Develop Reference

How to use FileDialog to select either specific files names extensions or all the files?

private void button1_Click(object sender, EventArgs e)
{
VistaOpenFileDialog dialog = new VistaOpenFileDialog();
{
dialog.Filter = "Images (*.jpg, *.bmp, *.gif)|*.jpg;*.bmp;*.gif";
dialog.Filter = "All Files (*.*)|*.*";
};
if (dialog.ShowDialog() == DialogResult.OK)
{
textBox1.Text = dialog.FileName;
Bitmap bmp = new Bitmap(Image.FromFile(dialog.FileName),
pictureBox2.Width, pictureBox2.Height);
pictureBox2.Image = bmp;
}
}
I'm using ookii package with VistaOpenFileDialog but i guess the idea should be the same as with the regular OpenFileDialog class.
now when i click it's showing the All Files option when i expand it i can't see the first option Images.
i want that it will show first the Images option and then to be able to switch the All Files.

You are overwriting your filter property. To add multiple file type filters:
dialog.Filter = "Images (*.jpg, *.bmp, *.gif)|*.jpg;*.bmp;*.gif|All Files (*.*)|*.*";

merge two picturebox and save

I am developing a c# windows form application.. I want to merge two picturebox and save it to custom file location.. I used following code to do it. But it only save 2nd picturebox image. Could anybody tell me how to merge this two picturebox and save it..
{
// open file dialog
OpenFileDialog open = new OpenFileDialog();
// image filters
open.Filter = "Image Files(*.jpg; *.jpeg; *.gif;*.png; *.bmp)|*.jpg; *.jpeg; *.gif; *.bmp;*.png";
if (open.ShowDialog() == DialogResult.OK)
{
// display image in picture box
pictureBox2.Image = new Bitmap(open.FileName);
//combine two images
// image file path
textBox1.Text = open.FileName;
}
}
private void button2_Click(object sender, EventArgs e)
{
SaveFileDialog dialog = new SaveFileDialog();
dialog.Filter = "JPG(*.JPG)|*.jpg";
if (dialog.ShowDialog() == DialogResult.OK)
{
previewimg.Image.Save(dialog.FileName);
pictureBox2.Image.Save(dialog.FileName);
}
}
}

Maybe need some adjustements (not tested) but I think it's useful:
using (var src1 = new Bitmap(#"c:\...\image1.png"))
using (var src2 = new Bitmap(#"c:\...\image2.png"))
using (var bmp = new Bitmap(src1.Width + src2.Width, src1.Height, PixelFormat.Format32bppPArgb))
using (var g = Graphics.FromImage(bmp))
{
g.Clear(Color.Black);
g.DrawImage(src1, new Rectangle(0, 0, src1.Width, src1.Height));
g.DrawImage(src2, new Rectangle(src1.Width, 0, src2.Width, src2.Height));
bmp.Save(#"c:\...\combined.png", ImageFormat.Png);
}
UPDATE
private void button2_Click(object sender, EventArgs e)
{
SaveFileDialog dialog = new SaveFileDialog();
dialog.Filter = "JPG(*.JPG)|*.jpg";
if (dialog.ShowDialog() == DialogResult.OK)
{
var src1 = previewimg.Image;
var src2 = pictureBox2.Image;
using (var bmp = new Bitmap(src1.Width + src2.Width, src1.Height, PixelFormat.Format32bppPArgb))
using (var g = Graphics.FromImage(bmp))
{
g.Clear(Color.Black);
g.DrawImage(src1, new Rectangle(0, 0, src1.Width, src1.Height));
g.DrawImage(src2, new Rectangle(src1.Width, 0, src2.Width, src2.Height));
bmp.Save(#"c:\...\combined.png", ImageFormat.Png);
}
}
}

How to move an image from a canvas to another

I'm trying to do a image processing software and for the moment I'm stuck on this.
I've open an image in my first canvas, and now I want to take the image and add some filters on it. Contrast, saturation and so on, and then to see it on the second canvas.
But my main problem is that I can't find out how to use pixels from my first canvas and manipulate them. How can I do this the easy way?
Thanks.
private void openImage_OnClick(object sender, RoutedEventArgs e)
{
Microsoft.Win32.OpenFileDialog dlg = new Microsoft.Win32.OpenFileDialog();
dlg.InitialDirectory = "c:\\";
dlg.DefaultExt = ".jpeg";
dlg.Filter = "Image files (*.png;*.jpg;*.jpeg)|*.png;*.jpg;*.jpeg";
Nullable<bool> result = dlg.ShowDialog();
if (result == true)
{
string filename = dlg.FileName;
ImageBrush brush = new ImageBrush();
brush.ImageSource = new BitmapImage(new Uri(#filename, UriKind.Relative));
CanvasOriginalImage.Background = brush;
}
}

C# Save Pitcherbox1 by Button1 in .png

I have been trying to save the image in pictureBox1. What am trying to do is to make it so people can "Save" the image from pictureBox1 by clicking on my "Save As" Button.
I am using Visual Studio 2010 with C#
This is what I have so far:
private void Button2_Click(System.Object sender, System.EventArgs e)
{
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.Filter = "Png Image|*.jpg";
saveFileDialog1.Title = "Save an Image File";
saveFileDialog1.ShowDialog();
if (saveFileDialog1.FileName != "")
pictureBox1.Image = new Bitmap ("c:/avatar.png");
{
SaveFileDialog dialog = new SaveFileDialog();
if (dialog.ShowDialog() == DialogResult.OK)
{
pictureBox1.Image.Save(#"C:\Documents and Settings\.Png", System.Drawing.Imaging.ImageFormat.Png);
}
}
}

I'm not sure what you are trying with your code, there seems to be quite a few things wrong in there. This is how I would do it:
private void Button2_Click(System.Object sender, System.EventArgs e)
{
if (pictureBox.Image != null)
{
using {var dialog = new SaveFileDialog())
{
dialog.Title = ...
saveFileDialog1.Filter = "Png Image|*.png";
...other properties...
if (dialog.ShowDialog == DialogResult.OK)
{
pictureBox.Image.Save(dialog.FileName, System.Drawing.Imaging.ImageFormat.Png)
}
}
}
}

Load a bitmap image into Windows Forms using open file dialog

I need to open the bitmap image in the window form using open file dialog (I will load it from drive). The image should fit in the picture box.
Here is the code I tried:
private void button1_Click(object sender, EventArgs e)
{
var dialog = new OpenFileDialog();
dialog.Title = "Open Image";
dialog.Filter = "bmp files (*.bmp)|*.bmp";
if (dialog.ShowDialog() == DialogResult.OK)
{
var PictureBox1 = new PictureBox();
PictureBox1.Image(dialog.FileName);
}
dialog.Dispose();
}

You have to create an instance of the Bitmap class, using the constructor overload that loads an image from a file on disk. As your code is written now, you're trying to use the PictureBox.Image property as if it were a method.
Change your code to look like this (also taking advantage of the using statement to ensure proper disposal, rather than manually calling the Dispose method):
private void button1_Click(object sender, EventArgs e)
{
// Wrap the creation of the OpenFileDialog instance in a using statement,
// rather than manually calling the Dispose method to ensure proper disposal
using (OpenFileDialog dlg = new OpenFileDialog())
{
dlg.Title = "Open Image";
dlg.Filter = "bmp files (*.bmp)|*.bmp";
if (dlg.ShowDialog() == DialogResult.OK)
{
PictureBox PictureBox1 = new PictureBox();
// Create a new Bitmap object from the picture file on disk,
// and assign that to the PictureBox.Image property
PictureBox1.Image = new Bitmap(dlg.FileName);
}
}
}
Of course, that's not going to display the image anywhere on your form because the picture box control that you've created hasn't been added to the form. You need to add the new picture box control that you've just created to the form's Controls collection using the Add method. Note the line added to the above code here:
private void button1_Click(object sender, EventArgs e)
{
using (OpenFileDialog dlg = new OpenFileDialog())
{
dlg.Title = "Open Image";
dlg.Filter = "bmp files (*.bmp)|*.bmp";
if (dlg.ShowDialog() == DialogResult.OK)
{
PictureBox PictureBox1 = new PictureBox();
PictureBox1.Image = new Bitmap(dlg.FileName);
// Add the new control to its parent's controls collection
this.Controls.Add(PictureBox1);
}
}
}

Works Fine.
Try this,
private void addImageButton_Click(object sender, EventArgs e)
{
OpenFileDialog of = new OpenFileDialog();
//For any other formats
of.Filter = "Image Files (*.bmp;*.jpg;*.jpeg,*.png)|*.BMP;*.JPG;*.JPEG;*.PNG";
if (of.ShowDialog() == DialogResult.OK)
{
pictureBox1.ImageLocation = of.FileName;
}
}

You should try to:
Create the picturebox visually in form (it's easier)
Set Dock property of picturebox to Fill (if you want image to fill form)
Set SizeMode of picturebox to StretchImage
Finally:
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog dlg = new OpenFileDialog();
dlg.Title = "Open Image";
dlg.Filter = "bmp files (*.bmp)|*.bmp";
if (dlg.ShowDialog() == DialogResult.OK)
{
PictureBox1.Image = Image.FromFile(dlg.Filename);
}
dlg.Dispose();
}

private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog open = new OpenFileDialog();
if (open.ShowDialog() == DialogResult.OK)
pictureBox1.Image = Bitmap.FromFile(open.FileName);
}

You, can also try like this, PictureBox1.Image = Image.FromFile("<your ImagePath>" or <Dialog box result>);

PictureBox.Image is a property, not a method. You can set it like this:
PictureBox1.Image = System.Drawing.Image.FromFile(dlg.FileName);

You can try the following:
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog fDialog = new OpenFileDialog();
fDialog.Title = "Select file to be upload";
fDialog.Filter = "All Files|*.*";
// fDialog.Filter = "PDF Files|*.pdf";
if (fDialog.ShowDialog() == DialogResult.OK)
{
textBox1.Text = fDialog.FileName.ToString();
}
}

It's simple. Just add:
PictureBox1.BackgroundImageLayout = ImageLayout.Zoom;