Asp.Net Regex C# replace function not working [duplicate] - c#
https://regex101.com/r/sB9wW6/1
(?:(?<=\s)|^)#(\S+) <-- the problem in positive lookbehind
Working like this on prod: (?:\s|^)#(\S+), but I need a correct start index (without space).
Here is in JS:
var regex = new RegExp(/(?:(?<=\s)|^)#(\S+)/g);
Error parsing regular expression: Invalid regular expression:
/(?:(?<=\s)|^)#(\S+)/
What am I doing wrong?
UPDATE
Ok, no lookbehind in JS :(
But anyways, I need a regex to get the proper start and end index of my match. Without leading space.
Make sure you always select the right regex engine at regex101.com. See an issue that occurred due to using a JS-only compatible regex with [^] construct in Python.
JS regex - at the time of answering this question - did not support lookbehinds. Now, it becomes more and more adopted after its introduction in ECMAScript 2018. You do not really need it here since you can use capturing groups:
var re = /(?:\s|^)#(\S+)/g;
var str = 's #vln1\n#vln2\n';
var res = [];
while ((m = re.exec(str)) !== null) {
res.push(m[1]);
}
console.log(res);
The (?:\s|^)#(\S+) matches a whitespace or the start of string with (?:\s|^), then matches #, and then matches and captures into Group 1 one or more non-whitespace chars with (\S+).
To get the start/end indices, use
var re = /(\s|^)#\S+/g;
var str = 's #vln1\n#vln2\n';
var pos = [];
while ((m = re.exec(str)) !== null) {
pos.push([m.index+m[1].length, m.index+m[0].length]);
}
console.log(pos);
BONUS
My regex works at regex101.com, but not in...
First of all, have you checked the Code Generator link in the Tools pane on the left?
All languages - "Literal string" vs. "String literal" alert - Make sure you test against the same text used in code, literal string, at the regex tester. A common scenario is copy/pasting a string literal value directly into the test string field, with all string escape sequences like \n (line feed char), \r (carriage return), \t (tab char). See Regex_search c++, for example. Mind that they must be replaced with their literal counterparts. So, if you have in Python text = "Text\n\n abc", you must use Text, two line breaks, abc in the regex tester text field. Text.*?abc will never match it although you might think it "works". Yes, . does not always match line break chars, see How do I match any character across multiple lines in a regular expression?
All languages - Backslash alert - Make sure you correctly use a backslash in your string literal, in most languages, in regular string literals, use double backslash, i.e. \d used at regex101.com must written as \\d. In raw string literals, use a single backslash, same as at regex101. Escaping word boundary is very important, since, in many languages (C#, Python, Java, JavaScript, Ruby, etc.), "\b" is used to define a BACKSPACE char, i.e. it is a valid string escape sequence. PHP does not support \b string escape sequence, so "/\b/" = '/\b/' there.
All languages - Default flags - Global and Multiline - Note that by default m and g flags are enabled at regex101.com. So, if you use ^ and $, they will match at the start and end of lines correspondingly. If you need the same behavior in your code check how multiline mode is implemented and either use a specific flag, or - if supported - use an inline (?m) embedded (inline) modifier. The g flag enables multiple occurrence matching, it is often implemented using specific functions/methods. Check your language reference to find the appropriate one.
line-breaks - Line endings at regex101.com are LF only, you can't test strings with CRLF endings, see regex101.com VS myserver - different results. Solutions can be different for each regex library: either use \R (PCRE, Java, Ruby) or some kind of \v (Boost, PCRE), \r?\n, (?:\r\n?|\n)/(?>\r\n?|\n) (good for .NET) or [\r\n]+ in other libraries (see answers for C#, PHP). Another issue related to the fact that you test your regex against a multiline string (not a list of standalone strings/lines) is that your patterns may consume the end of line, \n, char with negated character classes, see an issue like that. \D matched the end of line char, and in order to avoid it, [^\d\n] could be used, or other alternatives.
php - You are dealing with Unicode strings, or want shorthand character classes to match Unicode characters, too (e.g. \w+ to match Стрибижев or Stribiżew, or \s+ to match hard spaces), then you need to use u modifier, see preg_match() returns 0 although regex testers work - To match all occurrences, use preg_match_all, not preg_match with /...pattern.../g, see PHP preg_match to find multiple occurrences and "Unknown modifier 'g' in..." when using preg_match in PHP?- Your regex with inline backreference like \1 refuses to work? Are you using a double quoted string literal? Use a single-quoted one, see Backreference does not work in PHP
phplaravel - Mind you need the regex delimiters around the pattern, see https://stackoverflow.com/questions/22430529
python - Note that re.search, re.match, re.fullmatch, re.findall and re.finditer accept the regex as the first argument, and the input string as the second argument. Not re.findall("test 200 300", r"\d+"), but re.findall(r"\d+", "test 200 300"). If you test at regex101.com, please check the "Code Generator" page. - You used re.match that only searches for a match at the start of the string, use re.search: Regex works fine on Pythex, but not in Python - If the regex contains capturing group(s), re.findall returns a list of captures/capture tuples. Either use non-capturing groups, or re.finditer, or remove redundant capturing groups, see re.findall behaves weird - If you used ^ in the pattern to denote start of a line, not start of the whole string, or used $ to denote the end of a line and not a string, pass re.M or re.MULTILINE flag to re method, see Using ^ to match beginning of line in Python regex
- If you try to match some text across multiple lines, and use re.DOTALL or re.S, or [\s\S]* / [\s\S]*?, and still nothing works, check if you read the file line by line, say, with for line in file:. You must pass the whole file contents as the input to the regex method, see Getting Everything Between Two Characters Across New Lines. - Having trouble adding flags to regex and trying something like pattern = r"/abc/gi"? See How to add modifers to regex in python?
c#, .net - .NET regex does not support possessive quantifiers like ++, *+, ??, {1,10}?, see .NET regex matching digits between optional text with possessive quantifer is not working - When you match against a multiline string and use RegexOptions.Multiline option (or inline (?m) modifier) with an $ anchor in the pattern to match entire lines, and get no match in code, you need to add \r? before $, see .Net regex matching $ with the end of the string and not of line, even with multiline enabled - To get multiple matches, use Regex.Matches, not Regex.Match, see RegEx Match multiple times in string - Similar case as above: splitting a string into paragraphs, by a double line break sequence - C# / Regex Pattern works in online testing, but not at runtime - You should remove regex delimiters, i.e. #"/\d+/" must actually look like #"\d+", see Simple and tested online regex containing regex delimiters does not work in C# code - If you unnecessarily used Regex.Escape to escape all characters in a regular expression (like Regex.Escape(#"\d+\.\d+")) you need to remove Regex.Escape, see Regular Expression working in regex tester, but not in c#
dartflutter - Use raw string literal, RegExp(r"\d"), or double backslashes (RegExp("\\d")) - https://stackoverflow.com/questions/59085824
javascript - Double escape backslashes in a RegExp("\\d"): Why do regex constructors need to be double escaped?
- (Negative) lookbehinds unsupported by most browsers: Regex works on browser but not in Node.js - Strings are immutable, assign the .replace result to a var - The .replace() method does change the string in place - Retrieve all matches with str.match(/pat/g) - Regex101 and Js regex search showing different results or, with RegExp#exec, RegEx to extract all matches from string using RegExp.exec- Replace all pattern matches in string: Why does javascript replace only first instance when using replace?
javascriptangular - Double the backslashes if you define a regex with a string literal, or just use a regex literal notation, see https://stackoverflow.com/questions/56097782
java - Word boundary not working? Make sure you use double backslashes, "\\b", see Regex \b word boundary not works - Getting invalid escape sequence exception? Same thing, double backslashes - Java doesn't work with regex \s, says: invalid escape sequence - No match found is bugging you? Run Matcher.find() / Matcher.matches() - Why does my regex work on RegexPlanet and regex101 but not in my code? - .matches() requires a full string match, use .find(): Java Regex pattern that matches in any online tester but doesn't in Eclipse - Access groups using matcher.group(x): Regex not working in Java while working otherwise - Inside a character class, both [ and ] must be escaped - Using square brackets inside character class in Java regex - You should not run matcher.matches() and matcher.find() consecutively, use only if (matcher.matches()) {...} to check if the pattern matches the whole string and then act accordingly, or use if (matcher.find()) to check if there is a single match or while (matcher.find()) to find multiple matches (or Matcher#results()). See Why does my regex work on RegexPlanet and regex101 but not in my code?
scala - Your regex attempts to match several lines, but you read the file line by line (e.g. use for (line <- fSource.getLines))? Read it into a single variable (see matching new line in Scala regex, when reading from file)
kotlin - You have Regex("/^\\d+$/")? Remove the outer slashes, they are regex delimiter chars that are not part of a pattern. See Find one or more word in string using Regex in Kotlin - You expect a partial string match, but .matchEntire requires a full string match? Use .find, see Regex doesn't match in Kotlin
mongodb - Do not enclose /.../ with single/double quotation marks, see mongodb regex doesn't work
c++ - regex_match requires a full string match, use regex_search to find a partial match - Regex not working as expected with C++ regex_match - regex_search finds the first match only. Use sregex_token_iterator or sregex_iterator to get all matches: see What does std::match_results::size return? - When you read a user-defined string using std::string input; std::cin >> input;, note that cin will only get to the first whitespace, to read the whole line properly, use std::getline(std::cin, input); - C++ Regex to match '+' quantifier - "\d" does not work, you need to use "\\d" or R"(\d)" (a raw string literal) - This regex doesn't work in c++ - Make sure the regex is tested against a literal text, not a string literal, see Regex_search c++
go - Double backslashes or use a raw string literal: Regular expression doesn't work in Go - Go regex does not support lookarounds, select the right option (Go) at regex101.com before testing! Regex expression negated set not working golang
groovy - Return all matches: Regex that works on regex101 does not work in Groovy
r - Double escape backslashes in the string literal: "'\w' is an unrecognized escape" in grep - Use perl=TRUE to PCRE engine ((g)sub/(g)regexpr): Why is this regex using lookbehinds invalid in R?
oracle - Greediness of all quantifiers is set by the first quantifier in the regex, see Regex101 vs Oracle Regex (then, you need to make all the quantifiers as greedy as the first one)] - \b does not work? Oracle regex does not support word boundaries at all, use workarounds as shown in Regex matching works on regex tester but not in oracle
firebase - Double escape backslashes, make sure ^ only appears at the start of the pattern and $ is located only at the end (if any), and note you cannot use more than 9 inline backreferences: Firebase Rules Regex Birthday
firebasegoogle-cloud-firestore - In Firestore security rules, the regular expression needs to be passed as a string, which also means it shouldn't be wrapped in / symbols, i.e. use allow create: if docId.matches("^\\d+$").... See https://stackoverflow.com/questions/63243300
google-data-studio - /pattern/g in REGEXP_REPLACE must contain no / regex delimiters and flags (like g) - see How to use Regex to replace square brackets from date field in Google Data Studio?
google-sheets - If you think REGEXEXTRACT does not return full matches, truncates the results, you should check if you have redundant capturing groups in your regex and remove them, or convert the capturing groups to non-capturing by add ?: after the opening (, see Extract url domain root in Google Sheet
sed - Why does my regular expression work in X but not in Y?
word-boundarypcrephp - [[:<:]] and [[:>:]] do not work in the regex tester, although they are valid constructs in PCRE, see https://stackoverflow.com/questions/48670105
snowflake-cloud-data-platform snowflake-sql - If you are writing a stored procedure, and \\d does not work, you need to double them again and use \\\\d, see REGEX conversion of VARCHAR value to DATE in Snowflake stored procedure using RLIKE not consistent.
Related
Regex containing a [:alnum:] POSIX character class did not match string with C#, but online tool evaluates ok
I have a regex
(?'Conpany'Company) - (?'Model'Model) - (?'Version'V(?'Major'\d+).(?'Minor'\d+).(?'Bugfix'\d+).(?'Build'\d+)(?'PreRelease'-[[:alnum:]]*)?(?'Meta'\+[[:alnum:]]*)?) - (?'CompileDate'(?'Year'\d{4})(?'Month'\d{2})(?'Day'\d{2}))
that should match a SCPI String
Company - Model - V1.0.0.1718-RC1 - 20190821
If I try the regex with an online tool, everything works fine and the string matches the regex.
Now i'm trying to use that regex with C# to evaluate a command answer and the result is always false
var regex = #"(?'Conpany'Company) - (?'Model'Model) - (?'Version'V(?'Major'\d+).(?'Minor'\d+).(?'Bugfix'\d+).(?'Build'\d+)(?'PreRelease'-[[:alnum:]]*)?(?'Meta'\+[[:alnum:]]*)?)" - (?'CompileDate'(?'Year'\d{4})(?'Month'\d{2})(?'Day'\d{2}))";
//
responce = await rs232Device.SendCommand(query, DefaultTimeout);
var match = Regex.Match(responce.Message, regex, RegexOptions.IgnoreCase);
//
Assert.That(match.Success, Is.True);
I found out that the compile date - (?'CompileDate'(?'Year'\d{4})(?'Month'\d{2})(?'Day'\d{2})) from the regex everything is fine.
But I don't know why it doesn't work with the complete regex in C# while https://regex101.com/ could match the string.
.NET regex engine does not support POSIX character classes. You have [[:alnum:]] here, replacing it with \w (any word char), or [\p{L}\p{N}] (any letter or digit) or [^\W\p{Pc}] (any word char except the connector punctuation like _) will make it work.
See other POSIX character classes example mappings (they may fail to work exactly the same but at least similarly):
POSIX .NET Description
[:alpha:] \p{L} Any letters (\p{L} matches only those from the BMP plane)
[:alnum:] [\p{L}\p{N}] Any letters or digits
[:digit:] \p{N} or \d Any digits (there is also a [:d:] POSIX variation)
[:space:] \s or \p{Z} Any whitespace
[:blank:] [\p{Zs}\t] Any horizontal whitespace
Besides, some extend them to
POSIX .NET Description
[:ascii:] [\x00-\x7E] ASCII character set
[:xdigit:] [0-9a-fA-F] Chars that are used to define hex values
Besides, you must escape literal dots in the pattern.
Also, always use the Web regex tester that is compatible with the regex engine you plan to use with your pattern.
(?'Conpany'Company) - (?'Model'Model) - (?'Version'V(?'Major'\d+)\.(?'Minor'\d+)\.(?'Bugfix'\d+)\.(?'Build'\d+)(?'PreRelease'-\w*)?(?'Meta'\+\w*)?) - (?'CompileDate'(?'Year'\d{4})(?'Month'\d{2})(?'Day'\d{2}))
See the regex demo
Cannot Match Multiline String in C# Between Two Words [duplicate]
For example, this regex (.*)<FooBar> will match: abcde<FooBar> But how do I get it to match across multiple lines? abcde fghij<FooBar>
Try this: ((.|\n)*)<FooBar> It basically says "any character or a newline" repeated zero or more times.
It depends on the language, but there should be a modifier that you can add to the regex pattern. In PHP it is: /(.*)<FooBar>/s The s at the end causes the dot to match all characters including newlines.
The question is, can the . pattern match any character? The answer varies from engine to engine. The main difference is whether the pattern is used by a POSIX or non-POSIX regex library.
A special note about lua-patterns: they are not considered regular expressions, but . matches any character there, the same as POSIX-based engines.
Another note on matlab and octave: the . matches any character by default (demo): str = "abcde\n fghij<Foobar>"; expression = '(.*)<Foobar>*'; [tokens,matches] = regexp(str,expression,'tokens','match'); (tokens contain a abcde\n fghij item).
Also, in all of boost's regex grammars the dot matches line breaks by default. Boost's ECMAScript grammar allows you to turn this off with regex_constants::no_mod_m (source).
As for oracle (it is POSIX based), use the n option (demo): select regexp_substr('abcde' || chr(10) ||' fghij<Foobar>', '(.*)<Foobar>', 1, 1, 'n', 1) as results from dual
POSIX-based engines:
A mere . already matches line breaks, so there isn't a need to use any modifiers, see bash (demo).
The tcl (demo), postgresql (demo), r (TRE, base R default engine with no perl=TRUE, for base R with perl=TRUE or for stringr/stringi patterns, use the (?s) inline modifier) (demo) also treat . the same way.
However, most POSIX-based tools process input line by line. Hence, . does not match the line breaks just because they are not in scope. Here are some examples how to override this:
sed - There are multiple workarounds. The most precise, but not very safe, is sed 'H;1h;$!d;x; s/\(.*\)><Foobar>/\1/' (H;1h;$!d;x; slurps the file into memory). If whole lines must be included, sed '/start_pattern/,/end_pattern/d' file (removing from start will end with matched lines included) or sed '/start_pattern/,/end_pattern/{{//!d;};}' file (with matching lines excluded) can be considered.
perl - perl -0pe 's/(.*)<FooBar>/$1/gs' <<< "$str" (-0 slurps the whole file into memory, -p prints the file after applying the script given by -e). Note that using -000pe will slurp the file and activate 'paragraph mode' where Perl uses consecutive newlines (\n\n) as the record separator.
gnu-grep - grep -Poz '(?si)abc\K.*?(?=<Foobar>)' file. Here, z enables file slurping, (?s) enables the DOTALL mode for the . pattern, (?i) enables case insensitive mode, \K omits the text matched so far, *? is a lazy quantifier, (?=<Foobar>) matches the location before <Foobar>.
pcregrep - pcregrep -Mi "(?si)abc\K.*?(?=<Foobar>)" file (M enables file slurping here). Note pcregrep is a good solution for macOS grep users.
See demos.
Non-POSIX-based engines:
php - Use the s modifier PCRE_DOTALL modifier: preg_match('~(.*)<Foobar>~s', $s, $m) (demo)
c# - Use RegexOptions.Singleline flag (demo): - var result = Regex.Match(s, #"(.*)<Foobar>", RegexOptions.Singleline).Groups[1].Value;- var result = Regex.Match(s, #"(?s)(.*)<Foobar>").Groups[1].Value;
powershell - Use the (?s) inline option: $s = "abcde`nfghij<FooBar>"; $s -match "(?s)(.*)<Foobar>"; $matches[1]
perl - Use the s modifier (or (?s) inline version at the start) (demo): /(.*)<FooBar>/s
python - Use the re.DOTALL (or re.S) flags or (?s) inline modifier (demo): m = re.search(r"(.*)<FooBar>", s, flags=re.S) (and then if m:, print(m.group(1)))
java - Use Pattern.DOTALL modifier (or inline (?s) flag) (demo): Pattern.compile("(.*)<FooBar>", Pattern.DOTALL)
kotlin - Use RegexOption.DOT_MATCHES_ALL : "(.*)<FooBar>".toRegex(RegexOption.DOT_MATCHES_ALL)
groovy - Use (?s) in-pattern modifier (demo): regex = /(?s)(.*)<FooBar>/
scala - Use (?s) modifier (demo): "(?s)(.*)<Foobar>".r.findAllIn("abcde\n fghij<Foobar>").matchData foreach { m => println(m.group(1)) }
javascript - Use [^] or workarounds [\d\D] / [\w\W] / [\s\S] (demo): s.match(/([\s\S]*)<FooBar>/)[1]
c++ (std::regex) Use [\s\S] or the JavaScript workarounds (demo): regex rex(R"(([\s\S]*)<FooBar>)");
vba vbscript - Use the same approach as in JavaScript, ([\s\S]*)<Foobar>. (NOTE: The MultiLine property of the RegExp object is sometimes erroneously thought to be the option to allow . match across line breaks, while, in fact, it only changes the ^ and $ behavior to match start/end of lines rather than strings, the same as in JavaScript regex)
behavior.)
ruby - Use the /m MULTILINE modifier (demo): s[/(.*)<Foobar>/m, 1]
rtrebase-r - Base R PCRE regexps - use (?s): regmatches(x, regexec("(?s)(.*)<FooBar>",x, perl=TRUE))[[1]][2] (demo)
ricustringrstringi - in stringr/stringi regex funtions that are powered with the ICU regex engine. Also use (?s): stringr::str_match(x, "(?s)(.*)<FooBar>")[,2] (demo)
go - Use the inline modifier (?s) at the start (demo): re: = regexp.MustCompile(`(?s)(.*)<FooBar>`)
swift - Use dotMatchesLineSeparators or (easier) pass the (?s) inline modifier to the pattern: let rx = "(?s)(.*)<Foobar>"
objective-c - The same as Swift. (?s) works the easiest, but here is how the option can be used: NSRegularExpression* regex = [NSRegularExpression regularExpressionWithPattern:pattern options:NSRegularExpressionDotMatchesLineSeparators error:®exError];
re2, google-apps-script - Use the (?s) modifier (demo): "(?s)(.*)<Foobar>" (in Google Spreadsheets, =REGEXEXTRACT(A2,"(?s)(.*)<Foobar>"))
NOTES ON (?s):
In most non-POSIX engines, the (?s) inline modifier (or embedded flag option) can be used to enforce . to match line breaks.
If placed at the start of the pattern, (?s) changes the bahavior of all . in the pattern. If the (?s) is placed somewhere after the beginning, only those .s will be affected that are located to the right of it unless this is a pattern passed to Python's re. In Python re, regardless of the (?s) location, the whole pattern . is affected. The (?s) effect is stopped using (?-s). A modified group can be used to only affect a specified range of a regex pattern (e.g., Delim1(?s:.*?)\nDelim2.* will make the first .*? match across newlines and the second .* will only match the rest of the line).
POSIX note:
In non-POSIX regex engines, to match any character, [\s\S] / [\d\D] / [\w\W] constructs can be used.
In POSIX, [\s\S] is not matching any character (as in JavaScript or any non-POSIX engine), because regex escape sequences are not supported inside bracket expressions. [\s\S] is parsed as bracket expressions that match a single character, \ or s or S.
If you're using Eclipse search, you can enable the "DOTALL" option to make '.' match any character including line delimiters: just add "(?s)" at the beginning of your search string. Example: (?s).*<FooBar>
In many regex dialects, /[\S\s]*<Foobar>/ will do just what you want. Source
([\s\S]*)<FooBar> The dot matches all except newlines (\r\n). So use \s\S, which will match ALL characters.
We can also use (.*?\n)*? to match everything including newline without being greedy. This will make the new line optional (.*?|\n)*?
In Ruby you can use the 'm' option (multiline): /YOUR_REGEXP/m See the Regexp documentation on ruby-doc.org for more information.
"." normally doesn't match line-breaks. Most regex engines allows you to add the S-flag (also called DOTALL and SINGLELINE) to make "." also match newlines. If that fails, you could do something like [\S\s].
For Eclipse, the following expression worked:
Foo
jadajada Bar"
Regular expression:
Foo[\S\s]{1,10}.*Bar*
Note that (.|\n)* can be less efficient than (for example) [\s\S]* (if your language's regexes support such escapes) and than finding how to specify the modifier that makes . also match newlines. Or you can go with POSIXy alternatives like [[:space:][:^space:]]*.
Use: /(.*)<FooBar>/s The s causes dot (.) to match carriage returns.
Use RegexOptions.Singleline. It changes the meaning of . to include newlines. Regex.Replace(content, searchText, replaceText, RegexOptions.Singleline);
In notepad++ you can use this <table (.|\r\n)*</table> It will match the entire table starting from rows and columns You can make it greedy, using the following, that way it will match the first, second and so forth tables and not all at once <table (.|\r\n)*?</table>
In a Java-based regular expression, you can use [\s\S].
This works for me and is the simplest one: (\X*)<FooBar>
Generally, . doesn't match newlines, so try ((.|\n)*)<foobar>.
In JavaScript you can use [^]* to search for zero to infinite characters, including line breaks.
$("#find_and_replace").click(function() {
var text = $("#textarea").val();
search_term = new RegExp("[^]*<Foobar>", "gi");;
replace_term = "Replacement term";
var new_text = text.replace(search_term, replace_term);
$("#textarea").val(new_text);
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<button id="find_and_replace">Find and replace</button>
<br>
<textarea ID="textarea">abcde
fghij<Foobar></textarea>
Solution:
Use pattern modifier sU will get the desired matching in PHP.
Example:
preg_match('/(.*)/sU', $content, $match);
Sources:
Pattern Modifiers
In the context of use within languages, regular expressions act on strings, not lines. So you should be able to use the regex normally, assuming that the input string has multiple lines. In this case, the given regex will match the entire string, since "<FooBar>" is present. Depending on the specifics of the regex implementation, the $1 value (obtained from the "(.*)") will either be "fghij" or "abcde\nfghij". As others have said, some implementations allow you to control whether the "." will match the newline, giving you the choice. Line-based regular expression use is usually for command line things like egrep.
Try: .*\n*.*<FooBar> assuming you are also allowing blank newlines. As you are allowing any character including nothing before <FooBar>.
I had the same problem and solved it in probably not the best way but it works. I replaced all line breaks before I did my real match: mystring = Regex.Replace(mystring, "\r\n", "") I am manipulating HTML so line breaks don't really matter to me in this case. I tried all of the suggestions above with no luck. I am using .NET 3.5 FYI.
I wanted to match a particular if block in Java:
...
...
if(isTrue){
doAction();
}
...
...
}
If I use the regExp
if \(isTrue(.|\n)*}
it included the closing brace for the method block, so I used
if \(!isTrue([^}.]|\n)*}
to exclude the closing brace from the wildcard match.
Often we have to modify a substring with a few keywords spread across lines preceding the substring. Consider an XML element:
<TASK>
<UID>21</UID>
<Name>Architectural design</Name>
<PercentComplete>81</PercentComplete>
</TASK>
Suppose we want to modify the 81, to some other value, say 40. First identify .UID.21..UID., then skip all characters including \n till .PercentCompleted.. The regular expression pattern and the replace specification are:
String hw = new String("<TASK>\n <UID>21</UID>\n <Name>Architectural design</Name>\n <PercentComplete>81</PercentComplete>\n</TASK>");
String pattern = new String ("(<UID>21</UID>)((.|\n)*?)(<PercentComplete>)(\\d+)(</PercentComplete>)");
String replaceSpec = new String ("$1$2$440$6");
// Note that the group (<PercentComplete>) is $4 and the group ((.|\n)*?) is $2.
String iw = hw.replaceFirst(pattern, replaceSpec);
System.out.println(iw);
<TASK>
<UID>21</UID>
<Name>Architectural design</Name>
<PercentComplete>40</PercentComplete>
</TASK>
The subgroup (.|\n) is probably the missing group $3. If we make it non-capturing by (?:.|\n) then the $3 is (<PercentComplete>). So the pattern and replaceSpec can also be:
pattern = new String("(<UID>21</UID>)((?:.|\n)*?)(<PercentComplete>)(\\d+)(</PercentComplete>)");
replaceSpec = new String("$1$2$340$5")
and the replacement works correctly as before.
Typically searching for three consecutive lines in PowerShell, it would look like: $file = Get-Content file.txt -raw $pattern = 'lineone\r\nlinetwo\r\nlinethree\r\n' # "Windows" text $pattern = 'lineone\nlinetwo\nlinethree\n' # "Unix" text $pattern = 'lineone\r?\nlinetwo\r?\nlinethree\r?\n' # Both $file -match $pattern # output True Bizarrely, this would be Unix text at the prompt, but Windows text in a file: $pattern = 'lineone linetwo linethree ' Here's a way to print out the line endings: 'lineone linetwo linethree ' -replace "`r",'\r' -replace "`n",'\n' # Output lineone\nlinetwo\nlinethree\n
Option 1 One way would be to use the s flag (just like the accepted answer): /(.*)<FooBar>/s Demo 1 Option 2 A second way would be to use the m (multiline) flag and any of the following patterns: /([\s\S]*)<FooBar>/m or /([\d\D]*)<FooBar>/m or /([\w\W]*)<FooBar>/m Demo 2 RegEx Circuit jex.im visualizes regular expressions:
RegEx different substitutions based on groups?
So I'm relatively n00bish at regular expressions, and doing a little practicing. I'm playing with a dog-simple "deobfucator" that just looks for [dot] or (dot) or [at] or (at). Case-insensitive, and with or w/out any number of spaces before or after the match(s). This is for the usual: someemail [AT] domain (dot) com type of thing. I want to obviously turn it into someemail#domain.com. The RegEx I've come up with does the matching fine, but now I want to replace with either a . or a # depending on the match. i.e. I want the group matching the "dot" group to replace it with the literal ., and the group matching the "at" group with the literal #. I know I could just write 2 different (almost identical) RegEx's and run it through both, but for the sake of education, I'm trying to see if I can do it all in one RegEx? Here's the RegEx I came up with (probably not the smallest possible, which I'd also be interested in seeing): +(\[|\()(dot)(\)|\]) +| +(\[|\()(at)(\)|\]) + NOTE: before each + there's an empty space, for matching spaces. What I'm looking for is what I would use to do the replacement(s) properly? Update: Sorry all, forgot to add which language I was working with for this. In this case, I'm using a clipboard utility that can run RegEx's on it's input (whatever gets copied to the clipboard), and the engine it uses is C#/VB.NET. Ultimate goal for this little project is to just be able to copy an "obfuscated" email address or URL, and run the RegEx on it so that it's set on the clipboard in it's "unobfuscated" state. That said, I do tend to use RegEx's on many different languages, so converting them between languages generally isn't an issue.
.NET regex does not support conditional replacement patterns.
for the sake of education, I'm trying to see if I can do it all in one RegEx?
There are other regex engines that allow conditional replacement logic in a single regex replacement operation with conditional replacement patterns.
There are 3 engines that support this type of replacements: JGsoft V2, Boost, and PCRE2.
For conditionals to work in Boost, you need to pass regex_constants::format_all to regex_replace. For them to work in PCRE2, you need to pass PCRE2_SUBSTITUTE_EXTENDED to pcre2_substitute.
In PCRE2:
${1:+matched:unmatched} where 1 is a number between 1 and 99 referencing a numbered capturing group. If your regex contains named capturing groups then you can reference them in a conditional by their name: ${name:+matched:unmatched}.
If you want a literal colon in the matched part, then you need to escape it with a backslash. If you want a literal closing curly brace anywhere in the conditional, then you need to escape that with a backslash too. Plus signs have no special meaning beyond the :+ that starts the conditional, so they don't need to be escaped.
Also, see The Boost-Specific Format Sequences:
When specifying the format_all flag to regex_replace(), the escape sequences recognized are the same as those above for format_perl. In addition, conditional expressions of the following form are recognized:
?Ntrue-expression:false-expression
where N is a decimal digit representing a sub-match. If the corresponding sub-match participated in the full match, then the substitution is true-expression. Otherwise, it is false-expression. In this mode, you can use parens () for grouping. If you want a literal paren, you must escape it as \(.
In Boost replacement patterns, literal ( and ) must be escaped.
The syntax for JGsoft V2 replacement string conditionals is the same as that in the C++ Boost library.
So, your regex can be contracted to ( +)[[(](?:(dot)|(at))[])]( +):
( +) - Group 1: one or more spaces
[[(] - a [ or (
(?:(dot)|(at)) - Either (Group 2) a dot substring or (Group 3) an at substring
[])] - a ) or ]
( +) - Group 4: one or more spaces
And replace with $1(?{3}.:#)$4:
$1 - Group 1 value,
(?{3}.:#) - if Group 3 matched, replace with ., else with #
$4 - Group 4 value.
This is available in Notepad++:
If you are using Java, try replaceAll method from String class.
And finally you need to normalize it with white spaces:
- Pure Java - String after = before.trim().replaceAll("\\s+", " ");
- Pure Java - String after = before.replaceAll("\\s{2,}", " ").trim();
- Apache commons lang3 - String after = StringUtils.normalizeSpace(String str);
- ...
C# Regex Match whole word, with special characters
I have searched through some questions but couldn't find the exact answer i am looking for.
I have a requirement to search through large strings of text looking for keywords matches. I was using IndexOf, however, i require to find whole word matches e.g. if i search for Java, but the text contains JavaScript, it shouldn't match. This works fine using \b{pattern}\b, but if i search for something like C#, then it doesn't work.
Below is a few examples of text strings that i am searching through:
languages include Java,JavaScript,MySql,C#
languages include Java/JavaScript/MySql/C#
languages include Java, JavaScript, MySql, C#
Obviously the issue is with the special character '#'; so this also doesn't work when searching for C++.
Escape the pattern using Regex.Escape and replace the context-dependent \b word boundaries with (?<!\w) / (?!\w) lookarounds:
var rx = $#"(?<!\w){Regex.Escape(pattern)}(?!\w)";
The (?<!\w) is a negative lookbehind that fails the match if there is a start of string or a non-word char immediately before the current location, and (?!\w) is a negative looahead that fails the match if there is an end of string or a non-word char immediately after the current location.
Yeah, this is because there isn't a word boundary (a \b) after the #, because # isn't a "word" character. You could use a regular expression like the following, which searches for a character that isn't a part of a language name [^a-zA-Z+#] after the language:
\b{pattern}[^a-zA-Z+#]
Or, if you believe you can list all of the possible characters that aren't part of a language name (for example, whitespace, ,, ., and ;):
[\s,.;]{pattern}[\s,.;]
Alternately, if it is possible that a language name is at the very end of a string (depending on what you're getting the data from), you might need to also match the end of the string $ in addition to the separators, or similarly, the beginning of the string ^.
[\s,.;]{pattern}(?:[\s,.;]|$)
Why \b does not match word using .net regex
To review regular expresions I read this tutorial. Anyways that tutorial mentions that \b matches a word boundary (between \w and \W characters). That tutorial also gives a link where you can install expresso (program that helps when creating regular expressions). So I have created my regular expressions in expresso and I do inded get a match. Now when I copy the same regex to visual studio I do not get a match. Take a look: Why am I not getting a match? in the immediate window I am showing the content of variable output. In expresso I do get a match and in visual studio I don't. why?
The C# language and .NET Regular Expressions both have their own distinct set of backslash-escape sequences, but the C# compiler is intercepting the "\b" in your string and converting it into an ASCII backspace character so the RegEx class never sees it. You need to make your string verbatim (prefix with an at-symbol) or double-escape the 'b' so the backslash is passed to RegEx like so: #"\bCOMPILATION UNIT"; Or "\\bCOMPILATION UNIT" I'll say the .NET RegEx documentation does not make this clear. It took me a while to figure this out at first too. Fun-fact: The \r and \n characters (carriage-return and line-break respectively) and some others are recognized by both RegEx and the C# language, so the end-result is the same, even if the compiled string is different.
You should use #"\bCOMPILATION UNIT". This is a verbatim literal. When you do "\b" instead, it parses \b into a special character. You can also do "\\b", whose double backslash is parsed into a real backslash, but it's generally easier to just use verbatims when dealing with regex.