How to create and display a new form each time I Click a button (in my base form which is MDI Container) in C#. Each time I click button a new child form should open.
Google is your friend!
Here's some examples:
How to open the second form?
To show a new Form on click of a button in C#
https://msdn.microsoft.com/en-us/library/ws1btzy8(v=vs.90).aspx
Hope this helps!
Related
In my Visual Studio project file: <TargetFramework>net6.0-windows</TargetFramework>
I have a Winforms application whose main form has two buttons, button A and button B.
I have coded button A so that it disables itself when clicked, launches form A, and when form A is closed, control returns to the button click event where button A is re-enabled:
btnA.Enabled = false;
FormA frmA = new FormA();
btnA.Enabled = frmA.ShowDialog(this) == DialogResult.OK;
However this does not allow the user to do anything on the main form until frmA is closed.
When button A is clicked, I still want to disable button A so that the user cannot open another form A. But I also want the user to be able to click button B on the main form and have that logic work the same way: disable button B, launch form B, re-enable button B.
What I am trying to do is give the user the ability to launch one form A and one form B from the main form. Can I accomplish that with the pattern I've described? If so, how? (Note: There could be buttons C and D later.) I would gladly consider a different/better approach. Thanks Hedge.
I found a SO solution using Show() and capturing the close event on Form A:
WinForms; detecting form closed from another form
Not much coding involved at all.
i open a form on button click and the first one remain opened also.
I want the form below to be non interactive.
Means if user click on the form below he should be unable to.
I used topmost property but it doesn't solve my problem.
Use the Form.ShowDialog method to open a modal form:
using (MyForm frm = new MyForm())
frm.ShowDialog();
In my windows forms application, I have two forms, mainForm and recordForm. in main form there is some textboxes and buttons , and on a click of particular button I want to show the recordForm.
But I want when the second form is opened, then user can't perform any operation (like filling textboxes etc) until second form is closed. I tried this:
private void tsCustomer_Click(object sender, EventArgs e)
{
recordForm customers = new recordForm();
customers.Show();
}
tsCustomer is button on mainForm. How can i do this?
Change your code from:
customers.Show();
to:
customers.ShowDialog();
You have to use
customers.ShowDialog();
in order for the customer form to be modal.
How about Form.ShowDialog()?
From MSDN Site : Shows the form as a modal dialog box with no owner window.
This does not effectively relates two forms of your application. But showing the second form in modal form is what you want.
I have to display a usercontrol containing 2 datepickers, 2 buttons ( validate, cancel ) in a modal popup.
This popup is shown when the user has clicked on a specific button on the form.
Any ideas ?
Thnks in advance
You can add your user control to a Form -- say you called if frmPopup, create a new instance of it and call it with ShowDialog(). You need to have a pair of buttons on the Form as well to give the user a way to close or cancel the dialog. Microsoft has more information for you here
i wanna to do the following: but i donot how to do this in the correct way..
i have specific form has some buttons.. i wanna when click on a button a modal form appears,and this new form contains server controls and events fired when happening on this form how to handle this case like the dialog form in the Windows application..
Take a look on telerik controls :
http://demos.telerik.com/aspnet-ajax/window/examples/overview/defaultcs.aspx