Interesting problem posed by a friend recently: Imagine you've got a List< NodeType > of all nodes in a tree. How would you go about traversing down the tree from the root node, by row such that you find the first node with a specific value. So say that each node has 3 attributes: its name/location, the identity of its parent, and who "owns" the node. The problem is you want to find the highest node in the tree that you "own" no matter what branch its on. I understand the basic logic in so much as to find the first set of children you look for all nodes with a parent set as the first node. But how would you go about recursively search through a List<> of nodes to find the highest node you own?
You’re looking for breadth-first search. It is normally implemented using a queue:
public Node FindFirstByBreadthFirst(this Node node, Predicate<Node> match)
{
var queue = new Queue<Node>();
queue.Enqueue(tree.RootNode);
while (queue.Count > 0)
{
// Take the next node from the front of the queue
var node = queue.Dequeue();
// Process the node 'node'
if (match(node))
return node;
// Add the node’s children to the back of the queue
foreach (var child in node.Children)
queue.Enqueue(child);
}
// None of the nodes matched the specified predicate.
return null;
}
Algorithm:
Put the root node in a queue.
Repeat
Take item from queue;
Matching? return Item
Add all children to the queue
Until Queue is empty
Update: Haha, wow, this is completely wrong, I just realized (as in it is not doing what you asked for). Never mind -- looks like you already got a correct answer, anyway :)
I think I understand your problem. Let me know if I'm getting something wrong.
You have a NodeType class that looks something like this:
class NodeType
{
public string Name { get; }
public NodeType Parent { get; }
public int OwnderId { get; }
}
First order of business would be to write a function that takes a NodeType parameter and, given some enumerable collection of NodeType objects, returns all of its descendents in a recursive fashion:
IEnumerable<NodeType> GetNodeChildren(NodeType node, IEnumerable<NodeType> nodes)
{
var children = nodes.Where(n => n.Parent == node);
if (children.Any())
{
foreach (NodeType child in children)
{
yield return child;
var grandchildren = GetNodeChildren(child);
foreach (NodeType grandchild in grandchildren)
{
yield return grandchild;
}
}
}
}
Next up: write a function that takes a NodeType object and finds the highest descendent with a specified OwnerId. This is really a pretty simple operation, so I won't even define a proper function; I'll just use a lambda:
Func<NodeType, int, NodeType> findHighestDescendent = (node, id) => {
return GetNodeChildren(node).FirstOrDefault(child => child.OwnerId == id);
};
Now for any given Id value, it is quite trivial to find the highest matching NodeType:
int id = 10; // just for example
NodeType highestOwnedNode = nodes
.Select(n => findHighestDescendent(n, id))
.FirstOrDefault(n => (n != null));
public static Control FindChildControlByDepth(this Control Page, string ControlID, int depth)
{
if (depth > 10)
throw new ArgumentException("Cannot search beyond a depth of 10", "depth");
foreach (Control c in Page.Controls)
{
if (c.ID == ControlID)
return c;
if (depth > 0)
{
foreach (Control c1 in c.Controls)
{
if (c1.ID == ControlID)
return c1;
if (depth > 1)
{
foreach (Control c2 in c1.Controls)
{
if (c2.ID == ControlID)
return c2;
if (depth > 2)
{
foreach (Control c3 in c2.Controls)
{
if (c3.ID == ControlID)
return c3;
if (depth > 3)
{
foreach (Control c4 in c3.Controls)
{
if (c4.ID == ControlID)
return c4;
if (depth > 4)
{
foreach (Control c5 in c4.Controls)
{
if (c5.ID == ControlID)
return c5;
if (depth > 5)
{
foreach (Control c6 in c5.Controls)
{
if (c6.ID == ControlID)
return c6;
if (depth > 6)
{
foreach (Control c7 in c6.Controls)
{
if (c7.ID == ControlID)
return c7;
if (depth > 8)
{
foreach (Control c8 in c7.Controls)
{
if (c8.ID == ControlID)
return c8;
if (depth > 9)
{
foreach (Control c9 in c8.Controls)
{
if (c9.ID == ControlID)
return c9;
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
}
return null;
}
Related
I need to implement a DFS on a undirected graph.
My data structure is simple.
I have a Node class and a Dictionary
It contains the neighbours (Node) of each node in the graph. So the keys are nodes and the values are their directly connected nodes.
How can I implement the DFS for counting the cycles in the graph?
This is my current code:
foreach (Node n in nodeList)
{
while (loopFounded == false)
{
visitNode(n);
if (loopFounded == true)
{
loops.Add(loopIndex, new ArrayList(visiting));
visiting.Clear();
loopIndex = loopIndex + 1;
}
}
loopFounded = false;
}
The visitNode function is:
void visitNode(Node n)
{
if (visiting.Capacity != 0 && visiting.Contains(n))
{
Console.WriteLine("loop!");
loopFounded = true;
return;
}
visiting.Add(n);
if (neighbours.ContainsKey(n))
{
foreach (Node node in neighbours[n])
{
if (!visited.Contains(node) && !visiting.Contains(node))
{
visitNode(node);
}
}
visited.Add(n);
}
return;
}
It is returning only loops composed by couples of nodes...
Can someone help me? Thanks
EDIT:
Right thanks for helping earlier, I have been using and the step into and step over and it looks to be working but the nodes are not being deleted and I'm not sure why.
I actually use 5 arguments for the BST but just using the one for testing purposes. It compares and finds if it has any children no problem. Just wont set it to null.
only testing nodes with 0 or 1 children.
main
Tree aTree = new Tree();
aTree.InsertNode("a");
aTree.InsertNode("s");
aTree.InsertNode("3");
aTree.InsertNode("1");
aTree.InsertNode("p");
aTree.PreorderTraversal();
aTree.RemoveNode("p");
aTree.RemoveNode("3");
aTree.PreorderTraversal();
Console.ReadKey();
My Delete Methods are:
Tree Node
public void Remove(TreeNode root, TreeNode Delete) {
if (Data == null) {
}
if (Delete.Data.CompareTo(root.Data) < 0) {
root.nodeLeft.Remove(root.nodeLeft, Delete);
}
if (Delete.Data.CompareTo(root.Data) > 0) {
root.nodeRight.Remove(root.nodeRight, Delete);
}
if (Delete.Data == root.Data) {
//No child nodes
if (root.nodeLeft == null && root.nodeRight == null) {
root = null;
}
else if (root.nodeLeft == null)
{
TreeNode temp = root;
root = root.nodeRight;
root.nodeRight = null;
temp = null;
}
//No right child
else if (root.nodeRight == null)
{
TreeNode temp = root;
root = root.nodeLeft;
root.nodeLeft = null;
temp = null;
}
//Has both child nodes
else
{
TreeNode min = minvalue(root.nodeRight);
root.Data = min.Data;
root.nodeRight.Remove(root.nodeRight, min);
}
}
}
Find Min
public TreeNode minvalue(TreeNode node)
{
TreeNode current = node;
/* loop down to find the leftmost leaf */
while (current.nodeLeft != null)
{
current = current.nodeLeft;
}
return current;
}
Tree
public void RemoveNode(string Nation)
{
TreeNode Delete = new TreeNode(Nation);
root.Remove(root, Delete);
}
Remove is of return type void, but you're trying to assign it to root.nodeLeft and root.nodeRight, causing your type conversion error.
In general your Remove function needs to return the root of the sub-tree as the result, as in
public void Remove(TreeNode root, TreeNode Delete) {
if (Data == null) {
return null;
}
if (Delete.Data.CompareTo(root.Data) < 0) {
root.nodeLeft = (root.nodeLeft.Remove(root.nodeLeft, Delete));
return root;
}
... and so on.
Otherwise, since your nodes don't refer to their parents, there would be no way for the parent to know that the child node is gone, or that a new node is now at the root of the sub-tree.
I created a LinkedList class with a function delete to remove a certain node from the list if found, however it's not working:
public class LinkedList
{
public Node head;
<...>
public void delete(string n)
{
Node x = search(n); //returns the node to delete or null if not found
if (x != null)
x = x.next;
}
<...>
}
I figured all I needed to do is find the node and set it to the next one (so the node is "removed" out of the linked list), however it's not. If anyone could help me out it'd be much appreciated!
EDIT: Forgot to mention I have a single linked list.
EDIT2: My new code:
public void delete(string n)
{
Node x = head;
while (x != null && x.name != n)
{
if (x.next.name == n)
x.next = x.next.next;
x = x.next;
}
if (x != null)
x = null;
}
You'll want to loop through the list until the next node is the one you want to delete. Then set the current to the next nodes next node.
public void Delete(string value)
{
if (head == null) return;
if (head.Value == value)
{
head = head.Next;
return;
}
var n = head;
while (n.Next != null)
{
if (n.Next.Value == value)
{
n.Next = n.Next.Next;
return;
}
n = n.Next;
}
}
This of course assumes you only want to delete the first match.
Please critique my code. I noticed my last assert fails with value 277. I expected the value to 255 (1/2 500+10). Is this a valid test or have I done something wrong?
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using Microsoft.VisualStudio.TestTools.UnitTesting;
namespace RedBlackTree
{
public enum NodeColor
{
Red,
Black
}
public enum NodeSide
{
Left,
Right,
None
}
public class RedBlackTreeNode<T>
where T : IComparable<T>
{
public RedBlackTreeNode<T> Left { get; set; }
public RedBlackTreeNode<T> Right { get; set; }
public RedBlackTreeNode<T> Parent { get; set; }
public T Data {get; set;}
public NodeColor Color { get; set; }
public RedBlackTreeNode<T> Uncle
{
get
{
if (WhichSideAmIOn() == NodeSide.Left)
{
return this.Parent.Right;
}
else
return this.Parent.Left;
}
}
public string ToString()
{
return String.Format("Me: {0} Left: {1} Right: {2}", Data, Left != null ? Left.Data.ToString() : "null", Right != null ? Right.Data.ToString() : "null");
}
public NodeSide WhichSideAmIOn()
{
if (this.Parent == null) return NodeSide.None;
if (this.Parent.Left == this)
return NodeSide.Left;
if (this.Parent.Right == this)
return NodeSide.Right;
throw new Exception("Impossible - there can be only two sides. You must not be a child of your parent.");
}
}
public class RedBlackTree<T>
where T : IComparable<T>
{
private RedBlackTreeNode<T> Root { get; set; }
public void InsertNode(T data)
{
//make a node to hold the data - always red
RedBlackTreeNode<T> newNode = new RedBlackTreeNode<T>();
newNode.Data = data;
newNode.Color = NodeColor.Red;
//rule 1 - if the root is null, then hte new node is the root and roots can't be red.
if (Root == null)
{
Root = newNode;
Root.Color = NodeColor.Black;
return;
}
//otherwise if we're not the first node, insert by walking.
RedBlackTreeNode<T> walker = Root;
while (walker != null)
{
if (newNode.Data.CompareTo(walker.Data)< 0)
{
//walk left
if (walker.Left == null)
{
walker.Left = newNode;
newNode.Parent = walker;
break;
}
else
{
walker = walker.Left;
}
}
else if (newNode.Data.CompareTo(walker.Data) > 0)
{
//walk right
if (walker.Right == null)
{
walker.Right = newNode;
newNode.Parent = walker;
break;
}
else
{
walker = walker.Right;
}
}
else //todo: remove me
{
//we're equal, ignore this node in general
return;
}
}
//rebalance -
//at this point we have the parent , we have the newnode and we need to implement some rules.
Rebalance();
}
private void Rebalance()
{
RedBlackTreeNode<T> node = Root;
Stack<RedBlackTreeNode<T>> stack = new Stack<RedBlackTreeNode<T>>();
while (stack.Count !=0 || node !=null )
{
if (node != null)
{
stack.Push(node);
node = node.Left;
}
else
{
node = stack.Pop();
Rebalance(node);
node = node.Right;
}
}
}
private void Rebalance(RedBlackTreeNode<T> node)
{
if (node.Parent == null) return;
if (node.Parent.Color == NodeColor.Red) //rule 2 or 3
{
if (node.Uncle != null) //the rule 2 - change him to black as well
{
Rule2(node);
}
else //if my uncle doesn't exist, it's could be rule 3 or 4, which requires rotation
{
//if my parent and I are on the same side,
if (node.WhichSideAmIOn() == node.Parent.WhichSideAmIOn())
{
Rule3(node);
}
else
{
Rule4(node);
}
}
}
}
private void Rule2(RedBlackTreeNode<T> node)
{
//my parent + uncle needs to be black
if (node.Parent == null) throw new Exception("um how?");
node.Parent.Color = NodeColor.Black;
node.Uncle.Color = NodeColor.Black;
}
//The rule of two red nodes to the same side
//if the nodes of the tree are stacked in one direction and the two stacked nodes are red
//the middle node comes up to the parent and the top node becomes the left or right hand child.
private void Rule3(RedBlackTreeNode<T> node)
{
//make my grand parent, my parents left|right
//where am i?
NodeSide ns = node.WhichSideAmIOn();
if (node.Parent == null) throw new Exception("um how?");
RedBlackTreeNode<T> parent = node.Parent;
RedBlackTreeNode<T> grandParent = parent.Parent;
RedBlackTreeNode<T> greatGrandParent = grandParent.Parent;
//set my great, grand parent, to point at my parent
NodeSide gpSide = grandParent.WhichSideAmIOn();
if (gpSide == NodeSide.Left)
{
if (greatGrandParent !=null)
greatGrandParent.Left = parent;
}
else
{
if (greatGrandParent != null)
greatGrandParent.Right = parent;
}
//swap my grandparent into my parent's other child
if (ns == NodeSide.Left)
{
//set my parents right to my grandParent
parent.Right = grandParent;
grandParent.Left = null;
}
else if (ns == NodeSide.Right)
{
//set my parents right to my grandParent
parent.Left = grandParent;
grandParent.Right = null;
}
//reset the parent, update the root
parent.Parent = greatGrandParent;
if (greatGrandParent == null)
{
Root = parent;
}
grandParent.Parent = parent;
//swap colors
parent.Color = NodeColor.Black;
grandParent.Color = NodeColor.Red;
}
//The rule of two red nodes on different sides
//if the nodes of a tree are both red and one goes to the left, but the other goes to the right
//then the middle node becomes the parent and the top node becomes the left or right child
private void Rule4(RedBlackTreeNode<T> node)
{
if (node.Parent == null) throw new Exception("um how?");
RedBlackTreeNode<T> parent = node.Parent;
RedBlackTreeNode<T> grandParent = parent.Parent;
RedBlackTreeNode<T> greatGrandParent = grandParent.Parent;
//fix the reference that will be above me
NodeSide ns;
if (grandParent!= null)
{
ns = grandParent.WhichSideAmIOn();
//replace the reference to my grand parent with me
if (ns == NodeSide.Left)
{
greatGrandParent.Left = node;
}
else if (ns == NodeSide.Right)
{
greatGrandParent.Right = node;
}
}
//put my parent and my grand parent on the
//correct side of me.
ns = node.WhichSideAmIOn();
NodeSide parentSide = parent.WhichSideAmIOn();
if (ns == NodeSide.Left)
{
node.Left = grandParent;
node.Right = parent;
//I was the child of parent, wipe this refernce
parent.Left = null;
}
else
{
node.Left = parent;
node.Right = grandParent;
//i was the child of parent, wipe this reference
parent.Right = null;
}
parent.Parent = node;
grandParent.Parent = node;
//parent was the child of grandparent, wipe this reference
if (parentSide == NodeSide.Left) { grandParent.Left = null; }
if (parentSide == NodeSide.Right) { grandParent.Right = null; }
//reset my parent and root
node.Parent = greatGrandParent;
if (greatGrandParent == null)
{
Root = node;
}
//swap colors
node.Color = NodeColor.Black;
grandParent.Color = NodeColor.Red;
}
public void Print()
{
Stack<RedBlackTreeNode<T>> stack = new Stack<RedBlackTreeNode<T>>();
RedBlackTreeNode<T> temp = Root;
while (stack.Count != 0 || temp != null)
{
if (temp != null)
{
stack.Push(temp);
temp = temp.Left;
}
else
{
temp = stack.Pop();
Console.WriteLine(temp.Data.ToString());
temp = temp.Right;
}
}
}
public double Height
{
get
{
Stack<RedBlackTreeNode<T>> stack = new Stack<RedBlackTreeNode<T>>();
RedBlackTreeNode<T> temp = Root;
double currentHeight =0;
while (stack.Count != 0 || temp != null)
{
if (temp != null)
{
stack.Push(temp);
if (temp.Left != null || temp.Right != null)
{
currentHeight++;
}
temp = temp.Left;
}
else
{
temp = stack.Pop();
temp = temp.Right;
}
}
return currentHeight;
}
}
}
class Program
{
static void Main(string[] args)
{
RedBlackTree<int> rbt = new RedBlackTree<int>();
rbt.InsertNode(1);
rbt.InsertNode(2);
rbt.InsertNode(3);
rbt.InsertNode(4);
rbt.InsertNode(5);
rbt.InsertNode(6);
rbt.InsertNode(7);
rbt.InsertNode(8);
rbt.InsertNode(9);
rbt.InsertNode(10);
rbt.Print();
Assert.AreEqual(5, rbt.Height); //make sure sorted vals don't snake off to the left or right
//inert 500 more random numbers, height should remain balanced
Random random = new Random();
for (int i = 0; i < 500; i++)
{
rbt.InsertNode(random.Next(0, 10000));
}
Assert.AreEqual(255, rbt.Height);
}
}
}
I think your test is incorrect, although I think your code has other problems that the test isn't catching.
First of all, the Height property does not actually return the height, but the number of nodes with at least one child. If you want the height of the deepest node then you should do something like currentHeight = Math.Max(currentHeight, stack.Count) on each iteration instead. You may also want it to return an int rather than a double.
The number of nodes without children should be approximately half of them like you want, but red-black trees are not perfectly balanced. You can have a valid tree with one third of the nodes having one child, one third having two, and one third having none: start with a perfectly balanced tree with all black nodes at the last level and add a red child to each one. This maintains the red-black tree invariants, but as many as two-thirds of the nodes will have children.
Similarly, if you were to test depth it would be between log(N) and 2 log(N).
You may want to write tests that verify the invariants of the tree directly. Visit every node in the tree, and verify that every red node has a black parent and that every path to a leaf contains the same number of black nodes. If you run those tests after every insert in your test suite, you can be sure that the tree is always balanced.
As for the code itself, your Rebalance method crawls the entire tree on every insert. This means insert will require O(N) time and will negate the benefits of using a self-balancing tree. Retrieval will still be O(log N), but you could get the same result by keeping a sorted list and inserting elements into the appropriate place. You should only have to rebalance the tree along the path being inserted, which will only be O(log N) nodes.
I think some of your transformations are wrong. You don't check the color of the current node before calling Rule2, and that rule appears to change nodes to black without ensuring that other paths in the tree have the same number of black nodes. (I may be misreading it; red-black trees are too complicated to do entirely in my head.)
If you're looking for a reference implementation, the Wikipedia page on Red-black trees has an implementation in C that could easily be translated to C#, and SortedSet<T> is implemented using a red-black tree that you can view with Reflector.
Does anyone know of an algorithm that will merge treenodes in the following way?
treeA
\ child a
\node(abc)
\ child b
\node(xyz)
+
treeB
\ child a
\node(qrs)
\ child b
\node(xyz)
\node(pdq)
\ child c
\node(pdq)
= // do merge
treeMerged
\ child a
\node(abc)
\node(qrs)
\ child b
\node(xyz)
\node(pdq)
\ child c
\node(pdq)
Any help would be greatly appreciated.
Well, once I actually took the time to think about it, the solution turns out to be far more simple than I anticipated. (I've posted the critical part of the code below)
private TreeNode DoMerge(TreeNode source, TreeNode target) {
if (source == null || target == null) return null;
foreach (TreeNode n in source.Nodes) {
// see if there is a match in target
var match = FindNode(n, target.Nodes); // match paths
if (match == null) { // no match was found so add n to the target
target.Nodes.Add(n);
} else {
// a match was found so add the children of match
DoMerge(n, match);
}
}
return target;
}
Still interested to know if someone has a better solution?
Ok, I'll admit, when I first started messing with this, I didn't think it would be too hard, so I figured I'll try to do it using LINQ. It came out to be nuts, but it works. I'm SURE there are more elegant and efficient algorithms, but here it is!
First, I have a ToEnumerable extension method on the TreeNodeCollection class:
public static class TreeNodeCollectionExtensions
{
public static IEnumerable<TreeNode> ToEnumerable(this TreeNodeCollection nodes)
{
foreach (TreeNode node in nodes)
{
yield return node;
}
}
}
Then, I implement a custom comparer:
public class TreeNodeComparer : IEqualityComparer
{
public bool Equals(TreeNode x, TreeNode y)
{
return x.Text == y.Text;
}
public int GetHashCode(TreeNode obj)
{
return obj.Text.GetHashCode();
}
}
And finally, the crazyness:
private TreeView MergeTreeViews(TreeView tv1, TreeView tv2)
{
var result = new TreeView();
foreach (TreeNode node in tv2.Nodes)
{
result.Nodes.Add(node.Clone() as TreeNode);
}
foreach (TreeNode node in tv1.Nodes)
{
var nodeOnOtherSide = result.Nodes.ToEnumerable()
.SingleOrDefault(tr => tr.Text == node.Text);
if (nodeOnOtherSide == null)
{
TreeNode clone = node.Clone() as TreeNode;
result.Nodes.Add(clone);
}
else
{
var n = node.Nodes.ToEnumerable()
.Where(t => !(nodeOnOtherSide.Nodes.ToEnumerable()
.Contains(t, new TreeNodeComparer())));
foreach (TreeNode subNode in n)
{
TreeNode clone = subNode.Clone() as TreeNode;
nodeOnOtherSide.Nodes.Add(clone);
}
}
}
return result;
}
The way I coded it was that it returns a third "merged" treeView. You can change the code, so that it takes a third treeview as a parameter, so that you can pass in a treeView you may already have.
Again, I'm SURE there are better way to do this, but it SHOULD work.
One more thing I'd like to point out, this will only work for a TreeView that is two layers deep.
I came up with this recursive example, works perfect in C# (have been using it myself), note that you'll need to find a way to convert TreeNode.Nodes to an array:
public static TreeNode[] mergeTrees(TreeNode[] target, TreeNode[] source)
{
if (source == null || source.Length == 0)
{
return target;
}
if (target == null || target.Length == 0)
{
return source;
}
bool found;
foreach (TreeNode s in source)
{
found = false;
foreach (TreeNode t in target)
{
if (s.Text.CompareTo(t.Text) == 0)
{
found = true;
TreeNode[] updatedNodes = mergeTrees(Util.treeView2Array(t.Nodes), Util.treeView2Array(s.Nodes));
t.Nodes.Clear();
t.Nodes.AddRange(updatedNodes);
break;
}
}
if (!found)
{
TreeNode[] newNodes = new TreeNode[target.Length + 1];
Array.Copy(target, newNodes, target.Length);
newNodes[target.Length] = s;
target = newNodes;
}
}
return target;
}
If you are using the Node.Name attribute to set the actual path of the item, then a merge is somewhat simple.
First, create a TreeNodeCollection extension like so (this is needed to have a Case Sensitive Find() method for the TreeNodeCollection, which ensures that the Unique Path can be unique by Case as well) :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace TreeViewApp
{
public static class TreeNodeCollectionExtensions
{
public static TreeNode[] FindExact(this TreeNodeCollection coll, string keytofind)
{
TreeNode[] retval;
if (String.IsNullOrWhiteSpace(keytofind) || coll == null)
{
retval = new TreeNode[0];
}
else
{
TreeNode[] badfinds = coll.Find(keytofind, true);
List<TreeNode> goodfinds = new List<TreeNode>();
foreach (TreeNode bad in badfinds)
{
if (bad.Name == keytofind)
goodfinds.Add(bad);
}
retval = goodfinds.ToArray();
}
return retval;
}
}
}
Second, fill a treeview with your Source nodes...
Thrid, fill a treeview with your Target nodes...
Fourth, create an empty treeview.
and then, it's as simple as this:
private void btn_Merge_Click(object sender, EventArgs e)
{
//first merge
foreach (TreeNode sourceNode in this.treeview_Source.Nodes)
{
FindOrAdd(sourceNode, ref this.treeview_Merged);
}
//second merge
foreach (TreeNode targetNode in this.treeview_Target.Nodes)
{
FindOrAdd(targetNode, ref this.treeview_Merged);
}
}
private void FindOrAdd(TreeNode FindMe, ref TreeView InHere)
{
TreeNode[] found = InHere.Nodes.FindExact(FindMe.Name);
//if the node is not found, add it at the proper location.
if (found.Length == 0)
{
if (FindMe.Parent != null)
{
TreeNode[] foundParent = InHere.Nodes.FindExact(FindMe.Parent.Name);
if (foundParent.Length == 0)
InHere.Nodes.Add((TreeNode)FindMe.Clone());
else
foundParent[0].Nodes.Add((TreeNode)FindMe.Clone());
}
else
InHere.Nodes.Add((TreeNode)FindMe.Clone());
}
else
{
//if the item was found, check all children.
foreach (TreeNode child in FindMe.Nodes)
FindOrAdd(child, ref InHere);
}
}
Once again, this solution only works if you have unique paths... with the extension, it also accounts for uniqueness at the case level.
I posted this here in the hopes of helping someone who, like me, had to search for a solution for days on end without success and had to build my own.