Is it possible to debug a struct/class initialization member by member? - c#

Initializing a class like this:
var x = new Item()
{
ID = (int)...,
Name = (string)...,
..
};
I am getting an InvalidCastException on one of the assignments. There are quite a lot of them and the exception occurs on the whole expression even if I run the debugger line-by-line. The exception doesn't give any clue either what it's trying to cast to what.
Is there a way to debug each assignment individually? I've seen the debugger separately stops 3 times on expressions like foreach(x in y) so it seems a little strange it isn't doing that here, and detracts from the attraction of using this handy initialization syntax. Maybe there is a more fine-grained debug step I can use?

Your question is "Is it possible to debug a struct/class initialization member by member?".
So, up front, I'm not directly answering that question as worded because when I carefully read the body of your post it sounds like the essential question is how to identify the 'smoking line' root cause of this InvalidCastException right when it happens.
What I've found in similar situations is that if Visual Studio can be made to break at the moment the InvalidCastException occurs i.e. on that specific line then the Call Stack and local variables are much more immediate and useful.
Unfortunately, 'break when thrown' is suppressed by Visual Studio default settings for many exception types. But it's very easy to turn on 'break when thrown' for ALL exceptions. Just change this default setting in the Exceptions window in Visual Studio from this:
to this:
This doesn't "always" help but it's a good start. It's so easy why not try that first to see if rapid resolution is possible. Hope this turns out to be useful in your case.

Not sure if this is an option in VS 2017, I only have 2019 at hand. In your settings under Options -> Debugging -> General, uncheck Step over properties and operators. Then set a break point at your initializer and step through it with F11 (Step-Into). You will hit each property setter until the exception is thrown.

Please excuse me if I am missing something (will delete if thats the case) but using an invalid cast like this:
struct Item
{
public int ID { get; set; }
public Derived Derived { get; set; }
}
public class Base
{
public string Name { get; set; }
}
public class Derived : Base
{
public string AdditionalProperty { get; set; }
}
var baseClass = new Base()
{
Name = "foo",
};
try
{
var x = new Item()
{
ID = (int)20,
Derived = (Derived)baseClass,
};
}
catch(Exception e)
{
Console.WriteLine(e.Message);
}
neatly catches the error like this
Unable to cast object of type 'Base' to type 'Derived'.
in vs2017
However this breaks on the first error, we might wanna initalize an object this way and log all cast errors withouth exiting the initialisation. We can do this by implementing our own casting for this sample:
public static T TryCast<T>(Object _object)
{
try
{
return (T)_object;
}
catch (Exception e)
{
Console.WriteLine($"Cant cast object of type {_object.GetType().ToString()} to object of type {typeof(T)}");
}
return default(T);
}
public static T TryCast<T>(IConvertible _object)
{
try
{
return (T)Convert.ChangeType(_object, typeof(T));
}
catch (Exception e)
{
Console.WriteLine($"Cant convert object of type {_object.ToString()} to object of type {typeof(T)}");
}
return default(T);
}
New types for demonstrating purposes
struct Item
{
public int ID { get; set; }
public double FooDouble { get; set; }
public Base Base { get; set; }
public Derived Derived { get; set; }
public string Bar { get; set; }
}
public class Base
{
public string Name { get; set; }
}
public class Derived : Base
{
public string AdditionalProperty { get; set; }
}
We can then initalize our object like this:
var derived = new Derived()
{
Name = "DerivedFoo",
AdditionalProperty = "Bar"
};
var _base = new Base()
{
Name = "BaseFoo"
};
var x = new Item()
{
ID = Utils.TryCast<int>("please no"),
FooDouble = Utils.TryCast<double>(2),
Base = Utils.TryCast<Base>(derived),
Derived = Utils.TryCast<Derived>(_base),
Bar = "Foo"
};
And we neatly log any errors that might occur when casting:

Related

Auto-property initialization [duplicate]

How do you give a C# auto-property an initial value?
I either use the constructor, or revert to the old syntax.
Using the Constructor:
class Person
{
public Person()
{
Name = "Initial Name";
}
public string Name { get; set; }
}
Using normal property syntax (with an initial value)
private string name = "Initial Name";
public string Name
{
get
{
return name;
}
set
{
name = value;
}
}
Is there a better way?
In C# 5 and earlier, to give auto implemented properties an initial value, you have to do it in a constructor.
Since C# 6.0, you can specify initial value in-line. The syntax is:
public int X { get; set; } = x; // C# 6 or higher
DefaultValueAttribute is intended to be used by the VS designer (or any other consumer) to specify a default value, not an initial value. (Even if in designed object, initial value is the default value).
At compile time DefaultValueAttribute will not impact the generated IL and it will not be read to initialize the property to that value (see DefaultValue attribute is not working with my Auto Property).
Example of attributes that impact the IL are ThreadStaticAttribute, CallerMemberNameAttribute, ...
Edited on 1/2/15
C# 6 :
With C# 6 you can initialize auto-properties directly (finally!), there are now other answers that describe that.
C# 5 and below:
Though the intended use of the attribute is not to actually set the values of the properties, you can use reflection to always set them anyway...
public class DefaultValuesTest
{
public DefaultValuesTest()
{
foreach (PropertyDescriptor property in TypeDescriptor.GetProperties(this))
{
DefaultValueAttribute myAttribute = (DefaultValueAttribute)property.Attributes[typeof(DefaultValueAttribute)];
if (myAttribute != null)
{
property.SetValue(this, myAttribute.Value);
}
}
}
public void DoTest()
{
var db = DefaultValueBool;
var ds = DefaultValueString;
var di = DefaultValueInt;
}
[System.ComponentModel.DefaultValue(true)]
public bool DefaultValueBool { get; set; }
[System.ComponentModel.DefaultValue("Good")]
public string DefaultValueString { get; set; }
[System.ComponentModel.DefaultValue(27)]
public int DefaultValueInt { get; set; }
}
When you inline an initial value for a variable it will be done implicitly in the constructor anyway.
I would argue that this syntax was best practice in C# up to 5:
class Person
{
public Person()
{
//do anything before variable assignment
//assign initial values
Name = "Default Name";
//do anything after variable assignment
}
public string Name { get; set; }
}
As this gives you clear control of the order values are assigned.
As of C#6 there is a new way:
public string Name { get; set; } = "Default Name";
Sometimes I use this, if I don't want it to be actually set and persisted in my db:
class Person
{
private string _name;
public string Name
{
get
{
return string.IsNullOrEmpty(_name) ? "Default Name" : _name;
}
set { _name = value; }
}
}
Obviously if it's not a string then I might make the object nullable ( double?, int? ) and check if it's null, return a default, or return the value it's set to.
Then I can make a check in my repository to see if it's my default and not persist, or make a backdoor check in to see the true status of the backing value, before saving.
In C# 6.0 this is a breeze!
You can do it in the Class declaration itself, in the property declaration statements.
public class Coordinate
{
public int X { get; set; } = 34; // get or set auto-property with initializer
public int Y { get; } = 89; // read-only auto-property with initializer
public int Z { get; } // read-only auto-property with no initializer
// so it has to be initialized from constructor
public Coordinate() // .ctor()
{
Z = 42;
}
}
Starting with C# 6.0, We can assign default value to auto-implemented properties.
public string Name { get; set; } = "Some Name";
We can also create read-only auto implemented property like:
public string Name { get; } = "Some Name";
See: C# 6: First reactions , Initializers for automatically implemented properties - By Jon Skeet
In Version of C# (6.0) & greater, you can do :
For Readonly properties
public int ReadOnlyProp => 2;
For both Writable & Readable properties
public string PropTest { get; set; } = "test";
In current Version of C# (7.0), you can do : (The snippet rather displays how you can use expression bodied get/set accessors to make is more compact when using with backing fields)
private string label = "Default Value";
// Expression-bodied get / set accessors.
public string Label
{
get => label;
set => this.label = value;
}
In C# 9.0 was added support of init keyword - very useful and extremly sophisticated way for declaration read-only auto-properties:
Declare:
class Person
{
public string Name { get; init; } = "Anonymous user";
}
~Enjoy~ Use:
// 1. Person with default name
var anonymous = new Person();
Console.WriteLine($"Hello, {anonymous.Name}!");
// > Hello, Anonymous user!
// 2. Person with assigned value
var me = new Person { Name = "#codez0mb1e"};
Console.WriteLine($"Hello, {me.Name}!");
// > Hello, #codez0mb1e!
// 3. Attempt to re-assignment Name
me.Name = "My fake";
// > Compilation error: Init-only property can only be assigned in an object initializer
In addition to the answer already accepted, for the scenario when you want to define a default property as a function of other properties you can use expression body notation on C#6.0 (and higher) for even more elegant and concise constructs like:
public class Person{
public string FullName => $"{First} {Last}"; // expression body notation
public string First { get; set; } = "First";
public string Last { get; set; } = "Last";
}
You can use the above in the following fashion
var p = new Person();
p.FullName; // First Last
p.First = "Jon";
p.Last = "Snow";
p.FullName; // Jon Snow
In order to be able to use the above "=>" notation, the property must be read only, and you do not use the get accessor keyword.
Details on MSDN
In C# 6 and above you can simply use the syntax:
public object Foo { get; set; } = bar;
Note that to have a readonly property simply omit the set, as so:
public object Foo { get; } = bar;
You can also assign readonly auto-properties from the constructor.
Prior to this I responded as below.
I'd avoid adding a default to the constructor; leave that for dynamic assignments and avoid having two points at which the variable is assigned (i.e. the type default and in the constructor). Typically I'd simply write a normal property in such cases.
One other option is to do what ASP.Net does and define defaults via an attribute:
http://msdn.microsoft.com/en-us/library/system.componentmodel.defaultvalueattribute.aspx
My solution is to use a custom attribute that provides default value property initialization by constant or using property type initializer.
[AttributeUsage(AttributeTargets.Property, AllowMultiple = false, Inherited = true)]
public class InstanceAttribute : Attribute
{
public bool IsConstructorCall { get; private set; }
public object[] Values { get; private set; }
public InstanceAttribute() : this(true) { }
public InstanceAttribute(object value) : this(false, value) { }
public InstanceAttribute(bool isConstructorCall, params object[] values)
{
IsConstructorCall = isConstructorCall;
Values = values ?? new object[0];
}
}
To use this attribute it's necessary to inherit a class from special base class-initializer or use a static helper method:
public abstract class DefaultValueInitializer
{
protected DefaultValueInitializer()
{
InitializeDefaultValues(this);
}
public static void InitializeDefaultValues(object obj)
{
var props = from prop in obj.GetType().GetProperties()
let attrs = prop.GetCustomAttributes(typeof(InstanceAttribute), false)
where attrs.Any()
select new { Property = prop, Attr = ((InstanceAttribute)attrs.First()) };
foreach (var pair in props)
{
object value = !pair.Attr.IsConstructorCall && pair.Attr.Values.Length > 0
? pair.Attr.Values[0]
: Activator.CreateInstance(pair.Property.PropertyType, pair.Attr.Values);
pair.Property.SetValue(obj, value, null);
}
}
}
Usage example:
public class Simple : DefaultValueInitializer
{
[Instance("StringValue")]
public string StringValue { get; set; }
[Instance]
public List<string> Items { get; set; }
[Instance(true, 3,4)]
public Point Point { get; set; }
}
public static void Main(string[] args)
{
var obj = new Simple
{
Items = {"Item1"}
};
Console.WriteLine(obj.Items[0]);
Console.WriteLine(obj.Point);
Console.WriteLine(obj.StringValue);
}
Output:
Item1
(X=3,Y=4)
StringValue
little complete sample:
using System.ComponentModel;
private bool bShowGroup ;
[Description("Show the group table"), Category("Sea"),DefaultValue(true)]
public bool ShowGroup
{
get { return bShowGroup; }
set { bShowGroup = value; }
}
You can simple put like this
public sealed class Employee
{
public int Id { get; set; } = 101;
}
In the constructor. The constructor's purpose is to initialized it's data members.
private string name;
public string Name
{
get
{
if(name == null)
{
name = "Default Name";
}
return name;
}
set
{
name = value;
}
}
Have you tried using the DefaultValueAttribute or ShouldSerialize and Reset methods in conjunction with the constructor? I feel like one of these two methods is necessary if you're making a class that might show up on the designer surface or in a property grid.
Use the constructor because "When the constructor is finished, Construction should be finished". properties are like states your classes hold, if you had to initialize a default state, you would do that in your constructor.
To clarify, yes, you need to set default values in the constructor for class derived objects. You will need to ensure the constructor exists with the proper access modifier for construction where used. If the object is not instantiated, e.g. it has no constructor (e.g. static methods) then the default value can be set by the field. The reasoning here is that the object itself will be created only once and you do not instantiate it.
#Darren Kopp - good answer, clean, and correct. And to reiterate, you CAN write constructors for Abstract methods. You just need to access them from the base class when writing the constructor:
Constructor at Base Class:
public BaseClassAbstract()
{
this.PropertyName = "Default Name";
}
Constructor at Derived / Concrete / Sub-Class:
public SubClass() : base() { }
The point here is that the instance variable drawn from the base class may bury your base field name. Setting the current instantiated object value using "this." will allow you to correctly form your object with respect to the current instance and required permission levels (access modifiers) where you are instantiating it.
public Class ClassName{
public int PropName{get;set;}
public ClassName{
PropName=0; //Default Value
}
}
This is old now, and my position has changed. I'm leaving the original answer for posterity only.
Personally, I don't see the point of making it a property at all if you're not going to do anything at all beyond the auto-property. Just leave it as a field. The encapsulation benefit for these item are just red herrings, because there's nothing behind them to encapsulate. If you ever need to change the underlying implementation you're still free to refactor them as properties without breaking any dependent code.
Hmm... maybe this will be the subject of it's own question later
class Person
{
/// Gets/sets a value indicating whether auto
/// save of review layer is enabled or not
[System.ComponentModel.DefaultValue(true)]
public bool AutoSaveReviewLayer { get; set; }
}
I know this is an old question, but it came up when I was looking for how to have a default value that gets inherited with the option to override, I came up with
//base class
public class Car
{
public virtual string FuelUnits
{
get { return "gasoline in gallons"; }
protected set { }
}
}
//derived
public class Tesla : Car
{
public override string FuelUnits => "ampere hour";
}
I think this would do it for ya givng SomeFlag a default of false.
private bool _SomeFlagSet = false;
public bool SomeFlag
{
get
{
if (!_SomeFlagSet)
SomeFlag = false;
return SomeFlag;
}
set
{
if (!_SomeFlagSet)
_SomeFlagSet = true;
SomeFlag = value;
}
}

protobuf-net: Handling nulls in IEnumerable? Via what attributes/settings?

Some sample code below. The interesting/problem case is the Data property in
Mad. This code blows up (null value in the enumerable). Also, it works if i don't use the static attributes but instead the runtime type model, where i put in member.SupportNull = true for the fields (which is the behaviour i want), so what am i missing in the attributes / settings? Google search seems to indicate this is an open issue with probuf-net? That the same functionality is not available via attributes?
As as aside, if someone could suggest a way - i really love the runtime type model, i want to use that everywhere with a nice compiled model... but with it i lose the object versioning that protocol buffers solves! (via explicit tags). Is there any good way to maintain object version compatibility (simply adding fields) without doing all the static notation with fixed tags?
Basically the key thing with the runtime model is the assignment of tag indices and i can't think of a way of handling versions without explicitly specifying the tag indices via attributes...
[ProtoContract]
[ProtoInclude(1, typeof(ing))]
public class Eff
{
[ProtoMember(2)]
public string gg { get; set; }
}
[ProtoContract]
public class ing : Eff
{
[ProtoMember(1)]
public int zz { get; set; }
}
[ProtoContract]
public class Mad
{
[ProtoMember(1)]
public string Name { get; set; }
[ProtoMember(2)]
public IEnumerable<ing> Data { get; set; }
[ProtoMember(3)]
public ing Single { get; set; }
}
private static void Main(string[] args)
{
var obj = new Mad
{
Name = "test"
,Data = new[] { new ing {gg = "ooga", zz = -101},null,new ing()}
,Single = new ing {gg = "abc", zz = -999}
};
var m = new MemoryStream();
Serializer.Serialize(m, obj);
m.Seek(0, SeekOrigin.Begin);
var copy = Serializer.Deserialize<Mad>(m);
}
Short answer, it seems unavailable via attributes.
Workaround i'm doing for now - for every single type of interest(including the whole inheritance hierarchy) - add it to the type model yourself (with default handling so that it processes attributes), then call .GetFields() and set .SupportNull = true for each field (or only the relevant one)

How to handle nameof(this) to report class name

I'd like to use the following C#6 code
var joe = new Self();
Console.WriteLine(joe);
... and get the following output:
joe
The following attempt
class Self {
public string Name { get; set; } = nameof(this);
public override string ToString() {
return Name;
}
}
fails as nameof cannot be applied to this. Is it there a workaround for this problem?
EDIT. The scenario I'm working with assures that no two references point to the same Self object.
No, nameof is designed to refer to the compile-time name of the member you're referring to. If you want an object to have a Name property as part of its state, that is independent of how you get to the Name property - as Frédéric Hamidi says, there could be multiple variables (or none) referring to the same object. Basically you need to differentiate between an object and a variable which happens to refer to that object.
However, if you have a constructor to specify the name, you could then use a couple of tricks to make it easier to get the right name:
class Self
{
public string Name { get; }
public Self([CallerMemberName] string name = null)
{
this.Name = name;
}
}
Then:
class Foo
{
private Self me = new Self(); // Equivalent to new Self("me")
public void SomeMethod()
{
// Can't use the default here, as it would be "SomeMethod".
// But we can use nameof...
var joe = new Self(nameof(joe));
}
}
Maybe you can use the following method:
class Self
{
public override string ToString()
{
return this.GetType().Name;
}
}
You can simply use nameof on the variable itself:
Console.WriteLine(nameof(joe));
Here's a working example using the current Roslyn version
The idea for nameof is to make things type safe for specifying program elements during runtime but with compile time type safety checking.
One should atomize what one wants to display. For example in my error messages I include the pertinent information of the class name and the method as such and its checked, so if I change any of the names they are caught as a compile time error:
class Operation
{
public void Execute()
{
try { ... }
catch (Exception ex)
{
Console.Writeline($"{nameof(Operation)}.{nameof(Execute)} has encountered exception:{Environment.NewLine}{Environment.NewLine}{ex.Message}" );
}
}
}
Output
Operation.Excecute has exception:
...
With that said you should override ToString() and report the class name as such
public override string ToString() { return nameof(Self); }
I usually create an internal constant for it when dealing with long class names:
private const string SomeConst = nameof(Self);
Then you can use that in your code:
Console.WriteLine(SomeConst);

Writing out properties specific to a Derived Class

I need to determine which object my code is working with at a certain point and write out only the properties specific to that class. I cannot figure out how to do it. I was told I can do it, but I cannot figure it out. Can someone please show me how to determine which object I am working with and write the properties specific to that class only?
I've looked at other questions asked, but am not smart enough to make it fit my example.
Below, I've re-created an example of the code I am working with. I can see all the code, but I am allowed to only work in one method (for this example called "MethodIAmWorkingIn"). Only modifications I am allowed to make are in that method.
public class Program
{
static void Main(string[] args)
{
TestDetailsAndResultsContainer container = new TestDetailsAndResultsContainer();
DerivedClass1 derivedClass1 = new DerivedClass1();
derivedClass1.DerivedClass1Prop1 = "DerivedClass1Prop1";
derivedClass1.DerivedClass1Prop2 = "DerivedClass1Prop2";
DerivedClass2 derivedClass2 = new DerivedClass2();
derivedClass2.DerivedClass2Prop1 = "DerivedClass2Prop1";
derivedClass2.DerivedClass2Prop2 = "DerivedClass2Prop2";
container.TestDetails.Add(derivedClass1);
container.TestDetails.Add(derivedClass2);
TestResult testResult = new TestResult();
testResult.TestResultProp1 = "TestResultProp1";
testResult.TestResultProp2 = "TestResultProp2";
container.Data.Add(testResult);
Program p = new Program();
p.MethodIAmWorkingIn(container);
}
private void MethodIAmWorkingIn(TestDetailsAndResultsContainer container)
{
// I need to see if the container variable holds a DerivedClass1 or DerivedClass2 object.
foreach (var result in container.TestDetails)
{
var classINeedToDetermine = container.TestDetails.FirstOrDefault(m => m.TestDetailsProp1 == result.TestDetailsProp1);
if (classINeedToDetermine is DerivedClass1)
{
classINeedToDetermine = result as DerivedClass1;
}
else if (classINeedToDetermine is DerivedClass2)
{
classINeedToDetermine = result as DerivedClass2;
}
// Now I need to use the classINeedToDetermine object and write its specific properties.
// ???????????????????? I am stuck at this point ??????????????????
// I need to write one or the other below. Can this be done?
// If it is DerivedClass1, I need to write out those properties only.
Console.WriteLine(classINeedToDetermine.DerivedClass1Prop1);
Console.WriteLine(classINeedToDetermine.DerivedClass1Prop2);
// OR
// If it is DerivedClass2, I need to write out those properties only.
Console.WriteLine(classINeedToDetermine.DerivedClass2Prop1);
Console.WriteLine(classINeedToDetermine.DerivedClass2Prop2);
}
}
}
public class TestDetailsAndResultsContainer
{
public TestDetailsAndResultsContainer()
{
this.Data = new List<TestResult>();
this.TestDetails = new List<TestDetails>();
}
public List<TestDetails> TestDetails { get; set; }
public List<TestResult> Data { get; set; }
}
public abstract class TestDetails
{
public string TestDetailsProp1 { get; set; }
public string TestDetailsProp2 { get; set; }
}
public class TestResult
{
public string TestResultProp1 { get; set; }
public string TestResultProp2 { get; set; }
}
public class DerivedClass1 : TestDetails
{
public string DerivedClass1Prop1 { get; set; }
public string DerivedClass1Prop2 { get; set; }
}
public class DerivedClass2 : TestDetails
{
public string DerivedClass2Prop1 { get; set; }
public string DerivedClass2Prop2 { get; set; }
}
The as keyword does not do what you think it does.
Your classINeedToDetermine is a variable of type TestDetails. You can assign a subclass instance to it, but you still cannot access that subclasses specific properties via that variable.
You just need some scope:
if (classINeedToDetermine is DerivedClass1)
{
var derived1 = (DerivedClass1)result;
Console.WriteLine(derived1.DerivedClass1Prop1);
// etc
}
else if (classINeedToDetermine is DerivedClass2)
{
var derived2 = (DerivedClass2)result;
Console.WriteLine(derived2.DerivedClass2Prop1);
// etc
}
This kind of thing is not fun to maintain though.
Another way of doing it would be to use polymorphism: Your TestDetails class could define an abstract method called PrintProperties, and all your subclasses could implement it.
Then you just have to call PrintProperties on every object, without worrying about which subclass they are.
I'm not completely sure on what objects mean what here, but it should be something like this:
foreach(var v in result.GetType().GetProperties())
{
if(v.DeclaringType == result.GetType())
{
Console.WriteLine(v.GetValue(result));
}
}
Again, I wasn't totally clear on your usage of classINeedToDetermine versus result, but you can change those as you see so fit. I chose result as my example since classINeedToDetermine was null by that part of your code.
And by the way, this section of your code is redundant. It should be removed for clarity and efficiency.
if (classINeedToDetermine is DerivedClass1)
{
classINeedToDetermine = result as DerivedClass1;
}
else if (classINeedToDetermine is DerivedClass2)
{
classINeedToDetermine = result as DerivedClass2;
}
Edit:
On the other hand, if performance is more important to you than being scalable (read: if you know or have control over all the classes you'll be dealing with), you could use this is section to do something less, I hate to use this word for this, "generic."
if (classINeedToDetermine is DerivedClass1)
{
var typed = (DerivedClass1)result;
Console.WriteLine(typed.DerivedClass1Prop1);
Console.WriteLine(typed.DerivedClass1Prop2);
}
else if (classINeedToDetermine is DerivedClass2)
{
var typed = (DerivedClass2)result;
Console.WriteLine(typed.DerivedClass2Prop1);
Console.WriteLine(typed.DerivedClass2Prop2);
}
You can use Type.GetProperties to get all Properties for your class. Then you need to get the MethodInfo for the Get method via GetMethod.
Once you have the MethodInfo you can call Invoke, passing in your Derived Class. You can write then write the result to the Console.

How do I get the value of the used parameters in a constructor (C#)

I've got a question about getting the values from a constructor in a generic way.
namespace myTestNamespace
{
Public Class myTestClass()
{
Public myTestClass(int myInt,bool myBool, double myDouble)
{
//do / set something
}
Public myTestClass(int myInt,bool myBool)
{
//do / set something
}
}
}
Using (what you need);
Using myTestNamespace;
namespace MyIWannaLookForTheParametersName
{
Public Class MyLookUpClass()
{
Public void DoSomething()
{
List<object> myList = new List<object>();
myTestClass _ myTestClass = new myTestClass(1,true,2.5);
object mySaveObject = myTestClass;
mylist.Add(mySaveObject);
//how do I get the info from the right constructor
//(I used the one with 3 parameters_
//what was the value of myInt, myBool and myDouble
//how can I make it generic enough, so it will work with other classes with
// different constructors ass well?
}
}
}
Questions about intent aside, there's no generic way for you to do this. Information about what methods have been called and what values were supplied is not saved automatically. You are, of course, perfectly able to keep track of these things yourself, but you would have to write each class to do this explicitly.
Doing this in a generic way is asking for trouble. What if I did this?
public class Foo
{
public string Name { get; set; }
}
public class Bar
{
public Bar(Foo foo)
{
// ...
}
}
Then suppose I called it in this way:
Foo f = new Foo();
f.Name = "Jim";
Bar b = new Bar(f);
f.Name = "Bob";
Now, if such a generic system existed, what would be the value of foo for the Bar constructor? Either it reports "Bob" (which is what the value for Name is on the instance of Foo that was supplied), or it reports "Jim", meaning that the runtime or library would essentially have to be smart enough to make a deep copy of the object so that the state is not changed.
The bottom line is this: if you need access to the parameters passed to the constructor (or any other function), you'll have to store them somewhere explicitly.
You can't get thevalues from the constructor. You need to first place them in a property or a field within your class. The example you provided is a poor use of generics. You wouldbe better off placing the constructor values into properties and creating an interface with those properties.
I got what I needed with this method:
private static ParameterSettings[] GetListOfParametersFromIndicator(object indicatorClass, int loopId, myEnums.ParaOrResult paraOrResult)
{
return (from prop in indicatorClass.GetType().GetProperties()
let loopID = loopId
let Indicator = indicatorClass.GetType().Name
let value = (object)prop.GetValue(indicatorClass, null)
where prop.Name.Contains("_Constr_")
select new ParameterSettings { ParaOrResult=paraOrResult, LoopID= loopId, Indicator= Indicator, ParaName= prop.Name, Value= value }).ToArray();
}
where ParameterSettings is:
public struct ParameterSettings
{
public myEnums.ParaOrResult ParaOrResult { get; set; }
public int LoopID { get; set; }
public string Indicator { get; set; }
public string ParaName { get; set; }
public object Value { get; set; }
}
This info is ok for me. Thanks for the replies.
Regards,
Matthijs

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