I have written this segment of C# to help me understand how nested for loops can be used to render 2 dimensional data.
Here is what the output looks like.
████
███
██
█
I would like to make it so that the 4 blocks up top are rendered at the bottom, basically in the reverse order so that the steps ascend. However the console window only renders downward, so the conventional thinking won't be right. The following is my code.
static void Main(string[] args)
{
int i = 0;
int j = 0;
for (i = 0; i < 4; i++)
{
Console.Write('\n');
for (j = i; j < 4; j++)
{
Console.Write("█");
}
}
Console.ReadKey();
}
This is what I'd like the output to look like.
█
██
███
████
You need to reverse your loop condition from inremant to decremant..
for (i = 0; i < 4; i++)
{
Console.Write('\n');
for (j = i; j >= 0; j--)
{
Console.Write("█");
}
}
Output will be;
Here is a DEMO.
UPDATE: Since you change your mind, you need to add space every column (column number isi) 4 - 1 times.
public static void Main(string[] args)
{
int i = 0;
int j = 0;
for ( i = 0; i < 4; i++ )
{
for ( j = 0; j < 4; j++ )
{
if ( j < 3 - i )
Console.Write(" ");
else
Console.Write("█");
}
Console.Write('\n');
}
Console.ReadKey();
}
Here is a DEMO.
class Program
{
const int Dimension = 4;
static void Main(string[] args)
{
char[] blocks = new char[Dimension];
for (int j = 0; j < Dimension; j++)
blocks[j] = ' ';
for (int i = 0; i < Dimension; i++)
{
blocks[Dimension - i - 1] = '█';
for (int j = 0; j < Dimension; j++)
Console.Write(blocks[j]);
Console.WriteLine();
}
Console.ReadKey();
}
}
Should be:
for (j = 3 - i; j < 4; j++)
{
Console.Write("█");
}
The easiest way would be: just reverse your inner loop condition and decrement the counter instead of incrementing it:
for (i = 0; i < 4; i++)
{
Console.Write('\n');
for (j = i; j >= 0; j--)
{
Console.Write("█");
}
}
Console.ReadKey();
returning:
█
██
███
████
And for right-to-left version:
for (i = 0; i < 4; i++)
{
for(j = 0; j < 4; j++)
{
if(j < 3 - i)
Console.Write(" ");
else
Console.Write("█");
}
Console.Write('\n');
}
Console.ReadKey();
with a result:
█
██
███
████
Related
Hello. I have this task to sum the numbers as shown. Tried everything I can, but still not the right answer. Can I have some guidance?
static void Main(string[] args)
{
string input = Console.ReadLine();
int n = (int)char.GetNumericValue(input[0]);
int m = (int)char.GetNumericValue(input[2]);
int[,] matrix = new int[n, m];
int sum = 0;
//fill matrix
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++)
{
matrix[i, j] = (j * 3 + 1) + i * 3;
}
}
for (int i = 0; i < matrix.GetLength(0) - 1; i+=1)
{
for (int j = 0; j < matrix.GetLength(1) - i; j+=1)
{
if (i % 2 == 0)
{
sum += matrix[i, j + i] + matrix[i + 1, j + 1];
}
}
}
Console.WriteLine(sum);
}
I think you would've a easier time hard coding the input (and naming them as "columns" and "rows" instead, much more readable).
What is the expected output? Not sure I'm following this sum. I'm guessing, 297? If so:
for (int i = 0; i < matrix.GetLength(0); i++)
{
for (int j = 0; j < matrix.GetLength(1); j++)
{
Console.Write(matrix[i, j] + " ");
if(j == 5) Console.WriteLine();
if (matrix[i, j] % 2 != 0)
{
if (i == 0 || i == matrix.GetLength(0) - 1
|| j == 0 || j == matrix.GetLength(0))
{
sum += (matrix[i, j]);
}
else
{
sum += (matrix[i, j] * 2);
}
}
}
}
I need help with checking IF the position in array must save ' ' or '*' for later in program to print out a pyramid.
static void Main(string[] args)
{
Console.WriteLine("Enter size: ");
int s = int.Parse(Console.ReadLine());
char[,] pyramid = new char[s, s * 2 - 1];
FillArray(pyramid);
Out(pyramid);
Console.ReadLine();
}
static void FillArray(char[,] t)
{
for (int i = 0; i < t.GetLength(0); i++)
{
for (int j = 0; j < t.GetLength(1); j++)
{
if (j == t.GetLength(1) / 2 || j == t.GetLength(1) / 2 + i || j == t.GetLength(1) / 2 - i)
{
t[i, j] = '*';
}
else t[i, j] = ' ';
}
}
}
static void Out(char[,] t)
{
for (int i = 0; i < t.GetLength(0); i++)
{
for (int j = 0; j < t.GetLength(1); j++)
{
Console.Write(t[i, j]);
}
Console.WriteLine();
}
}
At the moment I get out something like this:
The code should be like this
int i, j, n;
Console.WriteLine("Enter size: ");
n = int.Parse(Console.ReadLine());
for (i = 0; i < n; i++)
{
for (j = 1; j <= n - i; j++)
Console.Write(" ");
for (j = 1; j <= 2 * i - 1; j++)
Console.Write("*");
Console.Write("\n");
}
I'm trying to learn how to work with 2D-array and I can't seem to understand how to print them correctly. I want to print them in a "square" like 5x5 but all I get is one line. I've tried both WriteLine and Write and changed some of the variables in the loops but I get either an error or not the result I want to have. The code is supposed to print out a 5x5 with a random sequence of 15 numbers in each column. I get the correct numbers out of it, it's only the layout that is wrong.
static void Main(string[] args)
{
Random rnd = new Random();
int[,] bricka = new int[5, 5];
int num = 0;
int num1 = 1;
for (int i = 0; i < bricka.GetLength(1); i++)
{
num += 16;
for (int j = 0; j < bricka.GetLength(0); j++)
{
bricka[j, i] = rnd.Next(num1, num);
}
num1 += 16;
}
for (int i = 0; i < bricka.GetLength(0); i++)
{
for (int j = 0; j < bricka.GetLength(1); j++)
{
Console.Write(bricka[i, j]+ " " );
}
}
Console.ReadKey();
}
This is my print, I would like to have the the 12 under the 8 and 14 under the 12 and so on.
http://i.imgur.com/tfyRxf1.png
You need to call WriteLine() after each line, so that each line is printed on a separate line:
for (int i = 0; i < bricka.GetLength(0); i++)
{
for (int j = 0; j < bricka.GetLength(1); j++)
{
Console.Write(bricka[i, j]+ " " );
}
Console.WriteLine();
}
That would be one way of doing it, anyway.
Is there any relation between number of neurons and ability of Hopfield network to recognize patterns?
I write neural network program in C# to recognize patterns with Hopfield network. My network has 64 neurons. When I train network for 2 patterns, every things work nice and easy, but when I train network for more patterns, Hopfield can't find answer!
So, according to my code, how can I use Hopfield network to learn more patterns?
Should I make changes in this code?
There is my train() function:
public void Train(bool[,] pattern)
{
//N is number of rows in our square matrix
//Convert input pattern to bipolar
int[,] PatternBipolar = new int[N, N];
for (int i = 0; i < N; i++)
for (int j = 0; j < N; j++)
{
if (pattern[i, j] == true)
{
PatternBipolar[i, j] = 1;
}
else
{
PatternBipolar[i, j] = -1;
}
}
//convert to row matrix
int count1 = 0;
int[] RowMatrix = new int[(int)Math.Pow(N, 2)];
for (int j = 0; j < N; j++)
for (int i = 0; i < N; i++)
{
RowMatrix[count1] = PatternBipolar[i, j];
count1++;
}
//convert to column matrix
int count2 = 0;
int[] ColMatrix = new int[(int)Math.Pow(N, 2)];
for (int j = 0; j < N; j++)
for (int i = 0; i < N; i++)
{
ColMatrix[count2] = PatternBipolar[i, j];
count2++;
}
//multiplication
int[,] MultipliedMatrix = new int[(int)Math.Pow(N, 2), (int)Math.Pow(N, 2)];
for (int i = 0; i < (int)Math.Pow(N, 2); i++)
for (int j = 0; j < (int)Math.Pow(N, 2); j++)
{
MultipliedMatrix[i, j] = ColMatrix[i] * RowMatrix[j];
}
//cells in the northwest diagonal get set to zero
for (int i = 0; i < (int)Math.Pow(N, 2); i++)
MultipliedMatrix[i, i] = 0;
// WightMatrix + MultipliedMatrix
for (int i = 0; i < (int)Math.Pow(N, 2); i++)
for (int j = 0; j < (int)Math.Pow(N, 2); j++)
{
WeightMatrix[i, j] += MultipliedMatrix[i, j];
}
And there is Present() function (this function is used to return answer for a given pattern):
public void Present(bool[,] Pattern)
{
int[] output = new int[(int)(int)Math.Pow(N, 2)];
for (int j = 0; j < N; j++)
for (int i = 0; i < N; i++)
{
OutputShowMatrix[i, j] = 0;
}
//convert bool to binary
int[] PatternBinary = new int[(int)Math.Pow(N, 2)];
int count = 0;
for (int j = 0; j < N; j++)
for (int i = 0; i < N; i++)
{
if (Pattern[i, j] == true)
{
PatternBinary[count] = 1;
}
else
{
PatternBinary[count] = 0;
}
count++;
}
count = 0;
int activation = 0;
for (int j = 0; j < (int)Math.Pow(N, 2); j++)
{
for (int i = 0; i < (int)Math.Pow(N, 2); i++)
{
activation = activation + (PatternBinary[i] * WeightMatrix[i, j]);
}
if (activation > 0)
{
output[count] = 1;
}
else
{
output[count] = 0;
}
count++;
activation = 0;
}
count = 0;
for (int j = 0; j < N; j++)
for (int i = 0; i < N; i++)
{
OutputShowMatrix[i, j] = output[count++];
}
In below images I trained Hopfield for characters A and P and when input patterns are like A or P, network recognize them in true way
Then I train it for character C:
This is where every things go wrong!
Now if I enter pattern like C, this issue happen:
And if enter pattern like A, see what happen:
And if train more patterns, whole of grid become black!
I've spotted only one mistake in your code: you perform only one iteration of node value calculation, without verifying if the values have converged. I've fixed this method like this:
public bool[,] Present(bool[,] pattern)
{
bool[,] result = new bool[N, N];
int[] activation = new int[N * N];
int count = 0;
for (int i = 0; i < N; i++)
for (int j = 0; j < N; j++)
{
activation[count++] = pattern[i, j] ? 1 : 0;
}
bool convergence = false;
while (!convergence)
{
convergence = true;
var previousActivation = (int[])activation.Clone();
for (int i = 0; i < N * N; i++)
{
activation[i] = 0;
for (int j = 0; j < N * N; j++)
{
activation[i] += (previousActivation[j] * WeightMatrix[i, j]);
}
activation[i] = activation[i] > 0 ? 1 : 0;
if (activation[i] != previousActivation[i])
{
convergence = false;
}
}
}
count = 0;
for (int i = 0; i < N; i++)
for (int j = 0; j < N; j++)
{
result[i, j] = activation[count++] == 1;
}
return result;
}
This slightly improves the results, however probably should also be improved to calculate the values asynchronously to avoid cycles.
Unfortunately, this still introduces the behaviour you've described. This is results from the phenomena called spurious patterns. For the network to learn more than one pattern consider training it with a Hebb rule. You can read about the spurious patterns, stability and learning of the Hopfield network here and here.
So I'm attempting to print a multiplication table in C# however I can't quite figure out how to get what I need.
So far my program outputs the following:
1 2 3
2 4 6
3 6 9
However, I need it to output this:
0 1 2 3
1 1 2 3
2 2 4 6
3 3 6 9
I've tried a lot of different ways to get the second output however I can't quite figure it out. I'm not necessarily asking for an answer but if someone could point me in the right direction it would be much appreciated.
This is the code I have as of now:
static void Main(string[] args)
{
for (int i = 1; i <= 3; i++)
{
for (int j = 1; j <= 3; j++)
{
Console.Write(i * j + "\t");
}
Console.Write("\n");
}
Console.ReadLine();
}
for (int i = 0; i <= 3; i++)
{
Console.Write(i + "\t");
for (int j = 1; j <= 3; j++)
{
if (i>0) Console.Write(i * j + "\t");
else Console.Write(j + "\t");
}
Console.Write("\n");
}
int tbl= int.Parse(Console.ReadLine());
int j = int.Parse(Console.ReadLine());
for (int i=1; i<=10; i++)
{
for (int j=1;j<=10; j++)
{
Console.WriteLine("{0}*{1}={2}", i, j, (i * j));`enter code here`
}
}
Console.ReadLine();
You should skip both 0's.
for (int i = 0; i <= 3; i++)
{
for (int j = 0; j <= 3; j++)
{
Console.Write((i == 0? j : (j == 0? i : i*j)) + "\t");
}
Console.Write("\n");
}
You could try one of this three solutions.
Solution 1 (without if else statement):
static void Main(string[] args)
{
for (int i = 0; i <= 3; i++)
{
Console.Write("{0}\t", i);
for (int j = 1; j <= 3; j++)
{
Console.Write("{0}\t", i * j);
}
Console.WriteLine();
}
Console.ReadLine();
}
Solution 2 (With if else statement):
static void Main(string[] args)
{
for (int i = 0; i <= 3; i++)
{
for (int j = 1; j <= 3; j++)
{
if (i == 0)
{
Console.Write("{0}\t", i);
}
else
{
Console.Write("{0}\t", i * j);
}
}
Console.WriteLine();
}
Console.ReadLine();
}
Solution 3 (With short-hand if else statement):
static void Main(string[] args)
{
for (int i = 0; i <= 3; i++)
{
for (int j = 1; j <= 3; j++)
{
Console.Write("{0}\t", (i == 0) ? i : i * j);
}
Console.WriteLine();
}
Console.ReadLine();
}
for (int i = 0; i <= 3; i++)
{
for (int j = 0; j <= 3; j++)
{
if (i == 0)
{
Console.Write(j);
}
else
{
if(j == 0)
{
Console.Write(i);
}
else
{
Console.Write(i * j);
}
}
}
Console.Write("\n");
}
Console.WriteLine("Enter A Number");
int j = Convert.ToInt32(Console.ReadLine());
for (int i = 0 ; i <= 10; i++) {
Console.WriteLine("{1} X {0} = {2}",i,j,i*j);
Console.ReadLine();
}
public class Program
{
//int num;
public static void Main(string[] args)
{
int num,num1;
Console.WriteLine("enter a any number num");
num = Convert.ToInt32(Console.ReadLine());
Console.WriteLine("enter any second number num1");
num1 = Convert.ToInt32(Console.ReadLine());
for(int i = num;i <= num1; i++)
{
for (int j = 1; j <= 10; j++)
{
Console.Write(i *j+ "\t");
}
}
Console.Write("\n");
}
}
using System;
/*
* Write a console-based application that displays a multiplication table of the product of
* every integer from 1 through 10 multiplied by every integer from 1 through 10. Save the
* file as DisplayMultiplicationTable.cs.
*/
namespace MultiplicationTable
{
class Program
{
static void Main(string[] args)
{
Console.WriteLine("\t\t\t\t\t\t\t\t\tMultiplication Table");
Console.WriteLine("------------------------------------------------------------------------------------------------------------------------------------------------------------");
const int END = 11;
for(int x = 1; x < END; x++)
{
for(int y = 1; y < END; y++)
{
int value = x * y;
Console.Write("{0} * {1} = {2}\t", y, x, value);
}
Console.WriteLine();
}
Console.ReadLine();
}
}
}
Output
Output of Code
I am attempting to complete the above code in a GUI. So far I have come up with the following code; but the output is not like the above output.
My Code for the GUI is as follows:
using System;
using System.Windows.Forms;
namespace DisplayMultiplicationTableGUI
{
public partial class Form1:Form
{
public Form1()
{
InitializeComponent();
}
private void ShowTableButton_Click(object sender, EventArgs e)
{
int a;
int b;
const int STOP = 11;
for(a = 1; a < STOP; a++)
{
for(b = 1; b < STOP; b++)
{
int value = a * b;
multiplicationTableLabel.Text += String.Format("{0} * {1} = {2} ", b, a, value);
}
multiplicationTableLabel.Text += "\n";
}
}
}
}