I know there are a lot of questions about WPF navigation, for application developed with MVVM pattern, and I have read tens and tens of answers but I'm missing probably something.
I started building an application following Rachel's article here. All works just fine, there's an ApplicationView Window with this XAML:
<Window x:Class="CashFlow.ApplicationView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:vm="clr-namespace:CashFlow.ViewModels"
xmlns:v="clr-namespace:CashFlow.Views"
Title="ApplicationView" Height="350" Width="600" WindowStartupLocation="CenterScreen">
<Window.Resources>
<!--Here the associations between ViewModels and Views-->
<DataTemplate DataType="{x:Type vm:HomeViewModel}">
<v:HomeView />
</DataTemplate>
</Window.Resources>
<!--Define here the application UI structure-->
<DockPanel>
<Border DockPanel.Dock="Left" BorderBrush="Black" BorderThickness="0,0,1,0">
<ItemsControl ItemsSource="{Binding PageViewModels}">
<ItemsControl.ItemTemplate>
<DataTemplate>
<Button Content="{Binding Name}"
Command="{Binding DataContext.ChangePageCommand, RelativeSource={RelativeSource AncestorType={x:Type Window}}}"
CommandParameter="{Binding}"
Margin="2,5" />
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
</Border>
<ContentControl Content="{Binding CurrentPageViewModel}" />
</DockPanel>
The ApplicationViewModel, that is set as DataContext for this window when the application starts, maintains an ObservableCollection of my ViewModels. Thanks to data templates, it's possible to associate every view with its viewmodel, using a ContentControl to render the views. Navigation in this case is accomplished with a "side bar" of buttons, binded to ApplicationViewModel commands that perform the changes of CurrentPageViewModel object.
I'm wondering how I can perform navigation without the presence of that sidebar of Buttons. Having only the Content control, I should be able to change the CurrentPageViewModel from the others viewmodel? Probably the answer will be very trivial, but I can't see that right now.
Your top level homeviewmodel can orchestrate navigation via an eventbus pattern. To use eventbus, you would inject an object that tracks objects that want to be notified of events. Then when a view model raises an event, the homeviewmodel receives it and performs the currentpageviewmodel assignment that will navigate you to the next viewmodel.
Ex:
Messenger defines two methods - RegisterForEvent<IEvent>(ViewModel aViewModel), and RaiseEvent(IEvent event).
So you would define a function to subscribe to the events -
HomeViewModel.cs
...
void SubscribeForEvents() {
Messenger.RegisterForEvent<NavigationEvent>(this);
}
Then you inject the Messenger into your other view models, and from those view models, raise the event:
Messenger.RaiseEvent(new NavigationEvent { TargetViewModel = new TargetViewModel() });
Where the event is something like
public class NavigationEvent : IEvent {
ViewModel TargetViewModel { get;set;}
}
C Bauer is right with what you are missing. I found in order to switch the data context, you'll need a messenger service to flag your "applicationviewmodel" to switch its data context. A good discussion with the steps you need are spelled out in a discussion here.
Register the message to be received in your applicationviewmodel, then handle the data context switch in your receive message function.
Also, this might be true or not, but I had to use 1 window, with multiple user controls as opposed to multiple windows if I wanted to have 1 window showing at all times. Lastly, I followed Sheridan's example and defined my data templates in my app.xaml as opposed to the window itself.
Related
I am developing plain WPF application on top of .NET 5.0.
I have navigation mechanism implemented based on DataTemplate(s)
<DataTemplate DataType="{x:Type viewmodels:FirstViewModel}">
<views:FirstView />
</DataTemplate>
<DataTemplate DataType="{x:Type viewmodels:SecondViewModel}">
<views:SecondView />
</DataTemplate>
and CurrentViewModel
<ContentControl Grid.Row="1" Content="{Binding CurrentViewModel}" VerticalAlignment="Stretch" HorizontalAlignment="Stretch" />
You can imagine there are navbar buttons changing the CurrentViewModel property.
Besides that I use Dependency Injection which provides all required services (including viewmodels).
Both FirstViewModel and SecondViewModel are singletons.
FirstView and SecondView are UserControl(s).
The problem:
Whenever I navigate between UserControls they re-render. This is very inconvinient, from performance perspective and application usability.
Let's say both UserControls have grids with searching features and more. I would like user to be able to navigate back to the same state which he left on the control (including focused elements and so on). Having singleton viewmodel allows to preserve state/values of the properties but it doesn't solve the problem of control being re-rendered whenever I navigate. I clearly see that each time FirstView constructor is being called on which it InitializeComponent() and later calls OnRender().
Grids have asynchronous Sources.
<DataGrid Style="{DynamicResource DataGridStyle}" ItemsSource="{Binding ActiveSearchResults, IsAsync=True}" AutoGenerateColumns="False" CanUserSortColumns="True" CanUserAddRows="False">
.
.
.
</DataGrid>
I don't want grid to be re-rendered each time I navigate and elements to lose their focus. When I navigate I also see the grid flikering.
Can you please suggest option I have?
Is it possible to have singleton UserControl?
Is it possible to have static property with a cached state?
I am pretty new to C# so I am just starting to learn the basics. Right now I have a ContentControl inside a Window like this:
<ContentControl Content="{Binding}" x:Name="SubView"/>
And I configured my resources of the Windows like this:
<Window.Resources>
<DataTemplate x:Name="StammdatenViewTemplate" DataType="{x:Type viewmodels:StammdatenViewModel}">
<views:StammdatenView DataContext="{Binding}" />
</DataTemplate>
<DataTemplate x:Name="AdministrationViewTemplate" DataType="{x:Type viewmodels:AdministrationViewModel}">
<views:AdministrationView DataContext="{Binding}" />
</DataTemplate>
</Window.Resources>
In my Window class I am setting the DataContext like this:
DataContext = new StammdatenViewModel();
Here is the thing I would like to do. I want to disable all the TextBoxes inside the ContentControl. I thought about adding a function to my StammdatenView.xaml.cs class (which is the class of my subview), then firing the event from the Window somehow. Though I would need access to the function inside the subview. Is that somehow possible and if yes how? Or would anyone suggest a different approach?
Thanks in advance.
Or would anyone suggest a different approach?
Yes. You should bind the IsEnabled property of each TextBox in the StammdatenView to a boolean property of the StammdatenViewModel.
You can then disable the TextBoxes by setting the source property in the view model class. This is one of the key aspects of the MVVM design pattern, i.e. that you handle your application logic in the view model.
Make sure that the view model class implements the INotifyPropertyChanged interface and provide change notifications as explained on MSDN.
You can create a INotifyPropertyChanged event on your view model, then bind it to the 'IsEnabled={Binding IsTextBoxEnabled}' attribute in your view template for the textbox.
public class ViewModel : BaseViewModel
{
private bool _isTextBoxEnabled;
public bool IsTextBoxEnabled
{
get { return _isTextBoxEnabled; }
set
{
if (value != _isTextBoxEnabled)
_isTextBoxEnabled = value;
this.RaisePropertyChanged("IsTextBoxEnabled");
}
}
}
XAML
<DataTemplate x:Key="template">
<StackPanel Orientation="Horizontal" DataContext="{Binding}">
<TextBox IsEnabled="{Binding IsTextBoxEnabled}" />
</StackPanel>
</DataTemplate>
This seems like such a basic question but after hours of searching around and not figuring out what I'm doing wrong I decided it's time to ask for help!
I'm new to WPF and the MVVM pattern, but am trying to create an application that has several windows you can navigate through by clicking buttons. This is accomplished by having the app window display UserControls using DataTemplates, so there's no content currently shared between pages (though there will be once I create the navigation area). Here's what the XAML looks like for the main window, with there currently only being one page in the application:
<Window x:Class="WPF_Application.ApplicationView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:local="clr-namespace:WPF_Application"
Title="ApplicationView" Height="300" Width="300" WindowStartupLocation="CenterScreen" WindowState="Maximized">
<Window.Resources>
<DataTemplate DataType="{x:Type local:LoginMenuViewModel}">
<local:LoginMenuView />
</DataTemplate>
</Window.Resources>
<DockPanel>
<ContentControl
Content="{Binding CurrentPageViewModel}" />
</DockPanel>
Now what I'd like to do is add a KeyBinding that reacts to the escape button being pressed. When this is done "LogoutCommand" should fire in the LoginMenuViewModel. I'm stuck getting the keybinding to trigger any commands within LoginMenuViewModel, and I've figured it's probably because the DataContext needs to be set to reference LoginMenuViewModel. For the life of me I can't get this to work.
Am I going about application-wide commands completely the wrong way? Is there some super simple fix that will make me smack my forehead in shame? Any insight is appreciated!
I do not know your ViewModel code, so it is not easy to give you details hints.
First of all, if your are using MVVM, you should have your own implementation of ICommand interface. You can find here the most common one (and a simple MVVM tutorial too).
After you have your own command class, your ViewModel should expose your LogoutCommand:
public class ViewModel
{
/* ... */
public ICommand LogoutCommand
{
get
{
return /* your command */
}
}
/* ... */
}
In your code behind you will set: DataContext = new ViewModel(); and at this point you can declare the KeyBindings that you need:
<Window.InputBindings>
<KeyBinding Key="Escape" Command="{Binding Path=LogoutCommand, Mode=OneWay}" />
</Window.InputBindings>
In this way when the Window is active and the user press the "Esc" key, your LogoutCommand is executed.
This is a brief summary that I hope will guide you in deepening the MVVM and its command system.
I have something like this:
<Window>
<Window.Resources>
<DataTemplate DataType="{x:Type local:VM1}">
<!-- View 1 Here -->
</DataTemplate>
<DataTemplate DataType="{x:Type local:VM2}">
<!-- View 2 here -->
</DataTemplate>
<Window.Resources>
<ContentPresenter Content="{Binding}"/>
</Window>
This will automatically swap out the view as I bind different viewmodels, which is very handy.
However, I have one view with a tabcontrol and many subviews. Each subview has several visual parts that are configured by a custom xml file (complex business case). Each time this view is created, the xml file is parsed which causes a small (1-2 second) delay. It's enough of a delay to be annoying and make the UI feel sluggish.
Is there a way to use the DataTemplate pattern without destroying and recreating the view each time a viewmodel is bound? I'd rather not change the viewmodel if possible.
For this case the easiest solution is to have the two views always there and change which one is visible. You can use a converter to change the visibility based on the type of the data context
<View1 Visibility="{Binding Converter={StaticResource TypeToVisibilityConverter, ConverterParameter=VM1}" />
<View2 Visibility="{Binding Converter={StaticResource TypeToVisibilityConverter, ConverterParameter=VM2}" />
And the converter will check if the type matches with the parameter to return Visible, or Collapsed otherwise.
You could wrap your VM into an additional class. Your DataTemplates will decide on the type of the Wrapper class but the real implementation will be exposer through a property of this Wrapper. When this property will change the DataTemplate wont be reloaded but all the bindings will be refreshed.
Wrapper class:
public class WrapperVM1:INotifyPropertyChanged
{
public Content VM1 { get{...} set{...} }
}
public class WrapperVM2:INotifyPropertyChanged
{
public Content VM2 { get{...} set{...} }
}
Now your data templates will describe wrapper class representations:
<DataTemplate DataType="{x:Type local:WrapperVM1}">
<TextBlock Text={Binding Content.SomPropertyInVM1}"/>
</DataTemplate>
<DataTemplate DataType="{x:Type local:WrapperVM2}">
<TextBlock Text={Binding Content.SomPropertyInVM2}"/>
</DataTemplate>
As you can see if you substitute the Content property of the wrapper with a new instance of VM this won't recreate the view but all bindings will update. However if you need to switch to other type of VM you will have to substitute the Wrapper class by the appropriate Wrapper.
I'm wondering how to go about creating different views in the main window when a button is pressed. I'm not sure of the correct terminology, so that has hampered my google fu.
I'm thinking that the main viewing area would be a content control, that I could change when a event happens. I made a small drawing to help illustrate my idea / thought.
Any input will be appreciated. Thanks!
It would be really easy to implement this senario using MVVM approach....
Make a ViewModel for you MainView. Then Define Properties of the ViewModels of your UserControls
For Example You have Two UserControl as FirstView and SecondView then make a properties in your viewmodels as ViewToLoadProperty of the type ViewModel (usually called as ViewModelBase)
Set bindings as
<!-- Panel For Hosting UserControls -->
<Border Grid.Column="2">
<ContentControl Name="userControlContentControl"
Content="{Binding Path=ViewToLoadProperty,
}">
<ContentControl.Resources>
<DataTemplate DataType="{x:Type ViewModelLayer:FirstViewModel}">
<ViewLayer:FirstView/>
</DataTemplate>
<DataTemplate DataType="{x:Type ViewModelLayer:SecondViewModel}">
<ViewLayer:SecondView />
</DataTemplate>
</ContentControl.Resources>
</ContentControl>
</Border>
<!-- Panel For Hosting UserControls -->
Then when you click the button Use a command to set the respective ViewModel Intance to this(ViewToLoadProperty) property...(Use RelayCommannds or something like it)
DataTempates would do the rest of the job by selecting the right View according to the right type of ViewModel
YOu can use MVVMLight toolkit if you are implementing MVVM Pattern.. :)
On the right you could have a frame. Then the button would bind a different page or user control to the content of that frame.