStream Nw, Byte[] dataByte, int thisRead, int Blocksize)
{
Bitmap bitmap;
using (var strm = new MemoryStream())
{
while (true)
{
thisRead = Nw.Read(dataByte, 0, Blocksize);
strm.Write(dataByte, 0, thisRead);
if (thisRead == 0)
break;
}
bitmap = new Bitmap(strm); // Error here
}
Bitmap bm3 = new Bitmap(bitmap);
bitmap.Dispose();
return bm3;
}
What's causing this error? I guess it has something to do with the MemoryStream.
edit: simplified the question
You nee to seek to the beginning of the stream before you can create the Bitmap in getScreen.
private Bitmap getScreen(NetworkStream Nw, Byte[] dataByte, int thisRead, int Blocksize)
{
Bitmap bitmap;
using (var strm = new MemoryStream())
{
while (true)
{
thisRead = Nw.Read(dataByte, 0, Blocksize);
strm.Write(dataByte, 0, thisRead);
if (thisRead == 0)
break;
}
stream.Seek(0, SeekOrigin.Begin; // <-- Go Back to beginning of stream
bitmap = new Bitmap(strm); // Error here
}
Bitmap bm3 = new Bitmap(bitmap);
bitmap.Dispose();
return bm3;
}
EDIT
Detailed explanation: After writing the last byte to the stream, the stream's current position is a the end of the stream. Creating a Bitmap from the screen now tries to read the bitmap from the stream, which doesn't work, as there is no more data after the current position (= the end of the stream).
So what you need to do is tell the stream to set the current position back to the beginning of the stream. Then, the bitmap information can be read.