C# - Minimize to tray at system startup - c#

In my application, I have an option to start the application when Windows is started. That works great. I also have it so that, when minimized, the application is minimized to the system tray. Is there a way that I could have it be automatically minimized when started up at the same time as Windows? The only way I could think of, is to retrieve the amount of time that they system has been on and use that data to decide whether the machine had recently started. Obviously there are a lot of flaws with that theory. Anybody have any other ideas as to how this could be done?

Implement a command line switch in your program that causes your program to minimize to the tray. When you start the program with Windows startup, just include the switch.
http://msdn.microsoft.com/en-us/library/acy3edy3.aspx

In your Form "Properties" in WindowState change to "Minimized", or in code:
//After this:
InitializeComponent();
//Place this line:
WindowState = FormWindowState.Minimized;
Hope this help!

Use a command line argument, e.g. /startminimised. In your app check for the presence of this switch (using Environment.GetCommandLineArgs) when the app starts, and automatically minimise if the switch is present.
Then in your "run on startup" option, ensure that the app is started with this switch e.g. set the Run registry key or Startup group shortcut to myapp.exe /startminimised.
When the user runs your app, however, they won't (normally!) specify the switch, so the app will appear as a window.

You can call your program with a parameter, for example "-minimized" and then handle that parameter in your program:
In your program.cs, handle the parameter, and then pass that parameter to Form1:
static void Main(string[] args)
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
if (args.Length != 0){
Application.Run(new Form1(args[0]));
}
else
{
Application.Run(new Form1("normalState"));
}
}
In your Form1.cs, you can call a function with the passed parameter and minimize the app:
public Form1(string parameter)
{
InitializeComponent();
SetStartup(); //This function will set your app in the registry to run on startup. I'll explain this function below.
MinimizeApp(parameter);
}
For example, with this function i used, if you start the application with the -minimized parameter, then it will start minimized, a notifyicon pops up in the taskbar and a bubble saying the app is started and running in the background.
public void MinimizeApp(string parameter)
{
if (parameter == "-minimized")
{
this.WindowState = FormWindowState.Minimized;
notifyIcon1.Visible = true;
notifyIcon1.BalloonTipText = "Program is started and running in the background...";
notifyIcon1.ShowBalloonTip(500);
Hide();
}
}
The SetStartup function puts your program into the registry, so it'll run on startup.
private void SetStartup(){
Microsoft.Win32.RegistryKey key;
key = Microsoft.Win32.Registry.CurrentUser.CreateSubKey(#"SOFTWARE\Microsoft\Windows\CurrentVersion\Run");
key.SetValue(AppName, Application.ExecutablePath.ToString());
string ApplicationPath = "\"" + Application.ExecutablePath.ToString() + "\" -minimized";
key.SetValue("MyApplicationName", ApplicationPath);
key.Close();
}
Right now, when you start your program with -minimized parameter, for example: "c:/programs/app.exe" -minimized then it will start minimized, and when you restart your computer, it also starts automatically minimized.

Related

How to check a Window already opened when button is clicked?

I am Working in Visual Studio 2008 Winforms Application project in Windows 7 (32 bit).I am doing the project in C#.
I have placed some buttons in a tab and added actions for that once it is clicked. While clicking the button am just running a .exe file in its action part.
My problem is that, i opened a window by clicking one button(so the .exe file is running), now while am clicking the button again it is opening same window again irrespective of checking that it is open or not. I want to solve this issue,as when a window is opened it must not open again on another click on same button. How to solve this issue. ?
Please help....
Thanks in advance..
You could check if the process is already running, when re-clicking the button:
private void btnStartExecutable_Click(object sender, EventArgs e)
{
Process[] processName = Process.GetProcessesByName("InsertProcessNameHere");
if (pname.Length == 0)
{
MessageBox.Show("Application isn't running yet.");
//Start application here
Process.Start("InsertProcessNameHere");
}
else
{
MessageBox.Show("Application is already running.");
//Don't start application, since it has been started already
}
}
You can try this:
bool processExited = true;
private void button1_Click(object sender, EventArgs e)
{
if (processExited)
{
Process process = new Process();
process.EnableRaisingEvents = true;
process.Exited += MyProcessExited;
process.StartInfo = new ProcessStartInfo();
process.StartInfo.FileName = "notepad.exe";
process.Start();
processExited = false;
}
else
{
MessageBox.Show("Still running");
}
}
void MyProcessExited(object sender, EventArgs e)
{
processExited = true;
}
The right answer here IMHO is that unless the two application shares a common resource or can talk to each other through some channel, there is no safe and efficient way to achieve what you want. Since the process is external, it could already be running before your calling app starts, or even while it's already running. You won't be able to tell if the process has been started from your app or not.
By the time I'm writing this your question does not yet state if you are in liberty to modify the external app you are calling. If you are however, using a Mutex would be a quick and easy way to solve your problem.
In your external app, whenever you want to make the other app aware of whatever condition you want (be it that the process is running or that a specific window is opened), have a Mutex instance created like this:
var mutex = new Threading.Mutex(true, "mutex unique identifier");
And in your calling app, try to create a Mutex instance with the same identifier:
bool alreadyExists;
var mutex = new Threading.Mutex(false, "mutex unique identifier", out alreadyExists);
Here the alreadyExists variable will tell you whether or not the external process is running or not. This is much safer than trying to identify it via its name, as other processes could have the same or a new version could be of a different name. Of course, the mutex identifier must be as unique as possible (like a Guid), otherwise you may encounter the same problem. ;)
Whenever you feel like the mutex must be released (at external app level), release it:
mutex.ReleaseMutex();
Note that if the process ends the mutex will be automatically released by the OS.
If the external app isn't a .NET based app, you can still create a mutex with Win32 API functions.
Thanks for the support.. I got the answer like this..
1) Creating an event'Exit' for the process in function button click
2) Define a function for the exit event where you set a flag
3) Check the flag is set or not everytime while opening the process in the function button click
Event for Exit: 'P' is the name of process:
p.Exited += new EventHandler(p_Exited);
p_Exited will be the function name where we will set the flag.
Thanks all...
If you know the name of the process that gets started or the path the .exe is run from you can use the Process class to check to see if it is currently running.
http://msdn.microsoft.com/en-us/library/system.diagnostics.process(v=vs.110).aspx

Hide icon in tray windows

I use a component in my C # application it loads the DLL, an icon appeared in the windows tray, is there any way to hide the icon in tray using the command line or any exe with arguments?
Thanks.
From the command line IMHO its not possible unless the exe supports it, eg:
static void Main(string[] args)
{
if (args.Length > 0)
{
if (args[0] == "HideFromWindowsTray")
{
this.ShowInTaskBar = false;
}
}
You could possibly do it using other techniques, eg have a wrapper exe that launches a exe and sets its ShowInTaskBar form property to False. To get inspiration on how you can do this, see HawkEye - The .Net Runtime Object Editor
ps next to each answer is a holo checkbox, tick it to accept answer and you'll get points too.

Restoring window from the system tray when allowing only one instance of that program

ok, the title is pretty long and should tell the problem i'm facing with.
Here is the code when minimizing to icon tray:
void MainFormResize(object sender, EventArgs e)
{
if (WindowState == FormWindowState.Minimized)
{
this.Hide();
this.ShowInTaskbar = false;
}
}
When the program is already opened and in sys tray, and still someone wants to open another instance of it, then:
private static void Main(string[] args)
{
bool createdNew = true;
using (Mutex mutex = new Mutex(true, "IPADcommunicator", out createdNew))
{
if (createdNew)
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new MainForm());
}
else
{
Process current = Process.GetCurrentProcess();
foreach (Process process in Process.GetProcessesByName(current.ProcessName))
{
if (process.Id != current.Id)
{
IntPtr handle = FindWindow(null,"IPADcommunicator");
SetForegroundWindow(handle);
ShowWindow(handle,5);
break;
}
}
...
Howeve, it is not working properly. The mainwindow is not restored.
I've googled a lot and haven't found solutions for that problem.
Thanks in advance!
Calling SetForegroundWindow() on an invisible window isn't going to work. There are many other possible failure mode, FindWindow() is a miserable one when you start passing null.
Don't invent this yourself, .NET already has great built-in support for single instance apps. You can even get a notification when a 2nd copy starts and pass the command line. Which is what you want here, simply restore the window instead of hacking the API. The code you need is here.
After looking through dozens of solutions including the link from Hans, I do not believe that the accepted answer's link will restore an app from the systray. All it seems to be doing is correctly managing a single instance and passing arguments to the single instance.
A more complete solution which was able to manage single instance, restore a minimised window and restore a systray window can be found on codeplex here.
http://www.codeproject.com/KB/cs/SingleInstanceAppMutex.aspx
It's also extremely simple to incorporate into your own code.

Why would Application.Exit fail to work?

I have an application that has been getting strange errors when canceling out of a dialog box. The application can't continue if the box is cancelled out of, so it exits, but it is not working for some reason, and thus it keeps running and crashes.
I debugged this problem, and somehow the application runs right past the Application.Exit call. I'm running in Debug mode, and this is relevant because of a small amount of code that depends on the RELEASE variable being defined. Here is my app exit code. I have traced the code and it entered the ExitApp method, and keeps on going, returning control to the caller and eventually crashing.
This is an application which provides reports over a remote desktop connection, so that's why the exit code is a bit weird. Its trying to terminate the remote session, but only when running under release because I don't want to shut down my dev machine for every test run.
private void ExitApp()
{
HardTerminalExit();
Application.Exit();
}
// When in Debug mode running on a development computer, this will not run to avoid shutting down the dev computer
// When in release mode the Remote Connection or other computer this is run on will be shut down.
[Conditional("RELEASE")]
private void HardTerminalExit()
{
WTSLogoffSession(WTS_CURRENT_SERVER_HANDLE, WTS_CURRENT_SESSION, false);
}
I've run a debugger right past the Application.Exit line and nothing happens, then control returns to the caller after I step past that line.
What's going on? This is a Windows Forms application.
This is an article which expands on the same train of thought you are going through: http://www.dev102.com/2008/06/24/how-do-you-exit-your-net-application/
Basically:
Environment.Exit - From MSDN: Terminates this process and gives the
underlying operating system the
specified exit code. This is the code
to call when you are using console
application.
Application.Exit - From MSDN: Informs all message pumps that they
must terminate, and then closes all
application windows after the messages
have been processed. This is the code
to use if you are have called
Application.Run (WinForms
applications), this method stops all
running message loops on all threads
and closes all windows of the
application. There are some more
issues about this method, read about
it in the MSDN page.
Another discussion of this: Link
This article points out a good tip:
You can determine if System.Windows.Forms.Application.Run has been called by checking the System.Windows.Forms.Application.MessageLoop property. If true, then Run has been called and you can assume that a WinForms application is executing as follows.
if (System.Windows.Forms.Application.MessageLoop)
{
// Use this since we are a WinForms app
System.Windows.Forms.Application.Exit();
}
else
{
// Use this since we are a console app
System.Environment.Exit(1);
}
Having had this problem recently (that Application.Exit was failing to correctly terminate message pumps for win-forms with Application.Run(new Form())), I discovered that if you are spawning new threads or starting background workers within the constructor, this will prevent Application.Exit from running.
Move all 'RunWorkerAsync' calls from the constructor to a form Load method:
public Form()
{
this.Worker.RunWorkerAsync();
}
Move to:
public void Form_Load(object sender, EventArgs e)
{
this.Worker.RunWorkerAsync();
}
Try Environment.Exit(exitCode).
I have went though this situation in many cases I use Thread.CurrentThread.Abort()
and the process is closed. It seems that Application.Exit isn't hooking up properly with current thread.
Also ensure any threads running in your application have the IsBackground property set to true. Non-background threads will easily block the application from exiting.
Make sure you have no Console.ReadLine(); in your app and Environment.Exit(1); will work and close your app.
I created the following that will exit the app anywhere. You don't have to worry if the Form is running or not, the test determines that and calls appropriate Exit.
public void exit(int exitCode)
{
if (System.Windows.Forms.Application.MessageLoop)
{
// Use this since we are a WinForms app
System.Windows.Forms.Application.Exit()
}
else
{
// Use this since we are a console app
System.Environment.Exit(exitCode);
}
} //* end exit()
Is this application run (in the Main method) using Application.Run()? Otherwise, Application.Exit() won't work.
If you wrote your own Main method and you want to stop the application, you can only stop by returning from the Main method (or killing the process).
Try this :
in Program.cs file :
after Application.Run(new form());
add Application.Exit();
private void frmLogin_FormClosing(object sender, FormClosingEventArgs e)
{
if (e.CloseReason == CloseReason.UserClosing)
{
DialogResult result = MessageBox.Show("Do you really want to exit?", "Dialog Title", MessageBoxButtons.YesNo);
if (result == DialogResult.Yes)
{
Environment.Exit(0);
}
else
{
e.Cancel = true;
}
}
else
{
e.Cancel = true;
}
}

how to run a winform from console application?

How do I create, execute and control a winform from within a console application?
The easiest option is to start a windows forms project, then change the output-type to Console Application. Alternatively, just add a reference to System.Windows.Forms.dll, and start coding:
using System.Windows.Forms;
[STAThread]
static void Main() {
Application.EnableVisualStyles();
Application.Run(new Form()); // or whatever
}
The important bit is the [STAThread] on your Main() method, required for full COM support.
I recently wanted to do this and found that I was not happy with any of the answers here.
If you follow Marc's advice and set the output-type to Console Application there are two problems:
1) If you launch the application from Explorer, you get an annoying console window behind your Form which doesn't go away until your program exits. We can mitigate this problem by calling FreeConsole prior to showing the GUI (Application.Run). The annoyance here is that the console window still appears. It immediately goes away, but is there for a moment none-the-less.
2) If you launch it from a console, and display a GUI, the console is blocked until the GUI exits. This is because the console (cmd.exe) thinks it should launch Console apps synchronously and Windows apps asynchronously (the unix equivalent of "myprocess &").
If you leave the output-type as Windows Application, but correctly call AttachConsole, you don't get a second console window when invoked from a console and you don't get the unnecessary console when invoked from Explorer. The correct way to call AttachConsole is to pass -1 to it. This causes our process to attach to the console of our parent process (the console window that launched us).
However, this has two different problems:
1) Because the console launches Windows apps in the background, it immediately displays the prompt and allows further input. On the one hand this is good news, the console is not blocked on your GUI app, but in the case where you want to dump output to the console and never show the GUI, your program's output comes after the prompt and no new prompt is displayed when you're done. This looks a bit confusing, not to mention that your "console app" is running in the background and the user is free to execute other commands while it's running.
2) Stream redirection gets messed up as well, e.g. "myapp some parameters > somefile" fails to redirect. The stream redirection problem requires a significant amount of p/Invoke to fixup the standard handles, but it is solvable.
After many hours of hunting and experimenting, I've come to the conclusion that there is no way to do this perfectly. You simply cannot get all the benefits of both console and window without any side effects. It's a matter of picking which side effects are least annoying for your application's purposes.
Here is the best method that I've found:
First, set your projects output type to "Windows Application", then P/Invoke AllocConsole to create a console window.
internal static class NativeMethods
{
[DllImport("kernel32.dll")]
internal static extern Boolean AllocConsole();
}
static class Program
{
static void Main(string[] args) {
if (args.Length == 0) {
// run as windows app
Application.EnableVisualStyles();
Application.Run(new Form1());
} else {
// run as console app
NativeMethods.AllocConsole();
Console.WriteLine("Hello World");
Console.ReadLine();
}
}
}
It´s very simple to do:
Just add following attribute and code to your Main-method:
[STAThread]
void Main(string[] args])
{
Application.EnableVisualStyles();
//Do some stuff...
while(!Exit)
{
Application.DoEvents(); //Now if you call "form.Show()" your form won´t be frozen
//Do your stuff
}
}
Now you´re fully able to show WinForms :)
You can create a winform project in VS2005/ VS2008 and then change its properties to be a command line application. It can then be started from the command line, but will still open a winform.
All the above answers are great help, but I thought to add some more tips for the absolute beginner.
So, you want to do something with Windows Forms, in a Console Application:
Add a reference to System.Windows.Forms.dll in your Console application project in Solution Explorer. (Right Click on Solution-name->add->Reference...)
Specify the name space in code: using System.Windows.Forms;
Declare the needed properties in your class for the controls you wish to add to the form.
e.g. int Left { get; set; } // need to specify the LEFT position of the button on the Form
And then add the following code snippet in Main():
static void Main(string[] args)
{
Application.EnableVisualStyles();
Form frm = new Form(); // create aForm object
Button btn = new Button()
{
Left = 120,
Width = 130,
Height = 30,
Top = 150,
Text = "Biju Joseph, Redmond, WA"
};
//… more code
frm.Controls.Add(btn); // add button to the Form
// …. add more code here as needed
frm.ShowDialog(); // a modal dialog
}
This worked for my needs...
Task mytask = Task.Run(() =>
{
MyForm form = new MyForm();
form.ShowDialog();
});
This starts the from in a new thread and does not release the thread until the form is closed. Task is in .Net 4 and later.
You should be able to use the Application class in the same way as Winform apps do. Probably the easiest way to start a new project is to do what Marc suggested: create a new Winform project, and then change it in the options to a console application
Its totally depends upon your choice, that how you are implementing.
a. Attached process , ex: input on form and print on console
b. Independent process, ex: start a timer, don't close even if console exit.
for a,
Application.Run(new Form1());
//or -------------
Form1 f = new Form1();
f.ShowDialog();
for b,
Use thread, or task anything,
How to open win form independently?
If you want to escape from Form Freeze and use editing (like text for a button) use this code
Form form = new Form();
Form.Button.Text = "randomText";
System.Windows.Forms.Application.EnableVisualStyles();
System.Windows.Forms.Application.Run(form);

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