I got this function for simply get the inner text of my xml:
XmlDocument document = new XmlDocument();
document.Load("game.xml");
string content = document.SelectSingleNode("Game/Client-Version").InnerText;
(this is the xml file (due to complications with stackoverflow posted on pastebin)): http://pastebin.com/EEeFAJpC
And now I am exactly looking for the function above, just to write. Like
document.WriteSingleNode("Game/Client-Version", "texttowrite");
I did not find anything helping me out.
This should work
XmlElement x = document.SelectSingleNode("Game/Client-Version") as XmlElement;
x.InnerText = "texttowrite";
Create your own extension method:
public void WriteSingleNode(this XmlDocument document, string NodeName, string InnerText)
{
// Create a new element node.
XmlNode newElem = document.CreateNode("element", "pages", "");
newElem.InnerText = InnerText;
Console.WriteLine("Add the new element to the document...");
document.DocumentElement.AppendChild(newElem);
Console.WriteLine("Display the modified XML document...");
Console.WriteLine(document.OuterXml);
}
Related
I am work on some innerxml of an XML document.
I have to concat several parts.
I have this:
<TRANFSERT><GOOD></GOOD></TRANSFERT>
I want to insert another part, <GOOD></GOOD>, before </TRANSFERT>.
I tried this:
int pos = xmldoc.indexOf("</GOOD>");
StringBuilder sb = new StringBuilder(xmlFinal);
sb.Append(xmlModifiee,pos,xmlModifiee.length);
xmlFinal = sb.ToString();
But it doesn't work.
How can I add a small part of XML in other XML?
You shouldn't interact with XML like with ordinary string.
Use provided System.Xml.XmlDocument or System.Xml.Linq.XDocument classes:
Ordinary XmlDocument single node selection and appending new element to it:
XmlDocument xmlDocument = new XmlDocument();
xmlDocument.Load("YourFile.xml");
XmlNode goodNode = xmlDocument.SelectSingleNode("TRANSFERT/GOOD");
XmlNode nodeToInsert = xmlDocument.CreateElement("INSERTEDNODE");
goodNode.AppendChild(nodeToInsert);
Ordinary XmlDocument iterating by nodes to find necessary (be aware for many-childed nodes) and add new child node to it:
XmlDocument xmlDocument = new XmlDocument();
xmlDocument.Load("YourFile.xml");
foreach (XmlNode rootNode in xmlDocument.ChildNodes)
{
if (rootNode.Name == "TRANSFERT")
{
foreach (XmlNode childNode in rootNode.ChildNodes)
{
if (childNode.Name == "GOOD")
{
XmlNode nodeToInsert = xmlDocument.CreateElement("INSERTEDNODE");
childNode.AppendChild(nodeToInsert);
}
}
}
}
Linq to XML variant:
XDocument xDoc = XDocument.Load("YourFIle.xml");
XElement rootElement = xDoc.Element("TRANSFERT");
XElement goodElement = rootElement.Element("GOOD");
goodElement.Add(new XElement("INSERTEDNODE"));
Simplified Linq to XML variant:
XDocument.Load("YourFIle.xml").Element("TRANSFERT").Element("GOOD").Add(new XElement("INSERTEDNODE"));
EDITED: answering the question, example was rewrited from changing InnerText values to Append/Add new child element to GOOD node.
StringBuilder.Append can only be used to add something to the end of the string. To add something inside the string, use StringBuilder.Insert like this:
sb.Insert(pos, xmlModifiee);
I have a simple XML doc with no Namespace
Here is the code I wrote in C# to search for a particular element based on Name.
public XmlElement SearchXML(string name)
{
XmlDocument xDoc = new XmlDocument();
string filePath = ConfigurationManager.AppSettings["path"];
xDoc.Load(filePath);
string xQryStr = "//NewPatient[Name='" + name + "']";
xDoc.SelectNodes(xQryStr);
XmlElement xmlEle = xDoc.DocumentElement;
return xmlEle;
}
The XML document is as follows
When I try to call the method SearchXML and pass Dennis as the arguement, instead of returning the xml element containing only the specific elements, it returns the entire document.
Where am I possibly erring?
Any help appreciated.
xDoc.SelectNodes(xQryStr) does not mutate the original doc. You need to store the return value of this method call and return that instead.
ATM you're simply returning the root element of the original doc (i.e. the entire tree)
EDIT
In answer to your comment, you could fish the first matched XmlElement as follows:
xDoc.SelectNodes(xQryStr).OfType<XmlElement>().FirstOrDefault()
This will return either null or an XmlElement
If you want to select a list of nodes based on an XPath expression, you need to use .SelectNodes in this fashion:
public XmlElement SearchXML(string name)
{
XmlDocument xDoc = new XmlDocument();
string filePath = ConfigurationManager.AppSettings["path"];
xDoc.Load(filePath);
string xQryStr = "//NewPatient[Name='" + name + "']";
XmlNodeList listOfNodes = xDoc.SelectNodes(xQryStr);
foreach(XmlNode node in listOfNodes
{
// do something with that list of XML nodes you've selected....
// XmlElement xmlEle = node;
// return xmlEle;
}
}
The call to .SelectNodes(xpath) returns a list of matching XML nodes (see the MSDN documentation on XmlDocument.SelectNodes) - once you have that list, you can iterate over the matched nodes and do something with them....
Or if you're expecting only a single XML node to match your XPath expression, you can use .SelectSingleNode, too:
string xQryStr = "//NewPatient[Name='" + name + "']";
XmlNode matchedNode = xDoc.SelectSingleNode(xQryStr);
if(matchedNode != null)
{
// do something with that list of XML nodes you've selected....
return matchedNode;
}
can you change
string xQryStr = "//NewPatient[Name='" + name + "']";
to
xQryStr = "/NewPatient[Name='" + name + "']";
see the below link
http://www.csharp-examples.net/xml-nodes-by-name/
I'm looking for the simplest way to convert a string containing valid XML into an XmlElement object in C#.
How can you turn this into an XmlElement?
<item><name>wrench</name></item>
Use this:
private static XmlElement GetElement(string xml)
{
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
return doc.DocumentElement;
}
Beware!!
If you need to add this element to another document first you need to Import it using ImportNode.
Suppose you already had a XmlDocument with children nodes, And you need add more child element from string.
XmlDocument xmlDoc = new XmlDocument();
// Add some child nodes manipulation in earlier
// ..
// Add more child nodes to existing XmlDocument from xml string
string strXml =
#"<item><name>wrench</name></item>
<item><name>screwdriver</name></item>";
XmlDocumentFragment xmlDocFragment = xmlDoc.CreateDocumentFragment();
xmlDocFragment.InnerXml = strXml;
xmlDoc.SelectSingleNode("root").AppendChild(xmlDocFragment);
The Result:
<root>
<item><name>this is earlier manipulation</name>
<item><name>wrench</name></item>
<item><name>screwdriver</name>
</root>
Use XmlDocument.LoadXml:
XmlDocument doc = new XmlDocument();
doc.LoadXml("<item><name>wrench</name></item>");
XmlElement root = doc.DocumentElement;
(Or in case you're talking about XElement, use XDocument.Parse:)
XDocument doc = XDocument.Parse("<item><name>wrench</name></item>");
XElement root = doc.Root;
You can use XmlDocument.LoadXml() to do this.
Here is a simple examle:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml("YOUR XML STRING");
I tried with this snippet, Got the solution.
// Sample string in the XML format
String s = "<Result> No Records found !<Result/>";
// Create the instance of XmlDocument
XmlDocument doc = new XmlDocument();
// Loads the XML from the string
doc.LoadXml(s);
// Returns the XMLElement of the loaded XML String
XmlElement xe = doc.DocumentElement;
// Print the xe
Console.out.println("Result :" + xe);
If any other better/ efficient way to implement the same, please let us know.
Thanks & Cheers
I have XML stored in string variable:
<ItemMasterList><ItemMaster><fpartno>xxx</fpartno><frev>000</frev><fac>Default</fac></ItemMaster></ItemMasterList>
Here I want to change XML tag <ItemMasterList> to <Masterlist>. How can I do this?
System.Xml.XmlDocument and the associated classes in that same namespace will prove invaluable to you here.
XmlDocument doc = new XmlDocument();
doc.LoadXml(yourString);
XmlDocument docNew = new XmlDocument();
XmlElement newRoot = docNew.CreateElement("MasterList");
docNew.AppendChild(newRoot);
newRoot.InnerXml = doc.DocumentElement.InnerXml;
String xml = docNew.OuterXml;
I know i am a bit late, but just have to add this answer as no one seems to know about this.
XDocument doc = XDocument.Parse("<ItemMasterList><ItemMaster><fpartno>xxx</fpartno><frev>000</frev><fac>Default</fac></ItemMaster></ItemMasterList>");
doc.Root.Name = "MasterList";
Which returns the following:
<MasterList>
<ItemMaster>
<fpartno>xxx</fpartno>
<frev>000</frev>
<fac>Default</fac>
</ItemMaster>
</MasterList>
You can use LINQ to XML to parse the XML string, create a new root and add the child elements and attributes of the original root to the new root:
XDocument doc = XDocument.Parse("<ItemMasterList>...</ItemMasterList>");
XDocument result = new XDocument(
new XElement("Masterlist", doc.Root.Attributes(), doc.Root.Nodes()));
Using the XmlDocument way, you can do this as follows (and keep the tree intact):
XmlDocument oldDoc = new XmlDocument();
oldDoc.LoadXml("<ItemMasterList><ItemMaster><fpartno>xxx</fpartno><frev>000</frev><fac>Default</fac></ItemMaster></ItemMasterList>");
XmlNode node = oldDoc.SelectSingleNode("ItemMasterList");
XmlDocument newDoc = new XmlDocument();
XmlElement ele = newDoc.CreateElement("MasterList");
ele.InnerXml = node.InnerXml;
If you now use ele.OuterXml is will return: (you you just need the string, otherwise use XmlDocument.AppendChild(ele) and you will be able to use the XmlDocument object some more)
<MasterList>
<ItemMaster>
<fpartno>xxx</fpartno>
<frev>000</frev>
<fac>Default</fac>
</ItemMaster>
</MasterList>
As pointed by Will A, we can do it that way but for case where InnerXml equals the OuterXml the following solution will work out:
// Create a new Xml doc object with root node as "NewRootNode" and
// copy the inner content from old doc object using the LastChild.
XmlDocument docNew = new XmlDocument();
XmlElement newRoot = docNew.CreateElement("NewRootNode");
docNew.AppendChild(newRoot);
// The below line solves the InnerXml equals the OuterXml Problem
newRoot.InnerXml = oldDoc.LastChild.InnerXml;
string xmlText = docNew.OuterXml;
I've got it writing the XML doc fine, and it will look something like this
<Team>
<Character Name="Bob" Class="Mage"/>
<Character Name="Mike" Class="Knight"/>
</Team>
I'm trying to find a way to access "Class" attribute of a single character and modify it. So far, i've got it to the point where I can pinpoint a specific character, but I can't figure out how to access the 'Class' attribute and modify it for the char.
void Write(string path, string charName, string varToChange, string value){
XmlNode curNode = null;
XmlDocument doc = new XmlDocument();
doc.Load(path);
XmlElement rootDoc = doc.DocumentElement;
curNode = rootDoc;
if(curNode.HasChildNodes){
for(int i=0; i<curNode.ChildNodes.Count; i++){
if(charName == curNode.ChildNodes[i].Attributes.GetNamedItem("Name").Value){
// Code would go here
}
}
}
return;
}
Use XPATH:
XmlDocument doc = new XmlDocument();
doc.Load(path);
var nodes = doc.SelectNodes(String.Format("/Team/Character[#Name=\"{0}\"]", charName));
foreach (XmlElement n in nodes)
{
n.SetAttribute(varToChange, value);
}
Use the XmlElement.SetAttribute('attribute to modify', 'value to set it to') method
edit:
I just noticed you were using XMLNode instead of XMLElement, so in order to update the attribute you can either just cast the XmlNode to an XmlElement like so
XmlElement el = (XmlElement)curNode;
el.SetAttribute("Class", "Value");
Otherwise you can create an attribute and then append it in order to update the attribute:
XmlAttribute attrib =
curNode.OwnerDocument.CreateAttribute("Class");
attrib.Value = "Value";
curNode.Attributes.Append(attrib);
Hope this helps