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Closed 10 years ago.
Im struggling to get the right syntax to use in c# for the vb function FormatNumber...i will say that 'iPremium' is an object as it returns data from a tableadapter.
the value that 'ipremium' holds is 943.4000 and the idea is to only have two decimal places after the '.', i would hope this is acheivable using the right syntax but unfortunately not being a c# expert, it could take a while to figure this out.
here's the vb code:
iPremium = FormatNumber(iPremium, 2, TriState.True)
any idea's on how this is acheivable?
thanks for any idea's and suggestions and excuse the ignorance if this is not worded correctly
var formattedNumber = iPremium.ToString("0.00");
or, if you wish to round the number, instead of just chopping-off precision:
var formattedNumber = Math.Round(iPremium, 2).ToString("0.00").Dump();
Here's a list of the various formats you can use with ToString: http://msdn.microsoft.com/en-us/library/dwhawy9k.aspx
var roundedNumber = Math.Round(iPremium, 2);
var formattedNumber = String.Format("{0:#.##}", roundedNumber);
I assume the TableAdapter returns a Datatable which can also be used strongly typed:
// first row as example (add using.System.Linq)
double value = table.AsEnumerable().First().Field<double>("iPremium");
Now you can use String.Format or just ToString with a custom format:
string result = value.ToString("0.00");
Related
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Closed 9 years ago.
To cut to the chase, when performing some calculations within my code i have a result that is something like. 7.6742332E-30, i have this value stored in a double variable for example, double result = 7.6742332E-30;
When i later check whether this value is greater than 0 the result is true, that it is greater than 0, i assume due to the 7.6742332.
So my question is this, why is the E-30 not being considered and how do i resolve this?
Any advice would be great and thanks so much i advance!
7.6742332E-30 is 0.0000000000000000000000000000076742332, which is a positive number.
7.6742332E-30 mathematcally equals 7.6742332 x 10^-30 which is a positive number
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Closed 10 years ago.
I am currently working on a console text analysis program for an assignment.
My problem is, I need to save all user entered words above 7 letters to a text file. The user can enter words by typing in their paragraph or by loading from a text file.
Any ideas on how I can do this ?
Thanks for any help in advance
Without giving you the code, think about what you really need to do.
Read in the entire text.
Split the text based on spaces / punctuation to identify each word. This will be stored in an array.
Test each split string's length.
Write the results to a file.
I'm not sure how you're getting the user-entered words, but you can do a simple LINQ statement to get the words greater than 7 letters:
//get all words into an array (wordArray)
var bigWords = wordArray.Where(w => w.Length > 7).ToArray();
Then you do something with the bigWords array.
I'm not going to do your assignment for you.
You should check functions such as String.Split, String.Length and String.Substring()
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Closed 10 years ago.
I'm porting a c++ class to C# and i have a difficulty.
I would like to find an equivalent of SpanIncluding.
Here is my cpp code :
while (Notes.Mid(j,1).SpanIncluding("0123456789").IsEmpty()!=NULL){}
Anyone can help me please ?
I believe SpanIncluding starts matching from the start of the string, stopping when the first non-matching character is found.
So one formulation in the general case would be this:
string match = new string(someString.ToCharArray().
TakeWhile(c => "0123456789".Contains(c)).ToArray());
(or an equivalent using a regular expression).
However, in the example given in the question there's only one character so the whole thing probably boils down to a test of whether this character is >= '0' and <= '9':
while(char.IsDigit(Notes[j])) { ... };
I found the MSDN page for SpanIncluding, and it seems like a ridiculously specific function. I can't really understand what it tries to solve, since it has some strange caveats.
LINQ would be one way of implementing it:
string text = "2334562";
IEnumerable<char> spannedChars = text.TakeWhile(c => "1234567890".Contains(c));
This is a more direct port of SpanIncluding than queen3's option, if I understand the MSDN page correctly, because the result set should stop the minute it hits a character not in the spanning string.
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Closed 10 years ago.
I have this piece of coding which is supposed to receive a URL as a string and this URL is supposed to be set as the Image Url :-
Heres the code
foreach (SPListItem item in oSpListCln)
{
if (item.Title.Equals("Rubicks"))
{
Title.Text = item.Title;
lblSyp.Text = item["Sypnosis"].ToString();
PicPic.ImageUrl = item["PicPic"].ToString();
}
}
The value of item["PicPic"] is http://www.froot.nl/wp-content/uploads/quick-brown-fox-froot.jpg,http://www.froot.nl/wp-content/uploads/quick-brown-fox-froot.jpg
This doesn't work is it cause I'm setting a string as a URL of an image cause when I hard coded the link it worked but when I set the link to a string and try, it doesn't. Does anyone know a way of how to do this?
Given that the returned string is comma-separated as you wrote in comments, you could do something like:
string[] urlParts = item["PicPic"].ToString().Split(',');
PicPic.ImageUrl = urlParts[0];
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Closed 10 years ago.
I want to code this part of a VB6 application in c#.
How can I change a long into a Hex value?
Public Function longToHex(l As Long) As String
longToHex = Hex(l)
If Len(longToHex) < 4 Then longToHex = String(4 - Len(longToHex), "0") & longToHex
longToHex = Right(longToHex, 2) & Left(longToHex, 2)
End Function
Just format to a padded hex string:
string.Format("{0:X4}", myLong.ToString().Length / 2)
Then transpose the first two characters with the last two.
The VB6 code appears to take the length of sData divided by 2, then converts the length to a Hex string and pads it with 0s to 4 characters if needed. It then transposes the first two characters with the last two.
Seems convoluted -- what is the code supposed to do? Half the length of the string in hex?
This might work: sLen = (sData.length / 2).ToString("X")