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How do you do a string split with 2 chars counts in C#?

I know how to do a string split if there's a letter, number, that I want to replace.
But how could I do a string.Split() by 2 char counts without replacing any existing letters, number, etc...?
Example:
string MAC = "00122345"
I want that string to output: 00:12:23:45

You could create a LINQ extension method to give you an IEnumerable<string> of parts:
public static class Extensions
{
public static IEnumerable<string> SplitNthParts(this string source, int partSize)
{
if (string.IsNullOrEmpty(source))
{
throw new ArgumentException("String cannot be null or empty.", nameof(source));
}
if (partSize < 1)
{
throw new ArgumentException("Part size has to be greater than zero.", nameof(partSize));
}
return Enumerable
.Range(0, (source.Length + partSize - 1) / partSize)
.Select(pos => source
.Substring(pos * partSize,
Math.Min(partSize, source.Length - pos * partSize)));
}
}
Usage:
var strings = new string[] {
"00122345",
"001223453"
};
foreach (var str in strings)
{
Console.WriteLine(string.Join(":", str.SplitNthParts(2)));
}
// 00:12:23:45
// 00:12:23:45:3
Explanation:
Use Enumerable.Range to get number of positions to slice string. In this case its the length of the string + chunk size - 1, since we need to get a big enough range to also fit leftover chunk sizes.
Enumerable.Select each position of slicing and get the startIndex using String.Substring using the position multiplied by 2 to move down the string every 2 characters. You will have to use Math.Min to calculate the smallest size leftover size if the string doesn't have enough characters to fit another chunk. You can calculate this by the length of the string - current position * chunk size.
String.Join the final result with ":".
You could also replace the LINQ query with yield here to increase performance for larger strings since all the substrings won't be stored in memory at once:
for (var pos = 0; pos < source.Length; pos += partSize)
{
yield return source.Substring(pos, Math.Min(partSize, source.Length - pos));
}

You can use something like this:
string newStr= System.Text.RegularExpressions.Regex.Replace(MAC, ".{2}", "$0:");
To trim the last colon, you can use something like this.
newStr.TrimEnd(':');
Microsoft Document

Try this way.
string MAC = "00122345";
MAC = System.Text.RegularExpressions.Regex.Replace(MAC,".{2}", "$0:");
MAC = MAC.Substring(0,MAC.Length-1);
Console.WriteLine(MAC);

A quite fast solution, 8-10x faster than the current accepted answer (regex solution) and 3-4x faster than the LINQ solution
public static string Format(this string s, string separator, int length)
{
StringBuilder sb = new StringBuilder();
for (int i = 0; i < s.Length; i += length)
{
sb.Append(s.Substring(i, Math.Min(s.Length - i, length)));
if (i < s.Length - length)
{
sb.Append(separator);
}
}
return sb.ToString();
}
Usage:
string result = "12345678".Format(":", 2);

Here is a one (1) line alternative using LINQ Enumerable.Aggregate.
string result = MAC.Aggregate("", (acc, c) => acc.Length % 3 == 0 ? acc += c : acc += c + ":").TrimEnd(':');

An easy to understand and simple solution.
This is a simple fast modified answer in which you can easily change the split char.
This answer also checks if the number is even or odd , to make the suitable string.Split().
input : 00122345
output : 00:12:23:45
input : 0012234
output : 00:12:23:4
//The List that keeps the pairs
List<string> MACList = new List<string>();
//Split the even number into pairs
for (int i = 1; i <= MAC.Length; i++)
{
if (i % 2 == 0)
{
MACList.Add(MAC.Substring(i - 2, 2));
}
}
//Make the preferable output
string output = "";
for (int j = 0; j < MACList.Count; j++)
{
output = output + MACList[j] + ":";
}
//Checks if the input string is even number or odd number
if (MAC.Length % 2 == 0)
{
output = output.Trim(output.Last());
}
else
{
output += MAC.Last();
}
//input : 00122345
//output : 00:12:23:45
//input : 0012234
//output : 00:12:23:4

C# Array Different indexes

Hi i want to search for character in a string array but i need to search Between 2 indices. For example between index 2 and 10. How can I do that?
foreach (var item in currentline[2 to 10])
{
if (item == ',' || item == ';')
{
c++;
break;
}
else
{
data += item;
c++;
}
}

As you can see, foreach enumerates over a collection or any IEnumerable.
As the comments say, you can use a for loop instead, and pick out the elements you want.
Alternatively, since you want to search for a character in a string, you can use IndexOf, using the start index and count overload to find where a character is.

As there is no use of the c++ in your code I will assume that it's a vestige of code.
You can simply addess your issue like this:
In the currentline
Take char from index 2 to 10
Till you find a char you don't want.
concatenate the resulting char array to a string.
Resulting Code:
var data = "##";//01234567891 -- index for the string below.
var currentline= "kj[abcabc;z]Selected data will be between: '[]';";
var exceptChar = ",;";
data += new string(
input.Skip(3)
.Take(8)
.TakeWhile(x=> !exceptChar.Contains(x))
.ToArray()
);

There is a string method called string.IndexOfAny() which will allow you to pass an array of characters to search for, a start index and a count. For your example, you would use it like so:
string currentLine = ",;abcde;,abc";
int index = currentLine.IndexOfAny(new[] {',', ';'}, 2, 10-2);
Console.WriteLine(index);
Note that the last parameter is the count of characters to search starting at the specified index, so if you want to start at index 2 and finish at index 10, the count will be finish-start, i.e. 10-2.

You can search for characters in strings and get their indexes with this LINQ solution:
string str = "How; are, you; Good ,bye";
char[] charArr = { ',', ';' };
int startIndex = 2;
int endIndex = 10;
var indexes = Enumerable.Range(startIndex, endIndex - startIndex + 1)
.Where(i=>charArr.Contains(str[i]))
.ToArray();
In this case we get Enumerable.Range(2, 9) which generates a sequence between 2 and 10 and the Where clause filters the indexes of the characters in str that are matching one of the characters inside charArr.

Thanks everey one finaly i fixed it by your guid thanks all
myarr = new mytable[50];
number_of_records = 0;
number_of_records = fulllines.Length;
for (int line = 1; line < fulllines.Length; line++)
{
int c = 0;
for (int i = 0; i < record_lenth; i++)
{
string data = "";
string currentline = fulllines[line];
string value = "";
for (int x = c; x < fulllines[line].Length; x++)
{
value += currentline[x];
}
foreach (var item in value)
{
if (item == ',' || item == ';')
{
c++;
break;
}
else
{
data += item;
c++;
}
}
}
}

Split string after certain character count

I need some help. I'm writing an error log using text file with exception details. With that I want my stack trace details to be written like the below and not in straight line to avoid the user from scrolling the scroll bar of the note pad or let's say on the 100th character the strings will be written to the next line. I don't know how to achieve that. Thanks in advance.
SAMPLE(THIS IS MY CURRENT OUTPUT ALL IN STRAIGHT LINE)
STACKTRACE:
at stacktraceabcdefghijklmnopqrstuvwxyztacktraceabcdefghijklmnopqrswxyztacktraceabcdefghijk
**MY DESIRED OUTPUT (the string will write to the next line after certain character count)
STACKTRACE:
at stacktraceabcdefghijklmno
pqrstuvwxyztacktraceabcdefgh
ijklmnopqrswxyztacktraceabcd
efghijk
MY CODE
builder.Append(String.Format("STACKTRACE:"));
builder.AppendLine();
builder.Append(logDetails.StackTrace);

Following example splits 10 characters per line, you can change as you like {N} where N can be any number.
var input = "stacktraceabcdefghijklmnopqrstuvwxyztacktraceabcdefghijklmnopqrswxyztacktraceabcdefghijk";
var regex = new Regex(#".{10}");
string result = regex.Replace(input, "$&" + Environment.NewLine);
Console.WriteLine(result);
Here is the Demo

you can use the following code:
string yourstring;
StringBuilder sb = new StringBuilder();
for(int i=0;i<yourstring.length;++i){
if(i%100==0){
sb.AppendLine();
}
sb.Append(yourstring[i]);
}

you may create a function for this
string splitat(string line, int charcount)
{
string toren = "";
if (charcount>=line.Length)
{
return line;
}
int totalchars = line.Length;
int loopcnt = totalchars / charcount;
int appended = 0;
for (int i = 0; i < loopcnt; i++)
{
toren += line.Substring(appended, charcount) + Environment.NewLine;
appended += charcount;
int left = totalchars - appended;
if (left>0)
{
if (left>charcount)
{
continue;
}
else
{
toren += line.Substring(appended, left) + Environment.NewLine;
}
}
}
return toren;
}

Best , Easiest and Generic Answer :). Just set the value of splitAt to the that number of character count after that u want it to break.
string originalString = "1111222233334444";
List<string> test = new List<string>();
int splitAt = 4; // change 4 with the size of strings you want.
for (int i = 0; i < originalString.Length; i = i + splitAt)
{
if (originalString.Length - i >= splitAt)
test.Add(originalString.Substring(i, splitAt));
else
test.Add(originalString.Substring(i,((originalString.Length - i))));
}

Add separator to string at every N characters?

I have a string which contains binary digits. How to separate string after each 8 digit?
Suppose the string is:
string x = "111111110000000011111111000000001111111100000000";
I want to add a separator like ,(comma) after each 8 character.
output should be :
"11111111,00000000,11111111,00000000,11111111,00000000,"
Then I want to send it to a list<> last 8 char 1st then the previous 8 chars(excepting ,) and so on.
How can I do this?

Regex.Replace(myString, ".{8}", "$0,");
If you want an array of eight-character strings, then the following is probably easier:
Regex.Split(myString, "(?<=^(.{8})+)");
which will split the string only at points where a multiple of eight characters precede it.

Try this:
var s = "111111110000000011111111000000001111111100000000";
var list = Enumerable
.Range(0, s.Length/8)
.Select(i => s.Substring(i*8, 8));
var res = string.Join(",", list);

There's another Regex approach:
var str = "111111110000000011111111000000001111111100000000";
# for .NET 4
var res = String.Join(",",Regex.Matches(str, #"\d{8}").Cast<Match>());
# for .NET 3.5
var res = String.Join(",", Regex.Matches(str, #"\d{8}")
.OfType<Match>()
.Select(m => m.Value).ToArray());

...or old school:
public static List<string> splitter(string in, out string csv)
{
if (in.length % 8 != 0) throw new ArgumentException("in");
var lst = new List<string>(in/8);
for (int i=0; i < in.length / 8; i++) lst.Add(in.Substring(i*8,8));
csv = string.Join(",", lst); //This we want in input order (I believe)
lst.Reverse(); //As we want list in reverse order (I believe)
return lst;
}

Ugly but less garbage:
private string InsertStrings(string s, int insertEvery, char insert)
{
char[] ins = s.ToCharArray();
int length = s.Length + (s.Length / insertEvery);
if (ins.Length % insertEvery == 0)
{
length--;
}
var outs = new char[length];
long di = 0;
long si = 0;
while (si < s.Length - insertEvery)
{
Array.Copy(ins, si, outs, di, insertEvery);
si += insertEvery;
di += insertEvery;
outs[di] = insert;
di ++;
}
Array.Copy(ins, si, outs, di, ins.Length - si);
return new string(outs);
}
String overload:
private string InsertStrings(string s, int insertEvery, string insert)
{
char[] ins = s.ToCharArray();
char[] inserts = insert.ToCharArray();
int insertLength = inserts.Length;
int length = s.Length + (s.Length / insertEvery) * insert.Length;
if (ins.Length % insertEvery == 0)
{
length -= insert.Length;
}
var outs = new char[length];
long di = 0;
long si = 0;
while (si < s.Length - insertEvery)
{
Array.Copy(ins, si, outs, di, insertEvery);
si += insertEvery;
di += insertEvery;
Array.Copy(inserts, 0, outs, di, insertLength);
di += insertLength;
}
Array.Copy(ins, si, outs, di, ins.Length - si);
return new string(outs);
}

If I understand your last requirement correctly (it's not clear to me if you need the intermediate comma-delimited string or not), you could do this:
var enumerable = "111111110000000011111111000000001111111100000000".Batch(8).Reverse();
By utilizing morelinq.

Here my two little cents too. An implementation using StringBuilder:
public static string AddChunkSeparator (string str, int chunk_len, char separator)
{
if (str == null || str.Length < chunk_len) {
return str;
}
StringBuilder builder = new StringBuilder();
for (var index = 0; index < str.Length; index += chunk_len) {
builder.Append(str, index, chunk_len);
builder.Append(separator);
}
return builder.ToString();
}
You can call it like this:
string data = "111111110000000011111111000000001111111100000000";
string output = AddChunkSeparator(data, 8, ',');

One way using LINQ:
string data = "111111110000000011111111000000001111111100000000";
const int separateOnLength = 8;
string separated = new string(
data.Select((x,i) => i > 0 && i % separateOnLength == 0 ? new [] { ',', x } : new [] { x })
.SelectMany(x => x)
.ToArray()
);

I did it using Pattern & Matcher as following way:
fun addAnyCharacter(input: String, insertion: String, interval: Int): String {
val pattern = Pattern.compile("(.{$interval})", Pattern.DOTALL)
val matcher = pattern.matcher(input)
return matcher.replaceAll("$1$insertion")
}
Where:
input indicates Input string. Check results section.
insertion indicates Insert string between those characters. For example comma (,), start(*), hash(#).
interval indicates at which interval you want to add insertion character.
input indicates Input string. Check results section. Check results section; here I've added insertion at every 4th character.
Results:
I/P: 1234XXXXXXXX5678 O/P: 1234 XXXX XXXX 5678
I/P: 1234567812345678 O/P: 1234 5678 1234 5678
I/P: ABCDEFGHIJKLMNOP O/P: ABCD EFGH IJKL MNOP
Hope this helps.

As of .Net 6, you can simply use the IEnumerable.Chunk method (Which splits elements of a sequence into chunks) then reconcatenate the chunks using String.Join.
var text = "...";
string.Join(',', text.Chunk(size: 6).Select(x => new string(x)));

This is much faster without copying array (this version inserts space every 3 digits but you can adjust it to your needs)
public string GetString(double valueField)
{
char[] ins = valueField.ToString().ToCharArray();
int length = ins.Length + (ins.Length / 3);
if (ins.Length % 3 == 0)
{
length--;
}
char[] outs = new char[length];
int i = length - 1;
int j = ins.Length - 1;
int k = 0;
do
{
if (k == 3)
{
outs[i--] = ' ';
k = 0;
}
else
{
outs[i--] = ins[j--];
k++;
}
}
while (i >= 0);
return new string(outs);
}

For every 1 character, you could do this one-liner:
string.Join(".", "1234".ToArray()) //result: 1.2.3.4

If you intend to create your own function to acheive this without using regex or pattern matching methods, you can create a simple function like this:
String formatString(String key, String seperator, int afterEvery){
String formattedKey = "";
for(int i=0; i<key.length(); i++){
formattedKey += key.substring(i,i+1);
if((i+1)%afterEvery==0)
formattedKey += seperator;
}
if(formattedKey.endsWith("-"))
formattedKey = formattedKey.substring(0,formattedKey.length()-1);
return formattedKey;
}
Calling the mothod like this
formatString("ABCDEFGHIJKLMNOPQRST", "-", 4)
Would result in the return string as this
ABCD-EFGH-IJKL-MNOP-QRST

A little late to the party, but here's a simplified LINQ expression to break an input string x into groups of n separated by another string sep:
string sep = ",";
int n = 8;
string result = String.Join(sep, x.InSetsOf(n).Select(g => new String(g.ToArray())));
A quick rundown of what's happening here:
x is being treated as an IEnumerable<char>, which is where the InSetsOf extension method comes in.
InSetsOf(n) groups characters into an IEnumerable of IEnumerable -- each entry in the outer grouping contains an inner group of n characters.
Inside the Select method, each group of n characters is turned back into a string by using the String() constructor that takes an array of chars.
The result of Select is now an IEnumerable<string>, which is passed into String.Join to interleave the sep string, just like any other example.

I am more than late with my answer but you can use this one:
static string PutLineBreak(string str, int split)
{
for (int a = 1; a <= str.Length; a++)
{
if (a % split == 0)
str = str.Insert(a, "\n");
}
return str;
}

C# line break every n characters

Suppose I have a string with the text: "THIS IS A TEST". How would I split it every n characters? So if n was 10, then it would display:
"THIS IS A "
"TEST"
..you get the idea. The reason is because I want to split a very big line into smaller lines, sort of like word wrap. I think I can use string.Split() for this, but I have no idea how and I'm confused.
Any help would be appreciated.

Let's borrow an implementation from my answer on code review. This inserts a line break every n characters:
public static string SpliceText(string text, int lineLength) {
return Regex.Replace(text, "(.{" + lineLength + "})", "$1" + Environment.NewLine);
}
Edit:
To return an array of strings instead:
public static string[] SpliceText(string text, int lineLength) {
return Regex.Matches(text, ".{1," + lineLength + "}").Cast<Match>().Select(m => m.Value).ToArray();
}

Maybe this can be used to handle efficiently extreme large files :
public IEnumerable<string> GetChunks(this string sourceString, int chunkLength)
{
using(var sr = new StringReader(sourceString))
{
var buffer = new char[chunkLength];
int read;
while((read= sr.Read(buffer, 0, chunkLength)) == chunkLength)
{
yield return new string(buffer, 0, read);
}
}
}
Actually, this works for any TextReader. StreamReader is the most common used TextReader. You can handle very large text files (IIS Log files, SharePoint Log files, etc) without having to load the whole file, but reading it line by line.

You should be able to use a regex for this. Here is an example:
//in this case n = 10 - adjust as needed
List<string> groups = (from Match m in Regex.Matches(str, ".{1,10}")
select m.Value).ToList();
string newString = String.Join(Environment.NewLine, lst.ToArray());
Refer to this question for details:
Splitting a string into chunks of a certain size

Probably not the most optimal way, but without regex:
string test = "my awesome line of text which will be split every n characters";
int nInterval = 10;
string res = String.Concat(test.Select((c, i) => i > 0 && (i % nInterval) == 0 ? c.ToString() + Environment.NewLine : c.ToString()));

Coming back to this after doing a code review, there's another way of doing the same without using Regex
public static IEnumerable<string> SplitText(string text, int length)
{
for (int i = 0; i < text.Length; i += length)
{
yield return text.Substring(i, Math.Min(length, text.Length - i));
}
}

Some code that I just wrote:
string[] SplitByLength(string line, int len, int IsB64=0) {
int i;
if (IsB64 == 1) {
// Only Allow Base64 Line Lengths without '=' padding
int mod64 = (len % 4);
if (mod64 != 0) {
len = len + (4 - mod64);
}
}
int parts = line.Length / len;
int frac = line.Length % len;
int extra = 0;
if (frac != 0) {
extra = 1;
}
string[] oline = new string[parts + extra];
for(i=0; i < parts; i++) {
oline[i] = line.Substring(0, len);
line = line.Substring(len);
}
if (extra == 1) {
oline[i] = line;
}
return oline;
}
string CRSplitByLength(string line, int len, int IsB64 = 0)
{
string[] lines = SplitByLength(line, len, IsB64);
return string.Join(System.Environment.NewLine, lines);
}
string m = "1234567890abcdefghijklmnopqrstuvwxhyz";
string[] r = SplitByLength(m, 6, 0);
foreach (string item in r) {
Console.WriteLine("{0}", item);
}