Develop Reference

Insert a string in a particular position into an other string

I am work on some innerxml of an XML document.
I have to concat several parts.
I have this:
<TRANFSERT><GOOD></GOOD></TRANSFERT>
I want to insert another part, <GOOD></GOOD>, before </TRANSFERT>.
I tried this:
int pos = xmldoc.indexOf("</GOOD>");
StringBuilder sb = new StringBuilder(xmlFinal);
sb.Append(xmlModifiee,pos,xmlModifiee.length);
xmlFinal = sb.ToString();
But it doesn't work.
How can I add a small part of XML in other XML?

You shouldn't interact with XML like with ordinary string.
Use provided System.Xml.XmlDocument or System.Xml.Linq.XDocument classes:
Ordinary XmlDocument single node selection and appending new element to it:
XmlDocument xmlDocument = new XmlDocument();
xmlDocument.Load("YourFile.xml");
XmlNode goodNode = xmlDocument.SelectSingleNode("TRANSFERT/GOOD");
XmlNode nodeToInsert = xmlDocument.CreateElement("INSERTEDNODE");
goodNode.AppendChild(nodeToInsert);
Ordinary XmlDocument iterating by nodes to find necessary (be aware for many-childed nodes) and add new child node to it:
XmlDocument xmlDocument = new XmlDocument();
xmlDocument.Load("YourFile.xml");
foreach (XmlNode rootNode in xmlDocument.ChildNodes)
{
if (rootNode.Name == "TRANSFERT")
{
foreach (XmlNode childNode in rootNode.ChildNodes)
{
if (childNode.Name == "GOOD")
{
XmlNode nodeToInsert = xmlDocument.CreateElement("INSERTEDNODE");
childNode.AppendChild(nodeToInsert);
}
}
}
}
Linq to XML variant:
XDocument xDoc = XDocument.Load("YourFIle.xml");
XElement rootElement = xDoc.Element("TRANSFERT");
XElement goodElement = rootElement.Element("GOOD");
goodElement.Add(new XElement("INSERTEDNODE"));
Simplified Linq to XML variant:
XDocument.Load("YourFIle.xml").Element("TRANSFERT").Element("GOOD").Add(new XElement("INSERTEDNODE"));
EDITED: answering the question, example was rewrited from changing InnerText values to Append/Add new child element to GOOD node.

StringBuilder.Append can only be used to add something to the end of the string. To add something inside the string, use StringBuilder.Insert like this:
sb.Insert(pos, xmlModifiee);

Select single node

From the following xml:
<response>
<content>
<Result xmlns="http://www.test.com/nav/webservices/types">
<Name>Test</Name>
</Result>
</content>
<status>ok</status>
</response>
I am trying to get the value of the Name element the following way but that does not work:
private static void Main()
{
var response = new XmlDocument();
response.Load("Response.xml");
var namespaceManager = new XmlNamespaceManager(response.NameTable);
namespaceManager.AddNamespace("ns", "http://www.test.com/nav/webservices/types");
Console.WriteLine(response.SelectSingleNode("/response/content/Result/Name", namespaceManager).InnerXml);
}
How can I select the Name element?

Your code would have worked just fineif the Xml had defined the namespace with a "ns:" prefix.
But in this case, the namespace is given without any prefix, which sets the default namespace for everything in the Result tag to ".../webservice/types".
To reflect this, you need to modify the Xpath, and tell the XmlDocument that the nodes you are looking for under Resultare in the webservice/types namespace. So your query will look like this:
Console.WriteLine(response.SelectSingleNode(#"/response/content/ns:Result/ns:Name", namespaceManager).InnerXml);

For getting directly the text value of a node there is a text() function, if used in the query it would look like:
/response/content/Result/Name/text()

Try this:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.InnerXml = "<response><content><Result xmlns=\"http://www.test.com/nav/webservices/types\"><Name>Test</Name></Result></content><status>ok</status>";
string elementValue = String.Empty;
if (xmlDoc != null)
{
xNode = xmlDoc.SelectSingleNode("/Result");
xNodeList = xNode.ChildNodes;
foreach (XmlNode node in xNodeList)
{
elementValue = node.InnerText;
}
}

Selecting value from first xml child node

I have an XML file that contains multiple URLs for different image file sizes, and I'm trying to get a single url to load into a picture box. My issue is that the child nodes are named similarly, and the parent nodes are named similarly as well. For example, I want to pull the first medium image (ending in SL160_.jpg). See below for XML code
<Items>
<SmallImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL._SL75_.jpg</URL>
</SmallImage>
<MediumImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL._SL160_.jpg</URL>
</MediumImage>
<LargeImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL.jpg</URL>
</LargeImage>
<MediumImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL._SL162_.jpg</URL>
</MediumImage>
<LargeImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL.jpg</URL>
</LargeImage>
</Items>
I've tried using GetElementsByTag, as well as trying to call something like doc.SelectSingleNode("LargeImage").SelectSingleNode("URL").InnerText, and GetElementByID. All of these have given me an Object set to null reference exception.
What can I do to specify that I want the url from the first found MediumImage node?

Use LinqToXML，It is rather simple
string xml = #"<Items>
<SmallImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL._SL75_.jpg</URL>
</SmallImage>
<MediumImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL.01_SL160_.jpg</URL>
</MediumImage>
<LargeImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL.jpg</URL>
</LargeImage>
<MediumImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL.02_SL162_.jpg</URL>
</MediumImage>
<LargeImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL.jpg</URL>
</LargeImage>
</Items>";
XElement root = XElement.Parse(xml);
var ele = root.Elements("MediumImage").Where(e => e.Element("URL").Value.EndsWith("SL160_.jpg")).FirstOrDefault();
Console.WriteLine(ele);

In addition to Sky Fang's answer, I think the OP wants this:
var firstMedImg = root.Elements("MediumImage").First();
var imgUrl = firstMedImg.Element("URL").Value;

XmlDocument doc = new XmlDocument();
// PATH TO YOUR DOCUMENT
doc.Load("daco.xml");
// Select LIST ALL ELEMENTS SmallImage,MediumImage,LargeImage
XmlNodeList listOfAllImageElements = doc.SelectNodes("/Items/*");
foreach (XmlNode imageElement in listOfAllImageElements)
{
// Select URL ELEMENT
XmlNode urlElement= node.SelectSingleNode("URL");
System.Console.WriteLine(urlElement.InnerText);
}
Console.ReadLine();
If you want to select multiple url's
XmlDocument doc = new XmlDocument();
// PATH TO YOUR DOCUMENT
doc.Load("daco.xml");
// Select LIST ALL ELEMENTS SmallImage,MediumImage,LargeImage
XmlNodeList listOfAllImageElements = doc.SelectNodes("/Items/*");
foreach (XmlNode imageElement in listOfAllImageElements)
{
// Select URL's ELEMENTs
XmlNodeList listOfAllUrlElements = imageElement.SelectNodes("URL");
foreach (XmlNode urlElement in listOfAllUrlElements)
{
System.Console.WriteLine(urlElement.InnerText);
}
}
Console.ReadLine();
if you have specific namespace in your xml file
XmlDocument doc = new XmlDocument();
doc.Load("doc.xml");
XmlNamespaceManager man = new XmlNamespaceManager(doc.NameTable);
// reaplace http://schemas.microsoft.com/vs/2009/dgml with your namespace
man.AddNamespace("x", "http://schemas.microsoft.com/vs/2009/dgml");
// next you have to use x: in your path like this
XmlNodeList node = doc.SelectNodes("/x:Items/x:*, man);

Adding info to a xml file

I have a XML file which contains about 850 XML nodes. Like this:
<NameValueItem>
<Text>Test</Text>
<Code>Test</Code>
</NameValueItem>
........ 849 more
And I want to add a new Childnode inside each and every Node. So I end up like this:
<NameValueItem>
<Text>Test</Text>
<Code>Test</Code>
<Description>TestDescription</Description>
</NameValueItem>
........ 849 more
I've tried the following:
XmlDocument doc = new XmlDocument();
doc.Load(xmlPath);
XmlNodeList nodes = doc.GetElementsByTagName("NameValueItem");
Which gives me all of the nodes, but from here am stuck(guess I need to iterate over all of the nodes and append to each and every) Any examples?

You need something along the lines of this example below. On each of your nodes, you need to create a new element to add to it. I assume you will be getting different values for the InnerText property, but I just used your example.
foreach (var rootNode in nodes)
{
XmlElement element = doc.CreateElement("Description");
element.InnerText = "TestDescription";
root.AppendChild(element);
}

You should just be able to use a foreach loop over your XmlNodeList and insert the node into each XmlNode:
foreach(XmlNode node in nodes)
{
node.AppendChild(new XmlNode()
{
Name = "Description",
Value = [value to insert]
});
}
This can also be done with XDocument using LINQ to XML as such:
XDocument doc = XDocument.Load(xmlDoc);
var updated = doc.Elements("NameValueItem").Select(n => n.Add(new XElement() { Name = "Description", Value = [newvalue]}));
doc.ReplaceWith(updated);

If you don't want to parse XML using proper classes (i.e. XDocument), you can use Regex to find a place to insert your tag and insert it:
string s = #"<NameValueItem>
<Text>Test</Text>
<Code>Test</Code>
</NameValueItem>";
string newTag = "<Description>TestDescription</Description>";
string result = Regex.Replace(s, #"(?<=</Code>)", Environment.NewLine + newTag);
but the best solution is Linq2XML (it's much better, than simple XmlDocument, that is deprecated at now).
string s = #"<root>
<NameValueItem>
<Text>Test</Text>
<Code>Test</Code>
</NameValueItem>
<NameValueItem>
<Text>Test2</Text>
<Code>Test2</Code>
</NameValueItem>
</root>";
var doc = XDocument.Load(new StringReader(s));
var elms = doc.Descendants("NameValueItem");
foreach (var element in elms)
{
element.Add(new XElement("Description", "TestDescription"));
}
var text = new StringWriter();
doc.Save(text);
Console.WriteLine(text);

How put value in each xml node

I have generated xmldocument by this code with C#,
protected XDocument generateXML()
{
XDocument xdoc = new XDocument(
new XDeclaration("1.0", "utf-8", "yes"),
new XElement("Invoices",
new XElement("Invoice",
new XElement("InvoiceNumber", "s10838652")
.......
return xdoc;
}
and in another method I have:
public override void RunWintrackConnector()
{
XDocument xml = generateXML();
.....
Then I would like to put data in each XML node: (instead of s10838652 I would like to assign (string.Concat(bill.invoice, bill.num);) to the InvoiceNumber node.)
I have the right part but not sure how get access to each node of xml:
xmlnode(for example InvoiceNumber) = Win2.IntegrationXML.XMLMisc.DirtyData.getStringValue(string.Concat(bill.invoice, bill.num));

xml
.Elements("Invoices")
.Elements("Invoice")
.Elements("InvoiceNumber")
.First()
.Value = string.Concat(bill.invoice, bill.num);
edit - to go over all your invoices:
foreach(var invoice in xml.Elements("Invoices").Elements("Invoice"))
{
invoice.Element("InvoiceNumber").Value = "asdf";
}
If you are familiar with XPath, this is equivalent to selecting all invoices with "Invoices/Invoice".

You can use XElement or XDocument to write the values you need.
var valueToInsert = Win2.IntegrationXML.XMLMisc.DirtyData
.getStringValue(string.Concat(bill.invoice, bill.num));
XDocument xml = generateXML();
xml.Element("Invoices")
.Elements("Invoice").First() //this First is just an example
.Element("InvoiceNumber")
.Value = valueToInsert;
Element() Returns the first found child node, and Elements() gets a list of all child nodes with that node name. Find out your pattern of how nodes are nested and you should be all set.
As a side note, you can do the above with a XDocument variable, but I prefer to keep everything as XElement for the added Linq compatibility.