Develop Reference

Reading data from System.IO.Stream to text or a file

I am using HttpWebRequest.GetStreamData() to get data from stream and then writing a couple of files in that variable.
Before calling the GetResponse() method on the stream, I need to get the copy of data and put it in text format.
Here's my code snippet
HttpWebRequest wr = (HttpWebRequest)WebRequest.Create(url);
wr.Method = "POST";
string requestbody = "Some Body Text"
Stream rs = wr.GetRequestStream();
foreach (fragment in Documents).ToList())
{
byte[] requestBytes = System.Text.Encoding.UTF8.GetBytes(requestbody);
rs.Write(requestBytes, 0, requestBytes.Length);
FileStream fileStream = new FileStream(fragment.FilePath, FileMode.Open, FileAccess.Read);
byte[] buffer = new byte[4096];
int bytesRead = 0;
while ((bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0)
{
rs.Write(buffer, 0, bytesRead);
}
fileStream.Flush();
fileStream.Close();
fileStream = null;
byte[] trailer = System.Text.Encoding.ASCII.GetBytes("Trailer Text");
rs.Write(trailer, 0, trailer.Length);
}
}
using (StreamReader strm = new StreamReader(rs))
{
string text = strm.ReadToEnd();
}
rs.Close();
rs = null;
The issue is I get error "stream was not readable".
When I check the property rs.canread, it is set to false.
Can anyone help me reading the content of my rs stream.
I have tried a couple of methods but none seems to be working as of now.

Exporting byte[] results to corrupted .zip

I am trying to make a CLR with .NET 2.0 integrated into MS SQL Server 2008. I call an API with and I should receive a .zip as response. I store the response into a Stream and I want to export this file to a physical .zip file.
I tried exporting the file with C# and SQL (BCB OR OLE) and all resulted into a corrupted file. So, I believe I am doing something wrong with in the making of the stream.
The C# code is the following:
private static byte[] GetStreamFileResult(Cookie loginCookie, Guid fileGuid, String baseUri)
{
byte[] output = null;
//String result = null;
string url = "some url"
CookieContainer cookies = new CookieContainer();
cookies.Add(new Uri(url), loginCookie);
WebRequest request = WebRequest.Create(url);
(request as HttpWebRequest).CookieContainer = cookies;
WebResponse response = request.GetResponse();
HttpWebResponse resp = response as HttpWebResponse;
Stream dataStream = response.GetResponseStream();
using (MemoryStream ms = new MemoryStream())
{
CopyStream(dataStream, ms);
output = ms.ToArray();
}
dataStream.Close();
response.Close();
return output;
}
The C# code to export the zip is the following:
File.WriteAllBytes("C:\\folder\\t.zip", stream); // Requires System.IO
The copy from stream to stream:
public static void CopyStream(Stream input, Stream output)
{
if (input != null)
{
using (StreamReader reader = new StreamReader(input))
using (StreamWriter writer = new StreamWriter(output))
{
writer.Write(reader.ReadToEnd());
}
}
}

Your CopyStream is broken. You need to talk binary. You're currently treating binary zip data as though it were text:
byte[] buffer = new byte[2048];
int bytesRead;
while((bytesRead = input.Read(buffer, 0, buffer.Length)) > 0) {
output.Write(buffer, 0, bytesRead);
}

Use fileinfo in stream

This is my code am trying to make a stream from the url and and i want to cut file into 6 pieces and download , because of that i want to connect the stream to file info but am getting some errors. thanks
FileInfo fs;
DateTime startTime = DateTime.UtcNow;
WebRequest request = WebRequest.Create("http://tegos.ru/new/mp3_full/David_Guetta_feat_Ne-Yo_and_Akon_-_Play_Hard.mp3");
WebResponse response = request.GetResponse();
using (Stream responseStream = response.GetResponseStream())
using (Stream fileStream = fs new FileInfo("")))
error 'System.IO.FileInfo' is a 'type' but is used like a 'variable'

Assuming you want to copy the stream from your HTTP response to a file:
using (Stream output = File.OpenWrite("pah_to_file"))
{
using (Stream input = http.Response.GetResponseStream())
{
byte[] buffer = new byte[2048]; // some buffer
int bytesRead;
while ((bytesRead = input.Read(buffer, 0, buffer.Length)) > 0)
{
output.Write(buffer, 0, bytesRead);
}
}
}
If it's not the case, do rephrase your question.

Download a file and read from it in the same time

I download a file with this method:
WebClient WC = new WebClient();
WC.DownloadFile(url, filePath);
And i want that in the same time to read the file in the same time with:
var fs = new FileStream(filePath, FileMode.Open, FileAccess.Read, FileShare.None);
but i get allways :
The process cannot access the file 'filePath' because it is being used by another process.
It's possible to download and read in the same time?
Edit
I now download the file with:
var req = (HttpWebRequest)HttpWebRequest.Create(url);
var fileStream = new FileStream(filePath,
FileMode.Create, FileAccess.ReadWrite, FileShare.ReadWrite);
using (var resp = req.GetResponse())
{
using (var stream = resp.GetResponseStream())
{
byte[] buffer = new byte[0x10000];
int len;
while ((len = stream.Read(buffer, 0, buffer.Length)) > 0)
{
fileStream.Write(buffer, 0, len);
}
}
}
And still get the error....

var req = (HttpWebRequest)HttpWebRequest.Create(url);
using (var resp = req.GetResponse())
{
using (var stream = resp.GetResponseStream())
{
byte[] buffer = new byte[0x10000];
int len;
while ((len = stream.Read(buffer, 0, buffer.Length))>0)
{
//Do with the content whatever you want
// ***YOUR CODE***
fileStream.Write(buffer, 0, len);
}
}
}

Try this way :
HttpWebRequest request = (HttpWebRequest) WebRequest.Create("http://www.domain.com/file.txt");
HttpWebResponse response = (HttpWebResponse) request.GetResponse();
var stream = response.GetResponseStream();
byte[] buffer = new byte[8192];
int bytesRead = 0;
while ((bytesRead = stream.Read(buffer, 0, 8192)) > 0)
{
// handle your raw data
// you needed raw data = buffer[0 to bytesRead - 1]
}
stream.Close();
response.Close();

How to upload a file on server in c# fastly than this

Currently i am using following code , is there any better (means fast) way to upload a file, here is my complete code, it is called at each file upload:
HttpWebRequest request = (HttpWebRequest)WebRequest.Create("request_uri_string");
FileStream fileStream = new FileStream("path_to_my_file",
FileMode.Open, FileAccess.Read);
Stream requestStream = request.GetRequestStream();
byte[] buffer = new Byte[checked((uint)Math.Min(4096,
(int)fileStream.Length))];
int bytesRead = 1;
while (bytesRead != 0)
{
bytesRead = fileStream.Read(buffer, 0, buffer.Length);
if (bytesRead > 0)
{
requestStream.Write(buffer, 0, bytesRead);
}
}
requestStream.Close();
fileStream.Close();
String responseFromServer = null;
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
if (((HttpWebResponse)response).StatusDescription.Contains("OK"))
{
Encoding encode = System.Text.Encoding.GetEncoding(((HttpWebResponse)response).CharacterSet);
Stream dataStream = response.GetResponseStream();
StreamReader reader = new StreamReader(dataStream, encode);
responseFromServer = reader.ReadToEnd();
reader.Close();
dataStream.Close();
}
response.Close();

Probably not faster, but easier:
WebClient client = new WebClient();
//client.Credentials = new NetworkCredential("username", "password");
client.UploadFile(uriString,fileName);