Develop Reference

How to override(use) BitmapFrame.Thumbnail property in WPF C#?

Hello! The problem is? that I've got a multipage Tiff file to show, and I use
BitmapFrame.Thumbnail property to show small size thumbnail of every frame(page) of my multipage Tiff file. But< for some reason? the property returns null. Please, give step by step description, of how this should be done?
I've already tried to create my own BitmapSource thumbnail with this method:
public static BitmapImage GetThumbnail(BitmapFrame bitmapFrame)
{
try
{
JpegBitmapEncoder encoder = new JpegBitmapEncoder();
MemoryStream memorystream = new MemoryStream();
BitmapImage tmpImage = new BitmapImage();
encoder.Frames.Add(bitmapFrame);
encoder.Save(memorystream);
tmpImage.BeginInit();
tmpImage.CacheOption = BitmapCacheOption.OnLoad;
tmpImage.StreamSource = new MemoryStream(memorystream.ToArray());
File.WriteAllBytes( $"{Path.GetTempFileName()}.jpg", memorystream.ToArray());
tmpImage.UriSource = new Uri($"{Path.GetTempFileName()}.jpg");
tmpImage.DecodePixelWidth = 80;
tmpImage.DecodePixelHeight = 120;
tmpImage.EndInit();
memorystream.Close();
return tmpImage;
}
catch (Exception ex)
{
return null;
throw ex;
}
}
then I convert the result to BitmapSource and create a list of BitmapFrames using:
List<BitmapFrame> tiffImageList = new List<BitmapFrame>();
tiffImageList.Add(new TiffImage() { index = imageIndex, image = BitmapFrame.Create(frame, (BitmapSource)GetThumbnail(frame))});
In the end I try to get property, but it returns null:
foreach (var tiffImage in tiffImageList)
{
Image image = new Image();
image.Source = tiffImage.image.Thumbnail;
}

I ran into a similar issue, modifying with the SDK PhotoViewerDemo example. Some valid jpg's are shown as white square thumbnails.
I think I found why the question code does not work. Ivan's question provides a correct constructor of BitmapFrame, but the functions have to create a BitmapSource, not a BitmapImage.
C# BitmapFrame.Thumbnail property is null for some images
I got it working with the function provided in that topic, using Ivan's call to the constructor, using the two bitmapsource arguments.
Code in the SDK example I now use is..
private BitmapSource CreateBitmapSource(Uri path)
{
BitmapImage bmpImage = new BitmapImage();
bmpImage.BeginInit();
bmpImage.UriSource = path;
bmpImage.EndInit();
return bmpImage;
}
private BitmapSource CreateThumbnail(Uri path)
{
BitmapImage bmpImage = new BitmapImage();
bmpImage.BeginInit();
bmpImage.UriSource = path;
bmpImage.DecodePixelWidth = 120;
bmpImage.EndInit();
return bmpImage;
}
// it has to be plugged in here,
public Photo(string path)
{
Source = path;
_source = new Uri(path);
// replaced.. Image = BitmapFrame.Create(_source);
// with this:
Image = BitmapFrame.Create(CreateBitmapSource(_source),CreateThumbnail(_source));
Metadata = new ExifMetadata(_source);
}

how to get header text with image from .DOCX file

i want to get header image form doc file. i use following code it gives me image path but i can't get it
DocumentFormat.OpenXml.Packaging.ImagePart img = header.ImageParts.FirstOrDefault();
string imgpath = img.Uri.OriginalString;

I think your approach didn't work because the doc file is a zip file.
I don't know in which format you need that image, but you can try something like this to retrieve an image object. I updated my answer with an working example hope it helps.
using (var document = WordprocessingDocument.Open("your document path", true))
{
//Get the header
var header = document.MainDocumentPart.HeaderParts.First();
//These are your paragraphs where you can get the headers Text from
var paragraphList = header.Header.Descendants<DocumentFormat.OpenXml.Wordprocessing.Paragraph>();
//Get the imageId
string imgId = header.GetIdOfPart(header.ImageParts.First());
var imageSource=new BitmapImage();
//Get the imageStream
using (var imgStream = ((ImagePart)header.GetPartById(imgId)).GetStream())
{
//Copy stream to BitmapImage
using (var memoryStream = new MemoryStream())
{
imgStream.CopyTo(memoryStream);
memoryStream.Position = 0;
imageSource.BeginInit();
imageSource.CreateOptions = BitmapCreateOptions.PreservePixelFormat;
imageSource.CacheOption = BitmapCacheOption.OnLoad;
imageSource.UriSource = null;
imageSource.StreamSource = memoryStream;
imageSource.EndInit();
}
imageSource.Freeze();
//Save BitmapImage to file
var encoder = new PngBitmapEncoder();
encoder.Frames.Add(BitmapFrame.Create(imageSource));
using (var stream = new FileStream("your path for the image.png", FileMode.Create))
encoder.Save(stream);
}
}
and this is an example how you can get position of your picture, but keep in mind it will only work if your picture got an absolute position.
List<DocumentFormat.OpenXml.Wordprocessing.Drawing> sdtElementDrawing =
header.Header.Descendants<DocumentFormat.OpenXml.Wordprocessing.Drawing>().ToList();
var distL= sdtElementDrawing.First().Anchor.DistanceFromLeft;

ObjectDisposedException when I try to use an Image source

I need to add an Image to my Panel, so I use the following code:
var image = new Image();
var source = new BitmapImage();
source.BeginInit();
source.CacheOption = BitmapCacheOption.OnLoad;
source.StreamSource = new FileStream(filename, FileMode.Open);
source.EndInit();
// I close the StreamSource so I can load again the same file
source.StreamSource.Close();
image.Source = source;
The problem is that when I try to use my image source I get an ObjectDisposedException:
var source = ((BitmapImage)image.Source).StreamSource;
// When I use source I get the exception
using (var stream = new MemoryStream((int)(source.Length)))
{
source.Position = 0;
source.CopyTo(stream);
// ...
}
It happens because I closed the source, but if I don't close it I can't be able to load again the same file.
How can I solve this problem (i.e. close the source to be able to load the same file more than once, and to be able to use the source without get the exception)?

The following solution should work for you:
var image = new Image();
var source = new BitmapImage();
source.BeginInit();
source.CacheOption = BitmapCacheOption.OnLoad;
// Create a new stream without disposing it!
source.StreamSource = new MemoryStream();
using (var filestream = new FileStream(filename, FileMode.Open))
{
// Copy the file stream and set the position to 0
// or you will get a FileFormatException
filestream.CopyTo(source.StreamSource);
source.StreamSource.Position = 0;
}
source.EndInit();
image.Source = source;

Convert raw images to bitmap in c#

My code currently looks like this:
if (fe == "CR2")
{
Image img = null;
byte[] ba = File.ReadAllBytes(open.FileName);
using (Image raw = Image.FromStream(new MemoryStream(ba)))
{
img = raw;
}
Bitmap bm = new Bitmap(img);
pictureBox1.Image = bm;
statusl.Text = fe;
}
When I open a RAW image the program stops and Visual Studio says:
Parameter is not valid: Image raw = Image.FromStream(new MemoryStream(ba))
Please help! How can I get a RAW file to show in a PictureBox ?

Create the bitmap like this:
Bitmap bmp = (Bitmap) Image.FromFile(open.FileName);
or without using bitmap:
this.pictureBox1.Image = Image.FromFile(open.FileName);
Example WPF:
BitmapDecoder bmpDec = BitmapDecoder.Create(new Uri(origFile),
BitmapCreateOptions.DelayCreation, BitmapCacheOption.None);
BitmapEncoder bmpEnc = new BmpBitmapEncoder();
bmpEnc.Frames.Add(bmpDec.Frames[0]);
Stream ms = new MemoryStream();
bmpEnc.Save(ms);
Image srcImage = Bitmap.FromStream(ms);

You're actually disposing an Image by specifying using (Image raw = Image.FromStream(new MemoryStream(ba))) later assigning the Disposed instance of image to picturebox which leads to this exception. To make to work you've to either don't dispose or clone the image.
Bitmap raw = Image.FromStream(new MemoryStream(ba) as Bitmap;
pictureBox1.Image = raw;
Or simply Clone
using (Image raw = Image.FromStream(new MemoryStream(ba)))
{
img = raw.Clone() as Bitmap;
}
Both of the above should work

you try this code :
private static void SaveImageToRawFile(string strDeviceName, Byte[] Image, int nImageSize)
{
string strFileName = strDeviceName;
strFileName += ".raw";
FileStream vFileStream = new FileStream(strFileName, FileMode.Create);
BinaryWriter vBinaryWriter = new BinaryWriter(vFileStream);
for (int vIndex = 0; vIndex < nImageSize; vIndex++)
{
vBinaryWriter.Write((byte)Image[vIndex]);
}
vBinaryWriter.Close();
vFileStream.Close();
}
private static void LoadRawFile(string strDeviceName, out Byte[] Buffer)
{
FileStream vFileStream = new FileStream(strDeviceName, FileMode.Open);
BinaryReader vBinaryReader = new BinaryReader(vFileStream);
Buffer = new Byte[vFileStream.Length];
Buffer = vBinaryReader.ReadBytes(Convert.ToInt32(vFileStream.Length));
vBinaryReader.Close();
vFileStream.Close();
}

Get Thumbnail from a smooth streaming file (.ism)

Does any body know how to get a thumbnail/snapshot of a specific frame of a smooth streaming file using C#.net and WPF.
Regards,
Allan

Here MyPanel is the container where your video is streaming.
var panelPoint = this.MyPanel.PointToScreen(new Point(this.MyPanel.ClientRectangle.X, this.MyPanel.ClientRectangle.Y));
using (var bitmap = new Bitmap(320, 240))
{
using (var graphics = Graphics.FromImage(bitmap))
{
graphics.CopyFromScreen(320, Point.Empty, new Size(320, 240));
}
if (SimpleIoc.Default.ContainsCreated<ICommonApplicationData>())
{
var imageGuidName = Guid.NewGuid();
fileName = Path.Combine("C:\", "TestFolder", imageGuidName + ".jpg");
bitmap.Save(fileName, ImageFormat.Jpeg);
var tempBitmapImage = new BitmapImage();
tempBitmapImage.BeginInit();
tempBitmapImage.UriSource = new Uri(fileName);
tempBitmapImage.EndInit();
image.Source = tempBitmapImage;
}
}