I am trying to create an xml in c# and specifying the namespace and then the prefix on each element.
<bk:library xmlns:bk="www.namespace.com/ww">
<bk:books>
<bk:book>
<bk:title>Title </bk:book>
</bk:book>
<bk:books>
</bk:library>
I have done the following code:
XmlDocument doc = new XmlDocument();
root = doc.AppendChild(doc.CreateElement("library"));
var booksNode = root.appendChild(doc.CreateElement("bk","books","www.namespace.com/ww"));
Console.WriteLine(doc.OuterXml);
I get something like this:
<bk:books xmlns:bk="www.namespace.com/ww">
So it outputs both the prefix and the namespace
It doesn't output the xml as I would like it (shown above).
Any idea how I can get the xml to be output like I have shown?
thanks
Try this
XmlDocument doc = new XmlDocument();
XmlElement root = (XmlElement)doc.AppendChild(doc.CreateElement("bk","library","www.namespace.com/ww"));
var booksNode = root.AppendChild(doc.CreateElement("bk", "books", "www.namespace.com/ww"));
Console.WriteLine(doc.OuterXml);
Related
I'm trying to read a node in a serialized XML file. Here is the the first part of the XML file (I'm using a screen cap because pasting ended up with weird formatting):
And this is the code I'm using to read the XML and the error it's throwing:
I'm trying to read the <ScenarioDescription> node.
As per request, here's the entire XML file. Unfortunately it's just a complete mess. Here is a link to the XML file.
You should You would need to specify the namespace. In this particular case, the default namespace is used to declare the http://schemas.datacontract.org/2004/07/ModelLib namespace.
var xml = new XmlDocument();
xml.LoadXml(str);
XmlNamespaceManager ns = new XmlNamespaceManager(xml.NameTable);
ns.AddNamespace("x", xml.DocumentElement.NamespaceURI);
var root = xml.DocumentElement;
var test = root.SelectSingleNode("//x:ScenarioDescription",ns);
var scenarioText = test.InnerText;
You can use the following code to access the ScenarioDescription node and its InnerText
var document = new XmlDocument();
document.Load(s);
var root = document.DocumentElement;
var node = root["ScenarioDescription"];
var text = node?.InnerText;
SelectSingleNode accepts the xpath expression, you simply can use XmlElement indexer instead. Otherwise you'll need to create a XmlNamespaceManager instance and add your root namespace to it
You can supply the XmlNamespaceManager object as a parameter to the
SelectNodes or SelectSingleNode method of the XmlDocument class to
execute XPath query expressions that reference namespace-qualified
element and attribute name
XmlElement xmlElementSAPD = xmlDocument.CreateElement("SAPD");
root.AppendChild(xmlElementSAPD);
xmlElementSAPD.AppendChild(XmlFunctions.GetXMLElement(xmlDocument, "smu", dr.GetString("sma").Trim()));
The c# code above creates XML below.
<SAPD>
<smu>123</smu>
</SAPD>
How can I change the code above so that I can get
<ns0:SAPD>
<ns0:smu>123</ns0:smu>
</ns0:SAPD>
Anyone? How can I add ns0: in xml nodes?
You have to add the namespace to your xml document.
Just to give you an idea have a look at the below
XmlDocument doc = new XmlDocument();
XmlSchema schema = new XmlSchema();
schema.Namespaces.Add("ns0", "http://www.sample.com/file");
doc.Schemas.Add(schema);
You prefix ns0 needs to be mapped with a namespace else the xml would not be valid.
Assumning ns0 is mapped to http://tempuri.org the below code can be used:
XmlDocument doc = new XmlDocument();
XmlElement sapd= doc.CreateElement("ns0","SAPD","http://tempuri.org");
XmlElement smu = doc.CreateElement("ns0", "smu", "http://tempuri.org");
smu.InnerText = "123";
sapd.AppendChild(smu);
doc.AppendChild(sapd);
doc.InnerXml.ToString();
I'm looking for the simplest way to convert a string containing valid XML into an XmlElement object in C#.
How can you turn this into an XmlElement?
<item><name>wrench</name></item>
Use this:
private static XmlElement GetElement(string xml)
{
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
return doc.DocumentElement;
}
Beware!!
If you need to add this element to another document first you need to Import it using ImportNode.
Suppose you already had a XmlDocument with children nodes, And you need add more child element from string.
XmlDocument xmlDoc = new XmlDocument();
// Add some child nodes manipulation in earlier
// ..
// Add more child nodes to existing XmlDocument from xml string
string strXml =
#"<item><name>wrench</name></item>
<item><name>screwdriver</name></item>";
XmlDocumentFragment xmlDocFragment = xmlDoc.CreateDocumentFragment();
xmlDocFragment.InnerXml = strXml;
xmlDoc.SelectSingleNode("root").AppendChild(xmlDocFragment);
The Result:
<root>
<item><name>this is earlier manipulation</name>
<item><name>wrench</name></item>
<item><name>screwdriver</name>
</root>
Use XmlDocument.LoadXml:
XmlDocument doc = new XmlDocument();
doc.LoadXml("<item><name>wrench</name></item>");
XmlElement root = doc.DocumentElement;
(Or in case you're talking about XElement, use XDocument.Parse:)
XDocument doc = XDocument.Parse("<item><name>wrench</name></item>");
XElement root = doc.Root;
You can use XmlDocument.LoadXml() to do this.
Here is a simple examle:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml("YOUR XML STRING");
I tried with this snippet, Got the solution.
// Sample string in the XML format
String s = "<Result> No Records found !<Result/>";
// Create the instance of XmlDocument
XmlDocument doc = new XmlDocument();
// Loads the XML from the string
doc.LoadXml(s);
// Returns the XMLElement of the loaded XML String
XmlElement xe = doc.DocumentElement;
// Print the xe
Console.out.println("Result :" + xe);
If any other better/ efficient way to implement the same, please let us know.
Thanks & Cheers
I have XML stored in string variable:
<ItemMasterList><ItemMaster><fpartno>xxx</fpartno><frev>000</frev><fac>Default</fac></ItemMaster></ItemMasterList>
Here I want to change XML tag <ItemMasterList> to <Masterlist>. How can I do this?
System.Xml.XmlDocument and the associated classes in that same namespace will prove invaluable to you here.
XmlDocument doc = new XmlDocument();
doc.LoadXml(yourString);
XmlDocument docNew = new XmlDocument();
XmlElement newRoot = docNew.CreateElement("MasterList");
docNew.AppendChild(newRoot);
newRoot.InnerXml = doc.DocumentElement.InnerXml;
String xml = docNew.OuterXml;
I know i am a bit late, but just have to add this answer as no one seems to know about this.
XDocument doc = XDocument.Parse("<ItemMasterList><ItemMaster><fpartno>xxx</fpartno><frev>000</frev><fac>Default</fac></ItemMaster></ItemMasterList>");
doc.Root.Name = "MasterList";
Which returns the following:
<MasterList>
<ItemMaster>
<fpartno>xxx</fpartno>
<frev>000</frev>
<fac>Default</fac>
</ItemMaster>
</MasterList>
You can use LINQ to XML to parse the XML string, create a new root and add the child elements and attributes of the original root to the new root:
XDocument doc = XDocument.Parse("<ItemMasterList>...</ItemMasterList>");
XDocument result = new XDocument(
new XElement("Masterlist", doc.Root.Attributes(), doc.Root.Nodes()));
Using the XmlDocument way, you can do this as follows (and keep the tree intact):
XmlDocument oldDoc = new XmlDocument();
oldDoc.LoadXml("<ItemMasterList><ItemMaster><fpartno>xxx</fpartno><frev>000</frev><fac>Default</fac></ItemMaster></ItemMasterList>");
XmlNode node = oldDoc.SelectSingleNode("ItemMasterList");
XmlDocument newDoc = new XmlDocument();
XmlElement ele = newDoc.CreateElement("MasterList");
ele.InnerXml = node.InnerXml;
If you now use ele.OuterXml is will return: (you you just need the string, otherwise use XmlDocument.AppendChild(ele) and you will be able to use the XmlDocument object some more)
<MasterList>
<ItemMaster>
<fpartno>xxx</fpartno>
<frev>000</frev>
<fac>Default</fac>
</ItemMaster>
</MasterList>
As pointed by Will A, we can do it that way but for case where InnerXml equals the OuterXml the following solution will work out:
// Create a new Xml doc object with root node as "NewRootNode" and
// copy the inner content from old doc object using the LastChild.
XmlDocument docNew = new XmlDocument();
XmlElement newRoot = docNew.CreateElement("NewRootNode");
docNew.AppendChild(newRoot);
// The below line solves the InnerXml equals the OuterXml Problem
newRoot.InnerXml = oldDoc.LastChild.InnerXml;
string xmlText = docNew.OuterXml;
My code doesn't return the node
XmlDocument xml = new XmlDocument();
xml.InnerXml = text;
XmlNode node_ = xml.SelectSingleNode(node);
return node_.InnerText; // node_ = null !
I'm pretty sure my XML and Xpath are correct.
My Xpath : /ItemLookupResponse/OperationRequest/RequestId
My XML :
<?xml version="1.0"?>
<ItemLookupResponse xmlns="http://webservices.amazon.com/AWSECommerceService/2005-10-05">
<OperationRequest>
<RequestId>xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxxx</RequestId>
<!-- the rest of the xml is irrelevant -->
</OperationRequest>
</ItemLookupResponse>
The node my XPath returns is always null for some reason. Can someone help?
Your XPath is almost correct - it just doesn't take into account the default XML namespace on the root node!
<ItemLookupResponse
xmlns="http://webservices.amazon.com/AWSECommerceService/2005-10-05">
*** you need to respect this namespace ***
You need to take that into account and change your code like this:
XmlDocument xml = new XmlDocument();
xml.InnerXml = text;
XmlNamespaceManager nsmgr = new XmlNamespaceManager(xml.NameTable);
nsmgr.AddNamespace("x", "http://webservices.amazon.com/AWSECommerceService/2005-10-05");
XmlNode node_ = xml.SelectSingleNode(node, nsmgr);
And then your XPath ought to be:
/x:ItemLookupResponse/x:OperationRequest/x:RequestId
Now, your node_.InnerText should definitely not be NULL anymore!
Sorry for the late reply but I had a similar problem just a moment ago.
if you REALLY want to ignore that namespace then just delete it from the string you use to initialise the XmlDocument
text=text.Replace(
"<ItemLookupResponse xmlns=\"http://webservices.amazon.com/AWSECommerceService/2005-10-05\">",
"<ItemLookupResponse>");
XmlDocument xml = new XmlDocument();
xml.InnerXml = text;
XmlNode node_ = xml.SelectSingleNode(node);
return node_.InnerText;